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IAL Maths (Edexcel) · Topic M1.5 · 38 cards
Statics of a particle flashcards
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- Equilibrium of a particleThe resultant force on the particle is zero: the components of the forces in any direction add to zero.
- Resultant forceThe single force with the same effect as all the forces acting together; its components are the sums of their components.
- Normal reactionThe contact force from a surface, perpendicular to the surface and away from it.
- ThrustA pushing force in a light rod, acting along the rod towards the particle. (A string can only pull: tension.)
- Coefficient of friction μThe constant for a pair of surfaces such that friction F ≤ μR. It has no units; μ = 0 means a smooth surface.
- Limiting equilibriumAt rest but on the point of moving: friction has reached its maximum, F = μR.
- Smooth surfaceA surface with no friction: the only contact force is the normal reaction.
- Angle of friction λThe angle between the total contact force and the normal in limiting equilibrium: tan λ = μ.
- Components of a force F at angle θ to a directionF cos θ along the direction; F sin θ perpendicular to it. (No — learn it)
- Magnitude and direction of a resultant with components X and YR = √(X² + Y²); tan φ = Y/X, with the quadrant taken from a sketch. (No — learn it)
- Friction on a particle at restF ≤ μR; F = μR in limiting equilibrium. (No — learn it)
- Components of weight on a plane at angle αmg sin α down the plane; mg cos α into the plane. (No — derive it)
- Condition for a particle to rest on a rough plane at angle α with no other forceμ ≥ tan α (the mass cancels). (No — derive it)
- Least force to move a particle of weight mg on rough horizontal groundP_min = mg sin λ, applied at angle λ above the horizontal, where tan λ = μ. (No — derive it)
- Triangle of forces: three forces P, Q, S in equilibriumP/sin(angle opposite P) = Q/sin(angle opposite Q) = S/sin(angle opposite S) — the sine rule. (No — learn it)
- Three forces in equilibrium drawn tip to tailThey form a closed triangle; each interior angle is 180° minus the angle between the two forces meeting there.
- Graph of friction against an increasing horizontal pull P on a particle at restF = P (a line through the origin, gradient 1) until F reaches μR; after that the particle slides.
- Force diagram: particle on a rough plane about to slide UPWeight vertically down; R perpendicular to the plane; friction μR DOWN the plane; applied force.
- Force diagram: particle on a rough plane about to slide DOWNWeight vertically down; R perpendicular to the plane; friction μR UP the plane; applied force.
- Graph of the pull P needed to move a particle against the angle θ above the horizontalFalls from μmg at θ = 0 to a minimum at tan θ = μ, then rises steeply.
- Why can resolving give at most two unknowns for a particle?Only two independent directions exist in a plane, so resolving gives two independent equations.
- Why is R ≠ mg cos α when a horizontal force pushes a particle on a plane?The horizontal force has a component P sin α into the plane, so R = mg cos α + P sin α.
- Why is there a range of forces that hold a particle at rest on a rough plane?Friction can act either way along the plane, up to μR. The two ends of the range are the two limiting cases.
- Why does pulling slightly upwards make a particle easier to move on rough ground?The upward component reduces R, and so the maximum friction μR, by more than the horizontal pull is reduced.
- Which way does friction act on a particle at rest?Along the surface, opposite to the motion that would happen if the surface were smooth.
- One force is removed from a set of forces in equilibrium. What is the resultant of the rest?Equal in size and opposite in direction to the force removed.
- Find the magnitude of the resultant of (4i + 2j) N and (−i + 2j) N, and its angle with i.Resultant (3i + 4j) N; magnitude 5 N; angle tan⁻¹(4/3) = 53.1° to i.
- A 40 N weight hangs from the midpoint of a string; each half makes 35° with the horizontal. Tension?2T sin 35° = 40, so T = 34.9 N.
- A 2.5 kg particle on a smooth plane at 30° is held by a horizontal force P. Find P.P cos 30° = 2.5g sin 30°, so P = 2.5g tan 30° = 14.1 N.
- A 5 kg particle on rough horizontal ground is about to slide when a horizontal 18 N force acts. Find μ.R = 5g = 49 N; μ = 18/49 = 0.367.
- A 3 kg particle rests on rough ground (μ = 0.3) with a 5 N horizontal force on it. Friction?5 N. The maximum, μR = 0.3 × 29.4 = 8.82 N, is not reached.
- A particle on a rough plane is about to slide when the plane is at 32°. Find μ.μ = tan 32° = 0.625.
- Least force to move an 8 kg particle on rough ground with μ = 0.25?At tan⁻¹ 0.25 = 14.0° above the horizontal: P = 8g sin 14.0° = 19.0 N.
- Friction for a particle that is simply 'at rest'Find F by resolving. Only use F = μR if the question says 'on the point of', 'about to', 'just' or 'limiting'.
- R = mg cos α on every inclined planeWrong whenever another force has a component perpendicular to the plane: always resolve perpendicular in full.
- Range of P on a rough plane: one equation for both casesRe-resolve for each case: friction changes direction and R usually changes too.
- Rounding with g = 9.8Keep full calculator values between steps; give final answers to 2 or 3 significant figures.
- Writing resolving equationsLabel each one with its direction, e.g. R(↑) or R(parallel to the plane), and write every term before simplifying.