ExaminerPrep › IAL Maths (Edexcel) › Flashcards
IAL Maths (Edexcel) · Topic P2.8 · 38 cards
Definite integration, areas and the trapezium rule flashcards
Test yourself one card at a time: say the answer, flip, then mark it. Cards you know drop out; the rest come back until you know them. Your progress stays in this browser.
- Definite integralAn integral with limits: ∫ₐᵇ f(x) dx = F(b) − F(a), where F′(x) = f(x). Its value is a number.
- Lower and upper limitsIn ∫ₐᵇ f(x) dx, a is the lower limit and b the upper limit; substitute both and subtract, upper minus lower.
- Ordinates (trapezium rule)The y-values y₀, y₁, …, yₙ at the equally spaced x-values a, a + h, …, b.
- Strip width hh = (b − a)/n, where n is the number of strips. n strips use n + 1 ordinates.
- Percentage error|estimate − exact value| ÷ exact value × 100%.
- Convex / concave (bending up / down)Convex: the curve bends upwards and chords lie above it. Concave: it bends downwards and chords lie below it.
- ∫ₐᵇ f(x) dx[F(x)]ₐᵇ = F(b) − F(a), where F is any integral of f. No + c. (No — learn it)
- Area between a curve and the x-axis (curve above the axis)Area = ∫ₐᵇ y dx. (No — learn it)
- Area between two graphs meeting at x = a and x = b∫ₐᵇ (y_top − y_bottom) dx. (No — derive it)
- ∫xⁿ dx (power rule, n ≠ −1)xⁿ⁺¹/(n + 1) + c: raise the power by one and divide by the new power. In a definite integral the + c cancels. (No — learn it)
- Trapezium rule∫ₐᵇ y dx ≈ ½h{y₀ + yₙ + 2(y₁ + y₂ + … + yₙ₋₁)}, h = (b − a)/n. (Yes)
- ∫ₐᵇ f(x) dx with the limits swappedSwapping the limits changes the sign: the integral from b to a equals −∫ₐᵇ f(x) dx. (No — derive it)
- Sign of ∫ₐᵇ y dx for a region below the x-axisNegative. The area is the size of the integral.
- A curve crosses the x-axis between the limitsSplit the integral at the crossing point; the parts have opposite signs and would partly cancel.
- Region bounded by a curve, a straight line and the x-axisUsually split it: area under the curve (integrate) plus a triangle or trapezium under the line (geometry).
- Trapezium rule on a curve that bends upwardsThe chords lie above the curve: the rule overestimates.
- Trapezium rule on a curve that bends downwardsThe chords lie below the curve: the rule underestimates.
- Effect of doubling the number of stripsThe chords hug the curve more closely; the error becomes smaller (roughly a quarter for smooth curves).
- Why is there no + c in a definite integral?It appears in both F(b) + c and F(a) + c, so it cancels on subtraction.
- Can a definite integral be zero when there is a region?Yes — equal areas above and below the x-axis cancel. Check where the curve crosses the axis.
- Why does 'top − bottom' work even below the x-axis?The vertical gap y_top − y_bottom is positive wherever the top graph is above, whatever the sign of y.
- Where do the limits for an area come from?From the region: where the curve meets the axis, where two graphs meet, or given lines x = a and x = b.
- Why does the trapezium rule count inner ordinates twice?Each inner ordinate is a side of two neighbouring trapezia.
- When can you find a percentage error for a trapezium estimate?Only when the exact value is known, e.g. when the integral can also be found algebraically.
- ∫₁² (4x³ − 2x) dx[x⁴ − x²]₁² = (16 − 4) − (1 − 1) = 12.
- ∫₄⁹ 1/√x dx[2√x]₄⁹ = 6 − 4 = 2.
- Area enclosed by y = 4x − x² and the x-axisLimits 0 and 4: [2x² − x³/3]₀⁴ = 32 − 64/3 = 32/3.
- ∫₀¹ (x² − 1) dx, and the area it represents[x³/3 − x]₀¹ = −2/3; the region is below the axis, so its area is 2/3.
- Area between y = x² and y = 2xMeet at x = 0, 2; line on top: ∫₀² (2x − x²) dx = 4 − 8/3 = 4/3.
- Trapezium rule, 2 strips: ∫₀¹ 1/(1 + x) dxh = 0.5; y = 1, 2/3, 1/2: 0.25{1 + 0.5 + 2(2/3)} = 17/24 ≈ 0.708.
- Estimate 4.2, exact value 4: percentage error?(4.2 − 4)/4 × 100 = 5%.
- Given ∫₀² f(x) dx ≈ 3.5, estimate ∫₀² (f(x) + 2) dx3.5 + ∫₀² 2 dx = 3.5 + 4 = 7.5.
- Subtracting F(a) without bracketsWrite (F(b)) − (F(a)); every term of F(a) changes sign.
- Giving a negative areaAreas are positive. A negative integral means the region is below the axis — state its size.
- Integrating straight across a root for an areaGives the difference of the areas, not their sum. Split at the root.
- Using the number of ordinates in h = (b − a)/nn is the number of strips; there is one more ordinate than strips.
- 'Over- or underestimate?' with no reasonGive the shape (bends up/down, chords above/below the curve) and then the conclusion.
- Rounding ordinates too earlyKeep at least 4 decimal places in the table; round only the final estimate.