ExaminerPrep › IAL Physics (Edexcel) › Flashcards
IAL Physics (Edexcel) · Topic 1.1 · 38 cards
Motion, vectors and projectiles flashcards
Test yourself one card at a time: say the answer, flip, then mark it. Cards you know drop out; the rest come back until you know them. Your progress stays in this browser.
- Scalar quantityA quantity with magnitude only (e.g. speed, mass, energy).
- Vector quantityA quantity with both magnitude and direction (e.g. displacement, velocity, force).
- DisplacementDistance in a stated direction from the starting point. A vector, unit m.
- VelocityRate of change of displacement. A vector, unit m s⁻¹.
- AccelerationRate of change of velocity. A vector, unit m s⁻².
- Resultant vectorThe single vector that has the same effect as two or more vectors combined.
- ProjectileA body moving freely under gravity alone after being launched (air resistance negligible).
- Uniform accelerationAcceleration that is constant in both magnitude and direction.
- The four equations of uniformly accelerated motionv = u + at · s = ½(u + v)t · s = ut + ½at² · v² = u² + 2as (Yes)
- Components of a vector F at angle θ to the horizontalHorizontal F cos θ; vertical F sin θ. (No — learn it)
- Magnitude and direction of the resultant of perpendicular vectors A and BR = √(A² + B²); angle to A = tan⁻¹(B/A). (No — learn it)
- Fall from rest through height h in time th = ½gt² (s = ut + ½at² with u = 0). (No — derive it)
- Time to the highest point for launch speed u at angle θt = u sin θ / g (vertical velocity becomes zero). (No — derive it)
- Gradient of a displacement–time graphVelocity (the gradient of the tangent gives instantaneous velocity).
- Gradient of a velocity–time graphAcceleration.
- Area under a velocity–time graphDisplacement. Areas below the time axis count as negative displacement.
- Area under an acceleration–time graphChange in velocity.
- Shape of the s–t graph for uniform acceleration from restA curve of steadily increasing gradient (a parabola through the origin).
- What does a curved velocity–time graph tell you?The acceleration is not uniform; find it from the gradient of a tangent, and the displacement from the area by counting squares.
- Core Practical 1: which graph gives g, and how?Plot h against t²; it is a straight line through the origin with gradient g/2, so g = 2 × gradient.
- Why are the horizontal and vertical motions of a projectile independent?Gravity acts only vertically, so the horizontal velocity stays constant while the vertical velocity changes at g.
- Velocity and acceleration of a projectile at its highest pointVelocity: horizontal only, equal to u cos θ. Acceleration: g = 9.81 m s⁻² downwards.
- When can you add two vectors by Pythagoras?Only when they are at right angles. At other angles use a scale drawing or add components.
- When can the equations of motion be used?Only for constant acceleration in a straight line.
- Core Practical 1: why use an electronic timer?Human reaction time (about 0.2 s) is comparable to fall times of 0.2–0.5 s.
- Core Practical 1: effect of measuring h from the top of the ballEvery h is too large by the ball's diameter: the line shifts (intercept) but the gradient, and so g, is unchanged.
- A boat moves at 9.0 m s⁻¹ east and is pushed 4.0 m s⁻¹ north by a current. Resultant velocity?√(9.0² + 4.0²) = 9.8 m s⁻¹ at tan⁻¹(4.0/9.0) = 24° north of east.
- Resolve 120 N acting at 40° above the horizontal.Horizontal 120 cos 40° = 92 N; vertical 120 sin 40° = 77 N.
- A car speeds up uniformly from 5.0 to 25 m s⁻¹ over 150 m. Acceleration?v² = u² + 2as → a = (625 − 25)/300 = 2.0 m s⁻². (Yes)
- A ball leaves a 2.0 m high ledge horizontally at 12 m s⁻¹. How far does it travel horizontally?t = √(2 × 2.0 / 9.81) = 0.64 s; distance = 12 × 0.639 = 7.7 m.
- v–t graph: 0 → 10 m s⁻¹ uniformly in 4.0 s, then constant for 6.0 s. Distance?Area = ½ × 4.0 × 10 + 6.0 × 10 = 80 m.
- A ball is kicked at 15 m s⁻¹ at 30° from level ground. Time of flight?u_V = 15 sin 30° = 7.5 m s⁻¹; time up = 7.5/9.81 = 0.76 s; total 1.5 s.
- Vector answer with no directionIncomplete. Give a sign with the positive direction stated, an angle from a named reference, or a compass direction.
- Angle given from the verticalThe vertical component is F cos θ and the horizontal component is F sin θ — the roles swap.
- A body below its launch point (upwards positive)Its displacement is negative: s = −h. Getting this sign wrong spoils every later step.
- “Show that” questionsShow every step and give the answer to one more significant figure than the value quoted.
- Finding a gradient from a graphUse a triangle covering at least half of the line and read its corners from the line, not from data points.
- Which value of g?Use 9.81 m s⁻² from the data list, not 10 m s⁻².