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IAL Physics (Edexcel) · Topic 4.2 · 37 cards
Circular motion flashcards
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- RadianThe angle at the centre of a circle subtended by an arc equal in length to the radius. 2π rad = 360°.
- Angular displacementThe angle through which a radius line turns about the centre, in rad or degrees.
- Angular velocity ωAngle turned through per unit time, ω = Δθ/Δt. Unit rad s⁻¹.
- Period T of circular motionTime for one complete revolution. T = 2π/ω.
- Centripetal accelerationThe acceleration of a body moving in a circle, directed towards the centre; a = v²/r = rω².
- Centripetal forceThe resultant force towards the centre needed to keep a body moving in a circle; F = mv²/r. It is provided by real forces.
- Arc length from angles = rθ, with θ in radians. (No — learn it)
- Linear speed from angular velocityv = ωr (Yes)
- Period from angular velocityT = 2π/ω (so ω = 2πf, with f = 1/T). (Yes)
- Two forms of the centripetal accelerationa = v²/r = rω² (Yes)
- Two forms of the centripetal forceF = ma = mv²/r = mrω² (Yes)
- Minimum speed at the top of a vertical circlev = √(gr): tension or reaction is zero and mg = mv²/r. (No — derive it)
- Conical pendulum angle θ to the verticaltan θ = v²/(rg), from T cos θ = mg and T sin θ = mv²/r. (No — derive it)
- Vector diagram for a = v²/rDraw v_A and v_B tail to tail with angle Δθ between them; Δv joins their tips and points to the centre; |Δv| = vΔθ.
- Direction of velocity and acceleration in uniform circular motionVelocity along the tangent; acceleration along the radius, towards the centre — always at 90° to each other.
- Free-body diagram: car on a banked trackWeight down; normal reaction perpendicular to the track. N cos θ balances the weight, N sin θ points to the centre.
- Graph to test F = mrω² (m and r fixed)F against ω²: straight line through the origin, gradient = mr.
- Path of a whirled ball when the string breaksA straight line along the tangent at the point of release, not along the radius.
- Why is a body moving in a circle at constant speed accelerating?Its velocity changes direction; a change in velocity is an acceleration (towards the centre).
- Why is a resultant force needed for circular motion?With no resultant force a body moves in a straight line (first law); to accelerate towards the centre, F = ma requires a force towards the centre.
- Why does the centripetal force do no work?It is perpendicular to the velocity, so there is no displacement along the force; speed and kinetic energy stay constant.
- What provides the centripetal force for a car on a flat bend?Sideways friction between the tyres and the road, acting towards the centre.
- How does banking help a vehicle round a bend?The tilted normal reaction has a horizontal component towards the centre, so less friction is needed; at one speed none is needed.
- Forces at the top and bottom of a vertical loop (rider inside)Top: N + mg = mv²/r. Bottom: N − mg = mv²/r. The reaction is largest at the bottom.
- Same rigid body, different radii: what is the same?Angular velocity ω is the same everywhere; speed v = ωr is larger further from the axis.
- Convert 54° to radians.54 × π/180 = 0.942 rad.
- A record turns at 33.3 rev per minute. Angular velocity?ω = 2π × 33.3 ÷ 60 = 3.49 rad s⁻¹.
- A point 0.30 m from an axis has period 0.50 s. Its speed?v = 2πr/T = 2π × 0.30 ÷ 0.50 = 3.8 m s⁻¹. (Yes)
- A 0.15 kg ball moves at 6.0 m s⁻¹ in a horizontal circle of radius 0.90 m. Tension?F = mv²/r = 0.15 × 36 ÷ 0.90 = 6.0 N. (Yes)
- Minimum speed at the top of a vertical loop of radius 4.0 m?v = √(gr) = √(9.81 × 4.0) = 6.3 m s⁻¹. (No — derive it)
- Centripetal acceleration 0.12 m from the axis of a shaft turning at 50 rev s⁻¹?ω = 2π × 50 = 314 rad s⁻¹; a = rω² = 0.12 × 314² = 1.2 × 10⁴ m s⁻². (Yes)
- A 900 kg car takes a flat bend of radius 60 m at 15 m s⁻¹. Friction needed?F = mv²/r = 900 × 225 ÷ 60 = 3.4 kN, towards the centre. (Yes)
- Angle in degrees in s = rθ or ω = Δθ/ΔtWrong: these need radians. Convert first (× π/180).
- Revolutions per minute givenω = 2π × (rev min⁻¹) ÷ 60. Do not forget either the 2π or the 60.
- Adding a “centripetal force” arrow to a free-body diagramDon't. Draw only real forces; their resultant towards the centre is the centripetal force.
- Radius of a conical pendulum or swing rideUse the horizontal distance from the axis to the body, not the length of the string or chain.
- Speeds at different points on a vertical circleThe speed is not constant: link speeds at different heights with conservation of energy.