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IAL Physics (Edexcel) · Topic 5.6 · 37 cards
Energy, damping and resonance flashcards
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- Free oscillationAn oscillation with no external periodic force acting; the system oscillates at its natural frequency.
- Forced oscillationAn oscillation driven by an external periodic force; in the steady state the system oscillates at the driving frequency.
- Natural frequency f₀The frequency at which a system oscillates when displaced and then left to oscillate freely.
- ResonanceThe large increase in amplitude of a forced oscillation when the driving frequency equals the natural frequency; energy is transferred most efficiently.
- DampingA force opposing the motion of an oscillator that transfers energy out of the system (usually to thermal energy), so the amplitude decreases.
- Critical dampingThe amount of damping that returns a displaced system to equilibrium in the shortest time without oscillating.
- Light and heavy dampingLight: oscillates with slowly decreasing amplitude. Heavy: no oscillation, but returns to equilibrium more slowly than critical damping.
- Ductile material (in damping)A material that can undergo large plastic deformation, repeatedly, without fracturing — so it can dissipate energy each cycle.
- Period of a mass–spring oscillatorT = 2π√(m/k); f = 1/T. (Yes)
- Total energy of a mass–spring oscillatorE = ½kA² (strain energy at the extreme). (No — derive it)
- Kinetic energy at displacement xE_k = ½k(A² − x²) = total − ½kx². (No — derive it)
- Energy and amplitude, any oscillatorE ∝ A²: doubling A gives 4E; halving E gives A/√2. (No — learn it)
- Core Practical 16 straight-line formT² = (4π²/k)m, so gradient of T² against m = 4π²/k. (No — derive it)
- Energy dissipated per cycle by plastic deformationArea enclosed by the force–extension loop. (No — learn it)
- Energy against displacement for an undamped oscillatorPE: parabola, zero at x = 0, maximum at ±A. KE: inverted parabola, maximum at x = 0. Total: horizontal line.
- Energy against time for an undamped oscillatorKE and PE both vary at twice the oscillation frequency, never negative, out of step; their sum is constant.
- Displacement–time graph with light dampingOscillation at almost constant period inside an exponentially decaying envelope; amplitude falls by the same fraction each cycle.
- Resonance curve (amplitude against driving frequency)Small at low frequency, sharp peak at (or just below) f₀, very small at high frequency.
- Effect of more damping on the resonance curvePeak lower, broader and at a slightly lower frequency; little change far from f₀.
- Core Practical 16 apparatusSpring hung from a vibration generator driven by a signal generator; slotted masses; metre rule and pointer to judge amplitude.
- Why does a forced oscillation reach a steady amplitude?The amplitude grows until the energy supplied by the driver each cycle equals the energy removed by damping each cycle.
- Why is the energy transfer greatest at resonance?The driving force is in step with the motion, so it does positive work on the oscillator throughout each cycle.
- How do car shock absorbers work?Oil is forced through small holes; viscous drag transfers the oscillation energy to thermal energy. Damping is near critical.
- Three ways a building in an earthquake zone limits its oscillationNatural frequency kept away from earthquake frequencies (e.g. base isolators); dampers remove energy; ductile steel deforms plastically, dissipating energy.
- Why must earthquake dampers be ductile, not brittle?Ductile metal can deform plastically many times, dissipating energy each cycle; a brittle material would crack and absorb little energy.
- Core Practical 16: why is there an intercept on the T² axis?Part of the spring's own mass oscillates with the load, adding an effective extra mass.
- Core Practical 16: how is the resonant frequency found?Increase the signal-generator frequency in small steps and find where the amplitude of the mass is greatest; repeat from above and average.
- m = 0.40 kg, k = 25 N m⁻¹, A = 6.0 cm. Total energy and maximum speed?E = ½ × 25 × 0.060² = 0.045 J; v_max = √(2 × 0.045 ÷ 0.40) = 0.47 m s⁻¹.
- Damping reduces the amplitude to 80% of its starting value. Fraction of energy left?0.80² = 0.64, so 64% of the energy remains (36% lost).
- Car body 1400 kg on suspension k = 2.0 × 10⁵ N m⁻¹; humps 6.0 m apart. Resonant speed?f₀ = (1/2π)√(k/m) = 1.9 Hz; v = f₀ × 6.0 = 11 m s⁻¹.
- T² against m has gradient 1.97 s² kg⁻¹. Spring constant?k = 4π² ÷ 1.97 = 20 N m⁻¹.
- Oscillation energy 1.97 × 10⁴ J at amplitude 0.10 m; dampers remove 3.2 kJ. New amplitude?A = 0.10 × √(16.5 ÷ 19.7) = 0.092 m.
- Amplitude and energy ratiosSquare an amplitude ratio to get the energy ratio; square-root an energy ratio to get the amplitude ratio.
- Defining resonanceName both: driving frequency = natural frequency; then maximum amplitude and maximum energy transfer. “Frequencies match” alone is too vague.
- Critical vs heavy dampingBoth avoid oscillation; critical is the quickest return to equilibrium. Always state both parts.
- Using √(k/m) as a frequency√(k/m) is ω in rad s⁻¹; divide by 2π for f in Hz.
- Where does damped energy go?Say it: transferred from kinetic/potential energy of the oscillator to thermal energy of the surroundings or damper.