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IAL Physics (Edexcel) · Topic 5.8 · 37 cards
Stars: radiation, distances and the HR diagram flashcards
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- Black bodyAn idealised object that absorbs all the electromagnetic radiation falling on it; its emitted spectrum depends only on its temperature.
- Luminosity LThe total power output of a star: the energy it radiates per second in all directions (W).
- Intensity IPower per unit area incident at right angles to the direction of the radiation (W m⁻²).
- Parallax angle pHalf the angular shift of a nearby star against distant stars over six months: the angle at the star subtended by 1 AU.
- Parsec (pc)The distance at which 1 AU subtends an angle of 1 arcsecond. 1 pc = 3.09 × 10¹⁶ m ≈ 3.26 ly.
- Light-year (ly)The distance light travels in a vacuum in one year: 9.46 × 10¹⁵ m.
- Standard candleAn astronomical object of known luminosity, so its distance can be found from the intensity received at Earth.
- Hertzsprung–Russell (HR) diagramA plot of luminosity (log scale) against surface temperature (log scale, decreasing to the right) for stars.
- Wien's displacement lawλmax T = 2.898 × 10⁻³ m K (T in kelvin). (Yes)
- Stefan–Boltzmann lawL = σAT⁴, σ = 5.67 × 10⁻⁸ W m⁻² K⁻⁴. (Yes)
- Luminosity of a spherical star of radius rL = 4πr²σT⁴ (A = 4πr²). (No — learn it)
- Intensity at distance d from a starI = L/4πd² (Yes)
- Distance by parallaxd = r/tan p ≈ r/p (r = 1 AU, p in radians); in parsecs d = 1/p with p in arcseconds. (No — learn it)
- Distance from a standard candled = √(L/4πI) (No — derive it)
- Black-body curve: effect of a higher temperatureCurve higher at every wavelength, peak at a shorter wavelength, area (∝ T⁴) much larger.
- What does the area under a black-body curve represent?The total power emitted per unit area of the surface, proportional to T⁴.
- HR diagram axesVertical: luminosity (or L/L☉), log scale. Horizontal: surface temperature, log scale, hottest on the LEFT.
- Positions on the HR diagramMain sequence: diagonal band. Red giants: above it, right. Supergiants: across the top. White dwarfs: bottom left.
- Lines of constant radius on an HR diagramDiagonal lines (L ∝ T⁴ at fixed r); stars get larger towards the top right.
- Path of a Sun-like star on the HR diagramMain sequence → up and right to red giant → (planetary nebula) → white dwarf at bottom left, fading down and right.
- Why is a red giant luminous although it is cool?L = 4πr²σT⁴: its enormous surface area more than makes up for the low temperature.
- Why is a white dwarf dim although it is hot?Its radius is tiny (about Earth-sized), so its surface area is very small.
- Why does parallax work only for nearby stars?The angle is ∝ 1/d; for distant stars it is too small to measure against its uncertainty.
- Why are parallax measurements taken six months apart?The Earth is on opposite sides of its orbit: the largest baseline (2 AU) and the largest shift.
- What decides how a star's life ends?Its mass. Up to about 8 M☉: white dwarf. More massive: supernova, then neutron star (core ≈ 1.4–3 M☉) or black hole (core > ≈ 3 M☉).
- Why do massive stars have shorter lives?They are far more luminous, so they use up their core hydrogen much faster despite having more of it.
- Luminosity vs apparent brightnessLuminosity is the star's power output; apparent brightness (intensity at Earth) also depends on distance, I = L/4πd².
- A star's spectrum peaks at 480 nm. Surface temperature?T = 2.898 × 10⁻³ ÷ 480 × 10⁻⁹ = 6040 K.
- Luminosity of a star of radius 7.0 × 10⁸ m and surface temperature 6000 K?L = 4π(7.0 × 10⁸)² × 5.67 × 10⁻⁸ × 6000⁴ = 4.5 × 10²⁶ W.
- Intensity at Earth from a star of luminosity 4.0 × 10²⁷ W at 5.0 × 10¹⁷ m?I = 4.0 × 10²⁷ ÷ (4π × (5.0 × 10¹⁷)²) = 1.3 × 10⁻⁹ W m⁻².
- Parallax angle 0.40 arcseconds. Distance in pc and in m?d = 1 ÷ 0.40 = 2.5 pc = 2.5 × 3.09 × 10¹⁶ = 7.7 × 10¹⁶ m.
- Star X: radius 2.0 times and temperature 1.5 times those of star Y. Ratio L_X/L_Y?L ∝ r²T⁴: 2.0² × 1.5⁴ = 4 × 5.06 = 20.
- Standard candle of luminosity 3.0 × 10²⁹ W, measured intensity 6.0 × 10⁻¹² W m⁻². Distance?d = √(3.0 × 10²⁹ ÷ (4π × 6.0 × 10⁻¹²)) = 6.3 × 10¹⁹ m.
- Before using Wien or Stefan–Boltzmann…Temperature in kelvin (°C + 273) and wavelength in metres (nm × 10⁻⁹).
- Finding d from I = L/4πd²Rearrange in symbols first: d = √(L/4πI). Don't forget the square root or the square on d.
- Percentage uncertainty in L = 4πr²σT⁴%L = 2 × %r + 4 × %T: the fourth power makes temperature errors dominate.
- Sketching an HR diagramLabel both axes with quantities, hottest temperature on the left, and mark main sequence, red giants, supergiants and white dwarfs.