246 free, high-quality past-paper-style questions on Number for Cambridge IGCSE Maths, each with a full mark scheme. Covers: Fractions, decimals and percentages; Estimation, rounding, bounds, ratio, proportion and money; Types of number, factors, HCF and LCM; and more. For when you have finished the past papers, or want to practise one topic at a time.Not sure of your level? Diagnostic test →Multiple choice or structured questions, with the mark scheme as a separate PDF.1,353 marks · Updated 26 October 2026 · Created by Evan Kotronis with AI assistance · How questions are checked
1IGMC-041-01-01Fractions, decimals and percentagesPaper CEasy4 marks
No calculator
Show all your working. Give each answer as a fraction in its simplest form.
(a)
Work out \(2\frac{3}{4} - 1\frac{5}{6}\).
(2)
(b)
Work out \(\frac{3}{5} \div \frac{9}{10}\).
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 for converting to improper fractions over a common denominator, e.g. \(\frac{33}{12} - \frac{22}{12}\)
✓ 1
A1 \(\frac{11}{12}\)
✓ 1
Part (b)
M1 for \(\frac{3}{5} \times \frac{10}{9}\) or equivalent, e.g. \(\frac{30}{45}\)
✓ 1
A1 \(\frac{2}{3}\)
✓ 1
Exam tip: Without a calculator, you must show the common denominator or the 'multiply by the reciprocal' step. A correct answer alone may not earn the method mark.
2IGMC-041-01-02Fractions, decimals and percentagesPaper CEasy4 marks
Calculator
A jacket normally costs $64.
(a)
In a sale, the price of the jacket is reduced by 15%. Work out the sale price.
(2)
(b)
The shop bought the jacket for $40 and sells it at the normal price of $64. Work out the percentage profit.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 for 64 × 0.85 or 64 − 0.15 × 64
✓ 1
A1 $54.40
✓ 1
Part (b)
M1 for \(\frac{64-40}{40}\) × 100 or \(\frac{64}{40}\) × 100 − 100
✓ 1
A1 60%
✓ 1
Common error: Percentage profit is calculated on the cost price ($40), not the selling price. Dividing 24 by 64 gives 37.5%, which is wrong.
3IGMC-041-01-03Fractions, decimals and percentagesPaper CEasy4 marks
No calculator
(a)
Write 0.35 as a fraction in its simplest form.
(1)
(b)
Write \(\frac{3}{8}\) as a percentage.
(1)
(c)
Write these numbers in order of size, starting with the smallest. 0.38 \(\frac{3}{8}\) 37% \(\frac{7}{20}\)
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 \(\frac{7}{20}\)
✓ 1
Part (b)
B1 37.5%
✓ 1
Part (c)
M1 for converting all four to the same form, e.g. 0.38, 0.375, 0.37, 0.35
✓ 1
A1 \(\frac{7}{20}\), 37%, \(\frac{3}{8}\), 0.38
✓ 1
Exam tip: When ordering, convert everything to decimals and write the decimals down. Then give the final answer using the original numbers, not the decimals.
4IGMC-041-01-04Fractions, decimals and percentagesPaper CEasy4 marks
Calculator
There are 840 students in a school.
(a)
45% of the students walk to school. Work out how many students walk to school.
(1)
(b)
126 students cycle to school. Work out the percentage of students who cycle to school.
(1)
(c)
All the other students travel by bus. Write the fraction of students who travel by bus in its simplest form.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 378
✓ 1
Part (b)
B1 15%
✓ 1
Part (c)
M1 for 100 − 45 − 15 (= 40%) or 840 − 378 − 126 (= 336)
✓ 1
A1 \(\frac{2}{5}\)
✓ 1
Common error: Leaving the answer to (c) as \(\frac{336}{840}\) or 40% loses the accuracy mark. The question asks for a fraction in its simplest form.
5IGMC-041-01-05Fractions, decimals and percentagesPaper CEasy3 marks
Calculator
Kofi invests $2500 in a savings account. The account pays simple interest at a rate of 3.2% per year.
(a)
Work out the interest Kofi earns in 4 years.
(2)
(b)
Work out the total amount in the account after 4 years.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 for 2500 × 0.032 × 4 or \(\frac{2500 \times 3.2 \times 4}{100}\)
✓ 1
A1 $320
✓ 1
Part (b)
B1 $2820, or FT 2500 + their answer to (a)
✓ 1
Common error: Simple interest is the same every year. Using the multiplier 1.032⁴ is compound interest and gives the wrong answer here.
6IGMC-041-03-01Estimation, rounding, bounds, ratio, proportion and moneyPaper CEasy3 marks
No calculator
(a)
Write 0.0047386 correct to 3 significant figures.
(1)
(b)
By rounding each number to 1 significant figure, estimate the value of \(\frac{48.7 \times 3.12}{0.198}\). Show all your working.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1: 0.00474
✓ 1
Part (b)
M1: \(\frac{50 \times 3}{0.2}\) seen
✓ 1
A1: 750
✓ 1
Common error: Leading zeros are not significant. 0.0047386 starts its significant figures at the 4, so 3 s.f. gives 0.00474, not 0.005.
7IGMC-041-03-02Estimation, rounding, bounds, ratio, proportion and moneyPaper CEasy4 marks
No calculator
Amira, Ben and Chen share 360 dollars in the ratio Amira : Ben : Chen = 2 : 3 : 4.
(a)
Work out how much Chen receives.
(2)
(b)
Chen then gives one quarter of his share to Amira. Find the new ratio Amira : Ben : Chen in its simplest form.
M1: new amounts 120, 120, 120 dollars (Amira 80 + 40, Ben 120, Chen 160 − 40)
✓ 1
A1: 1 : 1 : 1
✓ 1
Exam tip: Find the value of one share first (total ÷ sum of the ratio parts). Every other amount then follows by multiplying.
8IGMC-041-03-03Estimation, rounding, bounds, ratio, proportion and moneyPaper CEasy4 marks
No calculator
The side length of a square tile is 12.4 cm, correct to the nearest 0.1 cm.
Diagram not to scale
(a)
Write down the lower bound and the upper bound of the side length.
(2)
(b)
Calculate the upper bound of the perimeter of the tile.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1: lower bound 12.35 cm
✓ 1
B1: upper bound 12.45 cm
✓ 1
Part (b)
M1: 4 × 12.45
✓ 1
A1: 49.8 cm
✓ 1
Common error: The upper bound is 12.45, not 12.44 or 12.449. Use the half-unit either side of the rounded value.
9IGMC-041-03-04Estimation, rounding, bounds, ratio, proportion and moneyPaper CEasy5 marks
Calculator
The exchange rate is 1 euro (€) = 1.08 US dollars ($).
(a)
Change €250 into dollars.
(1)
(b)
Change $500 into euros. Give your answer correct to the nearest cent.
(2)
(c)
A jacket costs €85 in Paris and $95 in New York. Find which city sells the jacket more cheaply and by how many dollars.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1: $270
✓ 1
Part (b)
M1: 500 ÷ 1.08
✓ 1
A1: €462.96
✓ 1
Part (c)
M1: 85 × 1.08 = 91.80
✓ 1
A1: Paris, by $3.20
✓ 1
Exam tip: Check your conversion makes sense: one euro is worth more than one dollar, so the number of euros should be smaller than the number of dollars.
10IGMC-041-03-05Estimation, rounding, bounds, ratio, proportion and moneyPaper CEasy4 marks
No calculator
A recipe for 6 muffins uses 150 g of flour, 2 eggs and 90 ml of milk. The recipe can be scaled up or down to make any whole number of muffins.
(a)
Work out the mass of flour needed for 15 muffins.
(2)
(b)
Lina has 7 eggs and plenty of every other ingredient. Find the greatest number of muffins she can make.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1: 150 ÷ 6 × 15 or 150 × 2.5
✓ 1
A1: 375 g
✓ 1
Part (b)
M1: 6 ÷ 2 = 3 muffins per egg, or 7 ÷ 2 × 6
✓ 1
A1: 21
✓ 1
Exam tip: Work out the amount for one muffin (or one egg) first. Then scale up to any number.
11IGMC-041-00-01Types of number, factors, HCF and LCMPaper CEasy5 marks
No calculator
Here is a list of numbers.
9 17 21 25 31 36 39 64
From the list, write down
(a)
all the prime numbers,
(2)
(b)
all the square numbers,
(1)
(c)
a cube number,
(1)
(d)
a multiple of 13.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 for at least one of 17 or 31 correctly listed, with at most one incorrect number included
✓ 1
B1 for 17 and 31 only, with no other numbers included
✓ 1
Part (b)
B1 for 9, 25, 36 and 64 only
✓ 1
Part (c)
B1 for 64
✓ 1
Part (d)
B1 for 39
✓ 1
Common error: 21 and 39 are odd but not prime: 21 = 3 × 7 and 39 = 3 × 13. Test each odd number for small prime divisors before calling it prime.
12IGMC-041-00-02Types of number, factors, HCF and LCMPaper CEasy3 marks
No calculator
(a)
Write 360 as a product of its prime factors. Give your answer in index form.
(2)
(b)
Find the smallest positive integer k such that 360k is a square number.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 for a correct method, e.g. a factor tree or repeated division reaching 2, 2, 2, 3, 3, 5
✓ 1
A1 for 23 × 32 × 5
✓ 1
Part (b)
B1 for 10
✓ 1
Exam tip: A square number has every prime power even in its prime factorisation. Here 2³ needs one more 2 and 5 needs one more 5, so multiply by 2 × 5.
13IGMC-041-00-03Types of number, factors, HCF and LCMPaper CEasy4 marks
No calculator
(a)
List all the factors of 18.
(2)
(b)
Find the highest common factor (HCF) of 18 and 24.
(1)
(c)
Find the lowest common multiple (LCM) of 18 and 24.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B2 for 1, 2, 3, 6, 9, 18 with no extras
✓ 2
[B1 for at least 4 correct factors with no more than one incorrect]
—
Part (b)
B1 for 6
✓ 1
Part (c)
B1 for 72
✓ 1
Common error: Multiplying 18 × 24 = 432 gives a common multiple, but not the lowest one. List multiples of 24 until one is divisible by 18.
14IGMC-041-00-04Types of number, factors, HCF and LCMPaper CEasy3 marks
No calculator
At a bus station, a red bus leaves every 12 minutes and a blue bus leaves every 20 minutes. Both buses leave together at 08 00.
(a)
Find the next time both buses leave together.
(2)
(b)
Find how many times the two buses leave together from 08 00 to 13 00, including both of these times.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 for finding the LCM of 12 and 20 as 60, or listing multiples of 12 and 20 to 60
✓ 1
A1 for 09 00
✓ 1
Part (b)
B1 for 6
✓ 1
Exam tip: When the question says "including both of these times", count the start time as well: 5 hours gives 5 gaps but 6 departure times.
15IGMC-041-00-05Types of number, factors, HCF and LCMPaper CEasy4 marks
No calculator
(a)
From this list, write down the irrational numbers.
√5 0.25 2π √49 \(\frac{7}{9}\) ∛27
(2)
(b)
Write down an integer between √50 and √70.
(1)
(c)
Write down the prime number between 40 and 50 that is 1 more than a multiple of 6.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 for √5
✓ 1
B1 for 2π, with no incorrect numbers included
✓ 1
Part (b)
B1 for 8
✓ 1
Part (c)
B1 for 43
✓ 1
Common error: √49 = 7 and ∛27 = 3 are whole numbers, so they are rational. A root is only irrational when it does not simplify to a whole number or fraction.
16IGMC-041-02-01Indices, standard form and surdsPaper CEasy4 marks
No calculator
Simplify each expression.
(a)
\(x^5 \times x^3\)
(1)
(b)
\(\frac{y^{12}}{y^4}\)
(1)
(c)
\((2p^3)^4\)
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1: \(x^8\)
✓ 1
Part (b)
B1: \(y^8\)
✓ 1
Part (c)
B1: coefficient 16
✓ 1
B1: \(p^{12}\), giving \(16p^{12}\)
✓ 1
Common error: In (c) the power 4 applies to the 2 as well as to \(p^3\). Writing \(2p^{12}\) or \(8p^{12}\) loses a mark.
17IGMC-041-02-02Indices, standard form and surdsPaper CEasy4 marks
No calculator
Answer each part.
(a)
Write 0.000 407 in standard form.
(1)
(b)
Write 6.3 ×105 as an ordinary number.
(1)
(c)
Work out (4 ×106) × (7 ×10−2). Give your answer in standard form.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1: 4.07 ×10−4
✓ 1
Part (b)
B1: 630 000
✓ 1
Part (c)
M1: 28 ×104 or 280 000 seen
✓ 1
A1: 2.8 ×105
✓ 1
Exam tip: 28 ×10⁴ is not in standard form. The first number must be at least 1 and less than 10, so adjust the power of ten.
18IGMC-041-02-03Indices, standard form and surdsPaper CEasy4 marks
No calculator
Answer each part.
(a)
Write down the value of \(7^0\).
(1)
(b)
Find the value of \(3^{-2}\) as a fraction.
(1)
(c)
Find the value of \(n\) when \(2^n = \frac{1}{32}\).
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1: 1
✓ 1
Part (b)
B1: \(\frac{1}{9}\)
✓ 1
Part (c)
M1: \(32 = 2^5\) or \(\frac{1}{32} = 2^{-5}\) seen
✓ 1
A1: \(n = -5\)
✓ 1
Common error: A negative power gives a reciprocal, not a negative number. \(3^{-2}\) is \(\frac{1}{9}\), not \(-9\) or \(-6\).
19IGMC3-1-07c-01Types of number, factors, HCF and LCMPaper CEasy4 marks
No calculator
Two lighthouse lamps start flashing at the same moment. Lamp A flashes every 12 seconds and lamp B flashes every 18 seconds.
(a)
Write 12 and 18 each as a product of prime factors.
(2)
(b)
Find how many seconds pass before the lamps next flash together.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 12 = 22 × 3
✓ 1
B1 18 = 2 × 32
✓ 1
Part (b)
M1 attempt at the lowest common multiple, e.g. using 22 × 32 or listing multiples
✓ 1
A1 36 seconds
✓ 1
Exam tip: Use the prime factor form to build the LCM: take the highest power of each prime that appears.
20IGMC3-1-07c-02Fractions, decimals and percentagesPaper CEasy4 marks
Calculator
A solar panel has a listed price of €640. During a sale the price is reduced by 15%.
(a)
Calculate the sale price.
(2)
(b)
A sales tax of 23% is then added to the sale price. Calculate the price the customer pays.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 640 × 0.85 or 640 − 0.15 × 640
✓ 1
A1 €544
✓ 1
Part (b)
M1 544 × 1.23
✓ 1
A1 €669.12
✓ 1
Common error: Apply the 23% to the sale price, not to the original €640.
21IGMC3-1-07c-03Estimation, rounding, bounds, ratio, proportion and moneyPaper CEasy4 marks
No calculator
A runner covers \(\frac{3}{8}\) of a trail in the first hour and \(\frac{1}{4}\) of the trail in the second hour.
(a)
What fraction of the trail is still to be run after two hours?
(2)
(b)
The distance still to be run is 15 km. Work out the total length of the trail.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 1 − \(\frac{3}{8}\) − \(\frac{1}{4}\) or \(\frac{5}{8}\) found as the distance covered
✓ 1
A1 \(\frac{3}{8}\)
✓ 1
Part (b)
M1 15 ÷ \(\frac{3}{8}\) or 15 ÷ 3 × 8
✓ 1
A1 40 km
✓ 1
Exam tip: Convert to a common denominator before adding fractions, and remember that dividing by a fraction means multiplying by its reciprocal.
22IGMC3-1-07c-04Types of number, factors, HCF and LCMPaper CEasy3 marks
Calculator
A virus particle has a diameter of 1.2 × 10−7 m.
(a)
Write 1.2 × 10−7 as an ordinary number.
(1)
(b)
Particles are placed side by side in a straight line to make a length of 3 mm. Calculate how many particles are needed.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 0.00000012
✓ 1
Part (b)
M1 3 × 10−3 ÷ (1.2 × 10−7)
✓ 1
A1 25000
✓ 1
Common error: Convert millimetres to metres before dividing: 3 mm is 3 × 10⁻³ m, not 3 × 10³ m.
23IGMC3-1-07c-05Estimation, rounding, bounds, ratio, proportion and moneyPaper CEasy4 marks
Calculator
A concrete mix contains cement, sand and gravel in the ratio 1 : 2 : 4 by mass.
(a)
A batch of the mix has a total mass of 56 kg. Calculate the mass of sand in the batch.
(2)
(b)
A different batch contains 90 kg of gravel. Calculate the mass of cement in this batch.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 56 ÷ 7 (= 8)
✓ 1
A1 16 kg
✓ 1
Part (b)
M1 90 ÷ 4
✓ 1
A1 22.5 kg
✓ 1
Exam tip: Add the parts of the ratio first to find the value of one part.
24IGMC3-1-08r6-01Types of number, factors, HCF and LCMPaper CEasy7 marks
No calculator
During an outbreak study a clinic labels sample tubes with these numbers: 12, 17, 21, 27, 29, 36, 49.
(a)
Write down the two prime numbers.
(2)
(b)
Write down the two square numbers.
(2)
(c)
Write down the cube number.
(1)
(d)
Write 36 as a product of prime factors.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 17
✓ 1
B1 29
✓ 1
Part (b)
B1 36
✓ 1
B1 49
✓ 1
Part (c)
B1 27
✓ 1
Part (d)
M1 factor tree or repeated division by primes
✓ 1
A1 22 × 32 (accept 2 × 2 × 3 × 3)
✓ 1
Common error: 1 is not a prime number, and a prime has exactly two factors.
25IGMC3-1-08r6-02Fractions, decimals and percentagesPaper CEasy4 marks
Calculator
A shop reduces prices in a sale.
(a)
A jacket costs €85. In the sale its price is reduced by 15%. Calculate the sale price.
(2)
(b)
A pair of boots has a sale price of €36 after a reduction of 20%. Calculate the original price.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 85 × 0.85 or 85 − 0.15 × 85
✓ 1
A1 €72.25
✓ 1
Part (b)
M1 36 ÷ 0.8
✓ 1
A1 €45.00
✓ 1
Common error: To undo a percentage decrease, divide by the multiplier; do not add the percentage back on to the sale price.
26IGMC3-1-08r6-07Estimation, rounding, bounds, ratio, proportion and moneyPaper CEasy4 marks
Calculator
Three friends share the cost of €126 for a set of solar garden lights in the ratio 2 : 3 : 4.
(a)
Calculate the smallest share.
(2)
(b)
The exchange rate is €1 = £0.86. Convert €126 to pounds.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 126 ÷ (2 + 3 + 4) = 14
✓ 1
A1 €28
✓ 1
Part (b)
M1 126 × 0.86
✓ 1
A1 £108.36
✓ 1
Exam tip: Add the ratio parts first to find the value of one part.
27IGMC3-1-08r6-11Indices, standard form and surdsPaper CEasy4 marks
Calculator
A solar farm has 19.6 thousand panels, each producing 4.87 kWh in one day. The farm covers 0.52 km2. The energy per square kilometre, in thousands of kWh, is \(4.87\times19.6\div0.52\).
(a)
Show how this value can be estimated by rounding each number to 1 significant figure.
(2)
(b)
Calculate the value, giving your answer to 3 significant figures.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 5 × 20 ÷ 0.5
✓ 1
A1 200
✓ 1
Part (b)
M1 4.87 × 19.6 ÷ 0.52 (= 183.56...)
✓ 1
A1 184
✓ 1
Exam tip: Always round the divisor to 1 s.f. before you divide, so that the estimate is easy to do mentally.
28IGMC3-1-10r9-01Types of number, factors, HCF and LCMPaper CEasy4 marks
No calculator
An archaeologist labels pottery fragments with the numbers 29, 39, 49, 51, 57, 61, 87 and 91.
(a)
Write down the two prime numbers in the list.
(2)
(b)
Write 84 as a product of its prime factors.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 29
✓ 1
B1 61
✓ 1
Part (b)
M1 repeated division or factor tree reaching 2, 2, 3, 7
✓ 1
A1 22 × 3 × 7
✓ 1
Common error: Treating 1 or an odd number such as 39 as prime. Test odd numbers by dividing by 3, 5 and 7.
29IGMC3-1-10r9-02Estimation, rounding, bounds, ratio, proportion and moneyPaper CEasy4 marks
No calculator
A cyclist rides 3⁄8 of a 160 km route on the first day and 2⁄5 of the route on the second day.
(a)
Calculate the fraction of the route ridden in the first two days. Give your answer as a fraction in its simplest form.
(2)
(b)
Calculate the distance still to ride on the third day.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 15⁄40 + 16⁄40
✓ 1
A1 31⁄40
✓ 1
Part (b)
M1 (1 − 31⁄40) × 160 = 9⁄40 × 160 (ECF from (a))
✓ 1
A1 36 km
✓ 1
Exam tip: Use a common denominator before adding fractions, then find the fraction left by subtracting from 1.
30IGMC3-1-10r9-03Estimation, rounding, bounds, ratio, proportion and moneyPaper CEasy4 marks
Calculator
The cooling system in a data centre drew 640 kW of power last year. This year it draws 736 kW.
(a)
Calculate the percentage increase in power drawn.
(2)
(b)
A new design reduces the 736 kW by 8%. Calculate the new power drawn. Give your answer correct to 3 significant figures.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 (736 − 640) ÷ 640 × 100
✓ 1
A1 15%
✓ 1
Part (b)
M1 736 × 0.92
✓ 1
A1 677 kW (677.12)
✓ 1
Common error: Dividing the change by the new value instead of the original value when finding a percentage change.
31IGMC3-1-10r9-04Indices, standard form and surdsPaper CEasy3 marks
No calculator
A layer of dust on a pottery shard is 0.0000472 m thick. A dig site holds 3 × 104 shards, each of mass 2.5 × 102 g.
(a)
Write 0.0000472 in standard form.
(1)
(b)
Calculate the total mass of all the shards. Give your answer in standard form.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 4.72 × 10−5
✓ 1
Part (b)
M1 3 × 2.5 = 7.5 and 104 × 102 = 106
✓ 1
A1 7.5 × 106 g
✓ 1
Common error: When multiplying numbers in standard form, multiply the front numbers and add the powers of ten; do not multiply the powers.
32IGMC3-1-08r11-01Types of number, factors, HCF and LCMPaper CEasy6 marks
No calculator
Two signal lamps on a mountain ridge flash at different rates. Lamp P flashes every 18 seconds and lamp Q flashes every 30 seconds. They flash together at 08:00:00.
(a)
Write 18 and 30 as products of prime factors.
(2)
(b)
Find the lowest common multiple of 18 and 30.
(2)
(c)
Find how many seconds after 08:00:00 the lamps flash together for the third time.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 18 = 2 × 3 × 3 (or 2 × 32)
✓ 1
B1 30 = 2 × 3 × 5
✓ 1
Part (b)
M1 2 × 32 × 5 or a list of multiples of both numbers
✓ 1
A1 90
✓ 1
Part (c)
M1 3 × 90
✓ 1
A1 270 (ECF from (b))
✓ 1
Exam tip: Write numbers as products of prime factors; LCM takes the highest power of each prime and HCF the lowest power of the shared primes.
33IGMC3-1-08r11-02Fractions, decimals and percentagesPaper CEasy5 marks
No calculator
A food scientist tests a 840 g sample of cheese. Fat makes up \(\frac{3}{8}\) of the mass and protein makes up \(\frac{1}{4}\) of the mass.
(a)
Calculate the mass of fat in the sample.
(2)
(b)
Find the fraction of the sample that is neither fat nor protein.
(2)
(c)
Write the fraction of protein as a percentage.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 \(840 \times \frac{3}{8}\) or \(840 \div 8 \times 3\)
✓ 1
A1 315 g
✓ 1
Part (b)
M1 \(1 - \frac{3}{8} - \frac{1}{4}\) or \(1 - \frac{5}{8}\)
✓ 1
A1 \(\frac{3}{8}\)
✓ 1
Part (c)
B1 25%
✓ 1
Exam tip: To add or subtract fractions, first write them with a common denominator; here \(\frac{1}{4} = \frac{2}{8}\).
34IGMC3-1-08r11-03Fractions, decimals and percentagesPaper CEasy4 marks
Calculator
A shop sells mountaineering equipment.
(a)
A jacket costs €240. In a sale the price is reduced by 15%. Calculate the sale price.
(2)
(b)
Boots have a sale price of €144, which is 20% less than the original price. Calculate the original price.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 \(240 \times 0.85\) or \(240 - 0.15 \times 240\)
✓ 1
A1 €204
✓ 1
Part (b)
M1 \(144 \div 0.8\)
✓ 1
A1 €180
✓ 1
Common error: In a reverse percentage problem, divide by the multiplier (0.8); do not add 20% of the sale price.
35IGMC3-1-08r11-04Indices, standard form and surdsPaper CEasy4 marks
Calculator
A satellite link sends data at the speed of light, \(3.0 \times 10^{8}\) m/s. The satellite is \(3.6 \times 10^{7}\) m from the ground station.
(a)
Calculate the time taken for a signal to travel from the satellite to the ground station. Give your answer in standard form.
(2)
(b)
A file of \(4.8 \times 10^{9}\) bytes downloads at a steady rate of \(6.0 \times 10^{6}\) bytes per second. Calculate the time taken. Give your answer in standard form.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 \(3.6 \times 10^{7} \div 3.0 \times 10^{8}\)
✓ 1
A1 \(1.2 \times 10^{-1}\) s
✓ 1
Part (b)
M1 \(4.8 \times 10^{9} \div 6.0 \times 10^{6}\)
✓ 1
A1 \(8 \times 10^{2}\) s (accept 8.0 × 102)
✓ 1
Exam tip: Standard form must be \(a \times 10^{n}\) with \(1 \le a < 10\); 800 s written as \(80 \times 10^{1}\) would lose the mark.
36IGMC3-1-09r14-01Types of number, factors, HCF and LCMPaper CEasy6 marks
No calculator
Three instruments on a space probe each send a data burst to Earth at regular intervals: instrument P every 12 minutes, instrument Q every 18 minutes and instrument R every 30 minutes. At 08:00 all three send a burst at the same moment.
(a)
Write 18 as a product of its prime factors.
(2)
(b)
Find the lowest common multiple of 12, 18 and 30.
(2)
(c)
After 08:00, the three instruments send bursts together again several times up to and including 20:00 on the same day. Work out how many times this happens.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 correct prime factor tree or division (e.g. 18 = 2 × 9)
✓ 1
B1 18 = 2 × 32
✓ 1
Part (b)
M1 prime factorisations 12 = 22 × 3, 30 = 2 × 3 × 5 (or a correct list of multiples)
✓ 1
A1 LCM = 180
✓ 1
Part (c)
M1 12 hours = 720 minutes and 720 ÷ 180
✓ 1
A1 4
✓ 1
Exam tip: For LCM, use the highest power of each prime from the factorisations; for HCF, use the lowest power of each prime that is common to all.
37IGMC3-1-09r14-03Fractions, decimals and percentagesPaper CEasy5 marks
Calculator
The toll for a car crossing a river bridge was increased by 12%. The new toll is €5.60.
(a)
Calculate the toll before the increase.
(2)
(b)
Write down the increase in the toll, in euros.
(1)
(c)
On one day 3250 cars pay the new toll. Calculate the total toll collected from these cars.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 5.60 ÷ 1.12
✓ 1
A1 €5.00
✓ 1
Part (b)
B1 €0.60
✓ 1
Part (c)
M1 3250 × 5.60
✓ 1
A1 €18200
✓ 1
Common error: To find the original amount after a percentage increase, divide by 1.12; do not subtract 12% of the new amount.
38IGMC3-1-09r14-04Indices, standard form and surdsPaper CEasy4 marks
Calculator
A space probe is 2.4 × 108 km from Earth. A radio signal travels at 3.0 × 105 km/s.
(a)
Calculate the time taken for a signal to reach Earth from the probe. Give your answer in seconds in standard form.
(2)
(b)
Write this time in minutes, correct to 3 significant figures.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 (2.4 × 108) ÷ (3.0 × 105)
✓ 1
A1 8 × 102 s (accept 8.0 × 102)
✓ 1
Part (b)
M1 800 ÷ 60
✓ 1
A1 13.3 minutes
✓ 1
Exam tip: A number in standard form must be written as a × 10ⁿ with 1 ≤ a < 10, so 800 is 8 × 10² not 80 × 10¹.
39IGMC3-1-09r14-11Types of number, factors, HCF and LCMPaper CEasy4 marks
No calculator
Seven instruments on a space probe have identification numbers 21, 27, 29, 36, 49, 51 and 64.
(a)
Write down the prime number in the list.
(1)
(b)
Write down the number in the list that is both a square number and a cube number.
(1)
(c)
Find the sum of the identification numbers that are multiples of 3.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 29
✓ 1
Part (b)
B1 64
✓ 1
Part (c)
M1 identify 21, 27, 36, 51
✓ 1
A1 135
✓ 1
Common error: 1 is not a prime number, and numbers such as 51 and 21 look prime but have a factor of 3.
40IGMC3-1-09r17-01Types of number, factors, HCF and LCMPaper CEasy4 marks
No calculator
A space probe stores its sensor readings under these code numbers: 12, 17, 27, 36, 51, 64, 91.
(a)
From the list, write down the prime number.
(1)
(b)
From the list, write down the number that is both a square number and a cube number.
(1)
(c)
Write 36 as a product of its prime factors.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 17
✓ 1
Part (b)
B1 64
✓ 1
Part (c)
M1 repeated division by primes or a correct factor tree
✓ 1
A1 22 × 32
✓ 1
Common error: Writing 1 as a prime number, or stopping a factor tree at 4 or 9 instead of continuing to primes.
41IGMC3-1-09r17-02Types of number, factors, HCF and LCMPaper CEasy6 marks
No calculator
Two coffee roasters finish a batch at exactly 08:00. After that, roaster A finishes a batch every 18 minutes and roaster B finishes a batch every 24 minutes.
(a)
Write 18 and 24 each as a product of prime factors.
(2)
(b)
Find the lowest common multiple of 18 and 24.
(2)
(c)
At what time do the roasters next finish a batch together?
(1)
(d)
How many batches does roaster A finish between 08:00 and that time, counting the batch at the later time but not the one at 08:00?
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 18 = 2 × 32
✓ 1
B1 24 = 23 × 3
✓ 1
Part (b)
M1 uses the highest power of each prime, 23 × 32
✓ 1
A1 72
✓ 1
Part (c)
B1 09:12 (follow through from 72 minutes)
✓ 1
Part (d)
B1 4
✓ 1
Exam tip: For lowest common multiple from prime factors take the highest power of each prime; for highest common factor take the lowest.
42IGMC3-1-09r17-03Fractions, decimals and percentagesPaper CEasy5 marks
No calculator
Inspectors check the cables of a suspension bridge. On Monday they inspect 3/8 of the cables and on Tuesday they inspect 2/5 of the cables.
(a)
Work out the fraction of the cables inspected over the two days.
(2)
(b)
Write down the fraction of the cables not yet inspected.
(1)
(c)
The bridge has 240 cables. Work out how many have not been inspected.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 common denominator, 15/40 + 16/40
✓ 1
A1 31/40
✓ 1
Part (b)
B1 9/40
✓ 1
Part (c)
M1 240 × 9/40
✓ 1
A1 54
✓ 1
Common error: Adding the numerators and the denominators separately, for example ³/₈ + ²/₅ = ⁵/₁₃.
43IGMC3-1-09r17-04Types of number, factors, HCF and LCMPaper CEasy6 marks
Calculator
A coffee roaster buys green coffee beans at €8.40 per kilogram. The price then rises by 15%.
(a)
Calculate the new price per kilogram.
(2)
(b)
Roasting makes the beans lose 18% of their mass. Calculate the mass of roasted coffee obtained from 25 kg of green beans.
(2)
(c)
The roasted coffee is packed into bags that each hold 250 g. How many bags can be filled completely?
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 8.40 × 1.15
✓ 1
A1 €9.66
✓ 1
Part (b)
M1 25 × 0.82 (or 25 − 0.18 × 25)
✓ 1
A1 20.5 kg
✓ 1
Part (c)
M1 20.5 ÷ 0.25 (or 20 500 ÷ 250)
✓ 1
A1 82
✓ 1
Exam tip: Use a multiplier: an increase of 15% is × 1.15 and a loss of 18% is × 0.82. Check that the units of mass match before dividing.
44IGMC3-1-09r22-01Fractions, decimals and percentagesPaper CEasy4 marks
No calculator
A robot arm completes \(\frac{3}{8}\) of a welding job in the first hour and \(\frac{2}{5}\) of the job in the second hour.
(a)
Find the fraction of the job completed in the first two hours.
(2)
(b)
Find the fraction of the job still to be done.
(1)
(c)
Write your answer to part (b) as a decimal.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 common denominator of 40, e.g. \(\frac{15}{40}+\frac{16}{40}\)
✓ 1
A1 \(\frac{31}{40}\)
✓ 1
Part (b)
B1 \(\frac{9}{40}\) (ECF from (a))
✓ 1
Part (c)
B1 0.225 (ECF from (b))
✓ 1
Exam tip: Write each fraction over the same denominator before adding; do not add numerators and denominators separately.
45IGMC3-1-09r22-02Fractions, decimals and percentagesPaper CEasy4 marks
Calculator
A dress costs €85.00. In a sale the price is reduced by 24%. The shop paid €50.00 for the dress.
(a)
Calculate the sale price.
(2)
(b)
Calculate the shop's percentage profit on the cost price when the dress is sold at the sale price.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 \(85\times(1-0.24)\) or \(85\times0.76\)
✓ 1
A1 €64.60
✓ 1
Part (b)
M1 \(\frac{64.60-50}{50}\times100\)
✓ 1
A1 29.2%
✓ 1
Common error: Percentage profit is found as a percentage of the cost price, not of the selling price.
46IGMC3-1-09r22-03Types of number, factors, HCF and LCMPaper CEasy6 marks
No calculator
A fishing co-operative numbers its boats using the following numbers: 7, 12, 15, 21, 23, 29, 36, 49
(a)
Write down all the prime numbers in the list.
(2)
(b)
Write 36 as a product of its prime factors.
(2)
(c)
Find the highest common factor (HCF) of 36 and 90.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 7, 23 and 29 all identified
✓ 1
B1 no other numbers included
✓ 1
Part (b)
M1 correct factor tree or repeated division by primes
✓ 1
A1 \(2^2\times3^2\)
✓ 1
Part (c)
M1 \(90=2\times3^2\times5\) and \(36=2^2\times3^2\), or lists of common factors
✓ 1
A1 18
✓ 1
Common error: 1 is not a prime number, and 49 is not prime because it equals 7 × 7.
47IGMC3-1-09r24-01Types of number, factors, HCF and LCMPaper CEasy6 marks
No calculator
A library has 84 fiction books and 126 non-fiction books. The librarian packs them into identical boxes. Every box holds the same number of books, and no box contains both types.
(a)
Write 84 as a product of its prime factors.
(2)
(b)
Find the highest common factor (HCF) of 84 and 126.
(2)
(c)
Find the smallest number of boxes needed.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 attempt at repeated division by primes or a factor tree
✓ 1
A1 22 × 3 × 7
✓ 1
Part (b)
M1 126 = 2 × 32 × 7 (or a list of common factors)
✓ 1
A1 42
✓ 1
Part (c)
M1 84 ÷ 42 and 126 ÷ 42 (use of the HCF as the box size)
✓ 1
A1 2 + 3 = 5 boxes
✓ 1
Exam tip: For a 'smallest number of equal groups' problem, use the HCF as the group size, not the LCM.
48IGMC3-1-09r24-02Types of number, factors, HCF and LCMPaper CEasy4 marks
No calculator
Two swimmers start a training session together at the same end of a pool. One lap means swimming down the pool and back to the starting end. Ana takes 40 seconds for each lap and Ben takes 50 seconds for each lap. Each keeps a constant lap time without stopping.
(a)
Find the lowest common multiple (LCM) of 40 and 50.
(2)
(b)
They are next together at the starting end after a whole number of laps for each swimmer. Work out how many laps Ben has swum by then.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 multiples of 40 and 50 listed, or prime factorisation 23 × 5 and 2 × 52
✓ 1
A1 200
✓ 1
Part (b)
M1 200 ÷ 50 (ECF from (a))
✓ 1
A1 4 laps
✓ 1
Common error: Writing the HCF (10) instead of the LCM when asked when two repeating events next coincide.
49IGMC3-1-09r24-03Fractions, decimals and percentagesPaper CEasy5 marks
Calculator
A wind farm has 48 turbines. Three-eighths of the turbines are offshore and the rest are onshore.
(a)
Work out the number of offshore turbines.
(1)
(b)
20% of the onshore turbines are shut down for maintenance. Work out how many onshore turbines are shut down.
(2)
(c)
Write the number of turbines shut down as a percentage of all 48 turbines.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 18
✓ 1
Part (b)
M1 onshore = 48 − 18 = 30 (ECF from (a)), then 0.2 × 30
✓ 1
A1 6
✓ 1
Part (c)
M1 6 ÷ 48 × 100 (ECF from (b))
✓ 1
A1 12.5%
✓ 1
Exam tip: Check which total a percentage refers to: here the whole is all 48 turbines, not the 30 onshore ones.
50IGMC3-1-09r24-04Indices, standard form and surdsPaper CEasy5 marks
Calculator
A wind farm generates 2.4 × 105 kWh of electricity each day.
(a)
Write 4 500 000 in standard form.
(1)
(b)
Calculate the electricity generated in 30 days. Give your answer in standard form.
(2)
(c)
Work out how many days the wind farm takes to generate 1.8 × 107 kWh.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 4.5 × 106
✓ 1
Part (b)
M1 2.4 × 105 × 30
✓ 1
A1 7.2 × 106 kWh
✓ 1
Part (c)
M1 1.8 × 107 ÷ 2.4 × 105
✓ 1
A1 75 days
✓ 1
Common error: In standard form the first number must be at least 1 and less than 10; 72 × 10⁵ is not standard form.
51IGMC3-1-09r26-01Types of number, factors, HCF and LCMPaper CEasy4 marks
No calculator
An archaeological team labels the finds from one trench with these numbers: 12, 18, 25, 29, 33, 39.
(a)
Write down the prime number in the list.
(1)
(b)
Write down the square number in the list.
(1)
(c)
Find the highest common factor (HCF) of 12 and 18.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 29
✓ 1
Part (b)
B1 25
✓ 1
Part (c)
M1 12 = 22 × 3 and 18 = 2 × 32, or lists of factors of both
✓ 1
A1 HCF = 2 × 3 = 6
✓ 1
Exam tip: Write the prime factorisations or the factor lists clearly: the method mark is for showing them.
52IGMC3-1-09r26-02Fractions, decimals and percentagesPaper CEasy5 marks
Calculator
A cyclist plans a route of 72 km. She rides 3⁄8 of the route in the morning and 2⁄9 of the route in the afternoon.
(a)
Work out the distance she rides in the morning.
(1)
(b)
Work out the fraction of the route that she has still to ride. Give your answer as a fraction in its simplest form.
(2)
(c)
Write your answer to part (b) as a percentage. Give your answer correct to 1 decimal place.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 27 km
✓ 1
Part (b)
M1 1 − 3⁄8 − 2⁄9 using a common denominator of 72
✓ 1
A1 29⁄72
✓ 1
Part (c)
M1 29 ÷ 72 × 100
✓ 1
A1 40.3%
✓ 1
Exam tip: Common error: subtracting numerators and denominators separately. Always convert to a common denominator first.
53IGMC3-1-09r26-03Indices, standard form and surdsPaper CEasy5 marks
Calculator
A data centre has 3.2 × 104 storage drives. Each drive stores 6 × 1012 bytes of data.
(a)
Write 48 000 000 000 in standard form.
(1)
(b)
Calculate the total number of bytes the drives can store. Give your answer in standard form.
(2)
(c)
A different data centre must store 1.8 × 1015 bytes using the same type of drive. Work out the smallest number of drives needed.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 4.8 × 1010
✓ 1
Part (b)
M1 3.2 × 104 × 6 × 1012
✓ 1
A1 1.92 × 1017
✓ 1
Part (c)
M1 1.8 × 1015 ÷ (6 × 1012)
✓ 1
A1 300
✓ 1
Common error: A standard form number must have a first factor from 1 up to (but not including) 10. 19.2 × 10¹⁶ is not in standard form.
54IGMC3-1-09r26-06Estimation, rounding, bounds, ratio, proportion and moneyPaper CEasy4 marks
Calculator
An archaeologist measures a pottery shard.
(a)
The thickness of the shard is 0.004 862 m. Write this correct to 2 significant figures.
(1)
(b)
A density index is S = (19.8 × 4.07) ÷ 0.52. Estimate the value of S by rounding each number to 1 significant figure. Show your working.
(2)
(c)
Calculate the exact value of S. Give your answer correct to 3 significant figures.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 0.0049 m
✓ 1
Part (b)
M1 20 × 4 ÷ 0.5
✓ 1
A1 160
✓ 1
Part (c)
B1 155
✓ 1
Exam tip: Round each number to 1 significant figure before you estimate and show every rounded value.
55IGMC3-1-10r26-01Types of number, factors, HCF and LCMPaper CEasy4 marks
No calculator
A fashion workshop numbers its rolls of fabric. Five of the roll numbers are 14, 17, 21, 24 and 27.
(a)
Write down the cube number in the list.
(1)
(b)
Write 24 as a product of prime factors.
(2)
(c)
Write down the odd multiple of 7 in the list.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 27
✓ 1
Part (b)
M1 factor tree or repeated division by primes
✓ 1
A1 23 × 3
✓ 1
Part (c)
B1 21
✓ 1
Exam tip: Check each answer against the definition: a cube is n × n × n, and a multiple of 7 is in the 7 times table.
56IGMC3-1-10r26-02Indices, standard form and surdsPaper CEasy4 marks
Calculator
A fishing boat lands 840 kg of fish. 35% of the catch is cod and 210 kg is haddock.
(a)
Work out the mass of cod.
(2)
(b)
Write the mass of haddock as a fraction of the whole catch. Give your answer in its simplest form.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 0.35 × 840
✓ 1
A1 294 kg
✓ 1
Part (b)
M1 210/840
✓ 1
A1 1⁄4
✓ 1
Exam tip: Divide numerator and denominator by their highest common factor to reach simplest form.
57IGMC3-1-10r26-03Estimation, rounding, bounds, ratio, proportion and moneyPaper CEasy4 marks
Calculator
A warehouse robot moves along a straight rail at a constant speed. It travels 3.6 m in 24 s.
(a)
Work out the speed of the robot in metres per second.
(2)
(b)
Work out the distance the robot travels in 1 minute 30 seconds at this speed.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 3.6 ÷ 24
✓ 1
A1 0.15 m/s
✓ 1
Part (b)
M1 converts to 90 s and multiplies by speed, 0.15 × 90
✓ 1
A1 13.5 m
✓ 1
Common error: Common error: using 1.30 as 1.3 minutes. Convert 1 minute 30 seconds to 90 seconds.
58IGMC3-1-10r26-04Indices, standard form and surdsPaper CEasy4 marks
Calculator
A clothing factory uses very fine thread.
(a)
The diameter of the thread is 0.000 045 m. Write this in standard form.
(1)
(b)
One spool holds 2.5 × 103 m of thread. The factory uses 6 × 102 spools. Work out the total length of thread. Give your answer in standard form.
(2)
(c)
Write your answer to part (b) in kilometres, in standard form.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 4.5 × 10−5 m
✓ 1
Part (b)
M1 2.5 × 103 × 6 × 102
✓ 1
A1 1.5 × 106 m
✓ 1
Part (c)
B1 1.5 × 103 km
✓ 1
Exam tip: Check your first factor lies between 1 and 10 and your power of ten reflects the size of the number.
59IGMC3-1-10r31-01Types of number, factors, HCF and LCMPaper CEasy5 marks
Calculator
A space probe labels its data packets with whole numbers. Some of the labels are 12, 17, 25, 27, 29, 36 and 51.
(a)
Write down the two prime numbers in the list.
(2)
(b)
Write down the cube number in the list.
(1)
(c)
Write 36 as a product of prime factors.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 17
✓ 1
B1 29
✓ 1
Part (b)
B1 27
✓ 1
Part (c)
M1 correct factor tree or repeated division by primes
✓ 1
A1 22 × 32
✓ 1
Common error: 1 is not a prime number, and 51 is not prime because 51 = 3 × 17.
60IGMC3-1-10r31-02Types of number, factors, HCF and LCMPaper CEasy5 marks
No calculator
A coffee roaster loads 12 kg of green coffee beans. Roasting removes 15% of the mass.
(a)
Work out the mass lost during roasting.
(2)
(b)
Write down the mass of roasted coffee.
(1)
(c)
The roasted coffee is packed into bags that each hold 0.3 kg. Work out the number of bags that can be filled completely.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 0.15 × 12 or 10% + 5% of 12
✓ 1
A1 1.8 kg
✓ 1
Part (b)
B1 10.2 kg (ECF from (a))
✓ 1
Part (c)
M1 10.2 ÷ 0.3
✓ 1
A1 34 bags
✓ 1
Exam tip: Subtract the lost mass from the original mass to get the final mass.
61IGMC3-1-10r31-03Indices, standard form and surdsPaper CEasy5 marks
Calculator
A space probe is 1.2 × 1010 km from Earth. Radio signals travel at 3.0 × 105 km/s.
(a)
Write 5 600 000 000 in standard form.
(1)
(b)
Work out the time, in seconds, for a signal to travel from the probe to Earth. Give your answer in standard form.
(2)
(c)
Change your answer to part (b) into hours. Give your answer correct to 3 significant figures.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 5.6 × 109
✓ 1
Part (b)
M1 1.2 × 1010 ÷ (3.0 × 105)
✓ 1
A1 4.0 × 104 s
✓ 1
Part (c)
M1 4.0 × 104 ÷ 3600
✓ 1
A1 11.1 hours
✓ 1
Exam tip: Divide by 3600 to change seconds to hours.
62IGMC3-1-10r31-04Types of number, factors, HCF and LCMPaper CEasy5 marks
No calculator
Two inspection crews check a bridge. Crew A visits every 12 days and crew B visits every 18 days.
(a)
Write 18 as a product of prime factors.
(2)
(b)
Find the highest common factor (HCF) of 12 and 18.
(1)
(c)
Both crews visit on the same day. Find the number of days until they next visit on the same day.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 correct factor tree or division by primes
✓ 1
A1 2 × 32
✓ 1
Part (b)
B1 6
✓ 1
Part (c)
M1 listing multiples or using the LCM of 12 and 18
✓ 1
A1 36 days
✓ 1
Common error: Do not confuse the lowest common multiple (a large number) with the highest common factor (a small number).
63IGMC3-1-12r32-01Types of number, factors, HCF and LCMPaper CEasy6 marks
No calculator
At an airport gate, flights to one city depart every 12 minutes and flights to another city depart every 18 minutes. Both services have a departure at 06:00.
(a)
Write 12 and 18 each as a product of prime factors.
(2)
(b)
Find the highest common factor (HCF) of 12 and 18.
(2)
(c)
Find the next time after 06:00 when both services depart together.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 12 = 22 × 3
✓ 1
B1 18 = 2 × 32
✓ 1
Part (b)
M1 identifies the common prime factors 2 and 3
✓ 1
A1 6
✓ 1
Part (c)
M1 LCM = 22 × 32 = 36
✓ 1
A1 06:36
✓ 1
Exam tip: Use the prime factor form: the HCF takes the lowest powers and the LCM takes the highest powers.
64IGMC3-1-12r32-02Fractions, decimals and percentagesPaper CEasy5 marks
Calculator
A farmer plants 3/8 of a field with wheat and 1/4 with barley. The rest of the field is planted with oats. The whole field has area 48 hectares.
(a)
Find the fraction of the field planted with oats.
(2)
(b)
Write the fraction of the field planted with wheat as a percentage.
(1)
(c)
Work out the area planted with oats.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 1 − 3/8 − 1/4 (or 3/8 + 2/8 = 5/8)
✓ 1
A1 3/8
✓ 1
Part (b)
B1 37.5%
✓ 1
Part (c)
M1 3/8 × 48 (ECF from (a))
✓ 1
A1 18 hectares
✓ 1
Common error: Subtract the fractions from 1 only after writing them with a common denominator.
65IGMC3-1-12r32-03Fractions, decimals and percentagesPaper CEasy4 marks
Calculator
A band earns £1800 from a concert. The money is shared between the singer, the guitarist and the drummer in the ratio 5 : 3 : 2.
(a)
Find the guitarist's share.
(2)
(b)
Write the drummer's share as a percentage of the total.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 1800 ÷ (5 + 3 + 2) = 180
✓ 1
A1 £540
✓ 1
Part (b)
M1 2/10 × 100 (or 360/1800 × 100)
✓ 1
A1 20%
✓ 1
Exam tip: Add the parts of the ratio first to find the value of one part.
66IGMC3-1-12r32-04Indices, standard form and surdsPaper CEasy5 marks
Calculator
A passenger aircraft cruises at a speed of 8.0 × 102 km/h on a flight of 7.2 × 103 km.
(a)
Write 8.0 × 102 as an ordinary number.
(1)
(b)
Calculate the time for the flight in hours.
(2)
(c)
Write this time in seconds, in standard form.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 800
✓ 1
Part (b)
M1 7200 ÷ 800 (or 7.2 × 103 ÷ 8.0 × 102)
✓ 1
A1 9 hours
✓ 1
Part (c)
M1 9 × 3600 = 32 400 (ECF from (b))
✓ 1
A1 3.24 × 104
✓ 1
Common error: In standard form the number must be at least 1 and less than 10, so 32 400 is 3.24 × 10⁴, not 32.4 × 10³.
67IGMC3-1-11r36-01Types of number, factors, HCF and LCMPaper CEasy6 marks
No calculator
A marine biologist labels seven tanks with these numbers: 21, 29, 36, 45, 49, 51, 64
(a)
Write down the prime number from the list.
(1)
(b)
Write down the cube number from the list.
(1)
(c)
Write 36 as a product of its prime factors.
(2)
(d)
Find the highest common factor (HCF) of 36 and 45.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 29
✓ 1
Part (b)
B1 64
✓ 1
Part (c)
M1 correct factor tree or repeated division by primes
✓ 1
A1 22 × 32
✓ 1
Part (d)
M1 45 = 32 × 5 or a list of factors of both numbers
✓ 1
A1 9
✓ 1
Exam tip: Write the prime factorisations side by side and pick out only the factors that appear in both.
68IGMC3-1-11r36-06Estimation, rounding, bounds, ratio, proportion and moneyPaper CEasy5 marks
No calculator
A pier is 82 m long, measured to the nearest metre. A rope has length 4.6 m, measured to 1 decimal place.
(a)
Write down the lower bound and the upper bound of the length of the pier.
(2)
(b)
Write down the upper bound of the length of the rope.
(1)
(c)
Estimate how many ropes of length 4.6 m fit along the pier by rounding each length to 1 significant figure.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 81.5 m
✓ 1
B1 82.5 m
✓ 1
Part (b)
B1 4.65 m
✓ 1
Part (c)
M1 80 ÷ 5
✓ 1
A1 16
✓ 1
Common error: For a value given to the nearest unit, add and subtract half a unit; do not use a whole unit.
69IGMC3-1-11r36-13Fractions, decimals and percentagesPaper CEasy4 marks
Calculator
A diving centre in Malta charges €36 for each dive plus €18 equipment hire for each day.
(a)
Work out the total cost of 3 dives on one day, including one day of equipment hire.
(2)
(b)
The exchange rate is £1 = €1.16. Convert your answer to part (a) into pounds. Give your answer to the nearest penny.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 3 × 36 + 18
✓ 1
A1 €126
✓ 1
Part (b)
M1 126 ÷ 1.16 (ECF from (a))
✓ 1
A1 £108.62
✓ 1
Common error: To convert from euros to pounds at £1 = €1.16, divide by 1.16; multiplying gives an amount that is too large.
70IGMC3-1-10r42-01Types of number, factors, HCF and LCMPaper CEasy5 marks
No calculator
The squad numbers of seven players in a football academy are 12, 17, 21, 25, 29, 36 and 49. The head coach wears the number 84.
(a)
Write down the prime numbers in the list.
(2)
(b)
Write down the square number in the list that is also a multiple of 6.
(1)
(c)
Write 84 as a product of its prime factors.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 17
✓ 1
B1 29
✓ 1
Part (b)
B1 36
✓ 1
Part (c)
M1 factor tree or repeated division by prime numbers
✓ 1
A1 22 × 3 × 7
✓ 1
Exam tip: 1 is not a prime number, and 2 is the only even prime.
71IGMC3-1-10r42-03Indices, standard form and surdsPaper CEasy6 marks
Calculator
A runner plans to cover 64 km in a week. On Monday she runs \(\frac{3}{8}\) of the distance. On Tuesday she runs 25% of the distance still remaining after Monday.
(a)
Calculate the distance she runs on Monday.
(2)
(b)
Calculate the distance she runs on Tuesday.
(2)
(c)
Find the fraction of the weekly distance still to be run after Tuesday. Give your answer in its simplest form.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 \(\frac{3}{8}\) × 64
✓ 1
A1 24 km
✓ 1
Part (b)
M1 64 − 24 = 40
✓ 1
A1 25% of 40 = 10 km
✓ 1
Part (c)
M1 64 − 24 − 10 = 30
✓ 1
A1 \(\frac{15}{32}\)
✓ 1
Exam tip: Percentages of a remaining amount must use the remainder, not the original total.
72IGMC3-1-10r42-06Indices, standard form and surdsPaper CEasy4 marks
No calculator
This question is about indices.
(a)
Write 2−3 as a fraction.
(1)
(b)
Find the value of n in 5n ÷ 52 = 54.
(1)
(c)
Work out 4−2 × 43.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 \(\frac{1}{8}\)
✓ 1
Part (b)
B1 n = 6
✓ 1
Part (c)
M1 4−2+3 or \(\frac{1}{16}\) × 64
✓ 1
A1 4
✓ 1
Common error: A negative index means a reciprocal; it does not make the number negative.
73IGMC3-1-10r42-12Estimation, rounding, bounds, ratio, proportion and moneyPaper CEasy5 marks
Calculator
A rail operator uses the expression (38.7 × 4.12) ÷ 0.52 to work out a cost index.
(a)
Estimate the value of the expression by rounding each number to 1 significant figure.
(2)
(b)
Work out the value of the expression. Give your answer correct to 3 significant figures.
(2)
(c)
State whether your estimate in (a) is greater or less than the value in (b).
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 40 × 4 ÷ 0.5
✓ 1
A1 320
✓ 1
Part (b)
M1 159.444 ÷ 0.52 or 306.6…
✓ 1
A1 307
✓ 1
Part (c)
B1 greater, since 320 is greater than 307
✓ 1
Exam tip: Estimates round each number to 1 significant figure before calculating.
74IGMC-041-01-06Fractions, decimals and percentagesPaper CMedium6 marks
Calculator
The monthly rent of a flat increased by 12%. The new monthly rent is $1008.
(a)
Work out the monthly rent before the increase.
(2)
(b)
The following year, the monthly rent of $1008 decreased by 12%. Work out the new monthly rent.
(2)
(c)
Work out the overall percentage change from the original rent to the rent in part (b). State whether it is an increase or a decrease.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 for 1008 ÷ 1.12
✓ 1
A1 $900
✓ 1
Part (b)
M1 for 1008 × 0.88
✓ 1
A1 $887.04
✓ 1
Part (c)
M1 for \(\frac{900 - 887.04}{900}\) × 100 or \(\frac{887.04}{900}\) × 100
✓ 1
A1 1.44% decrease
✓ 1
Common error: In part (a), finding 12% of $1008 and subtracting it gives $887.04, which is wrong. The $1008 is 112% of the original, so divide by 1.12.
75IGMC-041-01-07Fractions, decimals and percentagesPaper CMedium6 marks
No calculator
Amira receives her monthly pay. She spends \(\frac{2}{5}\) of it on rent. She then spends \(\frac{1}{4}\) of the remaining money on food.
(a)
Show that the fraction of her pay that she spends on food is \(\frac{3}{20}\).
(2)
(b)
Work out the fraction of her pay that is left after rent and food.
(2)
(c)
Amira has $360 left after paying for rent and food. Work out her monthly pay.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 for remaining fraction \(1 - \frac{2}{5} = \frac{3}{5}\)
M1 for \(1 - \frac{2}{5} - \frac{3}{20}\) or \(\frac{3}{5} - \frac{3}{20}\)
✓ 1
A1 \(\frac{9}{20}\)
✓ 1
Part (c)
M1 for 360 ÷ \(\frac{9}{20}\) or 360 ÷ 9 × 20
✓ 1
A1 $800
✓ 1
Common error: \(\frac{1}{4}\) is a fraction of the money left after rent, not of the whole pay. Adding \(\frac{2}{5} + \frac{1}{4}\) directly gives the wrong fraction.
76IGMC-041-01-09Fractions, decimals and percentagesPaper CMedium5 marks
Calculator
A car is bought for $18 500. Its value decreases by 14% each year.
(a)
Work out the value of the car after 3 years.
(3)
(b)
Work out the total percentage of the original value that the car has lost after 3 years.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 for multiplier 0.86 seen
✓ 1
M1 for 18 500 × 0.863
✓ 1
A1 $11 767.04 (accept $11 800)
✓ 1
Part (b)
M1 for (1 − 0.863) × 100 or \(\frac{18500 - 11767.04}{18500}\) × 100
✓ 1
A1 36.4%
✓ 1
Common error: The car does not lose 3 × 14% = 42%. Each year's 14% is taken from a smaller value, so the total loss is less than 42%.
77IGMC-041-01-11Fractions, decimals and percentagesPaper CMedium5 marks
Calculator
The cash price of a television is $750. The television can also be bought on hire purchase by paying a deposit of 20% of the cash price followed by 12 monthly payments of $54.50.
(a)
Work out the deposit.
(1)
(b)
Work out the total cost of buying the television on hire purchase.
(2)
(c)
Work out how much more the hire purchase cost is than the cash price, as a percentage of the cash price.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 $150
✓ 1
Part (b)
M1 for 150 + 12 × 54.50
✓ 1
A1 $804
✓ 1
Part (c)
M1 for \(\frac{804 - 750}{750}\) × 100
✓ 1
A1 7.2%
✓ 1
Common error: Remember to add the deposit to the monthly payments. Using only 12 × $54.50 = $654 makes hire purchase look cheaper than paying cash.
78IGMC-041-03-06Estimation, rounding, bounds, ratio, proportion and moneyPaper CMedium4 marks
No calculator
8 workers take 15 days to build a wall. All workers work at the same rate.
(a)
Work out how many days 12 workers would take to build the same wall.
(2)
(b)
The wall must be built in 6 days. Find how many workers are needed in addition to the original 8.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1: 8 × 15 = 120 (worker-days)
✓ 1
A1: 10 days
✓ 1
Part (b)
M1: 120 ÷ 6 = 20
✓ 1
A1: 12
✓ 1
Common error: More workers means fewer days, so this is inverse proportion. Multiplying 15 by 12/8 gives a longer time, which cannot be right.
79IGMC-041-03-09Estimation, rounding, bounds, ratio, proportion and moneyPaper CMedium5 marks
Calculator
Priya invests $4500 at a rate of 3.2% per year compound interest.
(a)
Calculate the value of her investment at the end of 5 years. Give your answer correct to the nearest cent.
(2)
(b)
Sam also invests $4500 for 5 years, but at r% per year simple interest. At the end of 5 years Sam's investment has the same value as Priya's. Find r.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1: 4500 × 1.0325
✓ 1
A1: $5267.58
✓ 1
Part (b)
M1: total interest 5267.58 − 4500 = 767.58
✓ 1
M1: 767.58 ÷ (5 × 4500) × 100
✓ 1
A1: 3.41
✓ 1
Common error: Simple interest is the same each year, so divide the total interest by the number of years. Do not divide the final amount by 5.
80IGMC-041-03-10Estimation, rounding, bounds, ratio, proportion and moneyPaper CMedium5 marks
No calculator
A bag contains only red and blue counters. The ratio red : blue = 5 : 3. 12 blue counters are added to the bag. The ratio red : blue becomes 5 : 6.
(a)
Find the number of red counters in the bag.
(3)
(b)
Some red counters are now removed from the bag. The ratio red : blue becomes 1 : 2. Find how many red counters are removed.
Exam tip: Notice the number of red counters does not change when blue counters are added. Using a multiplier k lets you write both ratios as equations.
81IGMC-041-03-11Estimation, rounding, bounds, ratio, proportion and moneyPaper CMedium6 marks
Without using your calculator, estimate the value of E by rounding each number to 1 significant figure. Show your working.
(2)
(b)
Use your calculator to find the value of E. Give your answer correct to 3 significant figures.
(2)
(c)
Calculate the percentage error in your estimate, using the unrounded value of E.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1: \(\frac{60 \times 0.4}{\sqrt{9 + 7}}\) seen
✓ 1
A1: 24 ÷ 4 = 6
✓ 1
Part (b)
M1: 24.3492 ÷ √16.14 or 24.3492 ÷ 4.0174…
✓ 1
A1: 6.06
✓ 1
Part (c)
M1: (6.0608… − 6) ÷ 6.0608… × 100
✓ 1
A1: 1.00%
✓ 1
Common error: Percentage error is divided by the accurate value, not the estimate. Use the unrounded calculator value, not 6.06.
82IGMC-041-00-06Types of number, factors, HCF and LCMPaper CMedium6 marks
No calculator
A = 24 × 32 × 7 B = 22 × 33 × 5
(a)
Find the highest common factor (HCF) of A and B. Give your answer as an ordinary number.
(2)
(b)
Find the lowest common multiple (LCM) of A and B. Give your answer as an ordinary number.
(2)
(c)
Find the smallest positive integer n such that An is a cube number.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 for 22 × 32
✓ 1
A1 for 36
✓ 1
Part (b)
M1 for 24 × 33 × 5 × 7
✓ 1
A1 for 15 120
✓ 1
Part (c)
M1 for identifying that 22, 3 and 72 are needed, e.g. 22 × 3 × 72
✓ 1
A1 for 588
✓ 1
Exam tip: For the HCF take the lower power of each prime common to both numbers; for the LCM take the higher power of every prime that appears in either.
83IGMC-041-00-07Types of number, factors, HCF and LCMPaper CMedium5 marks
Calculator
A rectangular floor measures 4.2 m by 3.15 m. It is to be covered completely with identical square tiles, with no cutting and no gaps. The side length of each tile is a whole number of centimetres.
Diagram not to scale
(a)
Find the largest possible side length of a tile.
(3)
(b)
Find the number of tiles needed when this largest tile is used.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 for converting to 420 cm and 315 cm
✓ 1
M1 for a method for the HCF, e.g. 420 = 22 × 3 × 5 × 7 and 315 = 32 × 5 × 7
✓ 1
A1 for 105 cm
✓ 1
Part (b)
M1 for (420 ÷ 105) × (315 ÷ 105) or 4 × 3
✓ 1
A1 for 12
✓ 1
Common error: Working in metres hides the HCF. Convert both lengths to centimetres first so that you are finding the HCF of two whole numbers.
84IGMC-041-00-08Types of number, factors, HCF and LCMPaper CMedium4 marks
No calculator
A shop has 84 red sweets and 126 green sweets. All the sweets are packed into identical bags. Each bag contains the same number of red sweets and the same number of green sweets, and no sweets are left over.
(a)
Find the greatest number of bags that can be made.
(3)
(b)
Find the total number of sweets in each bag.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 for 84 = 22 × 3 × 7 or 126 = 2 × 32 × 7, or a correct list of factors of both numbers
✓ 1
M1 for selecting the common factors 2 × 3 × 7, or stating that the highest common factor is needed
✓ 1
A1 for 42
✓ 1
Part (b)
B1 for 5, or (84 + 126) ÷ their (a) if it is a whole number; accept '2 red and 3 green'
✓ 1
Exam tip: "Greatest number of equal groups with nothing left over" signals HCF; "next time things happen together" signals LCM.
85IGMC-041-00-10Types of number, factors, HCF and LCMPaper CMedium6 marks
No calculator
For each statement, decide whether it is true or false and justify your answer.
(a)
"The sum of any two prime numbers is always even."
(2)
(b)
"For every positive integer n, the number n2 + n + 1 is prime."
(2)
(c)
"For every positive integer n, the number n2 + n is even."
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 for false
✓ 1
B1 for a correct counter-example using the prime 2 with an odd prime, e.g. 2 + 3 = 5, which is odd
✓ 1
Part (b)
B1 for false
✓ 1
B1 for a correct counter-example with the factorisation or a factor shown, e.g. n = 4 gives 21 = 3 × 7
✓ 1
Part (c)
M1 for a valid general method, e.g. writing n2 + n = n(n + 1), or considering n even and n odd separately
✓ 1
A1 for true with complete reasoning, e.g. n and n + 1 are consecutive integers so one is even, making the product even; or if n is even both terms are even, and if n is odd both terms are odd, so the sum is even in either case
✓ 1
Common error: Checking a few cases does not prove a statement is always true. One counter-example proves it false, but "true" needs a general argument that covers every value of n.
86IGMC-041-00-11Types of number, factors, HCF and LCMPaper CMedium6 marks
No calculator
(a)
Find the lowest common multiple of 6, 8 and 15.
(2)
(b)
Find the smallest square number that is a multiple of 6, 8 and 15.
(2)
(c)
Find the smallest integer greater than 1000 that leaves a remainder of 1 when divided by 6, by 8 and by 15.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 for 23 × 3 × 5 or for listing multiples to a common value
✓ 1
A1 for 120
✓ 1
Part (b)
M1 for 24 × 32 × 52 or for recognising that each prime power of 120 must be made even
✓ 1
A1 for 3600
✓ 1
Part (c)
M1 for 120k + 1 with a multiple of 120 near 1000, e.g. 120 × 9 = 1080
✓ 1
A1 for 1081
✓ 1
Common error: In (b), 120² = 14 400 is a square multiple but not the smallest. Make each prime's power even, which needs only one extra 2, one 3 and one 5.
87IGMC-041-02-07Indices, standard form and surdsPaper CMedium6 marks
No calculator
Answer each part.
(a)
Write these numbers in order of size, starting with the smallest. 4.1 ×10−3 0.0039 3.9 ×10−4 0.04
(2)
(b)
Work out (8.4 ×107) ÷ (2.1 ×10−3). Give your answer in standard form.
(2)
(c)
Work out 3.2 ×104 + 5 ×103. Give your answer in standard form.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1: at least two of the standard form numbers correctly converted, or three of the four in correct relative order
✓ 1
B1: 3.9 ×10−4, 0.0039, 4.1 ×10−3, 0.04
✓ 1
Part (b)
M1: 8.4 ÷ 2.1 = 4 and 7 − (−3) = 10 used
✓ 1
A1: 4 ×1010
✓ 1
Part (c)
M1: 32 000 + 5000 or 3.2 ×104 + 0.5 ×104
✓ 1
A1: 3.7 ×104
✓ 1
Common error: When adding numbers in standard form, do not add the powers. Write both with the same power of ten, or as ordinary numbers, before adding.
88IGMC-041-02-10Indices, standard form and surdsPaper CMedium5 marks
Calculator
The population of the world is 8.1 ×109. The total land area of the world is 1.49 ×108 km2.
(a)
Calculate the average number of people per km2 of land.
(2)
(b)
On average, each person produces 0.74 kg of waste per day. Calculate the total waste produced by the world's population in one year of 365 days. Give your answer in kilograms, in standard form.
(2)
(c)
1 tonne = 1000 kg. Write your answer to part (b) in tonnes, in standard form.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1: (8.1 ×109) ÷ (1.49 ×108)
✓ 1
A1: 54.4
✓ 1
Part (b)
M1: 8.1 ×109 × 0.74 × 365
✓ 1
A1: 2.19 ×1012 kg
✓ 1
Part (c)
B1ft: 2.19 ×109 tonnes (follow through their (b) ÷ 1000)
✓ 1
Exam tip: Dividing by 1000 lowers the power of ten by 3. You can do this without re-entering the whole calculation.
89IGMC3-1-07c-06Estimation, rounding, bounds, ratio, proportion and moneyPaper CMedium4 marks
Calculator
A hospital recorded 4 800 outpatient appointments in one year and 5 640 in the next year.
(a)
Calculate the percentage increase in appointments.
(2)
(b)
In the third year the number of appointments falls by 15% from the second year. Calculate the number of appointments in the third year.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 (5640 − 4800) ÷ 4800 × 100
✓ 1
A1 17.5%
✓ 1
Part (b)
M1 5640 × 0.85
✓ 1
A1 4794
✓ 1
Common error: Percentage change is found as a fraction of the starting value, not the final value.
90IGMC3-1-07c-07Estimation, rounding, bounds, ratio, proportion and moneyPaper CMedium5 marks
Calculator
A solar farm has 4.8 hectares of panels. Each hectare produces 2.05 MWh of energy per day. A home uses 0.096 MWh per day. The number of homes the farm can supply is \(N = \frac{4.8 \times 2.05}{0.096}\).
(a)
Write 7 462 correct to 2 significant figures.
(1)
(b)
Estimate the value of N by rounding each number in the calculation to 1 significant figure.
(2)
(c)
Calculate the exact value of N.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 7500
✓ 1
Part (b)
M1 \(\frac{5 \times 2}{0.1}\) (all three numbers rounded to 1 s.f.)
✓ 1
A1 100
✓ 1
Part (c)
M1 4.8 × 2.05 = 9.84
✓ 1
A1 102.5
✓ 1
Exam tip: Check an answer against your estimate: an exact value far from the estimate points to a slip.
91IGMC3-1-07c-08Types of number, factors, HCF and LCMPaper CMedium4 marks
Calculator
A 3D printer uses 15 g of filament to print 4 identical parts.
(a)
Calculate the mass of filament needed to print 10 of these parts.
(2)
(b)
A spool holds 1.2 kg of filament. Calculate the greatest number of whole parts that can be printed from one spool.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 15 ÷ 4 × 10 or 15 × 2.5
✓ 1
A1 37.5 g
✓ 1
Part (b)
M1 1200 ÷ 3.75 (mass per part converted to grams)
✓ 1
A1 320
✓ 1
Common error: Convert 1.2 kg to grams before dividing by a mass in grams.
92IGMC3-1-08r6-03Types of number, factors, HCF and LCMPaper CMedium5 marks
No calculator
Warning lights on a wind farm flash at regular intervals. Light A flashes every 12 seconds and light B flashes every 20 seconds. At 06:00:00 both flash together.
(a)
Write 12 and 20 as products of prime factors.
(2)
(b)
Find the highest common factor of 12 and 20.
(1)
(c)
Find the number of seconds after 06:00:00 at which the two lights next flash together.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 12 = 22 × 3
✓ 1
B1 20 = 22 × 5
✓ 1
Part (b)
B1 4
✓ 1
Part (c)
M1 attempt at LCM, e.g. 22 × 3 × 5 or listing multiples
✓ 1
A1 60
✓ 1
Exam tip: The LCM uses every prime factor at its highest power; the HCF uses only the shared ones at their lowest power.
93IGMC3-1-08r6-04Indices, standard form and surdsPaper CMedium6 marks
No calculator
A solar farm covers 80 hectares. 3⁄5 of the area is covered by solar panels. 1⁄4 of the remaining area is used for access roads. The rest is grassland.
(a)
Find the fraction of the whole farm used for access roads.
(2)
(b)
Find the fraction of the whole farm that is grassland.
(2)
(c)
Calculate the area of grassland.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 1 − 3/5 = 2/5
✓ 1
A1 1/4 × 2/5 = 1/10
✓ 1
Part (b)
M1 1 − 3/5 − 1/10
✓ 1
A1 3/10
✓ 1
Part (c)
M1 3/10 × 80
✓ 1
A1 24 hectares
✓ 1
Common error: 'A quarter of the remainder' is a quarter of what is left, not a quarter of the whole.
94IGMC3-1-08r6-05Indices, standard form and surdsPaper CMedium5 marks
Calculator
An epidemiologist studies a virus and a city.
(a)
A virus particle has diameter 1.25 × 10−7 m. Calculate how many such particles placed side by side in a straight line would span 5 × 10−5 m.
(2)
(b)
In a city of 8.4 × 106 people, 0.35% are infected. Calculate the number infected. Give your answer in standard form.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 5 × 10−5 ÷ 1.25 × 10−7
✓ 1
A1 400
✓ 1
Part (b)
M1 8.4 × 106 × 0.0035
✓ 1
A1 29400
✓ 1
A1 2.94 × 104
✓ 1
Common error: 0.35% means 0.35 ÷ 100 = 0.0035, not 0.35.
95IGMC3-1-10r9-05Types of number, factors, HCF and LCMPaper CMedium5 marks
No calculator
Two cyclists ride repeated laps of a track. Aiko takes 72 seconds for one lap and Ben takes 90 seconds. They start together on the line.
(a)
Find the number of seconds until they are next level on the line together.
(3)
(b)
After the ride, the club packs 72 bottles and 90 energy bars into identical boxes. Every box has the same number of bottles and the same number of bars, with none left over. Find the greatest possible number of boxes.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 72 = 23 × 32 and 90 = 2 × 32 × 5
✓ 1
M1 LCM = 23 × 32 × 5
✓ 1
A1 360 s
✓ 1
Part (b)
M1 HCF = 2 × 32
✓ 1
A1 18 boxes
✓ 1
Exam tip: LCM answers are 'when things coincide'; HCF answers are 'how many equal groups'. Match the method to the wording.
96IGMC3-1-10r9-06Estimation, rounding, bounds, ratio, proportion and moneyPaper CMedium6 marks
Calculator
An archaeologist records the length of a bone as 24.6 cm, correct to the nearest 0.1 cm.
(a)
Write down the lower bound and the upper bound of the length.
(2)
(b)
A bracelet has a mass of 85 g, correct to the nearest 5 g. Write down the error interval for its mass, m.
(2)
(c)
Three bones, each recorded as 24.6 cm correct to the nearest 0.1 cm, are laid end to end. Calculate the lower bound of their total length.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 lower bound 24.55 cm
✓ 1
B1 upper bound 24.65 cm
✓ 1
Part (b)
B1 82.5 ≤ m
✓ 1
B1 m < 87.5
✓ 1
Part (c)
M1 3 × 24.55
✓ 1
A1 73.65 cm
✓ 1
Common error: Halving the wrong unit. The bounds are half of the rounding unit either side: 0.05 for 0.1 cm, and 2.5 for 5 g.
97IGMC3-1-10r9-07Estimation, rounding, bounds, ratio, proportion and moneyPaper CMedium5 marks
Calculator
A cycling club shares a prize fund among three riders in the ratio 7 : 5 : 3. The rider with the smallest share receives €168.
(a)
Calculate the total prize fund.
(3)
(b)
The rider with the largest share spends 35% of it on equipment. Calculate the amount spent.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 168 ÷ 3 = 56 for one part
✓ 1
M1 15 × 56
✓ 1
A1 €840
✓ 1
Part (b)
B1 largest share 7 × 56 = €392
✓ 1
A1 €137.20
✓ 1
Exam tip: Find the value of one part first, then multiply by the number of parts you need.
98IGMC3-1-10r9-09Indices, standard form and surdsPaper CMedium7 marks
Calculator
A data centre holds 4.8 × 1015 bytes of data on identical hard drives. Each drive holds 1.6 × 1013 bytes and the drives are full.
(a)
Calculate the number of drives. Give your answer in standard form.
(2)
(b)
Each drive costs €1.2 × 103. Calculate the total cost of the drives. Give your answer in standard form.
(2)
(c)
The data can be read at 2.5 × 109 bytes per second. Calculate the number of days needed to read all 4.8 × 1015 bytes. There are 86400 seconds in a day. Give your answer correct to 1 decimal place.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 (4.8 × 1015) ÷ (1.6 × 1013)
✓ 1
A1 3 × 102
✓ 1
Part (b)
M1 300 × 1.2 × 103
✓ 1
A1 €3.6 × 105
✓ 1
Part (c)
M1 4.8 × 1015 ÷ 2.5 × 109 = 1.92 × 106 s
✓ 1
M1 1.92 × 106 ÷ 86400
✓ 1
A1 22.2 days
✓ 1
Common error: Entering standard form on a calculator without brackets around the divisor, which changes the order of operations.
99IGMC3-1-08r11-05Fractions, decimals and percentagesPaper CMedium5 marks
Calculator
Three climbers share the €1 260 cost of hiring a guide in the ratio 5 : 3 : 2.
(a)
Calculate the largest share.
(2)
(b)
The other two shares are €378 and €252. Write the ratio 378 : 252 in its simplest form.
(1)
(c)
Write the smallest share as a percentage of the total cost.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 \(1260 \div (5+3+2) \times 5\)
✓ 1
A1 €630
✓ 1
Part (b)
B1 3 : 2
✓ 1
Part (c)
M1 \(252 \div 1260 \times 100\)
✓ 1
A1 20%
✓ 1
Exam tip: Add the parts of the ratio first to find the value of one part, then multiply.
100IGMC3-1-08r11-06Estimation, rounding, bounds, ratio, proportion and moneyPaper CMedium5 marks
Calculator
A climber walks along a path of length 3 870 m at an average speed of 0.46 m/s.
(a)
Estimate the time taken in seconds by rounding each value to 1 significant figure.
(2)
(b)
Calculate the time taken. Give your answer in seconds correct to 3 significant figures.
(2)
(c)
Is the estimate in part (a) smaller or larger than the calculated time?
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 rounds to 4000 and 0.5
✓ 1
A1 8000 s
✓ 1
Part (b)
M1 \(3870 \div 0.46\)
✓ 1
A1 8410 s (from 8413.04...)
✓ 1
Part (c)
B1 smaller
✓ 1
Common error: Time = distance ÷ speed. Dividing speed by distance gives the wrong answer and the wrong units.
101IGMC3-1-08r11-07Types of number, factors, HCF and LCMPaper CMedium5 marks
No calculator
Here are seven numbers: 51, 57, 64, 73, 81, 91, 97. They are the last two digits of customer codes at a telecoms company.
(a)
Write down the prime numbers in the list.
(2)
(b)
Write down the number in the list that is both a square number and a cube number.
(1)
(c)
Write 91 as a product of two prime numbers.
(1)
(d)
Write down the multiple of 19 in the list.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 73
✓ 1
B1 97
✓ 1
Part (b)
B1 64
✓ 1
Part (c)
B1 7 × 13
✓ 1
Part (d)
B1 57
✓ 1
Common error: 1 is not prime and a prime number has exactly two factors; test divisibility by 3, 7 and 11 before deciding.
102IGMC3-1-08r11-08Indices, standard form and surdsPaper CMedium4 marks
Calculator
A telecoms server stores data in packets. Each packet uses \(2^{6}\) bytes of memory.
(a)
A buffer has \(2^{14}\) bytes of memory. Find how many packets fit in the buffer. Give your answer as a number.
(2)
(b)
Write \(5^{-2}\) as a fraction.
(1)
(c)
Find the value of \(n\) when \(3^{n} = \frac{1}{81}\).
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 \(2^{14} \div 2^{6} = 2^{8}\)
✓ 1
A1 256
✓ 1
Part (b)
B1 \(\frac{1}{25}\)
✓ 1
Part (c)
B1 \(-4\)
✓ 1
Exam tip: When dividing powers of the same number, subtract the indices: \(a^{m} \div a^{n} = a^{m-n}\).
103IGMC3-1-09r14-02Types of number, factors, HCF and LCMPaper CMedium6 marks
Calculator
A coffee roaster loads 7.5 kg of green beans into a roasting drum. During roasting the beans lose 20% of their mass as moisture. The roasted beans are packed into bags that each hold 250 g and each bag is sold for €6.80.
(a)
Calculate the mass of the roasted beans, in kg.
(2)
(b)
Work out how many full bags can be filled with the roasted beans.
(2)
(c)
Calculate the income from selling all of these bags.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 7.5 × 0.8 or 7.5 − 0.20 × 7.5
✓ 1
A1 6 kg
✓ 1
Part (b)
M1 6000 ÷ 250 (or 6 ÷ 0.25)
✓ 1
A1 24 bags
✓ 1
Part (c)
M1 24 × 6.80
✓ 1
A1 €163.20
✓ 1
Common error: Convert all masses to the same unit (grams or kilograms) before dividing; 6 ÷ 250 is not the same as 6000 ÷ 250.
104IGMC3-1-09r14-05Estimation, rounding, bounds, ratio, proportion and moneyPaper CMedium7 marks
Calculator
A coffee shop mixes beans from Brazil, Colombia and Ethiopia in the ratio 5 : 3 : 2 to make 4.5 kg of a blend. The beans cost €14 per kg (Brazil), €18 per kg (Colombia) and €26 per kg (Ethiopia).
(a)
Calculate the mass of Colombian beans in the blend.
(2)
(b)
Calculate the total cost of the beans in the blend.
(3)
(c)
Work out the cost of the blend per kg.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 4.5 × 3 ÷ 10 (or 4.5 ÷ 10 = 0.45 per part)
✓ 1
A1 1.35 kg
✓ 1
Part (b)
M1 masses of other two types found (2.25 kg and 0.9 kg)
Exam tip: In ratio questions, add the parts first and find the value of one part; then multiply to get each share.
105IGMC3-1-09r14-06Estimation, rounding, bounds, ratio, proportion and moneyPaper CMedium6 marks
Calculator
A crew paints a steel bridge. They cover 48.7 m2 per hour and work for 2.04 hours. Each litre of paint covers 0.52 m2.
(a)
Estimate the number of litres of paint needed by rounding each number to 1 significant figure. Show your working.
(2)
(b)
Calculate the number of litres needed, correct to 3 significant figures.
(2)
(c)
Work out the percentage by which the estimate in part (a) is greater than the unrounded value 191.05 litres. Give your answer correct to 3 significant figures.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 50 × 2 ÷ 0.5 (all three values rounded to 1 s.f.)
✓ 1
A1 200 litres
✓ 1
Part (b)
M1 48.7 × 2.04 = 99.348 (area in m2)
✓ 1
A1 191 litres
✓ 1
Part (c)
M1 (200 − 191.05) ÷ 191.05 × 100
✓ 1
A1 4.68%
✓ 1
Common error: Rounding every value to 1 significant figure for an estimate is quick, but dividing by 0.52 rounded to 0.5 can change the answer noticeably.
106IGMC3-1-09r14-07Fractions, decimals and percentagesPaper CMedium4 marks
Calculator
A roasting company invests €12500 in a savings account that pays simple interest at 3.2% per year.
(a)
Calculate the total interest earned after 4 years.
(2)
(b)
The company needs the account to reach €15000 in total. Calculate how many years this takes.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 12500 × 0.032 × 4 (or 400 per year × 4)
✓ 1
A1 €1600
✓ 1
Part (b)
M1 interest needed 2500 ÷ interest per year 400
✓ 1
A1 6.25 years
✓ 1
Exam tip: Simple interest is the same amount every year: I = P × r × t with r as a decimal or divided by 100.
107IGMC3-1-09r14-10Types of number, factors, HCF and LCMPaper CMedium5 marks
No calculator
Two steel rods on a bridge are 126 cm and 210 cm long. They are cut into pieces which are all the same length. No steel is wasted and the pieces are as long as possible.
(a)
Write 126 as a product of its prime factors.
(2)
(b)
Find the highest common factor of 126 and 210, given that 210 = 2 × 3 × 5 × 7.
(2)
(c)
Find the total number of pieces.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 correct factorisation method
✓ 1
A1 2 × 32 × 7
✓ 1
Part (b)
M1 product of common prime factors 2 × 3 × 7
✓ 1
A1 42
✓ 1
Part (c)
B1 126 ÷ 42 + 210 ÷ 42 = 3 + 5 = 8
✓ 1
Exam tip: Cutting with no waste and as long as possible signals a highest common factor; filling a space or meeting again signals a lowest common multiple.
108IGMC3-1-09r17-05Indices, standard form and surdsPaper CMedium4 marks
Calculator
A radio signal travels at 3.0 × 105 km/s. A space probe is 4.5 × 109 km from Earth.
(a)
Calculate the time taken for the signal to reach Earth. Give your answer in seconds, in standard form.
(2)
(b)
Change your answer to hours. Give your answer correct to 3 significant figures. Use the exact value 1.5 × 104 s.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 4.5 × 109 ÷ (3.0 × 105)
✓ 1
A1 1.5 × 104 s
✓ 1
Part (b)
M1 15 000 ÷ 3600
✓ 1
A1 4.17 hours
✓ 1
Exam tip: Subtract the powers of ten when dividing, and keep the coefficient between 1 and 10 when writing standard form.
109IGMC3-1-09r17-06Estimation, rounding, bounds, ratio, proportion and moneyPaper CMedium8 marks
Calculator
A coffee blend is made from Arabica beans and Robusta beans in the ratio 5 : 3 by mass. A batch of the blend has mass 12.8 kg.
(a)
Show that the batch contains 4.8 kg of Robusta beans.
(2)
(b)
Arabica beans cost €14.50 per kilogram and Robusta beans cost €9.00 per kilogram. Calculate the cost of the beans in the batch.
(3)
(c)
The blend is sold at €17.25 per kilogram. Calculate the percentage profit on the cost of the batch, correct to 3 significant figures. Use €159.20 as the cost.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 12.8 ÷ 8 = 1.6 (one share) or 12.8 × 3/8
✓ 1
A1 4.8 kg, shown with no errors
✓ 1
Part (b)
B1 Arabica 8 kg costs €116
✓ 1
B1 Robusta 4.8 kg costs €43.20
✓ 1
A1 €159.20
✓ 1
Part (c)
M1 revenue 12.8 × 17.25 = €220.80
✓ 1
M1 (220.80 − 159.20) ÷ 159.20 × 100
✓ 1
A1 38.7%
✓ 1
Common error: Dividing the total mass by 5 or by 3 instead of by the total number of shares (8), and finding profit as a percentage of the selling price instead of the cost.
110IGMC3-1-09r17-07Estimation, rounding, bounds, ratio, proportion and moneyPaper CMedium5 marks
Calculator
A footbridge is built from 38 identical steel sections. Each section has mass 2140 kg.
(a)
Estimate the total mass of the sections by rounding each number to 1 significant figure.
(2)
(b)
Calculate the exact total mass.
(1)
(c)
Work out the percentage error in the estimate, correct to 3 significant figures. Use the exact total mass as the true value.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 rounds to 40 and 2000
✓ 1
A1 80 000 kg
✓ 1
Part (b)
B1 81 320 kg
✓ 1
Part (c)
M1 (81 320 − 80 000) ÷ 81 320 × 100
✓ 1
A1 1.62%
✓ 1
Exam tip: Percentage error is the size of the error divided by the true value, not by the estimate.
111IGMC3-1-09r17-13Types of number, factors, HCF and LCMPaper CMedium6 marks
No calculator
A rectangular bridge walkway measures 84 m by 60 m. It is to be covered with identical square slabs. The side of each slab is a whole number of metres and the slabs fit exactly with no cutting.
Diagram not to scale
(a)
Write 84 and 60 each as a product of prime factors.
(2)
(b)
Find the side length of the largest square slab that can be used.
(2)
(c)
Work out how many of these slabs are needed.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 84 = 22 × 3 × 7
✓ 1
B1 60 = 22 × 3 × 5
✓ 1
Part (b)
M1 multiplies the common prime factors, 22 × 3
✓ 1
A1 12 m
✓ 1
Part (c)
M1 (84 ÷ 12) × (60 ÷ 12)
✓ 1
A1 35
✓ 1
Exam tip: The largest slab that fits both dimensions exactly has side equal to the highest common factor of the two lengths.
112IGMC3-1-09r22-05Estimation, rounding, bounds, ratio, proportion and moneyPaper CMedium5 marks
Calculator
A robotics workshop makes a cleaning fluid by mixing lubricant oil and solvent in the ratio oil : solvent = 3 : 7.
(a)
The workshop uses 450 ml of oil. Calculate the volume of solvent needed.
(2)
(b)
Find the percentage of the mixture that is oil.
(1)
(c)
Each robot joint needs 30 ml of the mixture from part (a). How many joints can be treated?
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 \(450\div3\times7\)
✓ 1
A1 1050 ml
✓ 1
Part (b)
B1 30%
✓ 1
Part (c)
M1 \((450+1050)\div30\)
✓ 1
A1 50
✓ 1
Common error: A ratio 3 : 7 has 10 parts in total, so oil is \(\frac{3}{10}\) of the mixture, not \(\frac{3}{7}\).
113IGMC3-1-09r22-06Fractions, decimals and percentagesPaper CMedium6 marks
Calculator
The price of a fabric rises from €18.50 per metre to €21.46 per metre.
(a)
Calculate the percentage increase in the price.
(2)
(b)
A tailor buys 12.5 m of the fabric at the new price. Calculate the cost.
(2)
(c)
The tailor receives a bulk discount of 8% on the cost in part (b). Calculate the amount the tailor pays, correct to the nearest cent.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 \(\frac{21.46-18.50}{18.50}\times100\)
✓ 1
A1 16%
✓ 1
Part (b)
M1 \(12.5\times21.46\)
✓ 1
A1 €268.25
✓ 1
Part (c)
M1 \(268.25\times0.92\)
✓ 1
A1 €246.79
✓ 1
Exam tip: For a percentage change, divide the change by the original value, then multiply by 100.
114IGMC3-1-09r22-08Types of number, factors, HCF and LCMPaper CMedium6 marks
No calculator
Two patrol robots start together at the start line of a circular track. Robot A completes one lap every 24 seconds and robot B completes one lap every 40 seconds.
(a)
Find the number of seconds until the two robots are next at the start line together.
(2)
(b)
How many laps has each robot completed at that time?
(2)
(c)
A third robot C, with a lap time of 16 seconds, joins them at the start line. Find the time until all three robots are next at the start line together.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 LCM of 24 and 40, e.g. \(24=2^3\times3\), \(40=2^3\times5\) or lists of multiples
✓ 1
A1 120 s
✓ 1
Part (b)
B1 robot A: 5 laps
✓ 1
B1 robot B: 3 laps
✓ 1
Part (c)
M1 LCM of 24, 40 and 16, e.g. \(2^4\times3\times5\)
✓ 1
A1 240 s
✓ 1
Common error: The time they meet again is the lowest common multiple of the lap times, not the highest common factor.
115IGMC3-1-09r22-10Estimation, rounding, bounds, ratio, proportion and moneyPaper CMedium5 marks
Calculator
A trawler lands 1846 kg of fish on Monday.
(a)
Write 1846 correct to 2 significant figures.
(1)
(b)
Estimate the value of \(\frac{48.7\times2.03}{0.0987}\) by rounding each number to 1 significant figure.
(2)
(c)
The fish sell for €3.84 per kilogram. Calculate the value of Monday's catch, correct to the nearest euro.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 1800
✓ 1
Part (b)
M1 \(\frac{50\times2}{0.1}\)
✓ 1
A1 1000
✓ 1
Part (c)
M1 \(1846\times3.84\) (= 7088.64)
✓ 1
A1 €7089
✓ 1
Common error: Rounding to 2 significant figures must keep the zeros as place holders: 1800, not 18.
116IGMC3-1-09r24-05Estimation, rounding, bounds, ratio, proportion and moneyPaper CMedium6 marks
Calculator
A swimming club charges a yearly membership fee of €85 plus €4.50 for each session attended.
(a)
Work out the total cost for a member who attends 18 sessions in the year.
(2)
(b)
Next year the membership fee of €85 will increase by 8%. Work out the new membership fee.
(2)
(c)
Next year the session charge stays at €4.50. A member has exactly €199.80 to spend. Work out the greatest number of sessions the member can attend.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 85 + 18 × 4.50
✓ 1
A1 €166
✓ 1
Part (b)
M1 85 × 1.08 (or 85 + 0.08 × 85)
✓ 1
A1 €91.80
✓ 1
Part (c)
M1 (199.80 − 91.80) ÷ 4.50 (ECF from (b))
✓ 1
A1 24 sessions
✓ 1
Exam tip: Always show the multiplier or the calculation line; a correct method still earns marks if the final arithmetic slips.
117IGMC3-1-09r24-06Fractions, decimals and percentagesPaper CMedium6 marks
Calculator
A town library service shares a yearly book budget of £18 000 between three branches in the ratio 5 : 3 : 2.
(a)
Work out the amount received by each branch.
(2)
(b)
Next year the largest branch receives £11 250 and the ratio stays 5 : 3 : 2. Work out the new total budget.
(2)
(c)
Work out the percentage increase in the total budget.
Common error: Dividing the total by 3 (the number of branches) instead of by 10 (the number of parts in the ratio).
118IGMC3-1-09r24-07Estimation, rounding, bounds, ratio, proportion and moneyPaper CMedium5 marks
Calculator
The power per unit area of a wind farm site is estimated using the calculation \(\dfrac{49.5 \times 2.4}{0.198}\).
(a)
Estimate the value by rounding each number to 1 significant figure.
(3)
(b)
Use a calculator to work out the exact value. State whether the estimate in (a) is smaller or larger than the exact value.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 49.5 → 50 and 2.4 → 2
✓ 1
B1 0.198 → 0.2
✓ 1
A1 50 × 2 ÷ 0.2 = 500
✓ 1
Part (b)
B1 600
✓ 1
B1 estimate is smaller (500 < 600)
✓ 1
Exam tip: In an estimate, show each rounded number clearly before you divide; do not round the final answer only.
119IGMC3-1-09r24-08Indices, standard form and surdsPaper CMedium5 marks
No calculator
This question is about indices.
(a)
Work out \(5^{-2}\).
(1)
(b)
Simplify \((2x^{3})^{4}\).
(2)
(c)
Find the value of \(n\) when \(3^{n} = \frac{1}{81}\).
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 \(\frac{1}{25}\)
✓ 1
Part (b)
B1 24 = 16
✓ 1
B1 \(x^{12}\) (so \(16x^{12}\))
✓ 1
Part (c)
M1 \(\frac{1}{81} = 3^{-4}\) or \(81 = 3^4\)
✓ 1
A1 \(n = -4\)
✓ 1
Common error: A negative index means a reciprocal, not a negative answer: \(5^{-2}\) is \(\frac{1}{25}\), not \(-25\).
120IGMC3-1-09r24-10Types of number, factors, HCF and LCMPaper CMedium6 marks
No calculator
A library labels shelves using these numbers: 9, 11, 16, 27, 29, 36, 45
(a)
From the list, write down all the prime numbers.
(2)
(b)
From the list, write down one cube number and all the square numbers.
(2)
(c)
Find the smallest positive integer \(n\) such that \(45n\) is a square number.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 11
✓ 1
B1 29 (and no other numbers)
✓ 1
Part (b)
B1 27 as the cube number
✓ 1
B1 9, 16 and 36 as the square numbers
✓ 1
Part (c)
M1 45 = 32 × 5, so a further factor of 5 is needed
✓ 1
A1 \(n = 5\) (giving 225 = 152)
✓ 1
Exam tip: Write a number as a product of primes; a square number has every prime appearing an even number of times.
121IGMC3-1-09r26-04Estimation, rounding, bounds, ratio, proportion and moneyPaper CMedium4 marks
Calculator
An archaeological project has a budget of £9 600. It is shared between excavation, laboratory analysis and publication in the ratio 5 : 4 : 3.
(a)
Work out the amount for excavation.
(2)
(b)
The laboratory analysis share is then increased by 15%. Work out the new laboratory analysis amount.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 9600 ÷ (5 + 4 + 3) = 800
✓ 1
A1 £4000
✓ 1
Part (b)
M1 4 × 800 = 3200 and 3200 × 1.15
✓ 1
A1 £3680
✓ 1
Exam tip: Find the value of one part first, then multiply by the number of parts you need.
122IGMC3-1-09r26-05Fractions, decimals and percentagesPaper CMedium4 marks
Calculator
A cycling shop sells a bike in a sale for €460. This is 20% less than the original price.
(a)
Work out the original price of the bike.
(2)
(b)
The shop bought the bike for €400. Work out the percentage profit on the cost price when it is sold for €460.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 460 = 80% of original, so 460 ÷ 0.8
✓ 1
A1 €575
✓ 1
Part (b)
M1 (460 − 400) ÷ 400 × 100
✓ 1
A1 15%
✓ 1
Common error: Common error: working out 20% of €460 and adding it on. The sale price is 80% of the original, not the other way round.
123IGMC3-1-09r26-07Types of number, factors, HCF and LCMPaper CMedium5 marks
Calculator
Ava and Ben ride round a circular track. Ava takes 72 seconds for each lap and Ben takes 90 seconds for each lap. They start together at the start line and ride at constant speeds.
(a)
Write 72 as a product of prime factors.
(2)
(b)
Find the lowest common multiple (LCM) of 72 and 90.
(2)
(c)
Work out how many laps Ben has completed when they are next together at the start line.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 factor tree or repeated division by primes
✓ 1
A1 23 × 32
✓ 1
Part (b)
M1 90 = 2 × 32 × 5 or lists of multiples
✓ 1
A1 360
✓ 1
Part (c)
B1 4
✓ 1
Exam tip: For the LCM, take the highest power of each prime factor that appears in either number.
124IGMC3-1-09r26-11Fractions, decimals and percentagesPaper CMedium5 marks
Calculator
A server rack in a data centre uses electricity at a constant rate of 4.5 kW. It runs for 24 hours every day. Electricity costs €0.18 per kilowatt-hour (kWh).
(a)
Work out the energy used by the rack in one day.
(1)
(b)
Work out the cost of running the rack for 30 days.
(2)
(c)
The price per kWh is then reduced by 12%. Work out the cost for 30 days at the new price. Give your answer to the nearest cent.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 108 kWh
✓ 1
Part (b)
M1 108 × 30 × 0.18
✓ 1
A1 €583.20
✓ 1
Part (c)
M1 583.20 × 0.88
✓ 1
A1 €513.22
✓ 1
Exam tip: Money answers should be written to 2 decimal places, and units (kWh, €) should be included.
125IGMC3-1-10r26-05Fractions, decimals and percentagesPaper CMedium4 marks
Calculator
A robot uses 2⁄5 of its battery charge on task A and 1⁄3 of its full charge on task B.
(a)
Work out the fraction of the full charge used on both tasks. Give your answer as a fraction in its simplest form.
(2)
(b)
After both tasks, 960 mAh of charge remains. Work out the full charge of the battery.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 common denominator, 6⁄15 + 5⁄15
✓ 1
A1 11⁄15
✓ 1
Part (b)
M1 remaining fraction 4⁄15 and 960 ÷ 4⁄15
✓ 1
A1 3600 mAh
✓ 1
Exam tip: If a fraction of a quantity is known, divide by that fraction to find the whole.
126IGMC3-1-10r26-06Estimation, rounding, bounds, ratio, proportion and moneyPaper CMedium5 marks
Calculator
A designer buys a dress in Paris for €85. The exchange rate is €1 = £0.86. Later she borrows money to expand her studio.
(a)
Convert €85 to pounds (£).
(2)
(b)
She borrows £4000 at 3.5% simple interest per year for 3 years. Work out the total interest.
(2)
(c)
Work out the total amount she must repay.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 85 × 0.86
✓ 1
A1 £73.10
✓ 1
Part (b)
M1 4000 × 3.5 ÷ 100 × 3
✓ 1
A1 £420
✓ 1
Part (c)
B1 £4420
✓ 1
Exam tip: Simple interest is the same amount every year: principal × rate × time ÷ 100.
127IGMC3-1-10r26-07Fractions, decimals and percentagesPaper CMedium6 marks
Calculator
A fish farm has 1800 fish, all either salmon or trout. The ratio salmon : trout is 7 : 5.
(a)
Work out the number of salmon.
(2)
(b)
The farm sells 150 trout. Write the new ratio salmon : trout in its simplest form.
(2)
(c)
Work out the percentage of the remaining fish that are salmon. Give your answer correct to 3 significant figures.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 1800 ÷ 12 × 7
✓ 1
A1 1050
✓ 1
Part (b)
M1 1050 : 600 (trout 750 − 150)
✓ 1
A1 7 : 4
✓ 1
Part (c)
M1 1050 ÷ 1650 × 100
✓ 1
A1 63.6%
✓ 1
Exam tip: After a change, rebuild the actual numbers first, then form the new ratio.
128IGMC3-1-10r26-08Fractions, decimals and percentagesPaper CMedium6 marks
Calculator
A coat costs €120. The price rises to €138. In a later sale, the new price of €138 is reduced by 15%.
(a)
Work out the percentage increase from €120 to €138.
(2)
(b)
Work out the sale price.
(2)
(c)
Work out the overall percentage decrease from the original price of €120 to the sale price. Give your answer correct to 3 significant figures.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 (138 − 120) ÷ 120 × 100
✓ 1
A1 15%
✓ 1
Part (b)
M1 138 × 0.85
✓ 1
A1 €117.30
✓ 1
Part (c)
M1 (120 − 117.30) ÷ 120 × 100
✓ 1
A1 2.25% decrease
✓ 1
Common error: Common error: thinking +15% then −15% returns to the start. The second percentage is of a larger amount.
129IGMC3-1-10r26-11Types of number, factors, HCF and LCMPaper CMedium4 marks
Calculator
A robotics lab floor measures 840 cm by 1200 cm. It is to be covered completely with identical square tiles, with no cutting.
Diagram not to scale
(a)
Find the side length of the largest possible square tile.
(2)
(b)
Work out the number of these tiles needed.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 prime factors 840 = 23 × 3 × 5 × 7 and 1200 = 24 × 3 × 52, or lists of common factors
✓ 1
A1 120 cm
✓ 1
Part (b)
M1 (840 ÷ 120) × (1200 ÷ 120)
✓ 1
A1 70
✓ 1
Exam tip: The largest tile that fits both sides exactly has a side equal to the HCF of the two lengths.
130IGMC3-1-10r26-14Estimation, rounding, bounds, ratio, proportion and moneyPaper CMedium6 marks
Calculator
A robot arm weighs a sample and a controller computes a value V.
(a)
The mass of the sample is 4.6 kg, correct to 1 decimal place. Write down the lower bound and the upper bound of the mass.
(2)
(b)
Write 0.00678 correct to 2 significant figures.
(1)
(c)
The controller uses V = (49.8 × 3.9) ÷ 0.21. Estimate V by rounding each number to 1 significant figure.
(2)
(d)
Calculate V correct to 3 significant figures.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 4.55 kg
✓ 1
B1 4.65 kg
✓ 1
Part (b)
B1 0.0068
✓ 1
Part (c)
M1 50 × 4 ÷ 0.2
✓ 1
A1 1000
✓ 1
Part (d)
B1 925
✓ 1
Exam tip: Round to 1 significant figure first; leading zeros in a decimal such as 0.21 are not significant.
131IGMC3-1-10r31-05Fractions, decimals and percentagesPaper CMedium6 marks
Calculator
The price of roasted coffee beans rises by 12% to £19.04 per kg.
(a)
Calculate the price per kg before the rise.
(2)
(b)
The following month the price of £19.04 falls by 5%. Calculate the new price per kg, correct to the nearest penny.
(2)
(c)
Calculate the overall percentage change from the price in part (a) to the price in part (b). Use the unrounded price from part (b).
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 19.04 ÷ 1.12
✓ 1
A1 £17.00
✓ 1
Part (b)
M1 19.04 × 0.95
✓ 1
A1 £18.09
✓ 1
Part (c)
M1 1.12 × 0.95 = 1.064 or 18.088 ÷ 17
✓ 1
A1 6.4% increase
✓ 1
Common error: A reverse percentage problem needs division by the multiplier (1.12), not subtraction of 12%.
132IGMC3-1-10r31-06Estimation, rounding, bounds, ratio, proportion and moneyPaper CMedium6 marks
Calculator
Concrete for a bridge deck is made by mixing cement, sand and gravel in the ratio 2 : 3 : 7 by mass. One batch has a total mass of 4.8 tonnes.
(a)
Work out the mass of sand in one batch.
(2)
(b)
Work out the percentage of the batch that is gravel. Give your answer correct to 3 significant figures.
(2)
(c)
Gravel costs £22 per tonne. Work out the cost of the gravel in one batch.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 4.8 ÷ 12 × 3 or 0.4 × 3
✓ 1
A1 1.2 tonnes
✓ 1
Part (b)
M1 7 ÷ 12 × 100
✓ 1
A1 58.3%
✓ 1
Part (c)
M1 4.8 ÷ 12 × 7 = 2.8 tonnes and × 22
✓ 1
A1 £61.60
✓ 1
Exam tip: Add the parts of a ratio to find the total number of shares before dividing.
133IGMC3-1-10r31-07Indices, standard form and surdsPaper CMedium5 marks
No calculator
A space probe records signal strengths using powers and standard form.
(a)
Write 25 × 23 ÷ 24 as a single power of 2.
(2)
(b)
Work out (3 × 104) × (2 × 103). Give your answer in standard form.
(2)
(c)
Write 2−3 as a fraction.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 add powers 5 + 3 and subtract 4
✓ 1
A1 24
✓ 1
Part (b)
M1 3 × 2 = 6 and 104 × 103 = 107
✓ 1
A1 6 × 107
✓ 1
Part (c)
B1 1/8
✓ 1
Common error: A negative power means a reciprocal; it does not make the answer negative.
134IGMC3-1-10r31-08Estimation, rounding, bounds, ratio, proportion and moneyPaper CMedium6 marks
Calculator
Estimating a quantity for a probe's fuel use, a student wants to evaluate \(\frac{49.6 \times 3.08}{0.0197}\).
(a)
Round each number to 1 significant figure and so estimate the value of the expression.
(3)
(b)
Use a calculator to work out the value of the expression, correct to 3 significant figures.
(2)
(c)
State whether the estimate in part (a) is an overestimate or an underestimate. Give a reason.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 50, 3 and 0.02
✓ 1
M1 \(\frac{50 \times 3}{0.02}\)
✓ 1
A1 7500
✓ 1
Part (b)
M1 49.6 × 3.08 ÷ 0.0197 = 7754.7…
✓ 1
A1 7750
✓ 1
Part (c)
Underestimate, because 7500 is less than 7750
✓ 1
Exam tip: Show each rounded number in an estimate so that method marks can be awarded even if the arithmetic slips.
135IGMC3-1-12r32-05Fractions, decimals and percentagesPaper CMedium6 marks
Calculator
A farmer is reviewing her wheat business. The price of wheat rose from £0.24 per kg to £0.27 per kg. The yield was 5.5 tonnes per hectare last year and has fallen by 8% this year. A tractor part now costs £207 after a price rise of 15%.
(a)
Work out the percentage increase in the price of wheat.
(2)
(b)
Work out the yield this year, in tonnes per hectare.
(2)
(c)
Work out the price of the tractor part before the 15% rise.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 (0.27 − 0.24) ÷ 0.24 × 100
✓ 1
A1 12.5%
✓ 1
Part (b)
M1 5.5 × 0.92 (or 5.5 − 0.08 × 5.5)
✓ 1
A1 5.06
✓ 1
Part (c)
M1 207 ÷ 1.15
✓ 1
A1 £180
✓ 1
Common error: For a reverse percentage, divide by the multiplier (1.15); do not subtract 15% from the new price.
136IGMC3-1-12r32-08Types of number, factors, HCF and LCMPaper CMedium6 marks
No calculator
A choir has 72 singers who stand in equal rows, with the same number of singers in every row.
(a)
Write 72 as a product of prime factors.
(2)
(b)
The choir can stand in a single row or in a single column. Apart from these, find the number of different ways it can stand in equal rows, where each row has more than one singer and there is more than one row.
(2)
(c)
The choir wants to stand in a square formation, with the same number of rows as singers per row. Find the smallest number of extra singers needed.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 repeated division by primes or a factor tree
✓ 1
A1 23 × 32
✓ 1
Part (b)
M1 lists or counts the factors of 72: 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72
✓ 1
A1 10 ways
✓ 1
Part (c)
M1 identifies 81 as the next square number
✓ 1
A1 9
✓ 1
Common error: Remember that 1 and 72 are factors but do not give a useful arrangement with more than one row and more than one singer per row.
137IGMC3-1-12r32-09Estimation, rounding, bounds, ratio, proportion and moneyPaper CMedium4 marks
Calculator
A farmer mixes nitrogen, phosphate and potash in the ratio 5 : 2 : 1 by mass to make 160 kg of fertiliser. Separately, 4 workers take 9 hours to harvest a field. All workers work at the same rate.
(a)
Find the mass of nitrogen in the fertiliser.
(2)
(b)
Find the time that 6 workers would take to harvest the same field.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 160 ÷ 8 = 20 kg per part
✓ 1
A1 100 kg
✓ 1
Part (b)
M1 4 × 9 ÷ 6 (inverse proportion)
✓ 1
A1 6 hours
✓ 1
Common error: More workers means less time, so the proportion is inverse: do not multiply 9 by 6/4.
138IGMC3-1-12r32-11Indices, standard form and surdsPaper CMedium5 marks
Calculator
A farm plants 2.5 × 105 seeds on each hectare of a farm with 3.2 × 102 hectares. Each seed has a mass of 4.0 × 10−2 g.
(a)
Calculate the total number of seeds planted. Give your answer in standard form.
(2)
(b)
Calculate the total mass of the seeds in grams. Give your answer in standard form.
(2)
(c)
Write your answer to (b) in kilograms.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 2.5 × 105 × 3.2 × 102
✓ 1
A1 8 × 107
✓ 1
Part (b)
M1 8 × 107 × 4.0 × 10−2 (ECF from (a))
✓ 1
A1 3.2 × 106 g
✓ 1
Part (c)
B1 3200 kg (or 3.2 × 103 kg) (ECF)
✓ 1
Common error: When multiplying numbers in standard form, add the powers of 10; do not multiply them.
139IGMC3-1-11r36-02Types of number, factors, HCF and LCMPaper CMedium7 marks
Calculator
A harbour warehouse stores 360 crates. Exactly 3/8 of the crates contain fish feed and 0.35 of the crates contain nets. All the other crates contain rope.
(a)
Work out the number of crates that contain fish feed.
(2)
(b)
Work out the number of crates that contain nets.
(2)
(c)
Find the percentage of the crates that contain rope.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 360 × 3/8
✓ 1
A1 135
✓ 1
Part (b)
M1 0.35 × 360
✓ 1
A1 126
✓ 1
Part (c)
M1 360 − 135 − 126 = 99 (ECF from earlier parts)
✓ 1
M1 99 ÷ 360 × 100
✓ 1
A1 27.5
✓ 1
Common error: Candidates often add the fraction and the decimal directly; convert both to numbers of crates (or both to percentages) first.
140IGMC3-1-11r36-04Fractions, decimals and percentagesPaper CMedium6 marks
Calculator
A research tank needs 1350 litres of artificial seawater. It is made by mixing salt concentrate and fresh water in the ratio 2 : 7.
(a)
Show that the tank needs 300 litres of salt concentrate.
(2)
(b)
Work out the volume of fresh water needed.
(2)
(c)
Salt concentrate costs £3.20 per litre. Work out the cost of the concentrate for the tank.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 1350 ÷ (2 + 7) or 1350 × 2/9
✓ 1
A1 150 × 2 = 300 shown clearly
✓ 1
Part (b)
M1 1350 − 300 or 150 × 7
✓ 1
A1 1050
✓ 1
Part (c)
M1 300 × 3.20
✓ 1
A1 £960
✓ 1
Exam tip: Add the parts of the ratio first to find the value of one part, then multiply.
141IGMC3-1-11r36-05Indices, standard form and surdsPaper CMedium4 marks
Calculator
A single plankton cell has mass 3.2 × 10−9 g. A water sample contains 5 × 107 of these cells.
(a)
Calculate the total mass of the cells in the sample. Give your answer in standard form.
(2)
(b)
A whale shark has mass 1.6 × 107 g. Work out how many plankton cells have a total mass equal to that of the whale shark. Give your answer in standard form.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 3.2 × 10−9 × 5 × 107
✓ 1
A1 1.6 × 10−1
✓ 1
Part (b)
M1 1.6 × 107 ÷ (3.2 × 10−9)
✓ 1
A1 5 × 1015
✓ 1
Exam tip: Check that your answer is in the form a × 10ⁿ with 1 ≤ a < 10 before moving on.
142IGMC3-1-11r36-09Types of number, factors, HCF and LCMPaper CMedium6 marks
No calculator
The lamps of two lighthouses flash at regular intervals. Lamp A flashes every 12 seconds and lamp B flashes every 18 seconds. At 21:00:00 both lamps flash together.
(a)
Write 12 and 18 each as a product of prime factors.
(2)
(b)
Find the lowest common multiple (LCM) of 12 and 18.
(2)
(c)
Work out how many more times the lamps flash together in the 10 minutes after 21:00:00.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 12 = 22 × 3
✓ 1
B1 18 = 2 × 32
✓ 1
Part (b)
M1 22 × 32 or listing multiples of both numbers
✓ 1
A1 36
✓ 1
Part (c)
M1 600 ÷ 36 = 16.7... or listing multiples of 36 up to 600
✓ 1
A1 16
✓ 1
Common error: When counting whole flashes, round the quotient down, not to the nearest integer.
143IGMC3-1-10r42-02Types of number, factors, HCF and LCMPaper CMedium6 marks
No calculator
Two trains, X and Y, leave a rail terminus together at 06:00. Train X leaves every 12 minutes and train Y leaves every 15 minutes.
(a)
Find the next time at which both trains leave together.
(2)
(b)
A cleaner packs 84 first-class headrest covers and 126 standard-class headrest covers into identical boxes. Every box holds the same number of each class and no covers are left over. Find the greatest number of boxes she can fill.
(2)
(c)
Find the total number of covers in each box.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 attempt to find the lowest common multiple of 12 and 15
✓ 1
A1 07:00
✓ 1
Part (b)
M1 prime factors 84 = 22 × 3 × 7 and 126 = 2 × 32 × 7, or other valid method for the highest common factor
✓ 1
A1 42
✓ 1
Part (c)
M1 84 ÷ 42 and 126 ÷ 42
✓ 1
A1 5 (ECF from (b))
✓ 1
Common error: Use the highest common factor for sharing equally into groups and the lowest common multiple for repeating events.
144IGMC3-1-10r42-04Fractions, decimals and percentagesPaper CMedium6 marks
Calculator
An annual rail season ticket costs £1166 after a price rise of 6%.
(a)
Calculate the price of the ticket before the rise.
(2)
(b)
The price of a weekly ticket falls from £840 to £714. Calculate the percentage decrease.
(2)
(c)
A railcard gives 12.5% off the £1166 ticket. Calculate the price after the discount.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 1166 ÷ 1.06
✓ 1
A1 £1100
✓ 1
Part (b)
M1 (840 − 714) ÷ 840 × 100
✓ 1
A1 15%
✓ 1
Part (c)
M1 1166 × (1 − 0.125) or 1166 × 0.875
✓ 1
A1 £1020.25
✓ 1
Common error: For a reverse percentage, divide by the multiplier; do not subtract 6% of the new price.
145IGMC3-1-10r42-05Indices, standard form and surdsPaper CMedium5 marks
Calculator
The distance from the Earth to the Sun is 1.5 × 108 km. Light travels at 3.0 × 105 km/s.
(a)
Calculate the time taken for light to travel from the Sun to the Earth. Give your answer in seconds, in standard form.
(2)
(b)
Calculate the distance light travels in 365 days. Give your answer in kilometres, in standard form, correct to 3 significant figures.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 1.5 × 108 ÷ 3.0 × 105
✓ 1
A1 5.0 × 102 s
✓ 1
Part (b)
M1 365 × 24 × 3600 = 31 536 000 s
✓ 1
M1 3.0 × 105 × 31 536 000
✓ 1
A1 9.46 × 1012 km
✓ 1
Exam tip: Convert days to seconds so the units match the speed in km per second.
146IGMC3-1-10r42-07Estimation, rounding, bounds, ratio, proportion and moneyPaper CMedium6 marks
Calculator
A sports scientist designs a recovery drink mix. The carbohydrate, protein and electrolyte powders are mixed in the ratio 8 : 3 : 1 by mass.
(a)
A batch of the mix has a total mass of 600 g. Calculate the mass of protein powder in the batch.
(2)
(b)
Another batch contains 45 g of protein powder. Calculate the mass of carbohydrate powder in this batch.
(2)
(c)
A 240 ml serving of the drink contains 18 g of sugar. The mass of sugar is directly proportional to the volume. Calculate the mass of sugar in 350 ml of the drink.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 600 ÷ (8 + 3 + 1) × 3
✓ 1
A1 150 g
✓ 1
Part (b)
M1 45 ÷ 3 × 8
✓ 1
A1 120 g
✓ 1
Part (c)
M1 18 ÷ 240 × 350
✓ 1
A1 26.25 g
✓ 1
Exam tip: Add the parts of the ratio first to find the value of one part.
147IGMC3-1-10r42-14Estimation, rounding, bounds, ratio, proportion and moneyPaper CMedium5 marks
Calculator
A touring football team changes money at an exchange rate of £1 = €1.16.
(a)
A hotel bill is €312. Calculate the bill in pounds, correct to the nearest penny.
(2)
(b)
The manager changes £500 into euros. The bank takes 2% commission from the euros received. Calculate the number of euros the team receives.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 312 ÷ 1.16
✓ 1
A1 £268.97
✓ 1
Part (b)
M1 500 × 1.16 = 580
✓ 1
M1 580 × 0.98
✓ 1
A1 €568.40
✓ 1
Common error: To convert into the currency worth less per unit, multiply; to convert back, divide.
148IGMC-041-01-13Fractions, decimals and percentagesPaper CHard6 marks
Calculator
A trader buys 250 identical lamps for a total of $1800. She sells 60% of the lamps at a profit of 35% on the cost price of each lamp. She sells the rest of the lamps at a loss. Her overall profit on all 250 lamps is 15%.
(a)
Work out the selling price of each of the lamps sold at a profit.
(2)
(b)
Work out the percentage loss on each of the remaining lamps.
(4)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 for 1800 ÷ 250 (= 7.20) seen or implied, then × 1.35
✓ 1
A1 $9.72
✓ 1
Part (b)
M1 for total income 1800 × 1.15 (= 2070) with income 150 × 9.72 (= 1458); OR total profit 0.15 × 1800 (= 270) with profit 150 × 2.52 (= 378)
✓ 1
M1 for (2070 − 1458) ÷ 100 (= 6.12) OR (378 − 270) ÷ 100 (= 1.08 loss per lamp)
✓ 1
M1 for (7.20 − 6.12) ÷ 7.20 × 100 OR 1.08 ÷ 7.20 × 100, or equivalent
✓ 1
A1 15%
✓ 1
Exam tip: Find the cost of one lamp first ($7.20) and the number of lamps in each group (150 and 100). Then use the overall 15% profit to find either the total income or the total profit needed.
149IGMC-041-01-14Fractions, decimals and percentagesPaper CHard6 marks
No calculator
A water tank is \(\frac{3}{8}\) full. When 55 litres of water are added, the tank is \(\frac{5}{6}\) full.
(a)
Work out the capacity of the tank.
(3)
(b)
40% of the water in the tank is then used. Show that the tank is now exactly half full.
(2)
(c)
Work out how many litres of water are needed to fill the tank completely.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 for \(\frac{5}{6} - \frac{3}{8}\) \(\left(= \frac{11}{24}\right)\)
✓ 1
M1 for \(55 \div \frac{11}{24}\) or \(55 \div 11 \times 24\)
✓ 1
A1 for 120 litres
✓ 1
Part (b)
M1 for \(\frac{5}{6} \times 0.6\) or \(\frac{5}{6} \times 120 \times 0.6\) (= 100 × 0.6)
✓ 1
A1 for \(\frac{1}{2}\), or for 60 litres out of 120 litres shown
✓ 1
Part (c)
B1 for 60 litres
✓ 1
Common error: The 55 litres is the difference between the two fractions, not \(\frac{5}{6}\) of the tank. Subtract the fractions first, then divide 55 by that difference.
150IGMC-041-03-14Estimation, rounding, bounds, ratio, proportion and moneyPaper CHard7 marks
No calculator
Three positive quantities x, y and z satisfy x : y = 3 : 4 and y : z = 6 : 5.
(a)
Find the ratio x : y : z in its simplest form.
(2)
(b)
Given that x + y + z = 155, find the values of x and z.
(2)
(c)
The same number, n, is added to both x and z. The ratio of the new values becomes 11 : 12. Find n.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1: both ratios written with the same value of y, e.g. 9 : 12 and 12 : 10
✓ 1
A1: 9 : 12 : 10
✓ 1
Part (b)
M1: 155 ÷ 31 = 5
✓ 1
A1: x = 45 and z = 50
✓ 1
Part (c)
M1: \(\frac{45 + n}{50 + n} = \frac{11}{12}\)
✓ 1
M1: 540 + 12n = 550 + 11n
✓ 1
A1: n = 10
✓ 1
Exam tip: To combine two ratios, make the shared quantity the same in both. Here y becomes 12, the lowest common multiple of 4 and 6.
151IGMC-041-02-13Indices, standard form and surdsPaper CHard6 marks
Calculator
An adult has 5.0 litres of blood. Red blood cells make up 45% of the volume of the blood. The volume of one red blood cell is 9.0 ×10−17 m3. 1 litre = 1 ×10−3 m3.
(a)
Write 5.0 litres in m3, in standard form.
(1)
(b)
Calculate the number of red blood cells in this adult's blood. Give your answer in standard form.
(3)
(c)
Each red blood cell lasts 120 days and is then replaced. The total number of red blood cells stays the same. Calculate the number of red blood cells replaced each second. Give your answer in standard form, correct to 3 significant figures.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1: 5.0 ×10−3 m3
✓ 1
Part (b)
M1: 0.45 × 5.0 ×10−3, giving 2.25 ×10−3
✓ 1
M1: dividing their volume by 9.0 ×10−17
✓ 1
A1: 2.5 ×1013
✓ 1
Part (c)
M1: their (b) ÷ (120 × 24 × 60 × 60)
✓ 1
A1: 2.41 ×106
✓ 1
Common error: In (c), convert 120 days fully into seconds: 120 × 24 × 60 × 60 = 10 368 000. Dividing by 120 × 24 gives cells per hour, not per second.
152IGMC3-1-07c-09Fractions, decimals and percentagesPaper CHard7 marks
Calculator
A school sold 480 concert tickets. The ratio of adult tickets to child tickets sold was 5 : 7. An adult ticket costs €12 and a child ticket costs €7.50. One in every 8 adult tickets was sold at half price. The staging costs were €3 000.
(a)
Calculate the number of adult tickets sold.
(2)
(b)
Calculate the total money received from ticket sales.
(3)
(c)
Calculate the profit as a percentage of the staging costs.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 480 ÷ 12 × 5
✓ 1
A1 200
✓ 1
Part (b)
M1 200 ÷ 8 = 25 half-price adult tickets
✓ 1
M1 175 × 12 + 25 × 6 + 280 × 7.50
✓ 1
A1 €4350
✓ 1
Part (c)
M1 (4350 − 3000) ÷ 3000 × 100
✓ 1
A1 45%
✓ 1
Exam tip: Percentage profit is measured against the cost, so divide the profit by the cost.
153IGMC3-1-08r6-14Estimation, rounding, bounds, ratio, proportion and moneyPaper CHard7 marks
Calculator
A town has 15000 residents, and this number does not change. The ratio of vaccinated to unvaccinated residents is 7 : 3.
(a)
Calculate the number of vaccinated residents.
(2)
(b)
A campaign changes the ratio to 4 : 1. Calculate the number of vaccinated residents now.
(2)
(c)
Find the percentage increase in the number of vaccinated residents. Give your answer to 3 significant figures.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 15000 ÷ 10 × 7
✓ 1
A1 10500
✓ 1
Part (b)
M1 15000 ÷ 5 × 4
✓ 1
A1 12000
✓ 1
Part (c)
M1 12000 − 10500 = 1500
✓ 1
M1 1500 ÷ 10500 × 100
✓ 1
A1 14.3%
✓ 1
Exam tip: Percentage increase is always the change divided by the original amount, not by the new amount.
154IGMC3-1-10r9-14Indices, standard form and surdsPaper CHard7 marks
Calculator
In a museum collection of archaeological items, 5⁄12 of the items are pottery. Of the items that are not pottery, 3⁄7 are coins. The remaining 160 items are tools.
(a)
Find the fraction of the non-pottery items that are tools.
(1)
(b)
Calculate the number of items that are not pottery.
(2)
(c)
Calculate the total number of items in the collection.
(2)
(d)
Calculate the percentage of the items that are pottery. Give your answer correct to 1 decimal place.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 1 − 3⁄7 = 4⁄7
✓ 1
Part (b)
M1 160 ÷ 4⁄7 (ECF from (a))
✓ 1
A1 280
✓ 1
Part (c)
M1 non-pottery fraction = 7⁄12, so 280 ÷ 7⁄12 (ECF from (b))
✓ 1
A1 480
✓ 1
Part (d)
M1 5⁄12 × 100
✓ 1
A1 41.7%
✓ 1
Common error: Taking ³⁄₇ of the whole collection. It is a fraction of the non-pottery items only.
155IGMC3-1-08r11-14Fractions, decimals and percentagesPaper CHard5 marks
Calculator
A food scientist makes 400 g of syrup in which the ratio of the mass of sugar to the mass of water is 3 : 5.
(a)
Calculate the mass of sugar in the syrup.
(2)
(b)
She adds water to the syrup until the ratio of sugar to water is 3 : 7. Calculate the mass of water she adds.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 \(400 \times \frac{3}{8}\)
✓ 1
A1 150 g
✓ 1
Part (b)
M1 original mass of water \(= 250\) g
✓ 1
M1 new mass of water \(= 150 \times \frac{7}{3} = 350\) g
✓ 1
A1 100 g
✓ 1
Common error: Adding water changes only the water; the mass of sugar stays at 150 g, so use it as the fixed quantity.
156IGMC3-1-09r17-14Fractions, decimals and percentagesPaper CHard6 marks
No calculator
A space probe has a fuel tank that is full at launch. In the first manoeuvre 2/5 of the fuel is used. In the second manoeuvre 3/8 of the fuel remaining after the first manoeuvre is used. After the second manoeuvre 45 litres remain.
(a)
Show that the fraction of the original fuel used in the second manoeuvre is 9/40.
(2)
(b)
Find the fraction of the original fuel that remains after the second manoeuvre.
(2)
(c)
Calculate the volume of fuel in the full tank.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 3/5 remains after the first manoeuvre, and 3/8 × 3/5
✓ 1
A1 9/40, shown
✓ 1
Part (b)
M1 3/5 − 9/40 = 24/40 − 9/40 (or 5/8 × 3/5)
✓ 1
A1 3/8
✓ 1
Part (c)
M1 45 ÷ 3/8 (ECF from (b))
✓ 1
A1 120 litres
✓ 1
Common error: Taking ³/₈ of the whole tank in the second manoeuvre instead of ³/₈ of what was left.
157IGMC3-1-09r22-13Types of number, factors, HCF and LCMPaper CHard8 marks
No calculator
A fashion studio has 252 strips of black lace and 396 strips of gold lace. It makes identical packs, using all the strips with none left over.
(a)
Find the greatest number of packs the studio can make.
(3)
(b)
Write down the number of strips of each colour in one pack.
(2)
(c)
Find the smallest positive integer \(k\) such that \(252k\) is a square number, and write down \(\sqrt{252k}\).
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 \(252=2^2\times3^2\times7\) and \(396=2^2\times3^2\times11\)
✓ 1
M1 common factors \(2^2\times3^2\)
✓ 1
A1 36
✓ 1
Part (b)
B1 7 black (ECF from (a))
✓ 1
B1 11 gold (ECF from (a))
✓ 1
Part (c)
M1 all prime powers must be even, so an extra factor of 7 is needed
✓ 1
A1 \(k=7\)
✓ 1
A1 \(\sqrt{252\times7}=42\)
✓ 1
Exam tip: A square number has every prime factor appearing an even number of times.
158IGMC3-1-09r26-14Estimation, rounding, bounds, ratio, proportion and moneyPaper CHard8 marks
Calculator
A cyclist rides at a constant speed of 24 km/h for 2 hours 20 minutes. She then rides back along the same road, covering the same distance.
(a)
Work out the distance she rides outward.
(2)
(b)
Her return speed is 14 km/h. Work out her average speed for the whole journey. Give your answer correct to 1 decimal place.
(3)
(c)
On another day she wants an average speed of 20 km/h for the whole 112 km, with the same outward ride. Work out the speed she needs for the return. Give your answer correct to 1 decimal place.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 24 × 7/3 or 24 × 2.33…
✓ 1
A1 56 km
✓ 1
Part (b)
M1 return time = 56 ÷ 14 = 4 hours
✓ 1
M1 112 ÷ (7/3 + 4)
✓ 1
A1 17.7 km/h
✓ 1
Part (c)
M1 total time = 112 ÷ 20 = 5.6 hours
✓ 1
M1 return time = 5.6 − 7/3 = 3.2666… hours
✓ 1
A1 56 ÷ 3.2666… = 17.1 km/h
✓ 1
Common error: Common error: averaging the two speeds. Average speed is total distance divided by total time.
159IGMC3-1-10r31-13Types of number, factors, HCF and LCMPaper CHard7 marks
No calculator
Three instruments on a space probe transmit data every 12 minutes, every 20 minutes and every 45 minutes respectively. All three transmit together at 06:00.
(a)
Write each of 12, 20 and 45 as a product of prime factors.
(3)
(b)
Find the lowest common multiple of 12, 20 and 45 and write it in hours.
(2)
(c)
How many times do all three transmit together from 06:00 up to, but not including, 06:00 the next day? Include the transmission at 06:00.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 12 = 22 × 3
✓ 1
B1 20 = 22 × 5
✓ 1
B1 45 = 32 × 5
✓ 1
Part (b)
M1 22 × 32 × 5
✓ 1
A1 180 minutes = 3 hours
✓ 1
Part (c)
M1 24 ÷ 3
✓ 1
A1 8 times
✓ 1
Exam tip: Use the highest power of each prime from the factorisations to build the LCM.
160IGMC3-1-12r32-14Types of number, factors, HCF and LCMPaper CHard6 marks
No calculator
Three tractors on a farm are refuelled every 8 days, every 12 days and every 15 days. All three are refuelled together on day 0.
(a)
Find the lowest common multiple (LCM) of 8, 12 and 15 using prime factors.
(3)
(b)
Find how many times, after day 0, up to and including day 1000, all three tractors are refuelled on the same day.
(2)
(c)
Find the last day on or before day 1000 when all three are refuelled together.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 8 = 23, 12 = 22 × 3, 15 = 3 × 5
✓ 1
M1 takes the highest power of each prime
✓ 1
A1 23 × 3 × 5 = 120
✓ 1
Part (b)
M1 1000 ÷ 120 = 8.33…
✓ 1
A1 8
✓ 1
Part (c)
B1 8 × 120 = 960 (ECF from (a) and (b))
✓ 1
Exam tip: For repeating cycles, the common days are multiples of the LCM.
161IGMC3-1-11r36-14Estimation, rounding, bounds, ratio, proportion and moneyPaper CHard5 marks
Calculator
In a seal colony the ratio of males to females is 5 : 7. Later, 30 males leave the colony and 18 females join it. The ratio of males to females is then 1 : 2.
(a)
Let the number of males at the start be 5k. Find the value of k.
(3)
(b)
Work out the total number of seals in the colony after the changes.
M1 5 × 26 − 30 (= 100) and 7 × 26 + 18 (= 200) (ECF from (a))
✓ 1
A1 300
✓ 1
Exam tip: Write each group as a multiple of the ratio parts, apply the changes, then use the new ratio to form an equation.
162IGMC-041-02-05Indices, standard form and surdsPaper EEasy4 marks
No calculator
Simplify each expression. Give your answers in their simplest form.
(a)
\(\sqrt{50}\)
(1)
(b)
\(\sqrt{12} + \sqrt{75}\)
(2)
(c)
\(\sqrt{3} \times \sqrt{27}\)
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1: \(5\sqrt{2}\)
✓ 1
Part (b)
M1: \(2\sqrt{3}\) or \(5\sqrt{3}\) seen
✓ 1
A1: \(7\sqrt{3}\)
✓ 1
Part (c)
B1: 9
✓ 1
Common error: \(\sqrt{12} + \sqrt{75}\) is not \(\sqrt{87}\). Surds can only be added once they share the same root, so simplify each one first.
163IGMC-041-01-08Fractions, decimals and percentagesPaper EMedium6 marks
No calculator
In this question, show all your algebraic working.
(a)
Show that \(0.\dot{2}\dot{7} = \frac{3}{11}\).
(2)
(b)
Write \(0.1\dot{8}\) as a fraction in its simplest form.
(2)
(c)
Hence write \(0.\dot{2}\dot{7} + 0.1\dot{8}\) as a single fraction in its simplest form.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 for \(x = 0.2727...\) and \(100x = 27.2727...\) leading to \(99x = 27\)
✓ 1
A1 \(x = \frac{27}{99} = \frac{3}{11}\) shown
✓ 1
Part (b)
M1 for \(10x = 1.888...\) and \(100x = 18.888...\) leading to \(90x = 17\), or equivalent
✓ 1
A1 \(\frac{17}{90}\)
✓ 1
Part (c)
M1 for \(\frac{270}{990} + \frac{187}{990}\) or other correct common denominator
✓ 1
A1 \(\frac{457}{990}\)
✓ 1
Exam tip: Choose powers of 10 so that the recurring parts line up exactly after the decimal point. Then subtract to remove the recurring part.
164IGMC-041-01-12Fractions, decimals and percentagesPaper EMedium5 marks
Calculator
Lina invests $5000 in an account that pays compound interest.
(a)
The account pays 4% per year. Show that the value of the investment after 4 years is $5849.29, correct to the nearest cent.
(2)
(b)
A different account pays compound interest at \(r\)% per year. An investment of $5000 in this account is worth $6200 after 5 years. Find the value of \(r\), giving your answer correct to 3 significant figures.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 for 5000 × 1.044
✓ 1
A1 5849.2928 seen, rounding to $5849.29
✓ 1
Part (b)
M1 for \(5000\left(1 + \frac{r}{100}\right)^5 = 6200\)
✓ 1
M1 for \(1 + \frac{r}{100} = \sqrt[5]{1.24}\) (= 1.04396...)
✓ 1
A1 \(r\) = 4.40 (accept 4.396 or more accurate)
✓ 1
Exam tip: In a 'show that' question, write a more accurate value (such as 5849.2928) before rounding. This shows the answer was not simply copied.
165IGMC-041-03-07Estimation, rounding, bounds, ratio, proportion and moneyPaper EMedium5 marks
Calculator
y is inversely proportional to the square of x. When x = 5, y = 12.
(a)
Find an expression for y in terms of x.
(2)
(b)
Find y when x = 4.
(1)
(c)
Find the positive value of x when y = 3.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1: \(12 = \frac{k}{5^2}\)
✓ 1
A1: \(y = \frac{300}{x^2}\)
✓ 1
Part (b)
B1: 18.75
✓ 1
Part (c)
M1: \(x^2 = \frac{300}{3} = 100\)
✓ 1
A1: 10
✓ 1
Common error: Inversely proportional to the square means \(y = \frac{k}{x^2}\). Using \(y = \frac{k}{x}\) or \(y = kx^2\) loses every mark that follows.
166IGMC-041-03-08Estimation, rounding, bounds, ratio, proportion and moneyPaper EMedium4 marks
Calculator
A car travels a distance of 350 km, correct to the nearest 10 km. The journey takes 4.2 hours, correct to the nearest 0.1 hour.
(a)
Complete the statement for the distance, d km: …… ≤ d < ……
(1)
(b)
Calculate the upper bound of the average speed of the car.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1: 345 ≤ d < 355
✓ 1
Part (b)
B1: 4.15 used as the lower bound of the time
✓ 1
M1: 355 ÷ 4.15
✓ 1
A1: 85.5 km/h
✓ 1
Exam tip: To make a quotient as large as possible, divide the largest numerator by the smallest denominator.
167IGMC-041-00-09Types of number, factors, HCF and LCMPaper EMedium3 marks
No calculator
Two positive integers have a highest common factor of 12 and a lowest common multiple of 360.
(a)
Explain why 50 cannot be one of the two integers.
(1)
(b)
One of the integers is 72. Find the other integer.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 for either valid reason: 50 is not a multiple of 12 (both numbers must be multiples of the HCF), OR 50 is not a factor of 360 (both numbers must divide the LCM)
✓ 1
Part (b)
M1 for 12 × 360 ÷ 72, or 4320 ÷ 72, or a correct prime factor method (e.g. 72 = 23 × 32, 360 = 23 × 32 × 5, HCF 12 = 22 × 3)
✓ 1
A1 for 60
✓ 1
Exam tip: For two numbers, HCF × LCM = product of the numbers. Always check your answer: HCF(72, 60) = 12 and LCM(72, 60) = 360.
168IGMC-041-02-06Indices, standard form and surdsPaper EMedium5 marks
No calculator
Rationalise the denominator of each fraction. Give your answers in their simplest form.
(a)
\(\frac{6}{\sqrt{3}}\)
(2)
(b)
\(\frac{4}{3-\sqrt{5}}\)
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1: multiplying numerator and denominator by \(\sqrt{3}\), giving \(\frac{6\sqrt{3}}{3}\)
✓ 1
A1: \(2\sqrt{3}\)
✓ 1
Part (b)
M1: multiplying numerator and denominator by \(3+\sqrt{5}\)
✓ 1
M1: denominator \(9 - 5 = 4\)
✓ 1
A1: \(3+\sqrt{5}\)
✓ 1
Exam tip: For a denominator of the form \(a - \sqrt{b}\), multiply top and bottom by \(a + \sqrt{b}\). The difference of two squares then removes the surd from the denominator.
169IGMC-041-02-08Indices, standard form and surdsPaper EMedium6 marks
No calculator
Solve each equation.
(a)
\(3^x = 81\)
(1)
(b)
\(2^{x+1} = 8^{x-1}\)
(3)
(c)
\(25^y = \frac{1}{125}\)
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1: \(x = 4\)
✓ 1
Part (b)
M1: \(8 = 2^3\) used, giving \(2^{3x-3}\)
✓ 1
M1: \(x + 1 = 3x - 3\)
✓ 1
A1: \(x = 2\)
✓ 1
Part (c)
M1: \(5^{2y} = 5^{-3}\)
✓ 1
A1: \(y = -\frac{3}{2}\)
✓ 1
Exam tip: Write both sides as powers of the same base. Once the bases match, you can set the powers equal to each other.
170IGMC-041-02-09Indices, standard form and surdsPaper EMedium7 marks
No calculator
Simplify each expression.
(a)
\((16x^8)^{\frac{1}{2}}\)
(2)
(b)
\(\frac{12a^5b^{-2}}{3a^{-1}b^3}\)
(3)
(c)
\(\left(\frac{8}{27x^6}\right)^{-\frac{1}{3}}\)
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1: 4
✓ 1
B1: \(x^4\), giving \(4x^4\)
✓ 1
Part (b)
B1: 4
✓ 1
B1: \(a^6\)
✓ 1
B1: \(b^{-5}\) or \(\frac{1}{b^5}\), giving \(\frac{4a^6}{b^5}\)
✓ 1
Part (c)
M1: reciprocal \(\left(\frac{27x^6}{8}\right)^{\frac{1}{3}}\) or cube root \(\frac{2}{3x^2}\) seen
✓ 1
A1: \(\frac{3x^2}{2}\)
✓ 1
Common error: In (b), \(a^5 \div a^{-1}\) is \(a^{5-(-1)} = a^6\), not \(a^4\). Take care when subtracting a negative power.
171IGMC-041-02-11Indices, standard form and surdsPaper EMedium6 marks
No calculator
A rectangle has length \((3+\sqrt{2})\) cm and width \((3-\sqrt{2})\) cm.
Diagram not to scale
(a)
Find the perimeter of the rectangle.
(1)
(b)
Show that the area of the rectangle is a whole number of square centimetres, and find this area.
(2)
(c)
Find the exact length of a diagonal of the rectangle.
M1: one square correctly expanded, \(11 + 6\sqrt{2}\) or \(11 - 6\sqrt{2}\)
✓ 1
A1: \(\sqrt{22}\) cm
✓ 1
Common error: \((3+\sqrt{2})^2\) is not \(9 + 2\). Expand fully to get \(9 + 6\sqrt{2} + 2\). The middle term matters, even though it cancels later here.
172IGMC3-1-07c-10Fractions, decimals and percentagesPaper EMedium5 marks
Calculator
A fund pays compound interest. A sum of €8 000 is invested at 3.5% per year for 4 years.
(a)
Calculate the value of the investment after 4 years, correct to the nearest cent.
(3)
(b)
A battery pack is sold after an 18% reduction for €147.60. Calculate its original price.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 multiplier 1.035
✓ 1
M1 8000 × 1.0354
✓ 1
A1 €9180.18
✓ 1
Part (b)
M1 147.60 ÷ 0.82
✓ 1
A1 €180
✓ 1
Common error: For a reverse percentage divide by the multiplier (0.82); adding 18% to €147.60 gives the wrong price.
173IGMC3-1-07c-11Indices, standard form and surdsPaper EMedium6 marks
No calculator
Two support beams have lengths √50 m and √18 m. A rectangular solar panel has area 12 m2 and width (3 − √3) m.
Diagram not to scale
(a)
Write the total length of the two beams in the form a√2, where a is an integer.
(2)
(b)
Find the length of the panel in the form p + q√3, where p and q are integers.
(4)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 √50 = 5√2 or √18 = 3√2
✓ 1
A1 8√2
✓ 1
Part (b)
M1 length = 12 ÷ (3 − √3)
✓ 1
M1 multiply numerator and denominator by (3 + √3)
✓ 1
M1 denominator 9 − 3 = 6
✓ 1
A1 6 + 2√3 (≈ 9.4641)
✓ 1
Exam tip: To rationalise a denominator of the form a − √b, multiply top and bottom by a + √b so the surds cancel.
174IGMC3-1-07c-12Estimation, rounding, bounds, ratio, proportion and moneyPaper EMedium6 marks
Calculator
A metal plate is a rectangle. Its length is 12.4 cm and its width is 8.5 cm, each measured correct to the nearest 0.1 cm.
Diagram not to scale
(a)
Write down the lower bound and the upper bound of the length.
(2)
(b)
Calculate the upper bound of the area of the plate.
(2)
(c)
Calculate the lower bound of the perimeter of the plate.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 12.35 cm
✓ 1
B1 12.45 cm
✓ 1
Part (b)
M1 12.45 × 8.55
✓ 1
A1 106.4475 cm2
✓ 1
Part (c)
M1 2 × (12.35 + 8.45)
✓ 1
A1 41.6 cm
✓ 1
Common error: For a measurement to the nearest 0.1 cm, the bounds are 0.05 either side, not 0.1 either side.
175IGMC3-1-08r6-06Estimation, rounding, bounds, ratio, proportion and moneyPaper EMedium5 marks
Calculator
A household solar-panel system costs €4800 when new. Its value falls by 8% each year.
(a)
Calculate its value after 4 years, to the nearest cent.
(3)
(b)
Calculate the total percentage decrease in value over the 4 years. Give your answer to 3 significant figures.
Common error: Four decreases of 8% do not make a 32% decrease, because each is taken from a smaller value.
176IGMC3-1-08r6-08Indices, standard form and surdsPaper EMedium5 marks
No calculator
A rectangular solar panel has length \((3+\sqrt{5})\) m and width \((3-\sqrt{5})\) m.
Diagram not to scale
(a)
Show that the area of the panel is 4 m2.
(2)
(b)
Find the exact length of a diagonal of the panel.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 \((3+\sqrt{5})(3-\sqrt{5})\) expanded, or difference of two squares \(3^2-(\sqrt{5})^2\)
✓ 1
A1 9 − 5 = 4
✓ 1
Part (b)
M1 \(d^2=(3+\sqrt{5})^2+(3-\sqrt{5})^2\)
✓ 1
M1 \((14+6\sqrt{5})+(14-6\sqrt{5})=28\)
✓ 1
A1 \(\sqrt{28}=2\sqrt{7}\) m (5.2915 m to 5 s.f.)
✓ 1
Common error: \((a+b)^2\) is not \(a^2+b^2\); the middle term \(2ab\) must be included before it cancels.
177IGMC3-1-08r6-09Indices, standard form and surdsPaper EMedium5 marks
No calculator
Answer both parts, giving exact answers.
(a)
Simplify \(\sqrt{48}-\sqrt{12}\).
(2)
(b)
Rationalise the denominator and simplify \(\dfrac{6}{3-\sqrt{3}}\).
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 \(\sqrt{48}=4\sqrt{3}\) or \(\sqrt{12}=2\sqrt{3}\)
✓ 1
A1 \(2\sqrt{3}\)
✓ 1
Part (b)
M1 multiply numerator and denominator by \(3+\sqrt{3}\)
✓ 1
M1 denominator \(9-3=6\)
✓ 1
A1 \(3+\sqrt{3}\)
✓ 1
Exam tip: To rationalise \(a-\sqrt{b}\) multiply by \(a+\sqrt{b}\); the surds cancel in the denominator.
178IGMC3-1-08r6-12Indices, standard form and surdsPaper EMedium7 marks
No calculator
Answer all parts.
(a)
Evaluate \(27^{-\frac{2}{3}}\).
(2)
(b)
Solve \(2^{x+1}=\frac18\).
(2)
(c)
Simplify \(\dfrac{(2a^3b)^4}{8a^5b^2}\).
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 \(27^{\frac13}=3\) and take the reciprocal power
✓ 1
A1 \(\frac19\)
✓ 1
Part (b)
M1 \(\frac18=2^{-3}\)
✓ 1
A1 \(x=-4\)
✓ 1
Part (c)
M1 numerator \(16a^{12}b^4\)
✓ 1
M1 \(16\div8\) and subtract indices
✓ 1
A1 \(2a^7b^2\)
✓ 1
Common error: A negative index means a reciprocal, not a negative answer.
179IGMC3-1-10r9-08Indices, standard form and surdsPaper EMedium7 marks
No calculator
An archaeologist measures a rectangular stone slab. Its length is (3 + √5) metres and its width is (3 − √5) metres.
Diagram not to scale
(a)
Show that the area of the slab is 4 m2.
(2)
(b)
A rope of length 12 m is divided by the slab's length. Write 12 ÷ (3 + √5) in the form a − b√5, where a and b are integers.
(2)
(c)
Find the length of the diagonal of the slab. Give your answer in the form p√q, where q is an integer as small as possible.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 (3 + √5)(3 − √5) = 9 − 5 or expanding all four terms
✓ 1
A1 4 m2 shown
✓ 1
Part (b)
M1 multiply numerator and denominator by (3 − √5)
✓ 1
A1 a = 9, b = 3, so 9 − 3√5
✓ 1
Part (c)
M1 length2 = 14 + 6√5 and width2 = 14 − 6√5
✓ 1
M1 diagonal2 = 28
✓ 1
A1 2√7 m
✓ 1
Common error: Squaring (3 + √5) as 9 + 5. The cross term 6√5 must also appear.
180IGMC3-1-10r9-10Estimation, rounding, bounds, ratio, proportion and moneyPaper EMedium7 marks
Calculator
A touring bicycle costs €2400 when new. Its value falls by 15% of its value at the start of each year.
(a)
Calculate the value of the bicycle after 3 years.
(2)
(b)
A second bicycle is sold with a 20% discount for €1360. Calculate its price before the discount.
(2)
(c)
Show, by calculation, that the value of the first bicycle falls below €1000 for the first time during the 6th year.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 2400 × 0.853
✓ 1
A1 €1473.90
✓ 1
Part (b)
M1 1360 ÷ 0.8
✓ 1
A1 €1700
✓ 1
Part (c)
M1 value after 5 years = 2400 × 0.855
✓ 1
A1 €1064.89, which is above €1000
✓ 1
A1 value after 6 years = €905.16, which is below €1000
✓ 1
Common error: Taking 15% off the original price each year instead of multiplying by 0.85 repeatedly.
181IGMC3-1-10r9-11Indices, standard form and surdsPaper EMedium5 marks
No calculator
Evaluate and solve the following.
(a)
Evaluate 163/4.
(2)
(b)
Solve 8x − 1 = 1⁄16.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 161/4 = 2
✓ 1
A1 23 = 8
✓ 1
Part (b)
M1 write both sides as powers of 2: 23(x − 1) = 2−4
✓ 1
M1 3x − 3 = −4
✓ 1
A1 x = −1⁄3
✓ 1
Common error: Reading 16³/⁴ as 16 × 3 ÷ 4. The denominator is the root and the numerator is the power.
182IGMC3-1-08r11-09Indices, standard form and surdsPaper EMedium6 marks
No calculator
A rectangular rock platform has length \(\sqrt{18}\) m and width \(\sqrt{8}\) m.
Diagram not to scale
(a)
Write \(\sqrt{18}\) and \(\sqrt{8}\) in the form \(a\sqrt{2}\).
(2)
(b)
Find the perimeter of the platform in the form \(b\sqrt{2}\).
(2)
(c)
Find the exact area of the platform.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 \(\sqrt{18} = 3\sqrt{2}\)
✓ 1
B1 \(\sqrt{8} = 2\sqrt{2}\)
✓ 1
Part (b)
M1 \(2(3\sqrt{2} + 2\sqrt{2})\)
✓ 1
A1 \(10\sqrt{2}\) m
✓ 1
Part (c)
M1 \(3\sqrt{2} \times 2\sqrt{2}\)
✓ 1
A1 12 m2
✓ 1
Exam tip: Simplify a surd by writing the number under the root as a square number times another number: \(18 = 9 \times 2\).
183IGMC3-1-08r11-10Indices, standard form and surdsPaper EMedium5 marks
No calculator
Do not use decimals in this question.
(a)
Rationalise the denominator of \(\frac{10}{\sqrt{5}}\). Give your answer in the form \(a\sqrt{5}\).
(2)
(b)
Show that \(\frac{12}{4 - \sqrt{7}}\) can be written as \(\frac{16 + 4\sqrt{7}}{3}\).
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 multiplies numerator and denominator by \(\sqrt{5}\)
✓ 1
A1 \(2\sqrt{5}\)
✓ 1
Part (b)
M1 multiplies numerator and denominator by \(4 + \sqrt{7}\)
✓ 1
A1 \(\frac{48 + 12\sqrt{7}}{9}\)
✓ 1
A1 divides by 3 to reach \(\frac{16 + 4\sqrt{7}}{3}\)
✓ 1
Exam tip: To rationalise a denominator \(a - \sqrt{b}\), multiply top and bottom by \(a + \sqrt{b}\) so the denominator becomes \(a^{2} - b\).
184IGMC3-1-08r11-11Estimation, rounding, bounds, ratio, proportion and moneyPaper EMedium6 marks
Calculator
A mountain trail is 4.2 km long, correct to the nearest 0.1 km. A walker's average speed is 3.5 km/h, correct to the nearest 0.1 km/h.
(a)
Write down the upper bound of the length and the lower bound of the speed.
(2)
(b)
Calculate the upper bound of the time taken, in hours, correct to 3 significant figures.
(2)
(c)
The walker says that the trail takes 1.2 hours, correct to 2 significant figures. Show by calculation that this is justified.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 4.25 km
✓ 1
B1 3.45 km/h
✓ 1
Part (b)
M1 \(4.25 \div 3.45\)
✓ 1
A1 1.23 h
✓ 1
Part (c)
M1 lower bound of time \(4.15 \div 3.55 = 1.169\ldots\) (accept 1.17)
✓ 1
R1 both bounds, 1.17 and 1.23, round to 1.2 to 2 significant figures
✓ 1
Common error: For the greatest time use the greatest distance and the least speed; using both upper bounds gives the wrong bound.
185IGMC3-1-09r14-08Estimation, rounding, bounds, ratio, proportion and moneyPaper EMedium6 marks
Calculator
A bridge span is measured as 86.4 m, correct to the nearest 0.1 m. A walker takes 12.5 s, correct to the nearest 0.1 s, to cross a section of the bridge equal to this span at constant speed.
(a)
Write down the lower and upper bounds of the span length and of the time taken.
(2)
(b)
Calculate the lower bound for the speed, in m/s, correct to 3 significant figures.
(2)
(c)
Calculate the upper bound for the speed, in m/s, correct to 3 significant figures.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 86.35 ≤ length < 86.45
✓ 1
B1 12.45 ≤ time < 12.55
✓ 1
Part (b)
M1 lowest length ÷ greatest time = 86.35 ÷ 12.55
✓ 1
A1 6.88 m/s
✓ 1
Part (c)
M1 greatest length ÷ least time = 86.45 ÷ 12.45
✓ 1
A1 6.94 m/s
✓ 1
Common error: For a quotient, the lower bound uses the lower bound of the numerator and the upper bound of the denominator; mixing them gives a value that is not the true bound.
186IGMC3-1-09r14-09Indices, standard form and surdsPaper EMedium5 marks
No calculator
A rectangular solar panel on a space probe has area 13 m2 and length (4 + √3) m.
Diagram not to scale
(a)
Show that the width of the panel is (4 − √3) m.
(3)
(b)
Find the perimeter of the panel.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 width = 13 ÷ (4 + √3), then multiply top and bottom by (4 − √3)
✓ 1
M1 denominator (4 + √3)(4 − √3) = 16 − 3 = 13
✓ 1
A1 13(4 − √3) ÷ 13 = 4 − √3
✓ 1
Part (b)
M1 2 × [(4 + √3) + (4 − √3)]
✓ 1
A1 16 m
✓ 1
Exam tip: Multiplying (a + √b) by (a − √b) removes the surd because the product is a² − b.
187IGMC3-1-09r17-08Estimation, rounding, bounds, ratio, proportion and moneyPaper EMedium6 marks
Calculator
A rectangular solar panel on a space probe has length 2.45 m and width 1.80 m. Each measurement is correct to 3 significant figures.
Diagram not to scale
(a)
Write down the lower bound and the upper bound of the length.
(1)
(b)
Calculate the lower bound and the upper bound of the area of the panel.
(3)
(c)
Use your answers to give the area to the greatest accuracy that is justified. Give a reason.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 lower bound 2.445 m and upper bound 2.455 m
✓ 1
Part (b)
M1 uses a product of bounds, for example 2.455 × 1.805
✓ 1
A1 lower bound 4.388775 m2 (accept 4.39 or better)
✓ 1
A1 upper bound 4.431275 m2 (accept 4.43 or better)
✓ 1
Part (c)
B1 both bounds round to 4.4 to 2 significant figures
✓ 1
A1 area = 4.4 m2
✓ 1
Exam tip: For the largest product use both upper bounds, and for the smallest product use both lower bounds. Then see which rounded value both bounds share.
188IGMC3-1-09r17-09Indices, standard form and surdsPaper EMedium7 marks
No calculator
A bridge plate is a rectangle of length (3 + √5) m and width (3 − √5) m.
Diagram not to scale
(a)
Show that (3 + √5)2 = 14 + 6√5.
(2)
(b)
Find the area of the plate.
(2)
(c)
Find the length of the diagonal of the plate. Give your answer in the form a√b, where a and b are integers and b is as small as possible.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 expands (3 + √5)(3 + √5) with four terms
✓ 1
A1 9 + 3√5 + 3√5 + 5 = 14 + 6√5, shown
✓ 1
Part (b)
M1 (3 + √5)(3 − √5) = 9 − 5 (difference of two squares)
✓ 1
A1 4 m2
✓ 1
Part (c)
M1 diagonal2 = (3 + √5)2 + (3 − √5)2
✓ 1
A1 = 14 + 6√5 + 14 − 6√5 = 28
✓ 1
A1 √28 = 2√7 m (≈ 5.29 m)
✓ 1
Common error: Writing (3 + √5)² as 9 + 5, which leaves out the middle terms.
189IGMC3-1-09r17-10Indices, standard form and surdsPaper EMedium6 marks
No calculator
A probe computer uses numbers written as powers.
(a)
Evaluate 272/3.
(1)
(b)
Evaluate 16−3/4.
(2)
(c)
Solve 9x = 27x − 2.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 9
✓ 1
Part (b)
M1 161/4 = 2 and the negative index gives a reciprocal
✓ 1
A1 1/8
✓ 1
Part (c)
M1 writes both sides as powers of 3: 32x = 33(x − 2)
✓ 1
M1 2x = 3x − 6
✓ 1
A1 x = 6
✓ 1
Exam tip: To solve an equation with different bases, write every term as a power of the same prime number and then equate the indices.
190IGMC3-1-09r22-11Estimation, rounding, bounds, ratio, proportion and moneyPaper EMedium6 marks
Calculator
A designer handbag is sold at a discount of 15% and costs €127.50 after the discount. The boutique's annual sales are €240 000 this year and are expected to increase by 6% each year.
(a)
Calculate the original price of the handbag.
(2)
(b)
Calculate the boutique's sales after 3 years, correct to the nearest euro.
(2)
(c)
Find the total percentage increase in annual sales over the 3 years. Give your answer correct to 3 significant figures.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 \(127.50\div0.85\)
✓ 1
A1 €150
✓ 1
Part (b)
M1 \(240\,000\times1.06^3\)
✓ 1
A1 €285 844
✓ 1
Part (c)
M1 \((1.06^3-1)\times100\) or \(\frac{285\,844-240\,000}{240\,000}\times100\)
✓ 1
A1 19.1%
✓ 1
Common error: Three yearly increases of 6% do not give 18% overall; each increase applies to the new amount, so multiply by 1.06 three times.
191IGMC3-1-09r22-12Indices, standard form and surdsPaper EMedium7 marks
Exam tip: Take the root first and then the power for fractional indices; a negative index means reciprocal.
192IGMC3-1-09r22-14Types of number, factors, HCF and LCMPaper EMedium5 marks
No calculator
The time \(T\) hours needed to drain a fish pond is inversely proportional to the number \(n\) of identical pumps used. When 4 pumps are used, the pond takes 9 hours to drain.
(a)
Find an expression for \(T\) in terms of \(n\).
(2)
(b)
Find the time taken when 9 pumps are used.
(1)
(c)
The pond must be drained in 1.5 hours. Find the number of pumps needed.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 \(T=\frac{k}{n}\) or \(Tn\) constant
✓ 1
A1 \(T=\frac{36}{n}\)
✓ 1
Part (b)
B1 4 hours
✓ 1
Part (c)
M1 \(\frac{36}{n}=1.5\)
✓ 1
A1 24
✓ 1
Common error: Inverse proportion means more pumps give less time; the product \(Tn\) stays constant.
193IGMC3-1-09r24-12Indices, standard form and surdsPaper EMedium6 marks
No calculator
This question is about surds. All answers must be exact.
(a)
Write \(\sqrt{48}\) in the form \(a\sqrt{3}\), where \(a\) is an integer.
Rationalise the denominator of \(\dfrac{10}{3-\sqrt{5}}\). Give your answer in the form \(\dfrac{a+b\sqrt{5}}{c}\).
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 \(4\sqrt{3}\)
✓ 1
Part (b)
M1 \(\sqrt{12} = 2\sqrt{3}\), so numerator is \(6\sqrt{3}\) (ECF from (a))
✓ 1
A1 6
✓ 1
Part (c)
M1 multiply numerator and denominator by \(3+\sqrt{5}\)
✓ 1
A1 denominator \(9-5=4\)
✓ 1
A1 \(\dfrac{15+5\sqrt{5}}{2}\)
✓ 1
Exam tip: To rationalise a denominator of the form \(a-\sqrt{b}\), multiply top and bottom by \(a+\sqrt{b}\) to use the difference of two squares.
194IGMC3-1-09r26-08Indices, standard form and surdsPaper EMedium5 marks
No calculator
A rectangular archaeological trench has length (3 + √5) m and width (3 − √5) m.
Diagram not to scale
(a)
Show that the area of the trench is 4 m2.
(2)
(b)
Work out length ÷ width. Write your answer as a single fraction in the form (a + b√5)/c, where a, b and c are integers.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 (3 + √5)(3 − √5) = 9 − 3√5 + 3√5 − 5, or difference of two squares 9 − 5
✓ 1
A1 4 m2 shown
✓ 1
Part (b)
M1 multiply numerator and denominator by (3 + √5)
✓ 1
A1 numerator 14 + 6√5 and denominator 4
✓ 1
A1 (7 + 3√5)/2
✓ 1
Exam tip: To rationalise a denominator of the form a − √b, multiply top and bottom by a + √b.
195IGMC3-1-09r26-09Indices, standard form and surdsPaper EMedium6 marks
No calculator
Work out the following.
(a)
Evaluate 272/3.
(2)
(b)
Evaluate (1⁄4)−3/2.
(2)
(c)
Solve 23x − 1 = 32.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 271/3 = 3
✓ 1
A1 9
✓ 1
Part (b)
M1 43/2 or (√4)3
✓ 1
A1 8
✓ 1
Part (c)
M1 32 = 25 so 3x − 1 = 5
✓ 1
A1 x = 2
✓ 1
Exam tip: For a fractional index, take the root first, then the power. A negative index means reciprocal.
196IGMC3-1-09r26-13Fractions, decimals and percentagesPaper EMedium7 marks
No calculator
A laboratory report gives two ratios as recurring decimals.
(a)
The first ratio is 0.454545… (the digits 45 repeat forever). Show that it is equal to 5⁄11.
(3)
(b)
Which two of these fractions are terminating decimals? 7⁄20, 5⁄11, 3⁄8, 4⁄15
(2)
(c)
The second ratio is 0.272727… (the digits 27 repeat forever). Work out the sum of the two ratios as a single fraction in its simplest form.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 let x = 0.4545… so 100x = 45.4545…
✓ 1
M1 subtract: 99x = 45
✓ 1
A1 x = 45/99 = 5⁄11
✓ 1
Part (b)
B1 one correct choice and no more than two answers given
✓ 1
B1 7⁄20 and 3⁄8
✓ 1
Part (c)
M1 0.2727… = 27/99 = 3⁄11
✓ 1
A1 5⁄11 + 3⁄11 = 8⁄11
✓ 1
Exam tip: For a decimal with a 2-digit repeating block, multiply by 100 so the repeating parts line up and cancel on subtraction.
197IGMC3-1-10r26-09Indices, standard form and surdsPaper EMedium5 marks
No calculator
These questions use indices.
(a)
Simplify (9a4)1/2, where a ≥ 0.
(2)
(b)
Solve 4x = 8x − 1.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 3
✓ 1
B1 a2, giving 3a2
✓ 1
Part (b)
M1 writes both sides as powers of 2: 22x = 23(x − 1)
✓ 1
M1 2x = 3x − 3
✓ 1
A1 x = 3
✓ 1
Exam tip: To solve an index equation, rewrite both sides with the same base and then equate the powers.
198IGMC3-1-10r31-09Indices, standard form and surdsPaper EMedium6 marks
No calculator
A rectangular steel panel in a bridge has length \(\sqrt{48}\) m and width \(\sqrt{3}\) m.
Diagram not to scale
(a)
Show that \(\sqrt{48} = 4\sqrt{3}\).
(2)
(b)
Find the area of the panel as an integer.
(2)
(c)
Find the perimeter of the panel, giving your answer in the form \(a\sqrt{3}\).
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 \(\sqrt{48} = \sqrt{16 \times 3}\)
✓ 1
A1 \(\sqrt{16}\sqrt{3} = 4\sqrt{3}\)
✓ 1
Part (b)
M1 \(4\sqrt{3} \times \sqrt{3}\)
✓ 1
A1 12 m2
✓ 1
Part (c)
M1 \(2(4\sqrt{3} + \sqrt{3})\)
✓ 1
A1 \(10\sqrt{3}\) m
✓ 1
Common error: Write the larger square factor under the root first (16 rather than 4 × 12) so that only one simplification step is needed.
199IGMC3-1-10r31-10Estimation, rounding, bounds, ratio, proportion and moneyPaper EMedium8 marks
Calculator
The span of a bridge is 84 m, correct to the nearest metre. A cyclist crosses at a constant speed of 15 m/s, correct to 2 significant figures.
(a)
Write down the lower bound and upper bound of the span.
(2)
(b)
Calculate the upper bound for the time taken to cross the bridge. Give your answer correct to 3 significant figures.
(3)
(c)
Calculate the lower bound for the time taken, correct to 3 significant figures.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 83.5 m
✓ 1
B1 84.5 m
✓ 1
Part (b)
B1 lower bound of speed 14.5 m/s
✓ 1
M1 84.5 ÷ 14.5
✓ 1
A1 5.83 s
✓ 1
Part (c)
B1 upper bound of speed 15.5 m/s
✓ 1
M1 83.5 ÷ 15.5
✓ 1
A1 5.39 s
✓ 1
Exam tip: To get the greatest time, divide the greatest distance by the smallest speed.
200IGMC3-1-10r31-14Indices, standard form and surdsPaper EMedium7 marks
No calculator
A probe sends a repeating signal that a student writes as the recurring decimal 0.272727…, which is written \(0.\dot{2}\dot{7}\).
(a)
Show that \(0.\dot{2}\dot{7} = \frac{3}{11}\).
(3)
(b)
Write down the two irrational numbers in this list: \(\frac{3}{11}\), \(\sqrt{20}\), \(\frac{\pi}{2}\), 0.25.
(2)
(c)
Simplify \(\sqrt{20} + \sqrt{45}\), giving your answer in the form \(a\sqrt{5}\).
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 let \(x = 0.\dot{2}\dot{7}\) so \(100x = 27.\dot{2}\dot{7}\)
✓ 1
M1 subtract to get \(99x = 27\)
✓ 1
A1 \(x = \frac{27}{99} = \frac{3}{11}\)
✓ 1
Part (b)
B1 \(\sqrt{20}\)
✓ 1
B1 \(\frac{\pi}{2}\)
✓ 1
Part (c)
M1 \(2\sqrt{5} + 3\sqrt{5}\)
✓ 1
A1 \(5\sqrt{5}\)
✓ 1
Exam tip: To change a recurring decimal to a fraction, multiply by a power of 10 that matches the length of the repeating block.
201IGMC3-1-12r32-06Estimation, rounding, bounds, ratio, proportion and moneyPaper EMedium5 marks
Calculator
A music studio buys a mixing desk for £4200. Its value falls by 12% each year.
(a)
Calculate the value of the desk after 3 years. Give your answer to the nearest cent.
(3)
(b)
Work out the total fall in value over the 3 years as a percentage of the original value. Use the unrounded value from (a) and give your answer correct to 3 significant figures.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 multiplier 0.88
✓ 1
M1 4200 × 0.883
✓ 1
A1 £2862.18
✓ 1
Part (b)
M1 (4200 − 2862.1824) ÷ 4200 × 100 (or 1 − 0.883)
✓ 1
A1 31.9%
✓ 1
Common error: A fall of 12% a year for 3 years is not a 36% fall; the percentage is taken of a smaller value each year.
202IGMC3-1-12r32-07Estimation, rounding, bounds, ratio, proportion and moneyPaper EMedium6 marks
Calculator
An aircraft flies a distance of 540 km, correct to the nearest 10 km. The flight takes 1.5 hours, correct to 1 decimal place.
(a)
Write down the lower bound and the upper bound of the distance.
(2)
(b)
Calculate the upper bound of the average speed. Give your answer correct to 3 significant figures.
(2)
(c)
Calculate the lower bound of the average speed. Give your answer correct to 3 significant figures.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 535 km
✓ 1
B1 545 km
✓ 1
Part (b)
M1 545 ÷ 1.45
✓ 1
A1 376 km/h
✓ 1
Part (c)
M1 535 ÷ 1.55
✓ 1
A1 345 km/h
✓ 1
Exam tip: For a speed, the largest value uses the largest distance and the smallest time.
203IGMC3-1-12r32-10Estimation, rounding, bounds, ratio, proportion and moneyPaper EMedium6 marks
No calculator
A rectangular drone landing pad has length (2√5 + 3) metres and width (2√5 − 3) metres.
Diagram not to scale
(a)
Show that the area of the pad is 11 m2.
(2)
(b)
Find the perimeter of the pad. Give your answer in the form a√5.
(2)
(c)
Find the exact length of a diagonal of the pad.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 (2√5 + 3)(2√5 − 3) (difference of two squares or expands)
✓ 1
A1 20 − 9 = 11 (shown)
✓ 1
Part (b)
M1 2 × (sum of length and width)
✓ 1
A1 8√5 m
✓ 1
Part (c)
M1 (2√5 + 3)2 + (2√5 − 3)2 = 58
✓ 1
A1 √58 m
✓ 1
Exam tip: Two brackets that differ only in sign multiply to a difference of squares, so the surd terms cancel.
204IGMC3-1-11r36-03Fractions, decimals and percentagesPaper EMedium4 marks
Calculator
A logistics firm now pays €1.89 for each litre of diesel. This is after a price increase of 8%.
(a)
Calculate the price per litre before the increase.
(2)
(b)
The firm buys 2400 litres of diesel each week. Calculate how much more this costs each week at the new price than at the old price.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 1.89 ÷ 1.08
✓ 1
A1 €1.75
✓ 1
Part (b)
M1 2400 × (1.89 − 1.75)
✓ 1
A1 €336
✓ 1
Common error: Do not take 8% off €1.89. The new price is 108% of the old price, so divide by 1.08.
205IGMC3-1-11r36-07Indices, standard form and surdsPaper EMedium5 marks
No calculator
A rectangular glass panel in a museum roof has length (4 + √3) m and width (4 − √3) m.
Diagram not to scale
(a)
Show that the area of the panel is 13 m2.
(2)
(b)
Write (4 + √3)/(4 − √3) in the form (a + b√3)/13, where a and b are integers.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 (4 + √3)(4 − √3) expanded with all four terms
✓ 1
A1 16 − 3 = 13 with the √3 terms cancelling
✓ 1
Part (b)
M1 multiply numerator and denominator by (4 + √3)
✓ 1
M1 numerator (4 + √3)2 = 19 + 8√3
✓ 1
A1 (19 + 8√3)/13 (denominator 13)
✓ 1
Exam tip: To rationalise a denominator of the form a − √b, multiply top and bottom by a + √b so the denominator becomes a whole number.
206IGMC3-1-11r36-11Estimation, rounding, bounds, ratio, proportion and moneyPaper EMedium5 marks
Calculator
A port authority buys a crane for £480 000. The value of the crane decreases by 12% each year.
(a)
Calculate the value of the crane after 3 years. Give your answer to the nearest pound.
(2)
(b)
After how many complete years is the value of the crane first less than £250 000? Show your working.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 480 000 × 0.883
✓ 1
A1 £327 107
✓ 1
Part (b)
M1 evaluating 480 000 × 0.88n for at least two values of n
✓ 1
A1 after 5 years £253 311 (greater than £250 000) and after 6 years £222 914 (less than £250 000)
✓ 1
A1 6 years
✓ 1
Common error: A decrease of 12% each year means multiplying by 0.88 repeatedly, not subtracting 12% of the original amount each time.
207IGMC3-1-10r42-09Indices, standard form and surdsPaper EMedium5 marks
No calculator
A square display panel on a telescope has an area of 48 cm2.
(a)
Show that the side length of the panel is 4\(\sqrt{3}\) cm.
(2)
(b)
Find the perimeter of the panel in the form a\(\sqrt{3}\) cm.
(1)
(c)
Rationalise the denominator of \(\frac{24}{4\sqrt{3}}\) and give your answer in the form b\(\sqrt{3}\).
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 side = \(\sqrt{48}\)
✓ 1
A1 \(\sqrt{16}\) × \(\sqrt{3}\) = 4\(\sqrt{3}\)
✓ 1
Part (b)
B1 16\(\sqrt{3}\)
✓ 1
Part (c)
M1 multiply numerator and denominator by \(\sqrt{3}\)
✓ 1
A1 2\(\sqrt{3}\)
✓ 1
Common error: Look for the largest square factor when simplifying a surd, such as 16 in 48.
208IGMC3-1-10r42-10Estimation, rounding, bounds, ratio, proportion and moneyPaper EMedium7 marks
Calculator
A sports club invests €8000 at 3.5% per year compound interest. The club also owns a railway locomotive, which is part of a heritage line, valued at €2 400 000. The locomotive loses 7% of its value each year.
(a)
Calculate the value of the investment after 4 years. Give your answer correct to the nearest cent.
(3)
(b)
Calculate the interest earned in 4 years. Use the answer to (a) to the nearest cent.
(1)
(c)
Calculate the value of the locomotive after 6 years. Give your answer in standard form, correct to 3 significant figures.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 8000 × 1.0354
✓ 1
M1 evaluates 1.0354 = 1.1475… or equivalent
✓ 1
A1 €9180.18
✓ 1
Part (b)
B1 9180.18 − 8000 = €1180.18
✓ 1
Part (c)
M1 2 400 000 × 0.936
✓ 1
A1 1 552 776 or equivalent unrounded value
✓ 1
A1 1.55 × 106 €
✓ 1
Common error: A 7% yearly loss uses the multiplier 0.93, not 0.07, and the power is the number of years.
209IGMC-041-01-10Fractions, decimals and percentagesPaper EHard5 marks
No calculator
A shop increases the price of an item by a percentage and later decreases the new price by the same percentage.
(a)
The price is increased by 20% and then decreased by 20%. Show that the overall effect is a decrease of 4%.
(2)
(b)
A different price is increased by \(x\)% and then decreased by \(x\)%. The overall effect is a decrease of 9%. Find the value of \(x\).
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 for 1.2 × 0.8
✓ 1
A1 = 0.96, so a 4% decrease, shown
✓ 1
Part (b)
M1 for \(\left(1 + \frac{x}{100}\right)\left(1 - \frac{x}{100}\right) = 0.91\)
✓ 1
M1 for \(1 - \frac{x^2}{10000} = 0.91\) or \(x^2 = 900\)
✓ 1
A1 \(x = 30\)
✓ 1
Exam tip: Write each percentage change as a multiplier and multiply the multipliers together. The product is the overall multiplier.
210IGMC-041-03-12Estimation, rounding, bounds, ratio, proportion and moneyPaper EHard7 marks
Calculator
The area of a rectangular garden bed is 54 m2, correct to the nearest square metre. The length of the bed is 9.0 m, correct to the nearest 0.1 m.
Diagram not to scale
(a)
Calculate the lower bound of the width of the bed.
(3)
(b)
Calculate the upper bound of the width of the bed.
(2)
(c)
Explain whether the width can be stated correctly to 2 significant figures.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1: 53.5 and 9.05 identified as the bounds to use
✓ 1
M1: 53.5 ÷ 9.05
✓ 1
A1: 5.91 m
✓ 1
Part (b)
M1: 54.5 ÷ 8.95
✓ 1
A1: 6.09 m
✓ 1
Part (c)
M1: lower bound rounds to 5.9 and upper bound rounds to 6.1 (to 2 s.f.)
✓ 1
A1: No, because the two bounds do not round to the same value
✓ 1
Exam tip: For a lower bound of a quotient, use the smallest numerator and the largest denominator. Swapping them gives the upper bound.
211IGMC-041-03-13Estimation, rounding, bounds, ratio, proportion and moneyPaper EHard6 marks
Calculator
A new car loses 15% of its value in the first year. In each year after the first, it loses 9% of its value at the start of that year.
(a)
Find the number of complete years after which the value of the car first falls below 40% of its value when new. Show clear working.
(3)
(b)
After 4 years, the car is worth $11 230. Calculate the value of the car when it was new. Give your answer correct to the nearest dollar.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1: value after n years = 0.85 × 0.91n−1 × original, or repeated multiplication
✓ 1
M1: after 8 years 0.85 × 0.917 = 0.439… (above 0.4)
✓ 1
A1: 9 years, with 0.85 × 0.918 = 0.3997…
✓ 1
Part (b)
M1: multiplier 0.85 × 0.913 (= 0.6405…)
✓ 1
M1: 11 230 ÷ (0.85 × 0.913)
✓ 1
A1: $17 532
✓ 1
Common error: A 15% loss followed by three 9% losses is not a 42% loss. Multiply the decimal multipliers together, then divide to undo them.
212IGMC-041-00-12Types of number, factors, HCF and LCMPaper EHard5 marks
No calculator
N = 23 × 32 × 5k, where k is a positive integer. The highest common factor of N and 600 is 120.
(a)
Write 600 as a product of its prime factors.
(2)
(b)
Find the value of k.
(2)
(c)
Find the lowest common multiple of N and 600.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 for a correct method reaching 2, 2, 2, 3, 5, 5
✓ 1
A1 for 23 × 3 × 52
✓ 1
Part (b)
M1 for 120 = 23 × 3 × 5, so the lower power of 5 is 51
✓ 1
A1 for k = 1
✓ 1
Part (c)
B1 for 1800
✓ 1
Exam tip: The HCF uses the smaller power of 5 from the two numbers. Since 600 contains 5² but the HCF contains only 5¹, N must contain 5¹.
213IGMC-041-00-13Types of number, factors, HCF and LCMPaper EHard5 marks
No calculator
a and b are positive integers with a < b. The highest common factor of a and b is 6, and a + b = 60.
(a)
Find all the possible pairs of values of a and b.
(4)
(b)
Find the larger of the two possible values of the lowest common multiple of a and b.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 for writing a = 6p and b = 6q
✓ 1
M1 for p + q = 10
✓ 1
M1 for recognising that p and q must have no common factor other than 1, rejecting (2, 8) and (4, 6)
✓ 1
A1 for a = 6, b = 54 and a = 18, b = 42 only
✓ 1
Part (b)
B1 for 126
✓ 1
Common error: The pair 12 and 48 adds to 60 and both are multiples of 6, but their HCF is 12, not 6. Always check the HCF of each pair you find.
214IGMC-041-00-14Types of number, factors, HCF and LCMPaper EHard6 marks
No calculator
Two runners, Priya and Tomas, run laps of a track at constant speeds. Priya takes 72 seconds per lap and Tomas takes 84 seconds per lap. They start together from the start line.
(a)
Find how long it is until they are next together at the start line. Give your answer in minutes and seconds.
(2)
(b)
Find how many laps Priya has completed at this time.
(1)
(c)
A third runner, Kofi, joins them at the start. His lap time is t seconds, where t is an integer between 62 and 75. All three runners are next together at the start line after exactly 2520 seconds. Find the value of t.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 for LCM of 72 and 84, e.g. 23 × 32 × 7 = 504
✓ 1
A1 for 8 minutes 24 seconds
✓ 1
Part (b)
B1 for 7
✓ 1
Part (c)
M1 for 2520 = 23 × 32 × 5 × 7
✓ 1
M1 for recognising that t must be a factor of 2520 containing the factor 5 (since 504 does not)
✓ 1
A1 for t = 70
✓ 1
Exam tip: Compare the new LCM with the old one: 2520 ÷ 504 = 5, so Kofi's lap time must supply the missing factor 5 and also divide 2520. Test 65, 70 and 75 against both conditions.
215IGMC-041-02-12Indices, standard form and surdsPaper EHard7 marks
No calculator
Answer each part. Do not use a calculator, and show all your working.
(a)
Expand and simplify \((2+\sqrt{3})^2\).
(2)
(b)
Write \(\frac{5+\sqrt{3}}{2-\sqrt{3}}\) in the form \(a + b\sqrt{3}\), where \(a\) and \(b\) are integers.
(3)
(c)
Given that \(x = 2+\sqrt{3}\) and \(\frac{1}{x} = 2-\sqrt{3}\), find the value of \(x^2 + \frac{1}{x^2}\). You may use your answer to part (a).
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1: \(4 + 2\sqrt{3} + 2\sqrt{3} + 3\)
✓ 1
A1: \(7 + 4\sqrt{3}\)
✓ 1
Part (b)
M1: multiplying numerator and denominator by \(2+\sqrt{3}\)
M1: \(\frac{1}{x^2} = (2-\sqrt{3})^2 = 7 - 4\sqrt{3}\) and adding: \((7+4\sqrt{3}) + (7-4\sqrt{3})\); OR \(x + \frac{1}{x} = 4\) and using \(x^2+\frac{1}{x^2} = (x+\frac{1}{x})^2 - 2 = 16 - 2\)
✓ 1
A1: 14
✓ 1
Exam tip: In (c), squaring \(2 - \sqrt{3}\) gives the same terms as part (a) with the sign of the surd changed, so the surds cancel when you add. Spotting this saves working.
216IGMC-041-02-14Indices, standard form and surdsPaper EHard7 marks
No calculator
Answer each part. Show all your working.
(a)
Show that \(4^x \times 8^{x-1}\) can be written as \(2^{5x-3}\).
Show that \(\frac{2^{n+3} - 2^{n+1}}{2^n}\) has the same value for every value of \(n\), and find this value.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1: \(4^x = 2^{2x}\) and \(8^{x-1} = 2^{3x-3}\)
✓ 1
A1: \(2^{2x + 3x - 3} = 2^{5x-3}\) with no errors seen
✓ 1
Part (b)
B1: \(\frac{1}{4\sqrt{2}} = 2^{-\frac{5}{2}}\)
✓ 1
M1: \(5x - 3 = -\frac{5}{2}\)
✓ 1
A1: \(x = \frac{1}{10}\)
✓ 1
Part (c)
M1: \(\frac{2^n(2^3 - 2^1)}{2^n}\) or \(2^3 - 2^1\)
✓ 1
A1: 6
✓ 1
Common error: \(2^{n+3} - 2^{n+1}\) is not \(2^2\). Subtracting powers of the same base does not subtract the indices. Take out the common factor \(2^n\) first.
217IGMC3-1-07c-13Indices, standard form and surdsPaper EHard7 marks
M1 \(\left(\frac{8}{27}\right)^{\frac{2}{3}}\) or \(\left(\frac{2}{3}\right)^{2}\)
✓ 1
A1 \(\frac{4}{9}\)
✓ 1
Part (b)
B1 8
✓ 1
B1 x6y−3
✓ 1
Part (c)
M1 32(x−1) = 33(x+2)
✓ 1
M1 2x − 2 = 3x + 6
✓ 1
A1 x = -8
✓ 1
Common error: Write both sides with the same base first; multiplying the bases (for example 9 × 27) is not allowed.
218IGMC3-1-07c-14Estimation, rounding, bounds, ratio, proportion and moneyPaper EHard10 marks
Calculator
A cyclist rides a route of 25.0 km, measured to the nearest 0.1 km, in 90 minutes, measured to the nearest minute.
(a)
Write down the lower and upper bounds of (i) the distance and (ii) the time.
(2)
(b)
Calculate the lower bound of the average speed in km/h.
(2)
(c)
Calculate the upper bound of the average speed in km/h.
(2)
(d)
Use your answers to (b) and (c) to give the average speed to a suitable degree of accuracy. Justify your answer.
(2)
(e)
The cyclist rides 40 km at the lower bound speed from (b). Calculate the time taken in hours.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 24.95 km and 25.05 km
✓ 1
B1 89.5 minutes and 90.5 minutes
✓ 1
Part (b)
M1 24.95 ÷ (90.5 ÷ 60)
✓ 1
A1 16.54 km/h
✓ 1
Part (c)
M1 25.05 ÷ (89.5 ÷ 60)
✓ 1
A1 16.79 km/h
✓ 1
Part (d)
B1 both bounds round to 17 km/h to 2 significant figures
✓ 1
B1 so the speed is 17 km/h (2 s.f.)
✓ 1
Part (e)
M1 40 ÷ 16.54 (ECF from (b))
✓ 1
A1 2.418 hours
✓ 1
Exam tip: For a lower bound of a speed, use the lower bound of distance and the upper bound of time.
219IGMC3-1-08r6-10Estimation, rounding, bounds, ratio, proportion and moneyPaper EHard7 marks
Calculator
A clinic receives a vial containing 8.4 mL of vaccine, measured to the nearest 0.1 mL. Each dose is 0.35 mL, measured to the nearest 0.01 mL.
(a)
Write down the lower bound of the volume in the vial and the upper bound of the volume of a dose.
(2)
(b)
Calculate the lower bound for the number of doses that the vial can supply, treating the number of doses as a decimal. Give your answer to 3 significant figures.
(3)
(c)
The clinic claims that every such vial can supply 24 full doses. Decide whether the claim is justified and give a reason.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 8.35 mL
✓ 1
B1 0.355 mL
✓ 1
Part (b)
M1 lower bound of volume ÷ upper bound of dose
✓ 1
M1 8.35 ÷ 0.355
✓ 1
A1 23.5
✓ 1
Part (c)
B1 not justified
✓ 1
R1 the lower bound 23.5 is less than 24, so in the worst case fewer than 24 full doses are available
✓ 1
Common error: For a quotient, the smallest result uses the lower bound on top and the upper bound underneath.
220IGMC3-1-08r6-13Indices, standard form and surdsPaper EHard7 marks
Calculator
The power output P megawatts (MW) of a wind turbine is directly proportional to the cube of the wind speed v metres per second (m/s). When v = 6, P = 0.54.
(a)
Find the constant of proportionality k in \(P=kv^3\).
(2)
(b)
Calculate the power output when the wind speed is 9 m/s. Give your answer to 3 significant figures.
(2)
(c)
Calculate the wind speed needed for an output of 2.5 MW.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 \(0.54=k\times6^3\)
✓ 1
A1 \(k=0.0025\)
✓ 1
Part (b)
M1 \(0.0025\times9^3\)
✓ 1
A1 1.82 MW
✓ 1
Part (c)
M1 \(2.5=0.0025v^3\)
✓ 1
M1 \(v^3=1000\)
✓ 1
A1 10 m/s
✓ 1
Common error: Direct proportion to the cube means tripling the speed multiplies the power by 27, not by 3.
221IGMC3-1-10r9-12Estimation, rounding, bounds, ratio, proportion and moneyPaper EHard8 marks
Calculator
A cyclist rides a distance of 61.2 km, correct to the nearest 0.1 km, in a time of 2.45 hours, correct to the nearest 0.01 hour.
(a)
Calculate the upper bound of the average speed. Give your answer correct to 4 significant figures.
(3)
(b)
Calculate the lower bound of the average speed. Give your answer correct to 4 significant figures.
(3)
(c)
Explain whether the average speed can be stated as 25 km/h correct to 2 significant figures.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 upper bound of distance = 61.25 km and lower bound of time = 2.445 h
✓ 1
M1 61.25 ÷ 2.445
✓ 1
A1 25.05 km/h
✓ 1
Part (b)
M1 lower bound of distance = 61.15 km and upper bound of time = 2.455 h
✓ 1
M1 61.15 ÷ 2.455
✓ 1
A1 24.91 km/h
✓ 1
Part (c)
M1 both bounds, 25.05 and 24.91, round to 25 to 2 significant figures
✓ 1
A1 so yes, 25 km/h is justified
✓ 1
Common error: Using the upper bound of both quantities. The largest speed needs the largest distance and the smallest time.
222IGMC3-1-10r9-13Indices, standard form and surdsPaper EHard7 marks
Calculator
The power P kW used by a data-centre cooling fan is directly proportional to the cube of its speed s rpm. When s = 300, P = 2.7.
(a)
Find the constant of proportionality k in P = ks3. Give your answer in standard form.
(2)
(b)
Calculate the power used when the speed is 450 rpm. Give your answer correct to 3 significant figures.
(2)
(c)
The speed is increased by 20%. Calculate the percentage increase in the power used.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 2.7 = k × 3003
✓ 1
A1 k = 1 × 10−7
✓ 1
Part (b)
M1 1 × 10−7 × 4503 (ECF from (a))
✓ 1
A1 9.11 kW
✓ 1
Part (c)
M1 new speed = 1.2s
✓ 1
M1 power multiplied by 1.23 = 1.728
✓ 1
A1 72.8%
✓ 1
Common error: Increasing the power by 20% as well. Because of the cube, a 20% speed rise changes the power by a different percentage.
223IGMC3-1-08r11-12Fractions, decimals and percentagesPaper EHard7 marks
Calculator
The number of subscribers to a telecoms company is 250 000. It is predicted to fall by 6% each year.
(a)
Calculate the predicted number of subscribers after 3 years.
(2)
(b)
Find the least whole number of years after which the predicted number of subscribers is below 150 000.
(3)
(c)
Find the overall percentage decrease in the number of subscribers over the first 3 years. Give your answer correct to 3 significant figures.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 \(250000 \times 0.94^{3}\)
✓ 1
A1 207 646 (accept 207 600 or 208 000)
✓ 1
Part (b)
M1 attempt to find \(250000 \times 0.94^{n}\) for different values of \(n\)
✓ 1
A1 152 392 after 8 years (accept 152 000) or 143 249 after 9 years (accept 143 000)
Common error: A fall of 6% a year for 3 years is not an 18% fall; each year's fall is taken from a smaller number.
224IGMC3-1-08r11-13Indices, standard form and surdsPaper EHard7 marks
No calculator
(a)
Find the exact value of \(27^{\frac{2}{3}}\).
(2)
(b)
Find the exact value of \(16^{-\frac{3}{4}}\).
(2)
(c)
Solve \(4^{x+1} = 8^{x-2}\).
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 \(27^{\frac{1}{3}} = 3\)
✓ 1
A1 9
✓ 1
Part (b)
M1 \(16^{\frac{1}{4}} = 2\)
✓ 1
A1 \(\frac{1}{8}\)
✓ 1
Part (c)
M1 writes both sides as powers of 2: \(2^{2(x+1)} = 2^{3(x-2)}\)
✓ 1
M1 equates indices: \(2x + 2 = 3x - 6\)
✓ 1
A1 \(x = 8\)
✓ 1
Exam tip: For fractional powers, take the root first and then the power: \(a^{\frac{m}{n}} = (\sqrt[n]{a})^{m}\).
225IGMC3-1-09r14-12Fractions, decimals and percentagesPaper EHard5 marks
No calculator
A receiver on a space probe reports that the fraction of corrupted data packets is 0.3181818…, where the digits 1 and 8 repeat for ever.
(a)
Show that 0.3181818… = 7/22.
(3)
(b)
The probe sends 1540 packets. Work out how many are corrupted.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 let x = 0.3181818…, then 1000x = 318.1818… and 10x = 3.1818…
✓ 1
M1 subtract: 990x = 315
✓ 1
A1 x = 315/990 = 7/22
✓ 1
Part (b)
M1 1540 × 7/22 (or 1540 ÷ 22 = 70)
✓ 1
A1 490
✓ 1
Exam tip: Multiply by a power of 10 that lines up the repeating digits so that subtraction removes them.
226IGMC3-1-09r14-13Indices, standard form and surdsPaper EHard7 marks
Calculator
This question is about indices and signal strength on a space probe.
(a)
Work out the value of 27−2/3 as a fraction.
(2)
(b)
Solve 4x−1 = 8x ÷ 16.
(3)
(c)
The strength S of the signal, in microwatts, t hours after transmission is S = 80 × 2−t/4. Calculate S when t = 10. Give your answer correct to 3 significant figures.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 cube root of 27 = 3, or reciprocal
✓ 1
A1 1/9
✓ 1
Part (b)
M1 write each term as a power of 2: 22x−2 = 23x−4
✓ 1
M1 equate indices 2x − 2 = 3x − 4
✓ 1
A1 x = 2
✓ 1
Part (c)
M1 80 × 2−2.5
✓ 1
A1 14.1 microwatts
✓ 1
Common error: A negative index means reciprocal, not a negative number; a fractional index means a root, with the denominator giving the root.
227IGMC3-1-09r14-14Estimation, rounding, bounds, ratio, proportion and moneyPaper EHard7 marks
Calculator
The load L kN that a bridge beam can carry is inversely proportional to the square of its length s metres. A beam of length 5 m can carry 480 kN.
(a)
Find a formula for L in terms of s.
(2)
(b)
Calculate the load that a beam of length 8 m can carry.
(2)
(c)
A beam is designed to carry 300 kN. Calculate its length, correct to 3 significant figures.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 L = k ÷ s2 with 480 = k ÷ 25
✓ 1
A1 L = 12000 ÷ s2
✓ 1
Part (b)
M1 12000 ÷ 64
✓ 1
A1 187.5 kN
✓ 1
Part (c)
M1 300 = 12000 ÷ s2 so s2 = 40
✓ 1
M1 s = √40
✓ 1
A1 6.32 m
✓ 1
Common error: In inverse square proportion, doubling the length divides the load by 4, not by 2.
228IGMC3-1-09r17-12Indices, standard form and surdsPaper EHard6 marks
Calculator
The intensity I of a probe's radio signal is inversely proportional to the square of the distance d from the probe. At a distance of 4 × 106 km the intensity is 0.90 units.
(a)
Find the intensity at a distance of 6 × 106 km.
(3)
(b)
At what distance is the intensity 0.025 units? Give your answer in kilometres, in standard form.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 I = k/d2 with d in millions of km
✓ 1
M1 k = 0.90 × 16 = 14.4
✓ 1
A1 I = 14.4 ÷ 36 = 0.40 units
✓ 1
Part (b)
M1 d2 = 14.4 ÷ 0.025 = 576
✓ 1
M1 square root, d = 24 million km
✓ 1
A1 24 000 000 km = 2.4 × 107 km
✓ 1
Exam tip: Find the constant of proportionality first. Using millions of km as your unit keeps the numbers small, but convert back at the end.
229IGMC3-1-09r22-07Indices, standard form and surdsPaper EHard8 marks
No calculator
A fishing net is a rectangle with length \((5+\sqrt{3})\) m and width \((5-\sqrt{3})\) m.
Diagram not to scale
(a)
Show that the area of the net is a whole number of square metres and state its value.
(2)
(b)
Find the length of the diagonal of the net. Give your answer in the form \(a\sqrt{b}\), where \(b\) is as small as possible.
(3)
(c)
Write \(\frac{5+\sqrt{3}}{5-\sqrt{3}}\) in the form \(\frac{p+q\sqrt{3}}{r}\), where \(p\), \(q\) and \(r\) are integers with no common factor.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 \((5+\sqrt{3})(5-\sqrt{3})=25-3\)
✓ 1
A1 22 m²
✓ 1
Part (b)
M1 diagonal\(^2=(5+\sqrt{3})^2+(5-\sqrt{3})^2\)
✓ 1
A1 \((28+10\sqrt{3})+(28-10\sqrt{3})=56\)
✓ 1
A1 \(2\sqrt{14}\) m
✓ 1
Part (c)
M1 multiply numerator and denominator by \(5+\sqrt{3}\)
✓ 1
A1 numerator \(28+10\sqrt{3}\) and denominator 22
✓ 1
A1 \(\frac{14+5\sqrt{3}}{11}\)
✓ 1
Common error: When squaring \((5+\sqrt{3})\) do not forget the middle term: \((5+\sqrt{3})^2=25+10\sqrt{3}+3\).
230IGMC3-1-09r22-09Estimation, rounding, bounds, ratio, proportion and moneyPaper EHard7 marks
Calculator
A rectangular fish tank has a base of length 3.6 m and width 2.5 m, both measured to the nearest 0.1 m. The depth of water in the tank is 0.80 m, measured to the nearest 0.01 m.
(a)
Write down the lower bound and the upper bound of the length of the tank.
(2)
(b)
Calculate the upper bound of the area of the base of the tank.
(2)
(c)
Calculate the lower bound of the volume of water in the tank. Give your answer correct to 3 significant figures.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 lower bound 3.55 m
✓ 1
B1 upper bound 3.65 m
✓ 1
Part (b)
M1 \(3.65\times2.55\)
✓ 1
A1 9.3075 m²
✓ 1
Part (c)
B1 lower bound of depth 0.795 m
✓ 1
M1 \(3.55\times2.45\times0.795\) (= 6.9145...)
✓ 1
A1 6.91 m³
✓ 1
Exam tip: For a product, the lower bound uses the lower bound of every quantity; round only at the final step.
231IGMC3-1-09r24-11Estimation, rounding, bounds, ratio, proportion and moneyPaper EHard7 marks
Calculator
A swimmer swims 400 m, measured to the nearest 10 m, in a time of 320 seconds, measured to the nearest 10 seconds. The swimmer's average speed is distance ÷ time. Give each answer to 3 significant figures where needed.
(a)
Write down the lower bound of the time.
(1)
(b)
Calculate the upper bound of the average speed.
(2)
(c)
Calculate the lower bound of the average speed.
(2)
(d)
Hence decide whether the average speed can be stated correctly to 2 significant figures. Give a reason using your answers to (b) and (c).
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 315 s
✓ 1
Part (b)
M1 405 ÷ 315
✓ 1
A1 1.29 m/s
✓ 1
Part (c)
M1 395 ÷ 325
✓ 1
A1 1.22 m/s
✓ 1
Part (d)
M1 upper bound 1.2857… rounds to 1.3 and lower bound 1.2154… rounds to 1.2
✓ 1
A1 these differ, so the speed cannot be stated to 2 significant figures
✓ 1
Common error: For a quotient, the upper bound uses the upper bound of the numerator and the lower bound of the denominator.
232IGMC3-1-09r24-13Indices, standard form and surdsPaper EHard9 marks
No calculator
This question is about indices and exponential equations.
(a)
Work out \(27^{\frac{2}{3}}\).
(2)
(b)
Work out \(16^{-\frac{3}{4}}\).
(2)
(c)
Solve \(4^{x} = 8^{x-2}\).
(3)
(d)
Solve \(3^{2x-1} = \dfrac{1}{\sqrt{3}}\).
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 cube root of 27 is 3
✓ 1
A1 9
✓ 1
Part (b)
M1 fourth root of 16 is 2, so \(2^{-3}\)
✓ 1
A1 \(\frac{1}{8}\)
✓ 1
Part (c)
M1 write both sides as powers of 2: \(2^{2x} = 2^{3(x-2)}\)
✓ 1
M1 \(2x = 3x - 6\)
✓ 1
A1 \(x = 6\)
✓ 1
Part (d)
M1 \(\frac{1}{\sqrt{3}} = 3^{-\frac{1}{2}}\), so \(2x - 1 = -\frac{1}{2}\)
✓ 1
A1 \(x = \frac{1}{4}\)
✓ 1
Common error: Powers of different bases can only be equated once both sides are written with the same base.
233IGMC3-1-09r26-10Estimation, rounding, bounds, ratio, proportion and moneyPaper EHard10 marks
Calculator
A velodrome lap is 250 m long, measured correct to the nearest metre. A cyclist takes 18.2 s for one lap, measured correct to the nearest 0.1 s. Her average speed is lap length ÷ lap time.
(a)
Write down the lower bound and the upper bound of the lap time.
(2)
(b)
Calculate the upper bound of her average speed. Give your answer correct to 4 significant figures.
(3)
(c)
Calculate the lower bound of her average speed. Give your answer correct to 4 significant figures.
(3)
(d)
Ben says her speed is 14 m/s correct to 2 significant figures. Is he correct? Give a reason.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 18.15 s
✓ 1
B1 18.25 s
✓ 1
Part (b)
B1 uses upper bound of length 250.5 m
✓ 1
M1 250.5 ÷ 18.15 (lower bound of time)
✓ 1
A1 13.80 m/s
✓ 1
Part (c)
B1 uses lower bound of length 249.5 m and upper bound of time 18.25 s
✓ 1
M1 249.5 ÷ 18.25
✓ 1
A1 13.67 m/s
✓ 1
Part (d)
B1 Yes
✓ 1
B1 both bounds, 13.80 and 13.67, round to 14 to 2 significant figures
✓ 1
Exam tip: To find the largest quotient use the largest numerator and the smallest denominator; for the smallest quotient do the opposite.
234IGMC3-1-09r26-12Fractions, decimals and percentagesPaper EHard7 marks
Calculator
The volume of data in a data centre grows at a constant percentage rate each year.
(a)
The volume is 250 petabytes (PB) at the start. The growth rate is 18% per year. Calculate the volume after 3 years. Give your answer correct to 3 significant figures.
(2)
(b)
In another year, the volume of data in a second data centre increased by 18% to 590 PB. Work out the volume before the increase.
(2)
(c)
A third data centre grows from 250 PB to 400 PB in 3 years at a constant annual percentage growth rate. Calculate this annual percentage growth rate. Give your answer correct to 3 significant figures.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 250 × 1.183
✓ 1
A1 411 PB
✓ 1
Part (b)
M1 590 ÷ 1.18
✓ 1
A1 500 PB
✓ 1
Part (c)
M1 250 × (1 + r/100)3 = 400 or multiplier3 = 1.6
✓ 1
M1 cube root of 1.6 = 1.1696
✓ 1
A1 17.0%
✓ 1
Exam tip: For compound change over n years use original × multiplierⁿ; undo it with a root, not a division.
235IGMC3-1-10r26-10Indices, standard form and surdsPaper EHard9 marks
Calculator
A rectangular fashion banner has area (3 + √3) m2 and width (3 − √3) m.
Diagram not to scale
(a)
Show that the length of the banner is (2 + √3) m.
(3)
(b)
Work out the perimeter of the banner.
(2)
(c)
Calculate the length of a diagonal of the banner. Give your answer correct to 3 significant figures.
(4)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 length = (3 + √3)/(3 − √3), multiplies top and bottom by (3 + √3)
✓ 1
A1 numerator 12 + 6√3 and denominator 6
✓ 1
A1 2 + √3
✓ 1
Part (b)
M1 2[(2 + √3) + (3 − √3)]
✓ 1
A1 10 m
✓ 1
Part (c)
M1 Pythagoras: (2 + √3)2 + (3 − √3)2
✓ 1
M1 expands: 7 + 4√3 and 12 − 6√3
✓ 1
A1 19 − 2√3
✓ 1
A1 3.94 m
✓ 1
Exam tip: In a surd calculation, keep exact values until the final step and convert to a decimal only at the end.
236IGMC3-1-10r26-12Fractions, decimals and percentagesPaper EHard7 marks
Calculator
A fish stock is 12 500 tonnes. It decreases by 8% each year.
(a)
Calculate the stock after 4 years. Give your answer to the nearest tonne.
(2)
(b)
Work out the overall percentage decrease over the 4 years. Give your answer correct to 3 significant figures.
(2)
(c)
In another sea, a stock of 12 500 tonnes falls to 9000 tonnes in 3 years with the same percentage decrease each year. Calculate this annual percentage decrease. Give your answer correct to 3 significant figures.
Common error: Common error: multiplying 8% by 4 to get 32%. Each year's decrease is of a smaller amount.
237IGMC3-1-10r26-13Types of number, factors, HCF and LCMPaper EHard5 marks
No calculator
This question is about types of number and recurring decimals.
(a)
Here are five numbers: √16, √18, 0.35, π2, 2⁄3. Write down the two irrational numbers.
(2)
(b)
The number x = 0.136363… has the digits 36 repeating forever after the first digit 1. Show that x = 3⁄22.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 √18
✓ 1
B1 π2
✓ 1
Part (b)
M1 10x = 1.3636… and 1000x = 136.3636…
✓ 1
M1 subtract: 990x = 135
✓ 1
A1 x = 135/990 = 3⁄22
✓ 1
Exam tip: For a decimal that repeats after a non-repeating digit, choose two multiples of 10 so the repeating tails are identical before subtracting.
238IGMC3-1-10r31-11Estimation, rounding, bounds, ratio, proportion and moneyPaper EHard8 marks
Calculator
A bridge-maintenance fund of €200 000 is invested at 3.5% compound interest per year.
(a)
Calculate the value of the fund after 4 years, correct to the nearest cent.
(2)
(b)
Find the smallest whole number of years after which the fund first exceeds €250 000. Show your working.
(3)
(c)
A second fund of €200 000 grows at a fixed annual compound rate to €224 972.80 after 3 years. Find the annual percentage rate.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 200000 × 1.0354
✓ 1
A1 €229 504.60
✓ 1
Part (b)
M1 value after 6 years = €245 851.07 or similar
✓ 1
M1 value after 7 years = €254 455.85 or similar
✓ 1
A1 7 years
✓ 1
Part (c)
M1 224972.8 ÷ 200000 = 1.124864
✓ 1
M1 cube root of 1.124864 = 1.04
✓ 1
A1 4%
✓ 1
Exam tip: When asked for a whole number of years, test consecutive values and state which one first passes the target.
239IGMC3-1-10r31-12Fractions, decimals and percentagesPaper EHard7 marks
Calculator
The time T minutes to roast a batch of coffee is inversely proportional to the square root of the heater power P watts. When P = 1600, T = 15.
(a)
Find a formula for T in terms of P.
(2)
(b)
Find T when P = 2500.
(1)
(c)
Find P when T = 10.
(2)
(d)
The power is increased from 1600 W to 2500 W. Find the percentage decrease in the roasting time.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 \(T = \frac{k}{\sqrt{P}}\) and \(15 = \frac{k}{40}\)
✓ 1
A1 \(T = \frac{600}{\sqrt{P}}\)
✓ 1
Part (b)
B1 12 minutes
✓ 1
Part (c)
M1 \(\sqrt{P} = 600 \div 10 = 60\)
✓ 1
A1 3600 W
✓ 1
Part (d)
M1 \(\frac{15 - 12}{15} \times 100\) (ECF from (b))
✓ 1
A1 20%
✓ 1
Common error: Inverse proportion to a square root means the square root is in the denominator, so doubling power does not halve the time.
240IGMC3-1-12r32-12Estimation, rounding, bounds, ratio, proportion and moneyPaper EHard8 marks
Calculator
In music, the frequency of a note that is n semitones above the note A is f = 440 × 2n/12 hertz (Hz). A negative n means a note below A.
(a)
Find the frequency of the note 12 semitones above A.
(1)
(b)
A note has frequency 110 Hz. Find n.
(3)
(c)
Show that the frequency increases by the same factor for each extra semitone, and state the value of this factor to 3 significant figures.
(2)
(d)
Find the frequency of the note 7 semitones above A. Give your answer correct to 3 significant figures.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 880 Hz
✓ 1
Part (b)
M1 2n/12 = 110 ÷ 440 = 1/4
✓ 1
M1 writes 1/4 as 2−2
✓ 1
A1 n = −24
✓ 1
Part (c)
R1 f(n + 1) ÷ f(n) = 2(n+1)/12 ÷ 2n/12 = 21/12, independent of n
✓ 1
A1 1.06
✓ 1
Part (d)
M1 440 × 27/12
✓ 1
A1 659 Hz
✓ 1
Exam tip: Use the laws of indices: write both sides with the same base, then compare the powers.
241IGMC3-1-12r32-13Estimation, rounding, bounds, ratio, proportion and moneyPaper EHard7 marks
Calculator
An aircraft is flying a route of 3600 km. It has completed 0.7222… of the route, where the digit 2 repeats forever.
(a)
Show that the fraction of the route completed is 13/18.
(3)
(b)
Work out the distance the aircraft has flown.
(2)
(c)
The aircraft continues at 650 km/h. Calculate the time it still needs to reach the end of the route. Give your answer in hours correct to 3 significant figures.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 let x = 0.7222… so 10x = 7.222… and 100x = 72.222…
✓ 1
M1 subtracts: 90x = 65
✓ 1
A1 x = 65/90 = 13/18 (shown)
✓ 1
Part (b)
M1 13/18 × 3600
✓ 1
A1 2600 km
✓ 1
Part (c)
M1 (3600 − 2600) ÷ 650
✓ 1
A1 1.54 hours
✓ 1
Common error: Multiply by the right power of 10 so that the repeating digits line up before subtracting.
242IGMC3-1-11r36-08Estimation, rounding, bounds, ratio, proportion and moneyPaper EHard8 marks
Calculator
A cargo ship sails a distance of 1200 km, measured to the nearest 10 km. The journey takes 48 hours, measured to the nearest hour. The average speed is distance ÷ time.
(a)
Write down the lower bound of the distance and the upper bound of the time.
(2)
(b)
Calculate the lower bound of the average speed. Give your answer to 4 significant figures.
(2)
(c)
Calculate the upper bound of the average speed. Give your answer to 4 significant figures.
(2)
(d)
Use your answers to parts (b) and (c) to write down the average speed to a suitable degree of accuracy. Give a reason for your answer.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 1195 km
✓ 1
B1 48.5 hours
✓ 1
Part (b)
M1 1195 ÷ 48.5
✓ 1
A1 24.64 km/h
✓ 1
Part (c)
M1 1205 ÷ 47.5
✓ 1
A1 25.37 km/h
✓ 1
Part (d)
B1 both bounds round to 25 to 2 significant figures (24.64 and 25.37)
✓ 1
A1 25 km/h
✓ 1
Exam tip: For a quotient, the upper bound uses the upper bound of the top and the lower bound of the bottom.
243IGMC3-1-11r36-10Indices, standard form and surdsPaper EHard8 marks
No calculator
An architect uses indices to model scaling of a design.
(a)
Simplify \((27x^{6}y^{-3})^{\frac{2}{3}}\).
(3)
(b)
Find the value of \(k\) when \(8^{k}=\frac{1}{4}\).
(2)
(c)
Solve \(4^{x}=8^{x-1}\).
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 9
✓ 1
B1 x4
✓ 1
B1 y−2 (accept 9x4/y2 as a complete answer for all three marks)
✓ 1
Part (b)
M1 23k = 2−2
✓ 1
A1 k = −2/3
✓ 1
Part (c)
M1 22x = 23(x−1)
✓ 1
M1 2x = 3x − 3
✓ 1
A1 x = 3
✓ 1
Exam tip: Write every term as a power of the same prime base before comparing indices.
244IGMC3-1-10r42-08Estimation, rounding, bounds, ratio, proportion and moneyPaper EHard10 marks
Calculator
In a sports-science test, a runner completes 400 m, measured to the nearest metre, in a time of 50.0 s, measured to the nearest 0.1 s.
(a)
Write down the lower bound and the upper bound of (i) the distance, (ii) the time.
(4)
(b)
Calculate the upper bound of the runner's average speed. Give your answer correct to 3 significant figures.
(2)
(c)
Calculate the lower bound of the runner's average speed. Give your answer correct to 3 significant figures.
(2)
(d)
Use your answers to (b) and (c) to give the runner's average speed to a suitable degree of accuracy. Give a reason for your answer.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 distance lower bound 399.5 m
✓ 1
B1 distance upper bound 400.5 m
✓ 1
B1 time lower bound 49.95 s
✓ 1
B1 time upper bound 50.05 s
✓ 1
Part (b)
M1 400.5 ÷ 49.95
✓ 1
A1 8.02 m/s
✓ 1
Part (c)
M1 399.5 ÷ 50.05
✓ 1
A1 7.98 m/s
✓ 1
Part (d)
A1 8.0 m/s
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B1 both bounds round to 8.0 to 2 significant figures
✓ 1
Exam tip: For the greatest speed, divide the greatest distance by the smallest time.
245IGMC3-1-10r42-11Indices, standard form and surdsPaper EHard9 marks
No calculator
This question is about indices.
(a)
Work out 272/3.
(2)
(b)
Solve 2x+1 = \(\frac{1}{32}\).
(2)
(c)
Simplify (125a6)2/3.
(2)
(d)
Solve 8k = 4.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 cube root of 27 is 3, or \((27^{1/3})^2\)
✓ 1
A1 9
✓ 1
Part (b)
M1 \(\frac{1}{32}\) = 2−5
✓ 1
A1 x = −6
✓ 1
Part (c)
B1 25
✓ 1
B1 a4
✓ 1
Part (d)
M1 8 = 23 and 4 = 22
✓ 1
M1 3k = 2
✓ 1
A1 k = \(\frac{2}{3}\)
✓ 1
Exam tip: Write each side as a power of the same base, then equate the indices.
246IGMC3-1-10r42-13Fractions, decimals and percentagesPaper EHard7 marks
No calculator
This question is about recurring decimals and types of number.
(a)
Show that 0.2727… (where the digits 27 repeat) is equal to \(\frac{3}{11}\).
(3)
(b)
Write 0.4666… (where the digit 6 repeats) as a fraction in its simplest form.
(3)
(c)
From the list \(\sqrt{16}\), π, \(\frac{22}{7}\), 0.1212… (where 12 repeats), write down the irrational number.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 let x = 0.2727… so 100x = 27.2727…
✓ 1
M1 subtract to get 99x = 27
✓ 1
A1 x = \(\frac{27}{99}\) = \(\frac{3}{11}\)
✓ 1
Part (b)
M1 let y = 0.4666… so 10y = 4.666… and 100y = 46.666…
✓ 1
M1 subtract to get 90y = 42
✓ 1
A1 \(\frac{42}{90}\) = \(\frac{7}{15}\)
✓ 1
Part (c)
B1 π
✓ 1
Common error: Multiply by a power of 10 that lines up the repeating digits so the decimal parts cancel when subtracting.
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