148 free, high-quality past-paper-style questions on Transformations and vectors for Cambridge IGCSE Maths, each with a full mark scheme. Covers: Reflections, rotations, translations and enlargements described in words; Vectors, magnitude and vector geometry. For when you have finished the past papers, or want to practise one topic at a time.Not sure of your level? Diagnostic test →Multiple choice or structured questions, with the mark scheme as a separate PDF.849 marks · Updated 26 October 2026 · Created by Evan Kotronis with AI assistance · How questions are checked
1IGMC-047-00-01Reflections, rotations, translations and enlargements described in wordsPaper CEasy4 marks
No calculator
Triangle A has vertices at (1, 1), (3, 1) and (1, 4).
(a)
Triangle A is reflected in the x-axis to give triangle B. Write down the coordinates of the vertices of triangle B.
(2)
(b)
Triangle A is translated by the vector \(\begin{pmatrix}-4\\2\end{pmatrix}\) to give triangle C. Write down the coordinates of the vertices of triangle C.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
(1, −1), (3, −1), (1, −4)
—
B1 for at least two vertices correct
✓ 1
B1 for all three vertices correct
✓ 1
Part (b)
(−3, 3), (−1, 3), (−3, 6)
—
B1 for at least two vertices correct
✓ 1
B1 for all three vertices correct
✓ 1
Model sketch
Common error: Reflecting in the x-axis changes the sign of the y-coordinate, not the x-coordinate. The line stays fixed, so points move up or down across it.
2IGMC-047-00-02Reflections, rotations, translations and enlargements described in wordsPaper CEasy3 marks
No calculator
The point P has coordinates (2, 5).
(a)
P is rotated 90° clockwise about the origin. Write down the coordinates of its image.
(1)
(b)
P is rotated 180° about the origin. Write down the coordinates of its image.
(1)
(c)
P is reflected in the line y = x. Write down the coordinates of its image.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 for (5, −2)
✓ 1
Part (b)
B1 for (−2, −5)
✓ 1
Part (c)
B1 for (5, 2)
✓ 1
Exam tip: Check a clockwise rotation quickly: a point in the first quadrant rotated 90° clockwise about the origin must land in the fourth quadrant, with positive x and negative y.
3IGMC-047-00-03Reflections, rotations, translations and enlargements described in wordsPaper CEasy4 marks
No calculator
Triangle A has vertices (2, 1), (4, 1) and (2, 2). Triangle B has vertices (2, −1), (4, −1) and (2, −2). Triangle C has vertices (−3, 4), (−1, 4) and (−3, 5).
(a)
Describe fully the single transformation that maps triangle A onto triangle B.
(2)
(b)
Describe fully the single transformation that maps triangle A onto triangle C.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 for reflection
✓ 1
B1 for in the x-axis (or y = 0)
✓ 1
Part (b)
B1 for translation
✓ 1
B1 for vector \(\begin{pmatrix}-5\\3\end{pmatrix}\)
✓ 1
Exam tip: A full description of a reflection needs the equation of the mirror line, and a translation needs a column vector. Writing 'move 5 left and 3 up' instead of a column vector risks losing the mark.
4IGMC-047-00-04Reflections, rotations, translations and enlargements described in wordsPaper CEasy4 marks
No calculator
Triangle T has vertices (1, 2), (2, 2) and (1, 3). Triangle T is enlarged with scale factor 3 and centre (0, 0) to give triangle U.
(a)
Write down the coordinates of the vertices of triangle U.
(2)
(b)
Find the area of triangle U.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
(3, 6), (6, 6), (3, 9)
—
B1 for at least two vertices correct
✓ 1
B1 for all three vertices correct
✓ 1
Part (b)
M1 for area of T = ½ × 1 × 1 = 0.5 and multiplying by 32, or for ½ × 3 × 3 using triangle U
✓ 1
A1 for 4.5 square units
✓ 1
Common error: Lengths are multiplied by the scale factor, but areas are multiplied by the square of the scale factor. The area of U is 9 times the area of T, not 3 times.
5IGMC-047-00-10Reflections, rotations, translations and enlargements described in wordsPaper CEasy5 marks
No calculator
Triangle A has vertices (1, 1), (3, 1) and (1, 2). Triangle B has vertices (−1, 1), (−1, 3) and (−2, 1).
(a)
Describe fully the single transformation that maps triangle A onto triangle B.
(3)
(b)
Triangle A is reflected in the line y = −x. Write down the coordinates of the vertices of the image.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 for rotation
✓ 1
B1 for 90° anticlockwise (accept 270° clockwise)
✓ 1
B1 for centre (0, 0) or origin
✓ 1
Part (b)
(−1, −1), (−1, −3), (−2, −1)
—
B1 for at least two vertices correct
✓ 1
B1 for all three vertices correct
✓ 1
Common error: 'Rotation of 90° about the origin' is not a full description. The direction (clockwise or anticlockwise) is needed for any rotation that is not 180°.
6IGMC3-7-04d-01Reflections, rotations, translations and enlargements described in wordsPaper CEasy4 marks
No calculator
On a coordinate grid, a solar panel is drawn as triangle ABC with A = (1, 2), B = (4, 2) and C = (4, 5).
(a)
Triangle ABC is reflected in the y-axis. Write down the coordinates of the images of A, B and C.
(2)
(b)
Triangle ABC is translated by the vector \(\begin{pmatrix}-3\\2\end{pmatrix}\). Write down the coordinates of the images of A, B and C.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 at least two images correct
✓ 1
B1 (−1, 2), (−4, 2), (−4, 5)
✓ 1
Part (b)
B1 at least two images correct
✓ 1
B1 (−2, 4), (1, 4), (1, 7)
✓ 1
Model sketch
Common error: A reflection in the y-axis changes the sign of the x-coordinate only. The y-coordinate stays the same.
7IGMC3-7-04d-02Reflections, rotations, translations and enlargements described in wordsPaper CEasy4 marks
No calculator
Triangle PQR has vertices P = (2, 1), Q = (5, 1) and R = (5, 3).
(a)
Triangle PQR is mapped onto triangle P′Q′R′ with P′ = (−2, 1), Q′ = (−5, 1) and R′ = (−5, 3). Describe fully the single transformation that maps PQR onto P′Q′R′.
(2)
(b)
Triangle PQR is mapped onto triangle P″Q″R″ with P″ = (2, −4), Q″ = (5, −4) and R″ = (5, −2). Describe fully the single transformation that maps PQR onto P″Q″R″.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 reflection
✓ 1
B1 in the y-axis (the line x = 0)
✓ 1
Part (b)
B1 translation
✓ 1
B1 by the vector \(\begin{pmatrix}0\\-5\end{pmatrix}\)
✓ 1
Exam tip: Describe fully means naming the type of transformation and giving every detail it needs: a mirror line for a reflection, a vector for a translation.
8IGMC3-7-04d-03Reflections, rotations, translations and enlargements described in wordsPaper CEasy4 marks
No calculator
A rectangular label has vertices at (1, 1), (3, 1), (3, 2) and (1, 2) on a grid where each unit represents 1 cm. It is enlarged with scale factor 3 and centre of enlargement the origin O.
(a)
Write down the coordinates of the vertices of the image.
(2)
(b)
Work out the perimeter of the image, in cm.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 at least two vertices correct
✓ 1
B1 (3, 3), (9, 3), (9, 6), (3, 6)
✓ 1
Part (b)
M1 original perimeter = 2 × (2 + 1) = 6 cm
✓ 1
A1 18 cm (or 6 × 3)
✓ 1
Common error: Every length is multiplied by the scale factor, so the perimeter is multiplied by 3 as well. Do not multiply the coordinates of the centre, here the origin, by anything else.
9IGMC3-7-04d-04Reflections, rotations, translations and enlargements described in wordsPaper CEasy5 marks
No calculator
The position of a warehouse robot is recorded on a grid with the origin O at the charging point. The robot starts at A = (3, 1).
(a)
The robot's position A is rotated through 90° clockwise about O. Write down the coordinates of its new position.
(2)
(b)
A second position B = (−2, 4) is rotated through 180° about O. Write down the coordinates of its new position.
(1)
(c)
A third position C = (5, −2) is rotated through 90° anticlockwise about O. Write down the coordinates of its new position.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 attempt at a 90° clockwise turn, e.g. (y, −x)
✓ 1
A1 (1, −3)
✓ 1
Part (b)
B1 (2, −4)
✓ 1
Part (c)
M1 attempt at a 90° anticlockwise turn, e.g. (−y, x)
✓ 1
A1 (2, 5)
✓ 1
Exam tip: Check a rotation by sketching the point and its image: for 90° about the origin, they should be the same distance from O.
10IGMC3-7-09r13-01Reflections, rotations, translations and enlargements described in wordsPaper CEasy4 marks
No calculator
On a grid plan of an apiary, 1 unit represents 1 metre. A hive stands at H(2, 3).
(a)
The hive is moved by the translation \(\begin{pmatrix}5\\-4\end{pmatrix}\) to point P. Write down the coordinates of P.
(1)
(b)
The hive is then moved from P to Q(−1, 2). Write down the column vector of the translation that moves the hive from P to Q.
(1)
(c)
Find the column vector of the single translation that moves the hive from H directly to Q.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 P = (7, −1)
✓ 1
Part (b)
B1 \(\begin{pmatrix}-8\\3\end{pmatrix}\)
✓ 1
Part (c)
M1 adds the two translations, or subtracts the coordinates of H from those of Q
✓ 1
A1 \(\begin{pmatrix}-3\\-1\end{pmatrix}\)
✓ 1
Common error: Read a translation vector as (change in x, change in y): the top number is horizontal, the bottom number is vertical.
11IGMC3-7-09r13-02Reflections, rotations, translations and enlargements described in wordsPaper CEasy4 marks
No calculator
A triangular warning flag T is drawn on a grid of the pit lane. Its vertices are (2, 1), (2, 3) and (5, 1).
(a)
T is reflected in the line x = 6. Write down the coordinates of the vertices of the image.
(2)
(b)
Describe fully the single transformation that maps T onto the triangle with vertices (2, −1), (2, −3) and (5, −1).
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 two vertices correct
✓ 1
B1 all three: (10, 1), (10, 3), (7, 1)
✓ 1
Part (b)
B1 reflection
✓ 1
B1 in the x-axis (the line y = 0)
✓ 1
Exam tip: To reflect in a vertical line, each point keeps its y-coordinate and ends up the same distance from the mirror line on the other side.
12IGMC3-7-09r13-08Vectors, magnitude and vector geometryPaper CEasy4 marks
No calculator
A porter pushes a trolley along two corridors. The first corridor gives the displacement a = \(\begin{pmatrix}3\\-2\end{pmatrix}\) and the second gives b = \(\begin{pmatrix}-1\\4\end{pmatrix}\) (in metres).
(a)
Write down a + b as a column vector.
(1)
(b)
Work out 3a − 2b.
(2)
(c)
Write down the column vector of the displacement that returns the trolley to its start after a + b.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 \(\begin{pmatrix}2\\2\end{pmatrix}\)
✓ 1
Part (b)
M1 \(\begin{pmatrix}9\\-6\end{pmatrix}\) or \(\begin{pmatrix}-2\\8\end{pmatrix}\) found
✓ 1
A1 \(\begin{pmatrix}11\\-14\end{pmatrix}\)
✓ 1
Part (c)
B1 \(\begin{pmatrix}-2\\-2\end{pmatrix}\)
✓ 1
Common error: When subtracting a vector, change the signs of both of its components: −2b adds 2 and subtracts 8 here.
13IGMC3-7-09r13-09Vectors, magnitude and vector geometryPaper CEasy4 marks
No calculator
On a map of a race circuit, points A and B have coordinates A(1, 2) and B(4, 6).
Diagram not to scale
(a)
Write down the column vector \(\overrightarrow{AB}\).
(1)
(b)
The point C is such that \(\overrightarrow{AC}=2\overrightarrow{AB}\). Find the coordinates of C.
(2)
(c)
Write down the column vector \(\overrightarrow{CA}\).
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 \(\begin{pmatrix}3\\4\end{pmatrix}\)
✓ 1
Part (b)
M1 \(\begin{pmatrix}6\\8\end{pmatrix}\) or adds to the coordinates of A
✓ 1
A1 (7, 10)
✓ 1
Part (c)
B1 \(\begin{pmatrix}-6\\-8\end{pmatrix}\)
✓ 1
Exam tip: The vector from A to B is the coordinates of B minus the coordinates of A; reversing the direction changes both signs.
14IGMC3-7-10r13-01Reflections, rotations, translations and enlargements described in wordsPaper CEasy3 marks
No calculator
In a computer game, a sprite moves from S(4, −2) to T(1, 5) by a translation.
(a)
Write down the column vector of this translation.
(1)
(b)
The sprite makes the same move again from T. Write down its new coordinates.
(1)
(c)
Write down the column vector of the translation that takes the sprite from (−2, 12) straight back to S.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 \(\begin{pmatrix}-3\\7\end{pmatrix}\)
✓ 1
Part (b)
B1 (−2, 12)
✓ 1
Part (c)
B1 \(\begin{pmatrix}6\\-14\end{pmatrix}\)
✓ 1
Exam tip: Count the horizontal change first, then the vertical change, and keep the signs: moving left or down is negative.
15IGMC3-7-10r13-02Reflections, rotations, translations and enlargements described in wordsPaper CEasy4 marks
No calculator
A water-supply engineer draws the outline of a tank as a triangle with vertices (1, 2), (4, 2) and (4, 5) on a grid.
(a)
The triangle is reflected in the line x = −1. Write down the coordinates of the image of each vertex.
(2)
(b)
Describe fully the single transformation that maps the original triangle onto the triangle with vertices (1, −2), (4, −2) and (4, −5).
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 two vertices correct
✓ 1
B1 all three: (−3, 2), (−6, 2), (−6, 5)
✓ 1
Part (b)
B1 reflection
✓ 1
B1 in the x-axis (the line y = 0)
✓ 1
Common error: A point left of the mirror line moves to the right of it by the same distance, so measure from the line, not from the y-axis.
16IGMC3-7-10r13-12Reflections, rotations, translations and enlargements described in wordsPaper CEasy3 marks
No calculator
A robot arm in a pharmacy places a vial at the point P(3, 1) on a grid. P is rotated about the origin O. Write down the coordinates of its image after each rotation.
(a)
90° clockwise
(1)
(b)
180°
(1)
(c)
90° anticlockwise
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 (1, −3)
✓ 1
Part (b)
B1 (−3, −1)
✓ 1
Part (c)
B1 (−1, 3)
✓ 1
Exam tip: Sketch the point and the axes: a quarter turn moves a point in the first quadrant to the fourth (clockwise) or the second (anticlockwise).
17IGMC3-7-10r17-01Reflections, rotations, translations and enlargements described in wordsPaper CEasy4 marks
No calculator
On an archaeological site plan, a triangular marker has corners P(2, 1), Q(6, 1) and R(6, 4). The marker is translated by the column vector (−3, 5), written here as −3 across and 5 up.
(a)
Write down the coordinates of the images P′, Q′ and R′.
(2)
(b)
Describe fully the single transformation that maps P′Q′R′ back onto PQR.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 P′ (−1, 6) and Q′ (3, 6)
✓ 1
B1 R′ (3, 9)
✓ 1
Part (b)
B1 translation
✓ 1
B1 by the vector (3, −5), that is 3 across and 5 down
✓ 1
Exam tip: A translation is described by a column vector only. Do not add a centre or an angle.
18IGMC3-7-10r17-02Reflections, rotations, translations and enlargements described in wordsPaper CEasy5 marks
No calculator
A cycling coach plots a triangle with corners A(1, 2), B(4, 2) and C(4, 5) on a grid.
(a)
Triangle ABC is reflected in the line x = 5. Write down the coordinates of the images of A, B and C.
(2)
(b)
Triangle ABC is reflected in the x-axis. Write down the coordinates of the image of C.
(1)
(c)
Point B(4, 2) is reflected in a horizontal mirror line and its image is (4, 8). Find the equation of the mirror line.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 A′ (9, 2)
✓ 1
B1 B′ (6, 2) and C′ (6, 5)
✓ 1
Part (b)
B1 (4, −5)
✓ 1
Part (c)
M1 mirror line passes through the midpoint, with y = (2 + 8) ÷ 2
✓ 1
A1 y = 5
✓ 1
Common error: Giving the mirror line as x = 5 for a horizontal line. A horizontal line has an equation of the form y = number.
19IGMC3-7-10r17-03Reflections, rotations, translations and enlargements described in wordsPaper CEasy4 marks
No calculator
In a data centre floor plan, a server rack is marked at S(3, 1) and a cooling unit at T(2, 4).
(a)
S is rotated through 90° clockwise about the origin. Write down the coordinates of its image.
(1)
(b)
S is rotated through 180° about the point (1, 1). Find the coordinates of its image.
(2)
(c)
T is rotated through 90° anticlockwise about the origin. Write down the coordinates of its image.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 (1, −3)
✓ 1
Part (b)
M1 S is 2 units to the right of the centre, so the image is 2 units to the left
✓ 1
A1 (−1, 1)
✓ 1
Part (c)
B1 (−4, 2)
✓ 1
Exam tip: Check a rotation by drawing the line from the centre to the point and turning it. Use the direction given: clockwise or anticlockwise.
20IGMC3-7-10r17-04Reflections, rotations, translations and enlargements described in wordsPaper CEasy4 marks
Calculator
An archaeologist enlarges a plan of a rectangular room. The room has corners (1, 1), (4, 1), (4, 3) and (1, 3). The rectangle is enlarged with scale factor 3 and centre (0, 0).
(a)
Write down the coordinates of the corners of the image.
(2)
(b)
Work out the area of the image.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 two corners correct
✓ 1
B1 (3, 3), (12, 3), (12, 9) and (3, 9)
✓ 1
Part (b)
M1 original area 3 × 2 = 6 and area scale factor 32 (or image sides 9 and 6)
✓ 1
A1 54 square units
✓ 1
Common error: Multiplying the area by the scale factor 3 instead of by 3².
21IGMC3-7-10r19-01Reflections, rotations, translations and enlargements described in wordsPaper CEasy6 marks
No calculator
A marine biologist marks a triangular survey region PQR on a coordinate grid, where one unit represents 1 km. The vertices are P(2, 1), Q(5, 1) and R(5, 4).
(a)
Triangle PQR is reflected in the y-axis. Write down the coordinates of the images of P and R.
(2)
(b)
Describe fully the single transformation that maps triangle PQR onto the triangle with vertices (2, −1), (5, −1) and (5, −4).
(2)
(c)
Calculate the area of the survey region PQR.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 P′ = (−2, 1)
✓ 1
B1 R′ = (−5, 4)
✓ 1
Part (b)
B1 reflection
✓ 1
B1 in the x-axis (the line \(y=0\))
✓ 1
Part (c)
M1 \(\frac{1}{2}\times3\times3\)
✓ 1
A1 4.5 km\(^2\)
✓ 1
Common error: A reflection needs its mirror line stated; writing only 'reflection' earns only one of the two marks.
22IGMC3-7-10r19-02Reflections, rotations, translations and enlargements described in wordsPaper CEasy5 marks
No calculator
A warehouse robot docks at a charging point A(2, 3). A translation moves A to A′(7, 1) on the floor plan grid.
(a)
Write the translation as a column vector.
(2)
(b)
The same translation is applied to the point B(−3, 4). Find the coordinates of the image of B.
(1)
(c)
The same translation moves a point C to C′(9, −5). Find the coordinates of C.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 5 for the horizontal component
✓ 1
B1 −2 for the vertical component: \(\begin{pmatrix}5\\-2\end{pmatrix}\)
✓ 1
Part (b)
B1 (2, 2)
✓ 1
Part (c)
M1 subtract the vector: \((9-5,\,-5+2)\)
✓ 1
A1 (4, −3)
✓ 1
Exam tip: To find an original point from its image, apply the opposite of the translation (subtract the vector).
23IGMC3-7-10r19-03Reflections, rotations, translations and enlargements described in wordsPaper CEasy4 marks
No calculator
An architect enlarges a floor plan using an enlargement with centre the origin O(0, 0). The point A(2, 1) on the plan is mapped to A′(8, 4).
(a)
Write down the scale factor of the enlargement.
(1)
(b)
The point B(3, 5) is mapped to B′ by the same enlargement. Find the coordinates of B′.
(1)
(c)
The point C is mapped to C′(10, −6) by the same enlargement. Find the coordinates of C.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 4
✓ 1
Part (b)
B1 (12, 20)
✓ 1
Part (c)
M1 divide both coordinates of C′ by 4
✓ 1
A1 (2.5, −1.5)
✓ 1
Common error: To go back from the image to the original, divide by the scale factor; multiplying again gives the wrong point.
24IGMC3-7-10r19-04Reflections, rotations, translations and enlargements described in wordsPaper CEasy6 marks
No calculator
A container-bay layout includes triangle ABC with A(1, 1), B(3, 1) and C(3, 4). The triangle is rotated through 90° clockwise about the origin to give triangle A′B′C′.
(a)
Write down the coordinates of A′, B′ and C′.
(3)
(b)
Describe fully the single transformation that maps triangle A′B′C′ onto triangle ABC.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 A′ = (1, −1)
✓ 1
B1 B′ = (1, −3)
✓ 1
B1 C′ = (4, −3)
✓ 1
Part (b)
B1 rotation
✓ 1
B1 90° anticlockwise
✓ 1
B1 centre (0, 0) (the origin)
✓ 1
Exam tip: A rotation needs three details: the angle, the direction and the centre. Check one vertex with tracing paper or by turning the page.
25IGMC3-7-10r24-01Reflections, rotations, translations and enlargements described in wordsPaper CEasy4 marks
No calculator
In a computer game a character stands at A(2, 3) on a coordinate grid. It moves to B by the translation \(\begin{pmatrix}4\\-5\end{pmatrix}\). It then moves from B to C by the translation \(\begin{pmatrix}-3\\6\end{pmatrix}\).
(a)
Write down the coordinates of B.
(1)
(b)
Write down the coordinates of C.
(1)
(c)
Write the single translation that takes the character directly from A to C as a column vector.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 (6, −2)
✓ 1
Part (b)
B1 (3, 4)
✓ 1
Part (c)
M1 sum of the two vectors, or C − A
✓ 1
A1 \(\begin{pmatrix}1\\1\end{pmatrix}\)
✓ 1
Exam tip: A translation is described by a column vector only: top number for movement in the x-direction, bottom for the y-direction.
26IGMC3-7-10r24-02Reflections, rotations, translations and enlargements described in wordsPaper CEasy4 marks
No calculator
Triangle P has vertices (1, 1), (3, 1) and (3, 4). It is reflected in the line \(x = 5\) to give triangle Q.
(a)
Write down the coordinates of the vertices of Q.
(2)
(b)
Triangle R has vertices (1, −1), (3, −1) and (3, −4). Describe fully the single transformation that maps P onto R.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 (9, 1)
✓ 1
B1 (7, 1) and (7, 4)
✓ 1
Part (b)
B1 reflection
✓ 1
B1 in the x-axis (the line \(y = 0\))
✓ 1
Common error: A reflection must name its mirror line; 'a reflection' alone earns no accuracy mark.
27IGMC3-7-10r24-03Reflections, rotations, translations and enlargements described in wordsPaper CEasy5 marks
No calculator
On a game map, triangle ABC has vertices A(1, 1), B(4, 1) and C(4, 3). It is rotated 90° anticlockwise about the origin to give triangle A′B′C′.
(a)
Write down the coordinates of A′, B′ and C′.
(2)
(b)
Describe fully the single transformation that maps A′B′C′ onto ABC.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 A′(−1, 1) and B′(−1, 4)
✓ 1
B1 C′(−3, 4)
✓ 1
Part (b)
B1 rotation
✓ 1
B1 90° clockwise
✓ 1
B1 about the origin (0, 0)
✓ 1
Exam tip: A full description of a rotation needs three things: the angle, the direction and the centre of rotation.
28IGMC3-7-10r24-08Reflections, rotations, translations and enlargements described in wordsPaper CEasy5 marks
No calculator
A triangle T is translated by \(\begin{pmatrix}-3\\2\end{pmatrix}\) to give triangle U. Triangle U is then translated by \(\begin{pmatrix}5\\-6\end{pmatrix}\) to give triangle V.
(a)
Write the single translation that maps T onto V as a column vector.
(2)
(b)
Vertex A(1, 6) of T maps to a vertex of V. Write down the coordinates of that vertex.
(1)
(c)
Describe fully the single transformation that maps V onto T.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 add the two vectors
✓ 1
A1 \(\begin{pmatrix}2\\-4\end{pmatrix}\)
✓ 1
Part (b)
B1 (3, 2) (ECF from (a))
✓ 1
Part (c)
B1 translation
✓ 1
B1 by vector \(\begin{pmatrix}-2\\4\end{pmatrix}\)
✓ 1
Exam tip: The reverse of a translation uses the same vector with both signs changed.
29IGMC3-7-10r39-01Reflections, rotations, translations and enlargements described in wordsPaper CEasy4 marks
No calculator
An archaeologist records positions on a grid of 1 m squares, with coordinates (x, y). A marker at point A(2, 3) is moved by a translation with vector \(\begin{pmatrix}4\\-5\end{pmatrix}\).
(a)
Write down the coordinates of the new position of the marker.
(2)
(b)
A second marker at P(7, 1) is moved to Q(3, −4) by a single translation. Write down the column vector of this translation.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 x = 6
✓ 1
B1 y = −2, so (6, −2)
✓ 1
Part (b)
B1 −4 in the top position
✓ 1
B1 −5 in the bottom position, \(\begin{pmatrix}-4\\-5\end{pmatrix}\)
✓ 1
Common error: Find a translation vector by subtracting start from end, (new − old) for each coordinate, not the other way round.
30IGMC3-7-10r39-02Reflections, rotations, translations and enlargements described in wordsPaper CEasy5 marks
No calculator
A floor plan of a data centre uses coordinates (x, y) in metres. Triangle T has vertices at (2, 1), (5, 1) and (2, 4).
(a)
T is reflected in the line x = 6. Write down the coordinates of the vertices of the image.
(3)
(b)
Describe fully the single transformation that maps T onto the triangle with vertices (2, −1), (5, −1) and (2, −4).
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 (10, 1)
✓ 1
B1 (7, 1)
✓ 1
B1 (10, 4)
✓ 1
Part (b)
B1 reflection
✓ 1
B1 in the x-axis (accept the line y = 0)
✓ 1
Exam tip: To reflect in a vertical line, each point keeps its y-value and ends up the same distance on the other side of the mirror line.
31IGMC3-7-10r39-03Reflections, rotations, translations and enlargements described in wordsPaper CEasy7 marks
No calculator
The plan of a cycling track uses coordinates (x, y) in units of 10 m.
(a)
The point P(3, 1) is rotated through 90° clockwise about the origin O. Write down the coordinates of the image of P.
(2)
(b)
The point Q(−2, 4) is rotated through 180° about O. Write down the coordinates of the image of Q.
(2)
(c)
A single rotation about O maps R(4, 0) onto R′(0, 4) and S(0, 2) onto S′(−2, 0). Describe fully this rotation.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 x = 1
✓ 1
B1 y = −3, so (1, −3)
✓ 1
Part (b)
B1 x = 2
✓ 1
B1 y = −4, so (2, −4)
✓ 1
Part (c)
B1 rotation
✓ 1
B1 90° anticlockwise
✓ 1
B1 centre (0, 0)
✓ 1
Common error: Check the direction of a rotation with a quick sketch of one point. A 90° turn clockwise and a 90° turn anticlockwise give different images.
32IGMC3-7-10r39-04Vectors, magnitude and vector geometryPaper CEasy6 marks
No calculator
In a data centre, a cable is laid between points A(1, 2), B(5, 5) and C(−1, 6) on a grid with coordinates in metres.
Diagram not to scale
(a)
Write down the column vector \(\overrightarrow{AB}\).
(2)
(b)
Write down the column vector \(\overrightarrow{BC}\).
M1 \(\overrightarrow{AB}+\overrightarrow{BC}\) or C − A
✓ 1
A1 \(\begin{pmatrix}-2\\4\end{pmatrix}\)
✓ 1
Exam tip: Vectors add head to tail: the route A to B to C has the same overall displacement as going from A directly to C.
33IGMC3-7-12r41-01Reflections, rotations, translations and enlargements described in wordsPaper CEasy4 marks
No calculator
In a strategy game, a map is drawn on a coordinate grid. A scout starts at the point A(2, 3) and is moved by the translation with column vector (−4, 5) to the point B.
(a)
Write down the coordinates of B.
(1)
(b)
The scout is then moved from B to C(3, −1) by a single translation. Write down the column vector of this translation.
(2)
(c)
Write down the column vector of the translation that moves the scout from C back to A.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
A1 (−2, 8)
✓ 1
Part (b)
B1 horizontal component 5
✓ 1
B1 vertical component −9
✓ 1
Part (c)
B1 (−1, 4)
✓ 1
Common error: A column vector gives the horizontal change on top and the vertical change below; subtract the starting coordinates from the finishing coordinates, not the other way round.
34IGMC3-7-12r41-02Reflections, rotations, translations and enlargements described in wordsPaper CEasy4 marks
No calculator
On a map grid with 1 unit = 1 km, triangle T has vertices at the pumping stations A(1, 2), B(4, 2) and C(4, 5). T is reflected in the line x = 6 to give triangle U.
(a)
Write down the coordinates of the image of A in triangle U.
(1)
(b)
Triangle V has vertices (−1, −2), (−4, −2) and (−4, −5). Describe fully the single transformation that maps T onto V.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
A1 (11, 2)
✓ 1
Part (b)
B1 rotation
✓ 1
B1 180° (a half turn)
✓ 1
B1 centre (0, 0) (accept enlargement, scale factor −1, centre (0, 0))
✓ 1
Exam tip: A full description of a transformation needs its type and every detail that fixes it: a line for a reflection, an angle, direction and centre for a rotation.
35IGMC3-7-12r41-03Vectors, magnitude and vector geometryPaper CEasy6 marks
Calculator
Under a microscope, a drug particle is tracked on a grid in micrometres. It moves from P(1, 2) to Q(5, 5) and then to R(−3, 9).
Diagram not to scale
(a)
Write down the column vector that moves the particle from P to Q.
(1)
(b)
Calculate the distance PQ.
(2)
(c)
Calculate the distance PR. Give your answer correct to 3 significant figures.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 (4, 3)
✓ 1
Part (b)
M1 √(42 + 32)
✓ 1
A1 5 micrometres
✓ 1
Part (c)
M1 R − P = (−4, 7), or horizontal difference 4 and vertical difference 7
✓ 1
M1 √(42 + 72) = √65
✓ 1
A1 8.06 micrometres
✓ 1
Exam tip: Distances between two points come from Pythagoras' theorem applied to the horizontal and vertical differences.
36IGMC3-7-12r41-04Reflections, rotations, translations and enlargements described in wordsPaper CEasy5 marks
No calculator
In a game, a rectangular sprite has vertices at (1, 1), (3, 1), (3, 2) and (1, 2). It is enlarged by scale factor 3 with centre of enlargement (0, 0).
(a)
Write down the coordinates of the image of the vertex (3, 2).
(1)
(b)
Work out the area of the image rectangle.
(2)
(c)
The original sprite is instead enlarged by scale factor 2 with centre (1, 1). Find the coordinates of the image of the vertex (3, 2).
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
A1 (9, 6)
✓ 1
Part (b)
M1 image has width 6 and height 3
✓ 1
A1 18
✓ 1
Part (c)
M1 vector from centre to vertex (2, 1) multiplied by 2
✓ 1
A1 (5, 3)
✓ 1
Common error: With a centre other than the origin, multiply the distances from the centre, not the coordinates themselves.
37IGMC3-7-11r42-01Reflections, rotations, translations and enlargements described in wordsPaper CEasy6 marks
No calculator
A marine biologist plots the position of a tagged turtle on a coordinate grid where 1 unit represents 1 km. The turtle starts at T(3, −2) and swims to U by the translation \(\begin{pmatrix}-4\\5\end{pmatrix}\).
(a)
Write down the coordinates of U.
(2)
(b)
The turtle then swims from U to V(6, 1). Write down the column vector of the translation that maps U to V.
(2)
(c)
Describe fully the single transformation that maps T to V.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 x-coordinate −1
✓ 1
B1 y-coordinate 3
✓ 1
Part (b)
M1 6 − (−1) and 1 − 3 (or equivalent)
✓ 1
A1 \(\begin{pmatrix}7\\-2\end{pmatrix}\)
✓ 1
Part (c)
B1 Translation
✓ 1
B1 \(\begin{pmatrix}3\\3\end{pmatrix}\)
✓ 1
Common error: When subtracting coordinates to find a translation, write image minus object; with a negative starting coordinate, 6 − (−1) is 7, not 5.
38IGMC3-7-11r42-02Reflections, rotations, translations and enlargements described in wordsPaper CEasy5 marks
Calculator
An architect draws the floor plan of a museum on a coordinate grid. Point P(2, 5) marks a doorway and point Q(3, −2) marks a pillar.
(a)
P is reflected in the line y = 3. Write down the coordinates of the image of P.
(1)
(b)
Q is reflected in the line x = −1. Find the coordinates of the image of Q.
(2)
(c)
A triangular roof panel with vertices (1, 2), (1, 5) and (3, 2) is mapped onto the panel with vertices (−1, 2), (−1, 5) and (−3, 2). Describe fully the single transformation.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 (2, 1)
✓ 1
Part (b)
M1 Q is 4 units to the right of the line, so image is 4 units to the left of it (or x′ = 2(−1) − 3)
✓ 1
A1 (−5, −2)
✓ 1
Part (c)
B1 Reflection
✓ 1
B1 in the y-axis (the line x = 0)
✓ 1
Exam tip: For a reflection, state the type of transformation and the equation of the mirror line; "flip" is not a transformation name.
39IGMC3-7-11r42-13Reflections, rotations, translations and enlargements described in wordsPaper CEasy6 marks
Calculator
A marine biologist builds a scale model panel of a fish tank. Rectangle A has sides of 4 cm and 7 cm. Rectangle B is an enlargement of A with scale factor 3.
(a)
Write down the lengths of the sides of rectangle B.
(2)
(b)
Calculate the perimeter of rectangle B.
(2)
(c)
Rectangle C is also an enlargement of rectangle A and has a perimeter of 88 cm. Find the scale factor of this enlargement.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 12 cm
✓ 1
B1 21 cm
✓ 1
Part (b)
M1 2 × (12 + 21)
✓ 1
A1 66 cm
✓ 1
Part (c)
M1 Perimeter of A = 22 and 88 ÷ 22
✓ 1
A1 4
✓ 1
Exam tip: The scale factor can be found from any pair of corresponding lengths, including perimeters.
40IGMC3-7-11r42-14Reflections, rotations, translations and enlargements described in wordsPaper CEasy5 marks
No calculator
A logistics company marks the corners of a triangular loading zone on a grid. Triangle ABC has A(1, 1), B(4, 1) and C(4, 3). It is mapped onto triangle A′B′C′ with A′(−2, −3), B′(1, −3) and C′(1, −1).
(a)
Describe fully the single transformation that maps ABC onto A′B′C′.
(2)
(b)
The same transformation maps the point (10, −7) onto a point R. Find the coordinates of R.
(1)
(c)
The same transformation maps point D onto D′(5, 2). Find the coordinates of D.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 Translation
✓ 1
B1 \(\begin{pmatrix}-3\\-4\end{pmatrix}\)
✓ 1
Part (b)
B1 (7, −11)
✓ 1
Part (c)
M1 Add (3, 4) to (5, 2)
✓ 1
A1 (8, 6)
✓ 1
Common error: To go back from the image to the object, reverse the translation by adding the opposite of each component.
41IGMC-047-00-05Reflections, rotations, translations and enlargements described in wordsPaper CMedium7 marks
No calculator
Quadrilateral Q has vertices (3, 1), (5, 1), (5, 3) and (4, 3).
(a)
Q is reflected in the line x = 2 to give quadrilateral R. Write down the coordinates of the vertices of R.
(2)
(b)
R is reflected in the line y = −1 to give quadrilateral S. Write down the coordinates of the vertices of S.
(2)
(c)
Describe fully the single transformation that maps Q onto S.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
(1, 1), (−1, 1), (−1, 3), (0, 3)
—
B1 for at least two vertices correct
✓ 1
B1 for all four vertices correct
✓ 1
Part (b)
(1, −3), (−1, −3), (−1, −5), (0, −5)
—
B1 for at least two vertices correct, follow through from their R
✓ 1
B1 for all four vertices correct
✓ 1
Part (c)
B1 for rotation
✓ 1
B1 for 180°
✓ 1
B1 for centre (2, −1)
✓ 1
Model sketch
Exam tip: Reflections in two perpendicular lines combine to give a 180° rotation about the point where the lines cross. Here x = 2 and y = −1 meet at (2, −1). For a 180° rotation no direction is needed.
42IGMC-047-00-06Reflections, rotations, translations and enlargements described in wordsPaper CMedium6 marks
No calculator
Triangle T has vertices (1, 2), (3, 2) and (3, 3).
(a)
Triangle T is rotated 90° anticlockwise about the point (1, 0) to give triangle V. Find the coordinates of the vertices of triangle V.
(3)
(b)
Describe fully the single transformation that maps triangle V back onto triangle T.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
Relative to (1, 0), the vertices of T are (0, 2), (2, 2) and (2, 3). A rotation of 90° anticlockwise sends (x, y) to (−y, x), giving (−2, 0), (−2, 2) and (−3, 2). Adding (1, 0) back gives the vertices of V.
—
B1 for (−1, 0)
✓ 1
B1 for (−1, 2)
✓ 1
B1 for (−2, 2)
✓ 1
Part (b)
B1 for rotation
✓ 1
B1 for 90° clockwise (accept 270° anticlockwise)
✓ 1
B1 for centre (1, 0)
✓ 1
Model sketch
Common error: Rotating about the origin when the centre is (1, 0) gives the wrong images. Work out each vertex's displacement from the centre, rotate that displacement, then add it back on to the centre.
43IGMC-047-00-07Reflections, rotations, translations and enlargements described in wordsPaper CMedium5 marks
No calculator
Triangle P has vertices (2, 1), (4, 1) and (2, 4). Triangle Q has vertices (−2, −1), (4, −1) and (−2, 8).
(a)
Describe fully the single transformation that maps triangle P onto triangle Q.
(3)
(b)
Find the area of triangle Q.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 for enlargement
✓ 1
B1 for scale factor 3
✓ 1
B1 for centre (4, 2)
✓ 1
Part (b)
M1 for ½ × 6 × 9, or for area of P = 3 multiplied by 32
✓ 1
A1 for 27 square units
✓ 1
Exam tip: To find the centre of enlargement, draw or imagine lines through matching vertices, such as (2, 1) to (−2, −1) and (4, 1) to (4, −1). The centre is where these lines meet. Check that the image distances from the centre are 3 times the original distances.
44IGMC-047-00-09Reflections, rotations, translations and enlargements described in wordsPaper CMedium6 marks
Calculator
A shape is translated by the vector \(\begin{pmatrix}3\\-2\end{pmatrix}\) and then by the vector \(\begin{pmatrix}-5\\4\end{pmatrix}\).
(a)
Write down the vector of the single translation that has the same effect as these two translations.
(1)
(b)
After both translations, one vertex of the shape is at (1, 7). Find the coordinates of this vertex before the translations.
(2)
(c)
Write down the vector of the translation that maps the final shape back onto the original shape.
(1)
(d)
(Extended) Find the distance moved by each point under the single translation that has the same effect as both translations. Give your answer to 3 significant figures.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 for \(\begin{pmatrix}-2\\2\end{pmatrix}\)
✓ 1
Part (b)
M1 for (1 − (−2), 7 − 2) or reversing each translation in turn
✓ 1
A1 for (3, 5)
✓ 1
Part (c)
B1 for \(\begin{pmatrix}2\\-2\end{pmatrix}\), follow through from their single translation vector
✓ 1
Part (d)
M1 for \(\sqrt{(-2)^2 + 2^2}\)
✓ 1
A1 for 2.83 units (accept \(2\sqrt{2}\) or \(\sqrt{8}\))
✓ 1
Exam tip: Add translation vectors component by component: top numbers together, bottom numbers together. To undo a translation, change the sign of both components.
45IGMC-047-00-12Reflections, rotations, translations and enlargements described in wordsPaper CMedium6 marks
No calculator
Triangle T has vertices (1, 2), (4, 2) and (4, 3).
(a)
T is rotated 90° clockwise about the origin to give triangle U. Write down the coordinates of the vertices of U.
(2)
(b)
U is reflected in the x-axis to give triangle V. Write down the coordinates of the vertices of V.
(2)
(c)
Describe fully the single transformation that maps triangle T onto triangle V.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
(2, −1), (2, −4), (3, −4)
—
B1 for at least two vertices correct
✓ 1
B1 for all three vertices correct
✓ 1
Part (b)
(2, 1), (2, 4), (3, 4)
—
B1 for at least two vertices correct, follow through from their U
✓ 1
B1 for all three vertices correct
✓ 1
Part (c)
B1 for reflection
✓ 1
B1 for in the line y = x
✓ 1
Model sketch
Common error: Two transformations combined must be described as one transformation. Answers such as 'rotation then reflection' score nothing when a single transformation is asked for. Compare the coordinates of T and V directly.
46IGMC3-7-04d-06Reflections, rotations, translations and enlargements described in wordsPaper CMedium7 marks
No calculator
On a coordinate grid, triangle T has vertices (1, 1), (3, 1) and (3, 4). A bridge designer draws images of T under different transformations.
(a)
Triangle T is mapped onto triangle U with vertices (−1, −1), (−3, −1) and (−3, −4). Describe fully the single transformation that maps T onto U.
(3)
(b)
Triangle T is reflected in the line x = 4. Write down the coordinates of the vertices of the image.
(2)
(c)
Triangle T is mapped onto triangle V with vertices (1, −1), (3, −1) and (3, −4). Describe fully the single transformation that maps T onto V.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 rotation
✓ 1
B1 through 180° (half turn)
✓ 1
B1 about the origin (0, 0)
✓ 1
Part (b)
M1 each x-coordinate is the same distance on the other side of x = 4, e.g. x becomes 8 − x
✓ 1
A1 (7, 1), (5, 1), (5, 4)
✓ 1
Part (c)
B1 reflection
✓ 1
B1 in the x-axis (the line y = 0)
✓ 1
Exam tip: For a rotation of 180° the direction does not matter, but you must still state the angle and the centre.
47IGMC3-7-04d-07Reflections, rotations, translations and enlargements described in wordsPaper CMedium6 marks
No calculator
A designer scales a logo on a coordinate grid. Triangle ABC has A = (2, 3), B = (6, 3) and C = (6, 5). It is enlarged with scale factor 2 and centre of enlargement (0, 1) to give triangle A′B′C′.
(a)
Find the coordinates of A′, B′ and C′.
(3)
(b)
Describe fully the single transformation that maps triangle A′B′C′ onto triangle ABC.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 position of A relative to the centre is (2, 2), so the image is at (4, 4) from the centre
✓ 1
A1 at least two images correct
✓ 1
A1 (4, 5), (12, 5), (12, 9)
✓ 1
Part (b)
B1 enlargement
✓ 1
B1 scale factor ½
✓ 1
B1 centre (0, 1)
✓ 1
Model sketch
Common error: The centre of enlargement is not always the origin. Measure each point's position from the centre, scale that, then add the centre back.
48IGMC3-7-04d-08Reflections, rotations, translations and enlargements described in wordsPaper CMedium6 marks
No calculator
A camera on a robot arm tracks a triangular marker with vertices (1, 1), (2, 1) and (2, 3) on a grid.
(a)
The marker is translated by the vector \(\begin{pmatrix}4\\2\end{pmatrix}\). Write down the coordinates of its three vertices after the translation.
(2)
(b)
This image is then rotated through 90° clockwise about the origin. Write down the coordinates of its three vertices after the rotation.
(2)
(c)
State whether the final triangle is congruent to the original triangle, or only similar. Give a reason.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 adds 4 to each x-coordinate and 2 to each y-coordinate
✓ 1
A1 (5, 3), (6, 3), (6, 5)
✓ 1
Part (b)
M1 uses (x, y) → (y, −x) on the translated vertices (ECF from (a))
✓ 1
A1 (3, −5), (3, −6), (5, −6)
✓ 1
Part (c)
B1 congruent
✓ 1
B1 translations and rotations preserve lengths and angles (the size does not change)
✓ 1
Model sketch
Exam tip: Do the transformations in the order given, and use the image from the first step as the object for the second.
49IGMC3-7-09r13-03Reflections, rotations, translations and enlargements described in wordsPaper CMedium5 marks
No calculator
A hospital wing plan is drawn on a grid with 1 unit = 10 m. A triangular garden has vertices A(1, 1), B(4, 1) and C(4, 3).
(a)
The garden is rotated through 90° clockwise about the origin O. Write down the coordinates of the images A′, B′ and C′.
(2)
(b)
The triangle A′B′C′ is mapped onto the triangle with vertices (−1, 1), (−1, 4) and (−3, 4). Describe fully the single transformation.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 a vertex rotated correctly, e.g. A′ = (1, −1)
✓ 1
A1 A′(1, −1), B′(1, −4), C′(3, −4)
✓ 1
Part (b)
B1 rotation
✓ 1
B1 180°
✓ 1
B1 about the origin (0, 0)
✓ 1
Common error: Check the direction of a rotation with one vertex first: 90° clockwise about the origin sends (x, y) to (y, −x).
50IGMC3-7-09r13-04Reflections, rotations, translations and enlargements described in wordsPaper CMedium4 marks
No calculator
A rectangular honey frame is drawn on a grid with 1 unit = 1 cm. Its vertices are A(1, 1), B(3, 1), C(3, 2) and D(1, 2). The frame is enlarged by scale factor 3 with centre the origin.
(a)
Write down the coordinates of the vertices of the image.
(2)
(b)
Calculate the perimeter of the image, in cm.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 multiplies coordinates by 3 for at least one vertex
✓ 1
A1 (3, 3), (9, 3), (9, 6), (3, 6)
✓ 1
Part (b)
M1 image sides 6 and 3, or perimeter of ABCD (6) multiplied by 3
✓ 1
A1 18 cm
✓ 1
Exam tip: Lengths in an enlargement are multiplied by the scale factor, so you can find the new perimeter without drawing the shape.
51IGMC3-7-09r13-05Reflections, rotations, translations and enlargements described in wordsPaper CMedium4 marks
No calculator
A rear-wing template P has vertices (2, 2), (4, 2) and (4, 3) on a grid. Its image Q under an enlargement has vertices (3, 3), (7, 3) and (7, 5).
(a)
Describe fully the enlargement that maps P onto Q.
(3)
(b)
Q is translated by \(\begin{pmatrix}-5\\-2\end{pmatrix}\). Write down the image of the point (7, 5) under this translation.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 enlargement
✓ 1
B1 scale factor 2
✓ 1
B1 centre (1, 1)
✓ 1
Part (b)
B1 (2, 3)
✓ 1
Exam tip: To find the centre of an enlargement, draw lines through corresponding points; they meet at the centre.
52IGMC3-7-09r13-06Reflections, rotations, translations and enlargements described in wordsPaper CMedium5 marks
No calculator
In a hospital simulation, point P is at (4, 1). Transformation X is a reflection in the x-axis. Transformation Y is a translation \(\begin{pmatrix}0\\6\end{pmatrix}\).
(a)
P is transformed by X, and then its image is transformed by Y. Find the final coordinates.
(2)
(b)
P is transformed by Y, and then its image is transformed by X. Find the final coordinates.
(2)
(c)
Does the order of the two transformations matter? Give a reason.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 (4, −1) after X
✓ 1
A1 (4, 5)
✓ 1
Part (b)
M1 (4, 7) after Y
✓ 1
A1 (4, −7)
✓ 1
Part (c)
B1 Yes, because the final points (4, 5) and (4, −7) are different
✓ 1
Common error: Apply the transformations in the order stated: the second one acts on the image from the first, not on the original point.
53IGMC3-7-09r13-14Reflections, rotations, translations and enlargements described in wordsPaper CMedium6 marks
No calculator
A hospital theatre plan uses a grid. A triangular marker has vertices A(3, 1), B(5, 1) and C(5, 4). It is rotated through 90° anticlockwise about the point (2, 1).
(a)
Write down the coordinates of the image of each vertex.
(3)
(b)
Describe fully the single transformation that maps A′B′C′ back onto ABC.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 a vertex rotated correctly about (2, 1)
✓ 1
A1 A′(2, 2) and B′(2, 4)
✓ 1
A1 C′(−1, 4)
✓ 1
Part (b)
B1 rotation
✓ 1
B1 90° clockwise (or 270° anticlockwise)
✓ 1
B1 centre (2, 1)
✓ 1
Exam tip: For a rotation about a point that is not the origin, find each vertex's position relative to the centre, rotate that, then add the centre back.
54IGMC3-7-10r13-03Reflections, rotations, translations and enlargements described in wordsPaper CMedium4 marks
No calculator
A pharmacy laboratory plan uses a grid with 1 unit = 1 cm. A triangular bench has vertices (2, 1), (2, 3) and (3, 1). It is enlarged by scale factor 3 with centre (1, −1).
(a)
Find the coordinates of the vertices of the image.
(3)
(b)
Write down the length, in cm, of the image of the side from (2, 1) to (2, 3).
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 multiplies the distances from (1, −1) by 3
✓ 1
A1 two vertices correct
✓ 1
A1 (4, 5), (4, 11) and (7, 5)
✓ 1
Part (b)
B1 6 cm
✓ 1
Common error: When the centre is not the origin, multiply the distance from the centre, not the coordinates themselves.
55IGMC3-7-10r13-04Reflections, rotations, translations and enlargements described in wordsPaper CMedium5 marks
No calculator
A game level uses a grid. Shape A has vertices (1, 1), (3, 1) and (3, 2). Shape B has vertices (−1, 1), (−1, 3) and (−2, 3).
(a)
Describe fully the single transformation that maps A onto B.
(3)
(b)
A is rotated 90° anticlockwise about the origin, and the image is rotated 90° anticlockwise about the origin again. Describe fully the single transformation that maps A onto the final image.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 rotation
✓ 1
B1 90° anticlockwise
✓ 1
B1 about the origin (0, 0)
✓ 1
Part (b)
B1 rotation of 180°
✓ 1
B1 about the origin (0, 0)
✓ 1
Exam tip: A rotation needs three details: the word rotation, the angle with its direction, and the centre.
56IGMC3-7-10r13-05Vectors, magnitude and vector geometryPaper CMedium4 marks
No calculator
A water pipeline runs from A to B to C. The displacement from A to B is \(\overrightarrow{AB}=\)\(\begin{pmatrix}4\\-3\end{pmatrix}\) and from B to C is \(\overrightarrow{BC}=\)\(\begin{pmatrix}-1\\6\end{pmatrix}\) (in km). A has coordinates (−2, 5).
(a)
Write down \(\overrightarrow{AC}\) as a column vector.
(1)
(b)
Work out \(2\overrightarrow{AB}-\overrightarrow{BC}\).
(2)
(c)
Find the coordinates of C.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 \(\begin{pmatrix}3\\3\end{pmatrix}\)
✓ 1
Part (b)
M1 \(\begin{pmatrix}8\\-6\end{pmatrix}\) found
✓ 1
A1 \(\begin{pmatrix}9\\-12\end{pmatrix}\)
✓ 1
Part (c)
B1 (1, 8)
✓ 1
Common error: Add the vector from A to C to the coordinates of A to reach C; do not subtract it.
57IGMC3-7-10r13-06Reflections, rotations, translations and enlargements described in wordsPaper CMedium4 marks
No calculator
A pill-sorting robot works on a grid. A triangular marker T has vertices (1, 0), (3, 0) and (3, 1).
(a)
T is reflected in the line y = 2. Write down the vertices of the image.
(2)
(b)
The image from (a) is enlarged by scale factor 2 with centre the origin. Write down the vertices of the new image.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 reflects at least one vertex in y = 2
✓ 1
A1 (1, 4), (3, 4), (3, 3)
✓ 1
Part (b)
M1 doubles at least one coordinate pair
✓ 1
A1 (2, 8), (6, 8), (6, 6)
✓ 1
Exam tip: Write down the vertices after each transformation, so a slip in the first step does not hide correct work in the second.
58IGMC3-7-10r13-14Reflections, rotations, translations and enlargements described in wordsPaper CMedium4 marks
No calculator
A microscope-slide grid shows triangle X with vertices (2, 2), (4, 2) and (4, 3). Its image Y under an enlargement has vertices (2, 2), (8, 2) and (8, 5).
(a)
Describe fully the enlargement that maps X onto Y.
(3)
(b)
Find the image of the point (3, 4) under the same enlargement.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 enlargement
✓ 1
B1 scale factor 3
✓ 1
B1 centre (2, 2)
✓ 1
Part (b)
B1 (5, 8)
✓ 1
Exam tip: A point that does not move under an enlargement is the centre, so look for a vertex shared by the shape and its image.
59IGMC3-7-10r17-06Reflections, rotations, translations and enlargements described in wordsPaper CMedium5 marks
Calculator
A triangular tent footprint on a site plan has corners A(2, 2), B(4, 2) and C(4, 5). It is enlarged with scale factor 2 and centre (1, 1) to give triangle A′B′C′.
(a)
Find the coordinates of A′, B′ and C′.
(3)
(b)
Work out the area of triangle A′B′C′.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 uses the position of each corner relative to the centre, for example A is (1, 1) from the centre
✓ 1
A1 A′ (3, 3) and B′ (7, 3)
✓ 1
A1 C′ (7, 9)
✓ 1
Part (b)
M1 area of ABC = 1/2 × 2 × 3 = 3 and area scale factor 22
✓ 1
A1 12 square units
✓ 1
Common error: Measuring from the origin instead of from the centre of enlargement, which gives the wrong image points.
60IGMC3-7-10r17-08Reflections, rotations, translations and enlargements described in wordsPaper CMedium5 marks
No calculator
A survey triangle has corners P(−4, 1), Q(−1, 1) and R(−1, 3).
(a)
The triangle is reflected in the line y = x. Write down the coordinates of the three corners of the image.
(2)
(b)
Another image of PQR has corners (−4, −1), (−1, −1) and (−1, −3). Describe fully the single transformation.
(2)
(c)
A point is reflected in the line y = x and its image is (7, −2). Write down the coordinates of the original point.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 (1, −4) and (1, −1)
✓ 1
B1 (3, −1)
✓ 1
Part (b)
B1 reflection
✓ 1
B1 in the x-axis (the line y = 0)
✓ 1
Part (c)
B1 (−2, 7)
✓ 1
Common error: For a reflection in y = x the coordinates swap places and keep their signs. Do not change the signs.
61IGMC3-7-10r17-13Reflections, rotations, translations and enlargements described in wordsPaper CMedium5 marks
No calculator
On a mosaic floor plan, triangle M has corners (1, 1), (4, 1) and (1, 4). Its image N has corners (3, 0), (9, 0) and (3, 6).
(a)
Describe fully the single transformation that maps M onto N.
(3)
(b)
Work out the area of triangle N.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 enlargement
✓ 1
B1 scale factor 2
✓ 1
B1 centre (−1, 2)
✓ 1
Part (b)
M1 area of M = 1/2 × 3 × 3 = 4.5, then × 22 (or 1/2 × 6 × 6)
✓ 1
A1 18 square units
✓ 1
Exam tip: Find the scale factor from corresponding lengths. Then find the centre where lines through corresponding corners meet.
62IGMC3-7-10r19-05Reflections, rotations, translations and enlargements described in wordsPaper CMedium5 marks
No calculator
A harbour plan shows four berths as a quadrilateral Q with vertices (2, 1), (5, 1), (5, 3) and (3, 3).
(a)
Q is reflected in the line \(y=x\). Write down the coordinates of the four images.
(2)
(b)
Describe fully the single transformation that maps Q onto the quadrilateral with vertices (−2, −1), (−5, −1), (−5, −3) and (−3, −3).
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 at least two images correct
✓ 1
B1 all four correct: (1, 2), (1, 5), (3, 5), (3, 3)
✓ 1
Part (b)
B1 rotation
✓ 1
B1 180° (half-turn)
✓ 1
B1 centre (0, 0)
✓ 1
Common error: When reflecting in \(y=x\), the coordinates swap; reflecting in \(y=-x\) swaps them and changes both signs.
63IGMC3-7-10r19-06Reflections, rotations, translations and enlargements described in wordsPaper CMedium7 marks
No calculator
An architect draws a roof plan with triangle ABC, where A(2, 2), B(4, 2) and C(4, 3). Triangle ABC is mapped onto triangle A′B′C′ with A′(3, 3), B′(7, 3) and C′(7, 5) by a single enlargement.
(a)
Describe fully this enlargement.
(3)
(b)
The same enlargement maps the point P(5, 4) onto P′. Find the coordinates of P′.
(2)
(c)
Calculate the area of triangle A′B′C′.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 enlargement
✓ 1
B1 scale factor 2
✓ 1
B1 centre (1, 1)
✓ 1
Part (b)
M1 vector from the centre to P is \((4, 3)\), multiplied by 2
✓ 1
A1 (9, 7)
✓ 1
Part (c)
M1 \(\frac{1}{2}\times4\times2\)
✓ 1
A1 4 square units
✓ 1
Exam tip: To find the centre of an enlargement, draw lines through corresponding vertices; they meet at the centre.
64IGMC3-7-10r19-07Reflections, rotations, translations and enlargements described in wordsPaper CMedium5 marks
No calculator
Four sensor buoys form triangle ABC on a grid of a marine reserve, with A(3, 1), B(3, 4) and C(5, 1). Triangle ABC is mapped onto triangle A′B′C′ by a single rotation, where A′ = (1, −1), B′ = (4, −1) and C′ = (1, −3).
(a)
Describe fully this rotation.
(3)
(b)
Triangle ABC is also rotated through 180° about the point (2, 2). Find the coordinates of the image of B.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 rotation
✓ 1
B1 90° clockwise
✓ 1
B1 centre (1, 1)
✓ 1
Part (b)
M1 vector from (2, 2) to B is \((1, 2)\), reversed to \((-1,-2)\)
✓ 1
A1 (1, 0)
✓ 1
Common error: A 90° rotation is not the same as a reflection: check that the orientation (clockwise or anticlockwise) of the labelled vertices has turned, not flipped.
65IGMC3-7-10r19-08Reflections, rotations, translations and enlargements described in wordsPaper CMedium7 marks
No calculator
Coral plots in a reef survey are marked by triangle ABC with A(−3, 2), B(−1, 2) and C(−1, 5). Triangle ABC is reflected in the line \(y=-1\) to give triangle A′B′C′. Triangle A′B′C′ is then reflected in the y-axis to give triangle A″B″C″.
(a)
Write down the coordinates of A′, B′ and C′.
(2)
(b)
Write down the coordinates of A″, B″ and C″.
(2)
(c)
Describe fully the single transformation that maps triangle ABC onto triangle A″B″C″.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 at least two images correct
✓ 1
B1 all three correct: A′ = (−3, −4), B′ = (−1, −4), C′ = (−1, −7)
✓ 1
Part (b)
B1 at least two images correct (ECF from (a))
✓ 1
B1 all three correct: A″ = (3, −4), B″ = (1, −4), C″ = (1, −7)
✓ 1
Part (c)
B1 rotation
✓ 1
B1 180° (half-turn)
✓ 1
B1 centre (0, −1)
✓ 1
Model sketch
Exam tip: Check a combined transformation by tracking one vertex through every step, then test your proposed single transformation on that vertex.
66IGMC3-7-10r24-04Reflections, rotations, translations and enlargements described in wordsPaper CMedium4 marks
No calculator
A pharmacy design uses a rectangle R with vertices (1, 1), (3, 1), (3, 2) and (1, 2). Rectangle S is the image of R after an enlargement with scale factor 3 and centre the origin.
(a)
Write down the coordinates of the vertices of S.
(2)
(b)
Work out the area of S divided by the area of R.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 (3, 3) and (9, 3)
✓ 1
B1 (9, 6) and (3, 6)
✓ 1
Part (b)
M1 area of R = 2 and area of S = 6 × 3 = 18, using the vertices from (a)
✓ 1
A1 9
✓ 1
Common error: Area scales by the square of the scale factor, so it is multiplied by 9 here, not by 3.
67IGMC3-7-10r24-05Reflections, rotations, translations and enlargements described in wordsPaper CMedium6 marks
No calculator
On a gaming screen, triangle T has vertices (1, 1), (2, 1) and (2, 3). Triangle U has vertices (1, 2), (3, 2) and (3, 6).
(a)
Describe fully the single transformation that maps T onto U.
(3)
(b)
Describe fully the single transformation that maps U onto T.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 enlargement
✓ 1
B1 scale factor 2
✓ 1
B1 centre (1, 0)
✓ 1
Part (b)
B1 enlargement
✓ 1
B1 scale factor \(\frac{1}{2}\) (ECF from (a))
✓ 1
B1 centre (1, 0)
✓ 1
Exam tip: To find the centre of an enlargement, draw lines through matching vertices; they meet at the centre. Here (1, 1) to (1, 2) and (2, 1) to (3, 2) meet at (1, 0).
68IGMC3-7-10r24-06Reflections, rotations, translations and enlargements described in wordsPaper CMedium6 marks
No calculator
Triangle ABC has vertices A(2, 1), B(5, 1) and C(5, 3). It is reflected in the y-axis to give triangle A′B′C′. Triangle A′B′C′ is then rotated 90° clockwise about the origin to give triangle A″B″C″.
(a)
Write down the coordinates of A′, B′ and C′.
(2)
(b)
Write down the coordinates of A″, B″ and C″.
(2)
(c)
Describe fully the single transformation that maps ABC onto A″B″C″.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 A′(−2, 1) and B′(−5, 1)
✓ 1
B1 C′(−5, 3)
✓ 1
Part (b)
B1 A″(1, 2) and B″(1, 5) (ECF from (a))
✓ 1
B1 C″(3, 5)
✓ 1
Part (c)
B1 reflection
✓ 1
B1 in the line \(y = x\)
✓ 1
Model sketch
Common error: A rotation of 90° clockwise about the origin sends (x, y) to (y, −x); check one vertex before writing the others.
69IGMC3-7-10r24-07Vectors, magnitude and vector geometryPaper CMedium6 marks
No calculator
Let \(\mathbf{p} = \begin{pmatrix}2\\-1\end{pmatrix}\) and \(\mathbf{q} = \begin{pmatrix}-3\\4\end{pmatrix}\).
(a)
Work out \(2\mathbf{p} + \mathbf{q}\).
(2)
(b)
Work out \(\mathbf{p} - 3\mathbf{q}\).
(2)
(c)
A water pipe runs from A(−2, 5) to B. The vector \(\overrightarrow{AB}\) is \(\begin{pmatrix}7\\-3\end{pmatrix}\). Find the coordinates of B.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 \(\begin{pmatrix}4\\-2\end{pmatrix}\) + \(\begin{pmatrix}-3\\4\end{pmatrix}\) or one correct component
✓ 1
A1 \(\begin{pmatrix}1\\2\end{pmatrix}\)
✓ 1
Part (b)
M1 \(\begin{pmatrix}2\\-1\end{pmatrix}\) − \(\begin{pmatrix}-9\\12\end{pmatrix}\) or one correct component
✓ 1
A1 \(\begin{pmatrix}11\\-13\end{pmatrix}\)
✓ 1
Part (c)
M1 (−2 + 7, 5 − 3)
✓ 1
A1 (5, 2)
✓ 1
Common error: When subtracting a vector, change the sign of both components: \(-3\mathbf{q}\) gives \(+9\) and \(-12\).
70IGMC3-7-10r24-14Reflections, rotations, translations and enlargements described in wordsPaper CMedium6 marks
No calculator
Triangle K has vertices (1, 2), (3, 2) and (3, 5). It is rotated 90° anticlockwise about the point (1, 0) to give triangle L.
(a)
Find the coordinates of the vertices of L.
(3)
(b)
Describe fully the single transformation that maps L onto K.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 attempt at a 90° anticlockwise turn about (1, 0), e.g. relative positions (0, 2) become (−2, 0)
✓ 1
A1 (−1, 0) and (−1, 2)
✓ 1
A1 (−4, 2)
✓ 1
Part (b)
B1 rotation
✓ 1
B1 90° clockwise
✓ 1
B1 about (1, 0)
✓ 1
Exam tip: For a rotation about a point that is not the origin, measure each vertex relative to the centre, turn that vector, then add the centre back.
71IGMC3-7-10r39-05Reflections, rotations, translations and enlargements described in wordsPaper CMedium7 marks
No calculator
At a cycling race, triangular flags are drawn on a grid with coordinates (x, y) in units of 1 m. Triangle A has vertices (2, 2), (4, 2) and (2, 3). Triangle B has vertices (3, 4), (7, 4) and (3, 6).
(a)
Describe fully the single transformation that maps A onto B.
(3)
(b)
Work out the area of triangle B, in square units.
(2)
(c)
Triangle C is the image of A after an enlargement with scale factor 3 and centre (0, 0). Write down the coordinates of the vertex of C that is the image of (4, 2).
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 enlargement
✓ 1
B1 scale factor 2
✓ 1
B1 centre (1, 0)
✓ 1
Part (b)
M1 ½ × 4 × 2
✓ 1
A1 4
✓ 1
Part (c)
B1 12
✓ 1
B1 6, so (12, 6)
✓ 1
Exam tip: To find the centre of an enlargement, draw lines through matching corners of the two shapes. The centre is where they meet.
72IGMC3-7-10r39-06Vectors, magnitude and vector geometryPaper CMedium6 marks
No calculator
A cyclist's route is described using column vectors, with distances in kilometres. a = \(\begin{pmatrix}3\\-2\end{pmatrix}\) and b = \(\begin{pmatrix}-1\\4\end{pmatrix}\).
(a)
Work out a + b.
(2)
(b)
Work out 2a − 3b.
(2)
(c)
The cyclist starts at the point P(−2, 5) and is moved by the translation 2a + b. Find the coordinates of the finishing point.
Common error: When subtracting a vector that has a negative entry, remember that subtracting a negative gives a positive: 3 × (−1) = −3, so 6 − (−3) = 9 in the top row.
73IGMC3-7-10r39-07Reflections, rotations, translations and enlargements described in wordsPaper CMedium6 marks
No calculator
On the plan of an archaeological trench, triangle PQR has vertices P(1, 2), Q(4, 2) and R(4, 5).
(a)
Triangle PQR is reflected in the line y = x to give triangle P′Q′R′. Write down the coordinates of P′, Q′ and R′.
(3)
(b)
Triangle P′Q′R′ is then translated by \(\begin{pmatrix}-1\\3\end{pmatrix}\) to give triangle P″Q″R″. Write down the coordinates of P″, Q″ and R″.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 P′(2, 1)
✓ 1
B1 Q′(2, 4)
✓ 1
B1 R′(5, 4)
✓ 1
Part (b)
B1 P″(1, 4)
✓ 1
B1 Q″(1, 7)
✓ 1
B1 R″(4, 7)
✓ 1
(ECF from (a))
—
Model sketch
Exam tip: Reflection in y = x swaps the x- and y-coordinates of every point.
74IGMC3-7-10r39-08Reflections, rotations, translations and enlargements described in wordsPaper CMedium9 marks
No calculator
Tiles on a cycling training track are laid out on a grid with coordinates (x, y). Triangle A has vertices (1, 1), (3, 1) and (3, 2). Other triangles have these vertices: B: (−1, 1), (−3, 1), (−3, 2) C: (1, −1), (3, −1), (3, −2) D: (4, 2), (6, 2), (6, 3) E: (−1, −1), (−3, −1), (−3, −2)
(a)
Describe fully the single transformation that maps A onto B.
(2)
(b)
Describe fully the single transformation that maps A onto C.
(2)
(c)
Describe fully the single transformation that maps A onto D.
(2)
(d)
Describe fully the single transformation that maps A onto E.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 reflection
✓ 1
B1 in the y-axis (accept the line x = 0)
✓ 1
Part (b)
B1 reflection
✓ 1
B1 in the x-axis (accept the line y = 0)
✓ 1
Part (c)
B1 translation
✓ 1
B1 vector \(\begin{pmatrix}3\\1\end{pmatrix}\)
✓ 1
Part (d)
B1 rotation
✓ 1
B1 180°
✓ 1
B1 centre (0, 0)
✓ 1
(accept enlargement, scale factor −1, centre (0, 0), for full marks)
—
Common error: A reflection needs its mirror line stated, a rotation needs an angle, direction (unless 180°) and centre, and an enlargement needs a scale factor and centre.
75IGMC3-7-12r41-05Reflections, rotations, translations and enlargements described in wordsPaper CMedium5 marks
Calculator
A pharmacist's tray design is a triangle ABC with A(1, 1), B(3, 1) and C(3, 2), measured in cm. It is enlarged to give triangle A'B'C' with A'(3, −1), B'(7, −1) and C'(7, 1).
(a)
Describe fully the single transformation that maps ABC onto A'B'C'.
(3)
(b)
Calculate the area of triangle A'B'C'.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 enlargement
✓ 1
B1 scale factor 2
✓ 1
B1 centre (−1, 3)
✓ 1
Part (b)
M1 ½ × 4 × 2 (base 4 and height 2)
✓ 1
A1 4 cm2
✓ 1
Exam tip: To find the centre of an enlargement, draw lines through corresponding vertices; they meet at the centre.
76IGMC3-7-12r41-06Reflections, rotations, translations and enlargements described in wordsPaper CMedium5 marks
No calculator
The point P(3, 4) marks a valve on a water supply map. P is rotated 90° anticlockwise about the origin to give P'. Then P' is translated by the vector (5, −7) to give Q.
(a)
Find the coordinates of P'.
(1)
(b)
Find the coordinates of Q.
(2)
(c)
Q is reflected in a mirror line to give R(1, 2). Find the equation of the mirror line.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 (−4, 3)
✓ 1
Part (b)
M1 (−4 + 5, 3 − 7)
✓ 1
A1 (1, −4)
✓ 1
Part (c)
M1 the line is horizontal (midway in the y-direction)
✓ 1
A1 y = −1
✓ 1
Common error: A 90° anticlockwise rotation about the origin sends (x, y) to (−y, x); a clockwise turn sends it to (y, −x).
77IGMC3-7-12r41-07Reflections, rotations, translations and enlargements described in wordsPaper CMedium6 marks
Calculator
In a game, the point Z is rotated 90° anticlockwise about the centre M(2, 1) and its image is the point W(5, 3).
(a)
Find the coordinates of the image of the point W when it is rotated 90° anticlockwise about M.
(2)
(b)
Find the coordinates of Z.
(2)
(c)
Calculate the distance MZ. Give your answer correct to 3 significant figures.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 vector from M to W is (3, 2)
✓ 1
A1 rotated vector (−2, 3), so the image is (0, 4)
✓ 1
Part (b)
M1 reverses the turn, so rotates the vector from M to W by 90° clockwise: (3, 2) to (2, −3)
✓ 1
A1 Z = (4, −2)
✓ 1
Part (c)
M1 √(22 + 32) (ECF from (b))
✓ 1
A1 3.61
✓ 1
Exam tip: Check a rotation by confirming that the object and the image are the same distance from the centre.
78IGMC3-7-12r41-14Reflections, rotations, translations and enlargements described in wordsPaper CMedium6 marks
No calculator
Answer these questions about transformations on a coordinate grid.
(a)
A reflection maps the point (−1, 3) onto the point (5, 3). Describe fully this reflection.
(2)
(b)
Write down the coordinates of the image of (2, −5) after reflection in the line y = x.
(1)
(c)
The point (3, 4) is reflected in the x-axis and the image is then reflected in the y-axis. Write down the coordinates of the final image.
(1)
(d)
Describe fully the single transformation equivalent to the two reflections in part (c).
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 reflection
✓ 1
B1 in the line x = 2
✓ 1
Part (b)
B1 (−5, 2)
✓ 1
Part (c)
B1 (−3, −4)
✓ 1
Part (d)
B1 rotation of 180° (a half turn)
✓ 1
B1 centre (0, 0)
✓ 1
Common error: The mirror line for a reflection lies exactly halfway between an object point and its image, so find the midpoint of the two points.
79IGMC3-7-11r42-04Reflections, rotations, translations and enlargements described in wordsPaper CMedium7 marks
Calculator
An architect makes a scale plan of a courtyard as rectangle ABCD with A(2, 1), B(6, 1), C(6, 3) and D(2, 3).
(a)
The rectangle is enlarged with scale factor 3 and centre the origin. Find the coordinates of the image of C.
(2)
(b)
The rectangle is now enlarged with scale factor 2 and centre A. Find the coordinates of the image of C.
(3)
(c)
Calculate the perimeter of the image of ABCD in part (a).
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 Multiply each coordinate of C by 3
✓ 1
A1 (18, 9)
✓ 1
Part (b)
M1 Vector from A to C is (4, 2)
✓ 1
M1 Image position is A + 2(4, 2)
✓ 1
A1 (10, 5)
✓ 1
Part (c)
M1 Perimeter of ABCD = 12 (or sides 12 and 6 found)
✓ 1
A1 36
✓ 1
Exam tip: Under an enlargement every length is multiplied by the scale factor, so the perimeter of the image is the scale factor times the original perimeter.
80IGMC3-7-11r42-05Reflections, rotations, translations and enlargements described in wordsPaper CMedium6 marks
Calculator
A marine survey uses triangle T with vertices (1, 1), (3, 1) and (3, 4) to mark a patch of coral on a coordinate grid. T is reflected in the x-axis to give triangle T1. T1 is then translated by \(\begin{pmatrix}-4\\6\end{pmatrix}\) to give triangle T2.
(a)
Write down the coordinates of the vertices of T1.
(2)
(b)
Write down the coordinates of the vertices of T2.
(2)
(c)
T2 is mapped onto T1 by a single translation. Write down its column vector.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 y-coordinates change sign
✓ 1
A1 (1, −1), (3, −1), (3, −4)
✓ 1
Part (b)
M1 Add (−4, 6) to coordinates of T1 (ECF from (a))
✓ 1
A1 (−3, 5), (−1, 5), (−1, 2)
✓ 1
Part (c)
M1 Subtract: (1, −1) − (−3, 5), or reverse of \(\begin{pmatrix}-4\\6\end{pmatrix}\)
✓ 1
A1 \(\begin{pmatrix}4\\-6\end{pmatrix}\)
✓ 1
Model sketch
Common error: The reverse of a translation uses the negative of each component, so the reverse of \(\begin{pmatrix}-4\\6\end{pmatrix}\) is \(\begin{pmatrix}4\\-6\end{pmatrix}\).
81IGMC3-7-11r42-09Reflections, rotations, translations and enlargements described in wordsPaper CMedium6 marks
No calculator
A diver's marker buoy P is at (5, 3) on a grid of the seabed, where 1 unit is 1 m. A mooring point M is at (2, 1).
(a)
P is rotated through 90° clockwise about M. Find the coordinates of the image of P.
(2)
(b)
P is rotated through 180° about M. Find the coordinates of the image of P.
(2)
(c)
Write down the column vector of the translation that maps the image in (a) onto the image in (b).
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 Vector from M to P is (3, 2); clockwise quarter turn gives (2, −3) (or equivalent)
✓ 1
A1 (4, −2)
✓ 1
Part (b)
M1 Image is M − (3, 2) (or midpoint method)
✓ 1
A1 (−1, −1)
✓ 1
Part (c)
M1 (−1 − 4) and (−1 − (−2)) (ECF from (a), (b))
✓ 1
A1 \(\begin{pmatrix}-5\\1\end{pmatrix}\)
✓ 1
Exam tip: For a rotation about a point other than the origin, work with the vector from the centre to the point, turn that, and then add the centre back.
82IGMC3-7-11r42-12Reflections, rotations, translations and enlargements described in wordsPaper CMedium6 marks
Calculator
A logistics planner models three loading bays as triangle T with vertices (−4, 1), (−1, 1) and (−1, 3).
(a)
T is reflected in the line y = −1. Write down the coordinates of the vertices of the image.
(2)
(b)
T is mapped onto the triangle with vertices (6, 1), (3, 1) and (3, 3) by a single reflection. Describe fully this reflection.
(2)
(c)
Using the reflection in part (b) followed by a reflection in the x-axis, find the image of the point (0, 5).
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 Each point moves to the same distance on the other side of y = −1 (y′ = −2 − y)
✓ 1
A1 (−4, −3), (−1, −3), (−1, −5)
✓ 1
Part (b)
B1 Reflection
✓ 1
B1 in the line x = 1
✓ 1
Part (c)
M1 Reflection in x = 1 gives (2, 5) (ECF from (b))
✓ 1
A1 (2, −5)
✓ 1
Common error: The mirror line for a reflection is halfway between an object point and its image, so for x = −4 and x = 6 the line is x = 1, not x = 2.
83IGMC3-7-04d-11Reflections, rotations, translations and enlargements described in wordsPaper CHard8 marks
No calculator
On a coordinate grid, triangle PQR has P = (4, 2), Q = (6, 2) and R = (6, 3). It is rotated through 90° clockwise about the point (1, 0) to give triangle P′Q′R′.
(a)
Find the coordinates of P′, Q′ and R′.
(4)
(b)
Triangle P′Q′R′ is translated so that P′ moves to the origin. Write down the translation vector.
(1)
(c)
Write down the coordinates of the image of R′ after this translation.
(1)
(d)
The area of triangle PQR is 1 square unit. Write down the area of the final triangle and give a reason.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 subtracts the centre, e.g. P is (3, 2) from the centre
✓ 1
M1 turns each vector 90° clockwise, (x, y) → (y, −x), e.g. (2, −3)
✓ 1
M1 adds the centre back
✓ 1
A1 (3, −3), (3, −5), (4, −5)
✓ 1
Part (b)
B1 \(\begin{pmatrix}-3\\3\end{pmatrix}\)
✓ 1
Part (c)
B1 (1, −2) (ECF from (a) and (b))
✓ 1
Part (d)
B1 1 square unit
✓ 1
B1 rotation and translation do not change size (the triangles are congruent)
✓ 1
Model sketch
Exam tip: To rotate about a point other than the origin, shift the picture so the centre sits at the origin, rotate, then shift back.
84IGMC3-7-10r13-13Reflections, rotations, translations and enlargements described in wordsPaper CHard6 marks
No calculator
A puzzle game uses a grid. A triangle has vertices A(1, 1), B(3, 1) and C(3, 2). It is rotated through 90° clockwise about the point (2, 2), giving A′, B′ and C′.
(a)
Write down the coordinates of A′, B′ and C′.
(3)
(b)
The triangle A′B′C′ is translated so that A′ moves to (6, 1). Write down the column vector of this translation.
(1)
(c)
Find the coordinates of the images of B′ and C′ after this translation.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 a vertex rotated correctly about (2, 2)
✓ 1
A1 two vertices correct
✓ 1
A1 A′(1, 3), B′(1, 1), C′(2, 1)
✓ 1
Part (b)
B1 \(\begin{pmatrix}5\\-2\end{pmatrix}\)
✓ 1
Part (c)
B1 (6, −1)
✓ 1
B1 (7, −1)
✓ 1
Model sketch
Common error: Rotating about (2, 2) is not the same as rotating about the origin; measure each vertex from the centre first.
85IGMC3-7-10r39-09Reflections, rotations, translations and enlargements described in wordsPaper CHard8 marks
No calculator
On a grid of 1 m squares, triangle PQR has vertices P(4, 1), Q(4, 3) and R(5, 1).
(a)
Triangle PQR is rotated through 90° anticlockwise about the point C(2, 1) to give triangle P′Q′R′. Write down the coordinates of P′, Q′ and R′.
(3)
(b)
Triangle P′Q′R′ is reflected in the line y = 3 to give triangle P″Q″R″. Write down the coordinates of P″, Q″ and R″.
(3)
(c)
Triangle P″Q″R″ is enlarged with scale factor 2 and centre (2, 3). Find the coordinates of the image of R″.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 P′(2, 3)
✓ 1
B1 Q′(0, 3)
✓ 1
B1 R′(2, 4)
✓ 1
Part (b)
B1 P″(2, 3)
✓ 1
B1 Q″(0, 3)
✓ 1
B1 R″(2, 2)
✓ 1
(ECF from (a))
—
Part (c)
M1 R″ is 1 unit below the centre, so the image is 2 units below the centre
✓ 1
A1 (2, 1)
✓ 1
(ECF from (b))
—
Model sketch
Exam tip: For a rotation about a point that is not the origin, work with the position of each vertex relative to the centre, turn that, then add the centre back.
86IGMC-047-01-01Vectors, magnitude and vector geometryPaper EEasy4 marks
No calculator
\(\mathbf{a}=\begin{pmatrix}3\\-4\end{pmatrix}\) and \(\mathbf{b}=\begin{pmatrix}-1\\2\end{pmatrix}\).
(a)
Find \(2\mathbf{a}-3\mathbf{b}\) as a column vector.
(2)
(b)
Find \(|\mathbf{a}|\).
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1: \(2\mathbf{a}=\begin{pmatrix}6\\-8\end{pmatrix}\) and \(3\mathbf{b}=\begin{pmatrix}-3\\6\end{pmatrix}\) seen, or one component correct
✓ 1
A1: \(\begin{pmatrix}9\\-14\end{pmatrix}\)
✓ 1
Part (b)
M1: \(\sqrt{3^2+(-4)^2}\)
✓ 1
A1: 5
✓ 1
Common error: Subtracting a negative component: \(-3\times(-1)=+3\), so the top entry is \(6+3=9\), not \(6-3\).
87IGMC-047-01-02Vectors, magnitude and vector geometryPaper EEasy4 marks
Calculator
\(\mathbf{p}=\begin{pmatrix}7\\-2\end{pmatrix}\) and \(\mathbf{p}+\mathbf{q}=\begin{pmatrix}2\\5\end{pmatrix}\).
(a)
Find \(\mathbf{q}\) as a column vector.
(2)
(b)
Find \(|\mathbf{p}|\), giving your answer correct to 3 significant figures.
Exam tip: Squaring a negative component always gives a positive value, so the magnitude is never smaller because of a minus sign.
88IGMC-047-01-03Vectors, magnitude and vector geometryPaper EEasy4 marks
No calculator
A is the point (2, 5) and B is the point (−4, 1).
Diagram not to scale
(a)
Write \(\overrightarrow{AB}\) as a column vector.
(1)
(b)
\(\overrightarrow{AC}=\begin{pmatrix}3\\-2\end{pmatrix}\). Find the coordinates of C.
(1)
(c)
Find \(|\overrightarrow{AB}|\), giving your answer in the form \(k\sqrt{13}\).
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1: \(\begin{pmatrix}-6\\-4\end{pmatrix}\)
✓ 1
Part (b)
B1: (5, 3)
✓ 1
Part (c)
M1: \(\sqrt{(-6)^2+(-4)^2}=\sqrt{52}\)
✓ 1
A1: \(2\sqrt{13}\)
✓ 1
Common error: \(\overrightarrow{AB}\) is B minus A, not A minus B. Reversing the order gives the right length but the wrong direction.
89IGMC-047-01-04Vectors, magnitude and vector geometryPaper EEasy3 marks
No calculator
\(\mathbf{a}=\begin{pmatrix}6\\-9\end{pmatrix}\).
(a)
Show that \(\mathbf{c}=\begin{pmatrix}-4\\6\end{pmatrix}\) is parallel to \(\mathbf{a}\).
(1)
(b)
\(\mathbf{b}=\begin{pmatrix}k\\3\end{pmatrix}\) is parallel to \(\mathbf{a}\). Find the value of \(k\).
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1: \(\mathbf{c}=-\frac{2}{3}\mathbf{a}\) (or \(\mathbf{a}=-\frac{3}{2}\mathbf{c}\)) stated, so c is a multiple of a
✓ 1
Part (b)
M1: \(\mathbf{b}=-\frac{1}{3}\mathbf{a}\) or \(\frac{k}{6}=\frac{3}{-9}\)
✓ 1
A1: \(k=-2\)
✓ 1
Exam tip: Two vectors are parallel when one is a scalar multiple of the other; the scalar may be negative or a fraction.
90IGMC-047-01-05Vectors, magnitude and vector geometryPaper EEasy4 marks
No calculator
Answer both parts without a calculator.
(a)
Find the magnitude of \(\begin{pmatrix}-8\\15\end{pmatrix}\).
(2)
(b)
The vector \(\begin{pmatrix}p\\12\end{pmatrix}\) has magnitude 13 and \(p>0\). Find \(p\).
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1: \(\sqrt{64+225}=\sqrt{289}\)
✓ 1
A1: 17
✓ 1
Part (b)
M1: \(p^2+144=169\)
✓ 1
A1: \(p=5\)
✓ 1
Common error: Writing \(p+12=13\) is wrong: magnitudes combine through squares, so form \(p^2+12^2=13^2\).
91IGMC3-7-04d-05Vectors, magnitude and vector geometryPaper EEasy5 marks
Calculator
A survey drone makes two flights. The first has displacement u = \(\begin{pmatrix}5\\-2\end{pmatrix}\) km and the second has displacement v = \(\begin{pmatrix}-1\\6\end{pmatrix}\) km, where the top number is the distance east and the bottom number is the distance north.
(a)
Find u + v, the total displacement.
(1)
(b)
Find 3u − 2v.
(2)
(c)
Calculate the magnitude of u. Give your answer correct to 3 significant figures.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 \(\begin{pmatrix}4\\4\end{pmatrix}\)
✓ 1
Part (b)
M1 \(\begin{pmatrix}15\\-6\end{pmatrix}\) − \(\begin{pmatrix}-2\\12\end{pmatrix}\) (at least one correct product)
✓ 1
A1 \(\begin{pmatrix}17\\-18\end{pmatrix}\)
✓ 1
Part (c)
M1 √(52 + (−2)2) = √29
✓ 1
A1 5.39 km
✓ 1
Common error: The magnitude of a vector is a length, so it is never negative. Square each component, including a negative one, before adding.
92IGMC3-7-10r13-11Vectors, magnitude and vector geometryPaper EEasy4 marks
No calculator
In a game, a player stands at A(−2, 3) and an enemy stands at B(10, −2), with 1 unit = 1 metre.
Diagram not to scale
(a)
Write down the column vector \(\overrightarrow{AB}\).
(1)
(b)
Calculate the distance AB.
(2)
(c)
The player's weapon has a range of 15 m. Is the enemy within range? Explain.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 \(\begin{pmatrix}12\\-5\end{pmatrix}\)
✓ 1
Part (b)
M1 \(\sqrt{12^2+5^2}\)
✓ 1
A1 13 m
✓ 1
Part (c)
B1 Yes, because 13 m is less than 15 m
✓ 1
Common error: Use the differences in coordinates, B minus A, before squaring; adding the coordinates of the two points gives the wrong distance.
93IGMC-047-00-08Reflections, rotations, translations and enlargements described in wordsPaper EMedium6 marks
No calculator
Triangle A has vertices (2, 2), (4, 2) and (4, 6). Triangle A is enlarged with scale factor \(-\frac{1}{2}\) and centre (0, 0) to give triangle B.
(a)
Find the coordinates of the vertices of triangle B.
(2)
(b)
Describe fully the single transformation that maps triangle B onto triangle A.
(2)
(c)
The area of triangle A is 4 square units. Find the area of triangle B.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
(−1, −1), (−2, −1), (−2, −3)
—
B1 for at least two vertices correct
✓ 1
B1 for all three vertices correct
✓ 1
Part (b)
B1 for enlargement with centre (0, 0)
✓ 1
B1 for scale factor −2
✓ 1
Part (c)
M1 for 4 × \(\left(\frac{1}{2}\right)^2\) or \(\frac{1}{2}\) × 1 × 2 using the vertices of B
✓ 1
A1 for 1 square unit
✓ 1
Common error: A negative scale factor does not give a negative area. The area factor is the square of the scale factor: \((-\frac{1}{2})^2 = \frac{1}{4}\).
94IGMC-047-01-06Vectors, magnitude and vector geometryPaper EMedium6 marks
No calculator
OABC is a parallelogram with vertices in that order. \(\overrightarrow{OA}=\mathbf{a}\) and \(\overrightarrow{OC}=\mathbf{c}\). M is the midpoint of AB. Give each answer in terms of \(\mathbf{a}\) and \(\mathbf{c}\), in its simplest form.
Diagram not to scale
(a)
Find \(\overrightarrow{OB}\).
(1)
(b)
Find \(\overrightarrow{AC}\).
(1)
(c)
Find \(\overrightarrow{OM}\).
(2)
(d)
Find \(\overrightarrow{CM}\).
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1: \(\mathbf{a}+\mathbf{c}\)
✓ 1
Part (b)
B1: \(\mathbf{c}-\mathbf{a}\)
✓ 1
Part (c)
M1: any correct route, e.g. \(\overrightarrow{OA}+\frac{1}{2}\overrightarrow{AB}\) with \(\overrightarrow{AB}=\mathbf{c}\), or \(\overrightarrow{OB}-\frac{1}{2}\mathbf{c}\)
✓ 1
A1: \(\mathbf{a}+\frac{1}{2}\mathbf{c}\)
✓ 1
Part (d)
M1: any correct route, e.g. \(\overrightarrow{CO}+\overrightarrow{OM}=-\mathbf{c}+\mathbf{a}+\frac{1}{2}\mathbf{c}\), or \(\overrightarrow{CB}+\overrightarrow{BM}=\mathbf{a}-\frac{1}{2}\mathbf{c}\)
✓ 1
A1: \(\mathbf{a}-\frac{1}{2}\mathbf{c}\)
✓ 1
Exam tip: In a parallelogram, opposite sides are equal vectors: \(\overrightarrow{AB}=\overrightarrow{OC}=\mathbf{c}\) and \(\overrightarrow{CB}=\overrightarrow{OA}=\mathbf{a}\). Use this to move around the shape.
95IGMC-047-01-07Vectors, magnitude and vector geometryPaper EMedium5 marks
No calculator
In triangle OAB, \(\overrightarrow{OA}=\mathbf{a}\) and \(\overrightarrow{OB}=\mathbf{b}\). P lies on AB such that AP : PB = 1 : 3. Q lies on OB such that OQ : QB = 1 : 3.
Diagram not to scale
(a)
Find \(\overrightarrow{AB}\) in terms of \(\mathbf{a}\) and \(\mathbf{b}\).
(1)
(b)
Find \(\overrightarrow{OP}\) in terms of \(\mathbf{a}\) and \(\mathbf{b}\), in its simplest form.
M1: \(\tan\theta=\frac{3}{6}\), or equivalent such as \(\cos\theta=\frac{6}{\sqrt{45}}\) or \(\sin\theta=\frac{3}{\sqrt{45}}\)
✓ 1
A1: 26.6°
✓ 1
Exam tip: Sketch a quick right-angled triangle from the components: horizontal 6, vertical 3. The angle with the \(x\)-direction then follows from \(\tan\theta=\frac{\text{vertical}}{\text{horizontal}}\).
97IGMC-047-01-09Vectors, magnitude and vector geometryPaper EMedium6 marks
Calculator
O is the origin. A is the point (1, 2) and B is the point (7, 10). P lies on AB such that AP : PB = 3 : 1.
Diagram not to scale
(a)
Write \(\overrightarrow{AB}\) as a column vector.
(1)
(b)
Find \(|\overrightarrow{AB}|\).
(1)
(c)
Find the position vector of P.
(2)
(d)
Find \(|\overrightarrow{OP}|\), giving your answer correct to 3 significant figures.
Common error: \(\frac{3}{4}\overrightarrow{AB}\) is the vector from A to P, not the position of P. Add it to the position vector of A.
98IGMC-047-01-10Vectors, magnitude and vector geometryPaper EMedium5 marks
No calculator
\(\mathbf{a}=\begin{pmatrix}2\\1\end{pmatrix}\) and \(\mathbf{b}=\begin{pmatrix}-1\\3\end{pmatrix}\).
(a)
Find the values of \(m\) and \(n\) such that \(m\mathbf{a}+n\mathbf{b}=\begin{pmatrix}7\\7\end{pmatrix}\).
(4)
(b)
Find \(\left|\begin{pmatrix}7\\7\end{pmatrix}\right|\), giving your answer as a simplified surd.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1: \(2m-n=7\) and \(m+3n=7\) formed
✓ 1
M1: correct method to eliminate one variable, e.g. \(n=2m-7\) substituted to give \(7m-21=7\)
✓ 1
A1: \(m=4\)
✓ 1
A1: \(n=1\)
✓ 1
Part (b)
B1: \(7\sqrt{2}\)
✓ 1
Exam tip: Each row of the column vectors gives one equation. Check your values by substituting back: \(4\mathbf{a}+\mathbf{b}=\begin{pmatrix}7\\7\end{pmatrix}\).
99IGMC-047-01-11Vectors, magnitude and vector geometryPaper EMedium6 marks
Calculator
ABCDEF is a regular hexagon with centre O. \(\overrightarrow{OA}=\mathbf{a}\) and \(\overrightarrow{OB}=\mathbf{b}\).
Diagram not to scale
(a)
Find \(\overrightarrow{AB}\) in terms of \(\mathbf{a}\) and \(\mathbf{b}\).
M1: \(AC^2=6^2+6^2-2\times6\times6\cos120°\) or \(2\times6\sin60°\)
✓ 1
A1: 10.4 cm
✓ 1
Exam tip: A regular hexagon splits into six equilateral triangles about its centre, so every side and every radius has the same length and interior angles are 120°.
100IGMC3-7-04d-09Vectors, magnitude and vector geometryPaper EMedium5 marks
Calculator
Two fishing boats are positioned relative to a harbour O. The position vector of boat A is a = \(\begin{pmatrix}2\\5\end{pmatrix}\) km and the position vector of boat B is b = \(\begin{pmatrix}6\\1\end{pmatrix}\) km.
Diagram not to scale
(a)
Write down the vector \(\overrightarrow{AB}\) as a column vector.
(1)
(b)
A buoy M is at the midpoint of AB. Find the position vector of M.
(2)
(c)
Calculate the distance between the boats. Give your answer correct to 3 significant figures.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 \(\begin{pmatrix}4\\-4\end{pmatrix}\) (b − a)
✓ 1
Part (b)
M1 ½(a + b) or a + ½\(\overrightarrow{AB}\)
✓ 1
A1 \(\begin{pmatrix}4\\3\end{pmatrix}\)
✓ 1
Part (c)
M1 √(42 + (−4)2) = √32 (ECF from (a))
✓ 1
A1 5.66 km
✓ 1
Common error: \(\overrightarrow{AB}\) is the end position minus the start position, b − a, not a − b.
101IGMC3-7-04d-10Reflections, rotations, translations and enlargements described in wordsPaper EMedium6 marks
No calculator
Triangle T has vertices (2, 1), (4, 1) and (4, 4) on a coordinate grid. It is enlarged with scale factor −2 and centre of enlargement (1, 0) to give triangle T′.
(a)
Find the coordinates of the vertices of T′.
(3)
(b)
Work out the area of triangle T.
(1)
(c)
Work out the area of triangle T′.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 position relative to the centre is multiplied by −2, e.g. (2, 1) gives (1, 1) from the centre, then (−2, −2)
✓ 1
A1 at least two images correct
✓ 1
A1 (−1, −2), (−5, −2), (−5, −8)
✓ 1
Part (b)
B1 ½ × 2 × 3 = 3 square units
✓ 1
Part (c)
M1 area is multiplied by (−2)2 = 4 (ECF from (b))
✓ 1
A1 12 square units
✓ 1
Model sketch
Common error: Areas are multiplied by the square of the scale factor. A negative scale factor still gives a positive area scale factor.
102IGMC3-7-04d-13Vectors, magnitude and vector geometryPaper EMedium7 marks
Calculator
A light aircraft flies with a velocity through the air of \(\begin{pmatrix}60\\80\end{pmatrix}\) km/h, where the top number is the speed east and the bottom number is the speed north. A steady wind has velocity \(\begin{pmatrix}-20\\15\end{pmatrix}\) km/h. The velocity of the aircraft over the ground is the sum of these two velocities.
(a)
Write down the velocity of the aircraft over the ground.
(1)
(b)
Calculate the speed of the aircraft over the ground. Give your answer correct to 3 significant figures.
(2)
(c)
On another day the wind changes, and the aircraft, flying with the same velocity through the air, has a velocity over the ground of \(\begin{pmatrix}30\\90\end{pmatrix}\) km/h. Find the velocity of the wind and calculate the wind speed. Give the wind speed correct to 3 significant figures.
(4)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 \(\begin{pmatrix}40\\95\end{pmatrix}\) km/h
✓ 1
Part (b)
M1 √(402 + 952) (ECF from (a))
✓ 1
A1 103 km/h
✓ 1
Part (c)
M1 wind velocity = ground velocity − air velocity
✓ 1
A1 \(\begin{pmatrix}-30\\10\end{pmatrix}\) km/h
✓ 1
M1 √((−30)2 + 102) = √1000
✓ 1
A1 31.6 km/h
✓ 1
Common error: To find an unknown vector in a sum, subtract the known vector from the total; adding it again gives the wrong direction.
103IGMC3-7-09r13-10Vectors, magnitude and vector geometryPaper EMedium4 marks
Calculator
A bee leaves its hive and flies in a straight line to a flower. The displacement from the hive is \(\begin{pmatrix}240\\-130\end{pmatrix}\), in metres.
(a)
Calculate the distance from the hive to the flower, giving your answer to 3 significant figures.
(2)
(b)
The bee flies at a constant speed of 7.0 m/s. Calculate the time taken, in seconds, to 3 significant figures. Use the unrounded distance from (a).
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 \(\sqrt{240^2+130^2}\)
✓ 1
A1 273 m
✓ 1
Part (b)
M1 time = distance ÷ speed, i.e. 272.9… ÷ 7.0
✓ 1
A1 39.0 s
✓ 1
Exam tip: Keep the unrounded value on your calculator between parts and round only the final answer.
104IGMC3-7-09r13-11Vectors, magnitude and vector geometryPaper EMedium7 marks
Calculator
A hospital campus map has its origin O at the main gate, with 1 unit = 10 m. Points A and B have position vectors \(\overrightarrow{OA}=\)\(\begin{pmatrix}2\\5\end{pmatrix}\) and \(\overrightarrow{OB}=\)\(\begin{pmatrix}8\\-1\end{pmatrix}\).
Diagram not to scale
(a)
Find \(\overrightarrow{AB}\) as a column vector.
(1)
(b)
Calculate \(|\overrightarrow{AB}|\) in map units, to 3 significant figures.
(2)
(c)
Find the position vector of M, the midpoint of AB.
(2)
(d)
P lies on AB with AP : PB = 1 : 2. Find the position vector of P.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 \(\begin{pmatrix}6\\-6\end{pmatrix}\)
✓ 1
Part (b)
M1 \(\sqrt{6^2+(-6)^2}\)
✓ 1
A1 8.49
✓ 1
Part (c)
M1 \(\overrightarrow{OA}+\tfrac12\overrightarrow{AB}\) or average of the coordinates
Common error: A ratio AP : PB = 1 : 2 means AP is one third of AB, not one half.
105IGMC3-7-10r13-08Vectors, magnitude and vector geometryPaper EMedium5 marks
Calculator
A tracer particle in a tissue sample is displaced by \(\mathbf{d}_1=\)\(\begin{pmatrix}18\\-7\end{pmatrix}\) micrometres and then by \(\mathbf{d}_2=\)\(\begin{pmatrix}-5\\15\end{pmatrix}\) micrometres.
(a)
Find the resultant displacement \(\mathbf{d}_1+\mathbf{d}_2\).
(2)
(b)
Calculate the magnitude of the resultant displacement, in micrometres, to 3 significant figures.
(2)
(c)
A third displacement e returns the particle to its starting point. Write down e.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 adds the components
✓ 1
A1 \(\begin{pmatrix}13\\8\end{pmatrix}\)
✓ 1
Part (b)
M1 \(\sqrt{13^2+8^2}\)
✓ 1
A1 15.3 micrometres
✓ 1
Part (c)
B1 \(\begin{pmatrix}-13\\-8\end{pmatrix}\)
✓ 1
Exam tip: The magnitude of a vector is the square root of the sum of the squares of its components, and it is never negative.
106IGMC3-7-10r13-09Vectors, magnitude and vector geometryPaper EMedium5 marks
Calculator
A water pipe runs between two pumping stations A and B on a map with origin O (1 unit = 1 km). \(\overrightarrow{OA}=\)\(\begin{pmatrix}-3\\2\end{pmatrix}\) and \(\overrightarrow{OB}=\)\(\begin{pmatrix}9\\-6\end{pmatrix}\). A valve T lies on AB with AT : TB = 3 : 1.
Diagram not to scale
(a)
Find \(\overrightarrow{AB}\).
(1)
(b)
Find the position vector of T.
(2)
(c)
Calculate the distance OT in km, to 3 significant figures.
Common error: AT : TB = 3 : 1 means AT is three quarters of AB, because the parts add to 4.
107IGMC3-7-10r17-09Vectors, magnitude and vector geometryPaper EMedium6 marks
No calculator
A cyclist makes two displacements, in kilometres, given by p = (6, −8) and q = (−2, 5).
(a)
Calculate the magnitude of p.
(2)
(b)
Find 2p − 3q as a column vector.
(2)
(c)
Find the magnitude of p + q.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 √(62 + (−8)2)
✓ 1
A1 10 km
✓ 1
Part (b)
M1 (12, −16) − (−6, 15)
✓ 1
A1 (18, −31)
✓ 1
Part (c)
M1 p + q = (4, −3)
✓ 1
A1 5 km
✓ 1
Exam tip: Add or subtract vectors one component at a time, and only square the components when you find a magnitude.
108IGMC3-7-10r17-14Vectors, magnitude and vector geometryPaper EMedium7 marks
Calculator
A data centre uses cables whose displacements are vectors in metres. The vector v = (5, 12) and the vector w = (−12, 5).
(a)
Calculate the magnitude of v.
(2)
(b)
Write down a vector that is parallel to v and has magnitude 39.
(2)
(c)
Find the magnitude of 2v − w, correct to 3 significant figures.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 √(52 + 122)
✓ 1
A1 13
✓ 1
Part (b)
M1 3v
✓ 1
A1 (15, 36)
✓ 1
Part (c)
M1 2v − w = (10 + 12, 24 − 5) = (22, 19)
✓ 1
M1 √(222 + 192) = √845
✓ 1
A1 29.1
✓ 1
Common error: Subtracting a negative component incorrectly. For 2v − w the first component is 10 − (−12) = 22, not −2.
109IGMC3-7-10r19-10Vectors, magnitude and vector geometryPaper EMedium6 marks
Calculator
On an architect's plan, with all lengths in metres, the points A and B have position vectors \(\overrightarrow{OA}=\begin{pmatrix}4\\7\end{pmatrix}\) and \(\overrightarrow{OB}=\begin{pmatrix}-2\\3\end{pmatrix}\), where O is the origin.
Diagram not to scale
(a)
Find the position vector of the midpoint M of AB.
(2)
(b)
Find \(\overrightarrow{AB}\).
(2)
(c)
Calculate \(\left|\overrightarrow{AB}\right|\). Give your answer correct to 3 significant figures.
Common error: \(\overrightarrow{AB}\) is 'end minus start', that is \(\overrightarrow{OB}-\overrightarrow{OA}\); reversing the order gives the vector for BA.
110IGMC3-7-10r19-11Reflections, rotations, translations and enlargements described in wordsPaper EMedium8 marks
No calculator
A sonar footprint is drawn as triangle ABC with A(2, 1), B(5, 1) and C(5, 3) on a grid where 1 unit = 1 km. Triangle ABC is mapped onto triangle A′B′C′ by an enlargement with centre (1, 0) and scale factor −2.
(a)
Find the coordinates of A′, B′ and C′.
(3)
(b)
Describe fully the single enlargement that maps triangle A′B′C′ onto triangle ABC.
(3)
(c)
Calculate the area of triangle A′B′C′.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 A′ = (−1, −2)
✓ 1
B1 B′ = (−7, −2)
✓ 1
B1 C′ = (−7, −6)
✓ 1
Part (b)
B1 enlargement
✓ 1
B1 scale factor \(-\frac{1}{2}\)
✓ 1
B1 centre (1, 0)
✓ 1
Part (c)
M1 area of ABC is \(\frac{1}{2}\times3\times2=3\) and area scale factor \((-2)^2=4\)
✓ 1
A1 12 km\(^2\)
✓ 1
Common error: A negative scale factor puts the image on the opposite side of the centre; the area still scales by the square of the magnitude, so it is never negative.
111IGMC3-7-10r24-09Vectors, magnitude and vector geometryPaper EMedium5 marks
No calculator
In a game, a player at A(−1, 2) must reach a target at B(7, −4).
Diagram not to scale
(a)
Write down the vector \(\overrightarrow{AB}\).
(1)
(b)
Calculate the magnitude \(|\overrightarrow{AB}|\).
(2)
(c)
The player moves in a straight line from A to B at 2.5 units per second. Work out the time taken.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 \(\begin{pmatrix}8\\-6\end{pmatrix}\)
✓ 1
Part (b)
M1 \(\sqrt{8^2 + (-6)^2}\)
✓ 1
A1 10
✓ 1
Part (c)
M1 10 ÷ 2.5 (ECF from (b))
✓ 1
A1 4 seconds
✓ 1
Exam tip: The magnitude of \(\begin{pmatrix}x\\y\end{pmatrix}\) is \(\sqrt{x^2 + y^2}\); the signs disappear when you square.
112IGMC3-7-10r24-10Vectors, magnitude and vector geometryPaper EMedium5 marks
No calculator
In triangle OAB, \(\overrightarrow{OA} = \mathbf{a}\) and \(\overrightarrow{OB} = \mathbf{b}\). The point M is the midpoint of AB and the point N lies on OB such that \(ON = \frac{3}{4}OB\).
Diagram not to scale
(a)
Write \(\overrightarrow{AB}\) in terms of \(\mathbf{a}\) and \(\mathbf{b}\).
(1)
(b)
Show that \(\overrightarrow{OM} = \frac{1}{2}(\mathbf{a} + \mathbf{b})\).
(2)
(c)
Find \(\overrightarrow{NM}\) in terms of \(\mathbf{a}\) and \(\mathbf{b}\), in its simplest form.
Common error: \(\overrightarrow{NM}\) is M minus N (end minus start); reversing the order gives the opposite vector.
113IGMC3-7-10r39-10Reflections, rotations, translations and enlargements described in wordsPaper EMedium8 marks
Calculator
A layout plan for a data centre uses coordinates (x, y) in metres. Three temperature sensors are at A(2, 3), B(4, 3) and C(4, 4). Triangle ABC is enlarged with scale factor −2 and centre (1, 1) to give triangle A′B′C′.
(a)
Write down the coordinates of A′, B′ and C′.
(3)
(b)
Describe fully the single transformation that maps A′B′C′ onto ABC.
(3)
(c)
The area of triangle ABC is 1 m2. Find the area of triangle A′B′C′.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 A′(−1, −3)
✓ 1
B1 B′(−5, −3)
✓ 1
B1 C′(−5, −5)
✓ 1
Part (b)
B1 enlargement
✓ 1
B1 scale factor −½
✓ 1
B1 centre (1, 1)
✓ 1
Part (c)
M1 (−2)2 × 1
✓ 1
A1 4 m2
✓ 1
Common error: A negative scale factor places the image on the opposite side of the centre, but the area still scales by the square of the factor, so it is always positive.
114IGMC3-7-10r39-11Vectors, magnitude and vector geometryPaper EMedium6 marks
Calculator
A cyclist rides in a straight line from checkpoint A to checkpoint B on a map with coordinates in kilometres. A is at (2, −1) and B is at (8, 7).
Diagram not to scale
(a)
Write down the column vector \(\overrightarrow{AB}\).
(2)
(b)
Calculate the magnitude of \(\overrightarrow{AB}\).
(2)
(c)
The cyclist rides at a constant speed of 25 km/h. Find the time taken to ride from A to B, in minutes.
Exam tip: The magnitude of a vector is the length of the line it represents, found with Pythagoras on its two components.
115IGMC3-7-10r39-12Vectors, magnitude and vector geometryPaper EMedium7 marks
No calculator
A triangular trench OAB is marked out at an archaeological site. \(\overrightarrow{OA}\) = a and \(\overrightarrow{OB}\) = b. M is the midpoint of AB and X is the midpoint of OB.
Diagram not to scale
(a)
Write down \(\overrightarrow{AB}\) in terms of a and b.
(1)
(b)
Find \(\overrightarrow{OM}\) in terms of a and b. Give your answer in its simplest form.
(2)
(c)
Find \(\overrightarrow{XM}\) in terms of a.
(2)
(d)
Write down two geometrical facts about the lines XM and OA.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 b − a
✓ 1
Part (b)
M1 \(\overrightarrow{OA}+\tfrac12\overrightarrow{AB}\) or a + ½(b − a)
✓ 1
A1 ½(a + b)
✓ 1
Part (c)
M1 \(\overrightarrow{OM}-\overrightarrow{OX}\) or ½(a + b) − ½b
✓ 1
A1 ½a
✓ 1
Part (d)
B1 XM is parallel to OA
✓ 1
B1 XM is half the length of OA
✓ 1
Exam tip: To get from one point to another, choose a route you already know in vectors, such as going back to O and out again, and add the vectors.
116IGMC3-7-12r41-08Vectors, magnitude and vector geometryPaper EMedium7 marks
No calculator
In a model of a drug molecule, atom A has position vector (1, 2) and atom B has position vector (7, 10) relative to the origin O.
Diagram not to scale
(a)
Find the vector AB.
(1)
(b)
Find the position vector of M, the midpoint of AB.
(2)
(c)
The atom C lies on the line AB extended so that vector AC = 3/2 × vector AB. Find the position vector of C.
(2)
(d)
Calculate the magnitude of the vector AC.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
A1 (6, 8)
✓ 1
Part (b)
M1 ½(1 + 7, 2 + 10) or (1, 2) + ½(6, 8)
✓ 1
A1 (4, 6)
✓ 1
Part (c)
M1 (1, 2) + 3/2 × (6, 8)
✓ 1
A1 (10, 14)
✓ 1
Part (d)
M1 1.5 × √(62 + 82) or √(92 + 122)
✓ 1
A1 15
✓ 1
Exam tip: The magnitude of a vector (x, y) is √(x² + y²). Multiplying a vector by a positive number k multiplies its magnitude by k.
117IGMC3-7-12r41-09Vectors, magnitude and vector geometryPaper EMedium7 marks
Calculator
In a strategy game, four towers O, A, B and C are at the corners of a parallelogram OABC, labelled in order. The vector OA is a and the vector OC is c. The point M is the midpoint of BC.
Diagram not to scale
(a)
Write down the vector AB in terms of c.
(1)
(b)
Write down the vector OB in terms of a and c.
(1)
(c)
Find the vector OM in terms of a and c. Give your answer in its simplest form.
(2)
(d)
Now a = (4, 0) and c = (1, 3). Calculate the distance OM. Give your answer correct to 3 significant figures.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 c
✓ 1
Part (b)
B1 a + c
✓ 1
Part (c)
M1 OB + ½ BC with BC = −a
✓ 1
A1 ½a + c
✓ 1
Part (d)
M1 OM = (3, 3)
✓ 1
M1 √(32 + 32)
✓ 1
A1 4.24
✓ 1
Common error: In a parallelogram, opposite sides are equal vectors in the same direction; BC is the vector −a because it runs from B to C, opposite in direction to OA.
118IGMC3-7-11r42-06Vectors, magnitude and vector geometryPaper EMedium6 marks
Calculator
A delivery drone leaves a depot O and flies to a point A, then to a point B. Distances are in km. The displacement from O to A is \(\overrightarrow{OA}=\begin{pmatrix}6\\-8\end{pmatrix}\) and the displacement from O to B is \(\overrightarrow{OB}=\begin{pmatrix}-2\\5\end{pmatrix}\).
Diagram not to scale
(a)
Find \(\overrightarrow{AB}\).
(2)
(b)
Calculate \(|\overrightarrow{OA}|\).
(2)
(c)
Calculate \(|\overrightarrow{AB}|\), giving your answer correct to 3 significant figures.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 \(\overrightarrow{OB}-\overrightarrow{OA}\)
✓ 1
A1 \(\begin{pmatrix}-8\\13\end{pmatrix}\)
✓ 1
Part (b)
M1 \(\sqrt{6^2+(-8)^2}\)
✓ 1
A1 10
✓ 1
Part (c)
M1 \(\sqrt{(-8)^2+13^2}\) (or \(\sqrt{233}\)) (ECF from (a))
✓ 1
A1 15.3 (km)
✓ 1
Exam tip: The magnitude of a column vector is found with Pythagoras; the sign of a component does not matter once it is squared.
119IGMC3-7-11r42-10Vectors, magnitude and vector geometryPaper EMedium7 marks
Calculator
Two robots move across a warehouse floor. The vector \(\mathbf{p}=\begin{pmatrix}2\\k\end{pmatrix}\) is parallel to \(\mathbf{q}=\begin{pmatrix}-6\\9\end{pmatrix}\).
(a)
Find the value of k.
(2)
(b)
Calculate \(|\mathbf{q}|\), giving your answer correct to 3 significant figures.
(2)
(c)
Using your value of k, find \(|3\mathbf{p}-\mathbf{q}|\), giving your answer correct to 3 significant figures. Use exact values until the final answer.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 Equate ratios of components, 2/(−6) = k/9 (or p = −⅓q)
✓ 1
A1 k = −3
✓ 1
Part (b)
M1 \(\sqrt{(-6)^2+9^2}\)
✓ 1
A1 10.8
✓ 1
Part (c)
M1 3(2, −3) − (−6, 9)
✓ 1
A1 \(\begin{pmatrix}12\\-18\end{pmatrix}\)
✓ 1
A1 \(\sqrt{468}\) = 21.6 (ECF from (a))
✓ 1
Common error: Take care subtracting a vector with negative components: 3p − q means 6 − (−6) = 12 and −9 − 9 = −18.
120IGMC-047-00-11Reflections, rotations, translations and enlargements described in wordsPaper EHard5 marks
No calculator
Triangle A has vertices (0, 4), (2, 4) and (2, 6). Triangle B has vertices (3, 1), (3, 3) and (5, 3). (0, 4) maps to (3, 1), (2, 4) maps to (3, 3) and (2, 6) maps to (5, 3).
(a)
Describe fully the single transformation that maps triangle A onto triangle B.
(2)
(b)
Find the image of the point (6, −2) under this transformation.
(2)
(c)
Write down the coordinates of the point on the x-axis that is mapped onto itself by this transformation.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 for reflection
✓ 1
B1 for in the line y = x + 1
✓ 1
Part (b)
M1 for using the midpoint on y = x + 1 with a perpendicular joining line, or the rule (x, y) → (y − 1, x + 1)
✓ 1
A1 for (−3, 7)
✓ 1
Part (c)
B1 for (−1, 0)
✓ 1
Exam tip: The mirror line passes through the midpoint of each point and its image, and it is perpendicular to the line joining them. The midpoint of (0, 4) and (3, 1) is (1.5, 2.5), which lies on y = x + 1.
121IGMC-047-00-13Reflections, rotations, translations and enlargements described in wordsPaper EHard7 marks
No calculator
Rectangle R has vertices (−4, 2), (8, 2), (8, 8) and (−4, 8). R is enlarged with scale factor \(\frac{1}{3}\) and centre (2, −1) to give rectangle S.
(a)
Find the coordinates of the vertices of S.
(3)
(b)
Describe fully the single transformation that maps S onto R.
(2)
(c)
Find the area of S.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
(0, 0), (4, 0), (4, 2), (0, 2)
—
M1 for a correct method, e.g. (−4 − 2, 2 − (−1)) = (−6, 3) multiplied by \(\frac{1}{3}\) and added to (2, −1)
✓ 1
A1 for two vertices correct
✓ 1
A1 for all four vertices correct
✓ 1
Part (b)
B1 for enlargement with centre (2, −1)
✓ 1
B1 for scale factor 3
✓ 1
Part (c)
M1 for 12 × 6 × \(\left(\frac{1}{3}\right)^2\), or for 4 × 2 using their S
✓ 1
A1 for 8 square units
✓ 1
Model sketch
Exam tip: For a fractional scale factor, the image lies between the centre and the original shape. Multiply each displacement from the centre by the scale factor. Do not multiply the coordinates themselves unless the centre is the origin.
122IGMC-047-00-14Reflections, rotations, translations and enlargements described in wordsPaper EHard7 marks
Calculator
A rotation of 180° about the point C maps the point P(3, −1) onto the point P′(−5, 7).
(a)
Find the coordinates of C.
(2)
(b)
Find the image of the point Q(0, 4) under the same rotation.
(2)
(c)
A translation also maps P onto P′. Write down the vector of this translation and find its magnitude. Give the magnitude to 3 significant figures.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 for \(\left(\frac{3 + (-5)}{2}, \frac{-1 + 7}{2}\right)\)
✓ 1
A1 for (−1, 3)
✓ 1
Part (b)
M1 for using C as the midpoint of Q and its image, e.g. (2 × (−1) − 0, 2 × 3 − 4)
✓ 1
A1 for (−2, 2)
✓ 1
Part (c)
B1 for \(\begin{pmatrix}-8\\8\end{pmatrix}\)
✓ 1
M1 for \(\sqrt{(-8)^2 + 8^2}\) or \(\sqrt{128}\)
✓ 1
A1 for 11.3 units. An answer left only as \(8\sqrt{2}\) does not earn this mark, because it is not given to 3 s.f.
✓ 1
Common error: Squaring a negative component on a calculator without brackets, as in −8², gives −64 instead of 64. Always type (−8)² when finding a magnitude.
123IGMC-047-01-12Vectors, magnitude and vector geometryPaper EHard8 marks
No calculator
In triangle OAB, \(\overrightarrow{OA}=\mathbf{a}\) and \(\overrightarrow{OB}=\mathbf{b}\). M is the midpoint of OA. N lies on AB such that AN : NB = 2 : 1. The line MN is extended to meet the line OB extended at X, where \(\overrightarrow{OX}=k\mathbf{b}\).
Diagram not to scale
(a)
Find \(\overrightarrow{AB}\) in terms of \(\mathbf{a}\) and \(\mathbf{b}\).
(1)
(b)
Find \(\overrightarrow{ON}\) in terms of \(\mathbf{a}\) and \(\mathbf{b}\), in its simplest form.
(2)
(c)
Find \(\overrightarrow{MN}\) in terms of \(\mathbf{a}\) and \(\mathbf{b}\), in its simplest form.
M1: \(\overrightarrow{MX}=\lambda\overrightarrow{MN}\) and comparing coefficients of \(\mathbf{a}\): \(-\frac{1}{2}=-\frac{\lambda}{6}\), so \(\lambda=3\)
✓ 1
A1: \(k=3\times\frac{2}{3}=2\)
✓ 1
Exam tip: For points on a straight line, write one vector as a scalar multiple of another, then match the coefficients of \(\mathbf{a}\) and of \(\mathbf{b}\) separately.
124IGMC-047-01-13Vectors, magnitude and vector geometryPaper EHard7 marks
Calculator
Distances are in kilometres. At 12:00 a boat is at the point with position vector \(\begin{pmatrix}2\\3\end{pmatrix}\). It moves with constant velocity \(\begin{pmatrix}4\\-1\end{pmatrix}\) km/h. A lighthouse L is at the point with position vector \(\begin{pmatrix}10\\5\end{pmatrix}\). The vector \(\begin{pmatrix}0\\1\end{pmatrix}\) points due north.
Diagram not to scale
(a)
Write down the position vector of the boat \(t\) hours after 12:00.
(2)
(b)
Find the time when the boat is due south of L, and its distance from L at that time.
(3)
(c)
Find the distance of the boat from L at 15:00, giving your answer correct to 3 significant figures.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1: \(x\)-component \(2+4t\)
✓ 1
B1: \(y\)-component \(3-t\)
✓ 1
Part (b)
M1: \(2+4t=10\)
✓ 1
A1: \(t=2\), so 14:00
✓ 1
A1: boat at (10, 1), distance 4 km
✓ 1
Part (c)
M1: boat at \(\begin{pmatrix}14\\0\end{pmatrix}\), vector from L \(\begin{pmatrix}4\\-5\end{pmatrix}\) and \(\sqrt{4^2+5^2}\)
✓ 1
A1: 6.40 km
✓ 1
Common error: Position after \(t\) hours is the start position plus \(t\) times the velocity. Adding the velocity only once gives the position after 1 hour, whatever the value of \(t\).
125IGMC-047-01-14Vectors, magnitude and vector geometryPaper EHard7 marks
No calculator
OABC is a trapezium. \(\overrightarrow{OA}=\mathbf{a}\), \(\overrightarrow{OC}=\mathbf{c}\) and \(\overrightarrow{CB}=2\mathbf{a}\). The diagonals OB and AC meet at X.
Diagram not to scale
(a)
Find, in terms of \(\mathbf{a}\) and \(\mathbf{c}\), (i) \(\overrightarrow{OB}\) (ii) \(\overrightarrow{AC}\).
(2)
(b)
\(\overrightarrow{OX}=\mu\overrightarrow{OB}\) and \(\overrightarrow{AX}=\lambda\overrightarrow{AC}\). Find \(\overrightarrow{OX}\) in terms of \(\mathbf{a}\) and \(\mathbf{c}\).
Exam tip: When two lines cross, write the crossing point in two different ways using two unknown scalars, then compare coefficients because \(\mathbf{a}\) and \(\mathbf{c}\) are not parallel.
126IGMC3-7-04d-12Vectors, magnitude and vector geometryPaper EHard8 marks
Calculator
In triangle OAB, \(\overrightarrow{OA} = \mathbf{a}\) and \(\overrightarrow{OB} = \mathbf{b}\). The point P lies on AB such that AP : PB = 3 : 1. The point Q is the midpoint of OP.
Diagram not to scale
(a)
Write down \(\overrightarrow{AB}\) in terms of a and b.
(1)
(b)
Show that \(\overrightarrow{OP} = \frac{1}{4}\mathbf{a} + \frac{3}{4}\mathbf{b}\).
(2)
(c)
Find \(\overrightarrow{AQ}\) in terms of a and b, in its simplest form.
(2)
(d)
Given that a = \(\begin{pmatrix}4\\2\end{pmatrix}\) and b = \(\begin{pmatrix}0\\6\end{pmatrix}\), calculate \(|\overrightarrow{OP}|\). Give your answer correct to 3 significant figures.
Exam tip: For a point dividing a line in a given ratio, start from a known point and add the correct fraction of the line vector, here 3/4 of \(\overrightarrow{AB}\) from A.
127IGMC3-7-04d-14Vectors, magnitude and vector geometryPaper EHard7 marks
No calculator
In a frame design, OABC is a parallelogram with \(\overrightarrow{OA} = \mathbf{a}\) and \(\overrightarrow{OC} = \mathbf{c}\). The point M is the midpoint of AB. The point X lies on the diagonal OB such that \(\overrightarrow{OX} = \frac{2}{3}\overrightarrow{OB}\).
Diagram not to scale
(a)
Write down \(\overrightarrow{OB}\) in terms of a and c.
(1)
(b)
Find \(\overrightarrow{OM}\) in terms of a and c.
(2)
(c)
Show that \(\overrightarrow{CM} = \mathbf{a} - \frac{1}{2}\mathbf{c}\).
(1)
(d)
Show that C, X and M lie on a straight line.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 a + c
✓ 1
Part (b)
M1 \(\overrightarrow{OM} = \mathbf{a} + \frac{1}{2}\overrightarrow{AB}\) with \(\overrightarrow{AB} = \mathbf{c}\)
R1 \(\overrightarrow{CX}\) is a multiple of \(\overrightarrow{CM}\) and they share the point C, so C, X, M are collinear
✓ 1
Exam tip: To show three points are collinear, show that two of the vectors between them are multiples of each other and mention the shared point.
128IGMC3-7-09r13-12Vectors, magnitude and vector geometryPaper EHard7 marks
No calculator
A triangular piece of honeycomb is modelled as triangle OAB, where \(\overrightarrow{OA}=\mathbf{a}\) and \(\overrightarrow{OB}=\mathbf{b}\). The point P lies on AB with AP : PB = 2 : 1.
Diagram not to scale
(a)
Write \(\overrightarrow{AB}\) in terms of a and b.
(1)
(b)
Show that \(\overrightarrow{OP}=\tfrac13\mathbf{a}+\tfrac23\mathbf{b}\).
(2)
(c)
R lies on OB with \(\overrightarrow{OR}=\tfrac23\mathbf{b}\). Show that RP is parallel to OA.
Exam tip: To show two lines are parallel, show one vector is a scalar multiple of the other, then say so in a sentence.
129IGMC3-7-09r13-13Vectors, magnitude and vector geometryPaper EHard8 marks
Calculator
A camera drone above a race circuit is displaced by the vector d = \(\begin{pmatrix}k\\-12\end{pmatrix}\) metres, where k is a constant.
(a)
Given that |d| = 13, find the two possible values of k.
(3)
(b)
Take k = 5. Find the positive value of λ for which λd has magnitude 6.5.
(2)
(c)
With k = 5, the drone is also blown by a wind displacement \(\begin{pmatrix}7\\0\end{pmatrix}\) m. Calculate the magnitude of the total displacement d + \(\begin{pmatrix}7\\0\end{pmatrix}\), to 3 significant figures.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 k2 + 144 = 169
✓ 1
M1 k2 = 25
✓ 1
A1 k = 5 or k = −5
✓ 1
Part (b)
M1 |λ| × 13 = 6.5
✓ 1
A1 λ = 0.5
✓ 1
Part (c)
M1 adds the vectors
✓ 1
A1 \(\begin{pmatrix}12\\-12\end{pmatrix}\)
✓ 1
A1 17.0 m
✓ 1
Common error: Squaring gives both a positive and a negative root, so state both values of k when the question asks for all possibilities.
130IGMC3-7-10r13-07Reflections, rotations, translations and enlargements described in wordsPaper EHard6 marks
Calculator
A water network is plotted on a grid with 1 unit = 1 km. An enlargement with centre C(3, −1) and scale factor −2 maps point P onto P′(9, 5).
(a)
Find the coordinates of P.
(2)
(b)
The point Q(1, 1) is mapped by the same enlargement to Q′. Find the coordinates of Q′.
(2)
(c)
Calculate the length of P′Q′, in km, to 3 significant figures.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 vector from C to P′ is (6, 6), so vector from C to P is (6, 6) ÷ (−2) = (−3, −3)
✓ 1
A1 P = (0, −4)
✓ 1
Part (b)
M1 vector from C to Q is (−2, 2), multiplied by −2 gives (4, −4)
✓ 1
A1 Q′ = (7, −5)
✓ 1
Part (c)
M1 \(\overrightarrow{P'Q'}=\)\(\begin{pmatrix}-2\\-10\end{pmatrix}\) and \(\sqrt{2^2+10^2}\)
✓ 1
A1 10.2 km
✓ 1
Common error: With a negative scale factor the image lies on the opposite side of the centre, so reverse the direction as well as scaling the distance.
131IGMC3-7-10r13-10Vectors, magnitude and vector geometryPaper EHard8 marks
No calculator
In a game, the map of a field is the parallelogram OABC with \(\overrightarrow{OA}=\mathbf{a}\) and \(\overrightarrow{OC}=\mathbf{c}\). The point M is the midpoint of BC, and N lies on OB with \(\overrightarrow{ON}=\tfrac23\overrightarrow{OB}\).
Diagram not to scale
(a)
Write down \(\overrightarrow{OB}\) in terms of a and c.
(1)
(b)
Show that \(\overrightarrow{AM}=-\tfrac12\mathbf{a}+\mathbf{c}\).
(2)
(c)
Find \(\overrightarrow{AN}\) in terms of a and c.
(2)
(d)
Show that A, N and M lie on a straight line.
(2)
(e)
Write down the ratio AN : NM.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 a + c
✓ 1
Part (b)
M1 \(\overrightarrow{OM}=\overrightarrow{OB}+\tfrac12\overrightarrow{BC}\) with \(\overrightarrow{BC}=-\mathbf{a}\), or \(\overrightarrow{OC}+\tfrac12\overrightarrow{CB}\)
R1 the vectors are parallel and share the point A, so the points are collinear
✓ 1
Part (e)
B1 2 : 1
✓ 1
Exam tip: To prove three points are collinear, show two vectors between them are multiples of each other and mention the common point.
132IGMC3-7-10r17-10Vectors, magnitude and vector geometryPaper EHard7 marks
Calculator
On an excavation plan, O is the origin, A has position vector a and B has position vector b. M is the midpoint of AB. N lies on OB so that ON = 2/3 OB.
Diagram not to scale
(a)
Write down the vector AB in terms of a and b.
(1)
(b)
Show that the position vector of M is 1/2(a + b).
(2)
(c)
Find MN in terms of a and b, in its simplest form.
(2)
(d)
Given that a = (4, 2) and b = (−2, 6), find the length of MN.
Common error: Writing MN as OM − ON. The vector from M to N is the position of N minus the position of M.
133IGMC3-7-10r17-11Vectors, magnitude and vector geometryPaper EHard7 marks
Calculator
On a cycling-track survey, O is the origin, A has position vector a and B has position vector b. P lies on AB so that AP : PB = 1 : 3. Q is the point with position vector 3a + b.
Diagram not to scale
(a)
Show that the position vector of P is 3/4a + 1/4b.
(2)
(b)
Show that O, P and Q lie on a straight line.
(2)
(c)
Find the ratio OP : PQ.
(1)
(d)
Given that a = (2, 1) and b = (6, 9), find the length of PQ.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 OP = a + 1/4(b − a)
✓ 1
A1 3/4a + 1/4b, shown
✓ 1
Part (b)
M1 OQ = 3a + b = 4(3/4a + 1/4b)
✓ 1
R1 OQ = 4 OP, so the vectors are parallel and share the point O
✓ 1
Part (c)
B1 1 : 3
✓ 1
Part (d)
M1 PQ = 3 OP = 3(3, 3) = (9, 9)
✓ 1
A1 9√2 (≈ 12.73)
✓ 1
Exam tip: To show that points are collinear, show that one vector between them is a scalar multiple of another and that they share a point.
134IGMC3-7-10r17-12Vectors, magnitude and vector geometryPaper EHard8 marks
Calculator
In a data centre, a cable runs from rack R to rack S with displacement vector (k, 12) metres. The cable has length 13 m.
(a)
Find the two possible values of k.
(3)
(b)
Rack R has position vector (2, −1) and k is positive. Find the position vector of S.
(2)
(c)
Rack T has position vector (−5, 3). Calculate the distance ST, correct to 3 significant figures.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 k2 + 122 = 132
✓ 1
M1 k2 = 25
✓ 1
A1 k = 5 or k = −5
✓ 1
Part (b)
M1 (2, −1) + (5, 12)
✓ 1
A1 (7, 11)
✓ 1
Part (c)
M1 ST = (−5 − 7, 3 − 11) = (−12, −8) (ECF from (b))
✓ 1
M1 √(144 + 64) = √208
✓ 1
A1 14.4 m
✓ 1
Common error: Giving only k = 5. Squaring removes the sign, so both a positive and a negative value satisfy the equation.
135IGMC3-7-10r19-12Vectors, magnitude and vector geometryPaper EHard7 marks
No calculator
In a roof frame, triangle OAB has \(\overrightarrow{OA}=\mathbf{a}\) and \(\overrightarrow{OB}=\mathbf{b}\). The point P lies on AB such that AP : PB = 2 : 1. The point M is the midpoint of OB.
Diagram not to scale
(a)
Write down \(\overrightarrow{AB}\) in terms of \(\mathbf{a}\) and \(\mathbf{b}\).
(1)
(b)
Show that \(\overrightarrow{OP}=\frac{1}{3}\mathbf{a}+\frac{2}{3}\mathbf{b}\).
(2)
(c)
Find \(\overrightarrow{MP}\) in terms of \(\mathbf{a}\) and \(\mathbf{b}\).
(2)
(d)
In a particular frame, \(\mathbf{a}=\begin{pmatrix}6\\0\end{pmatrix}\) and \(\mathbf{b}=\begin{pmatrix}0\\9\end{pmatrix}\), with lengths in metres. Calculate \(\left|\overrightarrow{MP}\right|\).
M1 \(\overrightarrow{MP}=\begin{pmatrix}2\\1.5\end{pmatrix}\) and \(\sqrt{2^2+1.5^2}\)
✓ 1
A1 2.5 m
✓ 1
Exam tip: Reach a point by a route you already know (here O to A to P) and write each step in terms of \(\mathbf{a}\) and \(\mathbf{b}\).
136IGMC3-7-10r19-13Vectors, magnitude and vector geometryPaper EHard8 marks
Calculator
A plot of land is the parallelogram OABC, with \(\overrightarrow{OA}=\mathbf{a}\) and \(\overrightarrow{OC}=\mathbf{c}\). The point M is the midpoint of AB. The point X lies on OB such that \(\overrightarrow{OX}=\frac{2}{3}\overrightarrow{OB}\).
Diagram not to scale
(a)
Write down \(\overrightarrow{OB}\) in terms of \(\mathbf{a}\) and \(\mathbf{c}\).
(1)
(b)
Find \(\overrightarrow{CM}\) in terms of \(\mathbf{a}\) and \(\mathbf{c}\).
(2)
(c)
Show that X lies on the line CM.
(3)
(d)
Given that \(\mathbf{a}=\begin{pmatrix}6\\0\end{pmatrix}\) and \(\mathbf{c}=\begin{pmatrix}2\\5\end{pmatrix}\), with lengths in metres, calculate \(\left|\overrightarrow{CM}\right|\). Give your answer correct to 3 significant figures.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 \(\mathbf{a}+\mathbf{c}\)
✓ 1
Part (b)
M1 \(\overrightarrow{CM}=\overrightarrow{CB}+\overrightarrow{BM}\) or \(\overrightarrow{OM}-\overrightarrow{OC}\), using \(\overrightarrow{AB}=\mathbf{c}\)
R1 \(\overrightarrow{CX}\) is a multiple of \(\overrightarrow{CM}\) and they share the point C, so C, X and M are collinear
✓ 1
Part (d)
M1 \(\overrightarrow{CM}=\begin{pmatrix}5\\-2.5\end{pmatrix}\) and \(\sqrt{5^2+2.5^2}\)
✓ 1
A1 5.59 m
✓ 1
Exam tip: To show three points are collinear, show that two of the vectors between them are parallel and that they share a common point, then state this conclusion.
137IGMC3-7-10r19-14Vectors, magnitude and vector geometryPaper EHard10 marks
Calculator
A warehouse robot makes a displacement \(\mathbf{u}=\begin{pmatrix}x\\-6\end{pmatrix}\) metres, where \(x>0\) and \(\left|\mathbf{u}\right|=10\). A second displacement is \(\mathbf{v}=\begin{pmatrix}12\\y\end{pmatrix}\) metres, and a third is \(\mathbf{w}=\begin{pmatrix}-2\\5\end{pmatrix}\) metres.
(a)
Find the value of \(x\).
(3)
(b)
Given that \(\mathbf{v}\) is parallel to \(\mathbf{u}\), find the value of \(y\).
(2)
(c)
Find the value of \(\lambda\) for which the vector \(\mathbf{u}+\lambda\mathbf{w}\) has equal horizontal and vertical components.
(3)
(d)
Calculate \(\left|\mathbf{u}+\lambda\mathbf{w}\right|\) for this value of \(\lambda\). Give your answer correct to 3 significant figures.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 \(x^2+(-6)^2=10^2\)
✓ 1
M1 \(x^2=64\)
✓ 1
A1 \(x=8\)
✓ 1
Part (b)
M1 \(\mathbf{v}=1.5\mathbf{u}\) since \(\frac{12}{8}=1.5\) (ECF from (a))
✓ 1
A1 \(y=-9\)
✓ 1
Part (c)
M1 \(\mathbf{u}+\lambda\mathbf{w}=\begin{pmatrix}8-2\lambda\\-6+5\lambda\end{pmatrix}\) (ECF from (a))
✓ 1
M1 \(8-2\lambda=-6+5\lambda\)
✓ 1
A1 \(\lambda=2\)
✓ 1
Part (d)
M1 \(\sqrt{4^2+4^2}\) (ECF from (c))
✓ 1
A1 5.66 m
✓ 1
Common error: Remember that a magnitude is the square root of the sum of squared components; adding the components directly (4 + 4) is a frequent slip.
138IGMC3-7-10r24-11Vectors, magnitude and vector geometryPaper EHard8 marks
Calculator
A water pipe runs from point A to point B. The displacement from A to B is \(\begin{pmatrix}k\\12\end{pmatrix}\) km and the length of the pipe is 13 km.
(a)
Find the possible values of \(k\).
(3)
(b)
The pipe runs west of A, so \(k\) is negative. Point A is at (8, −3). Find the coordinates of B.
(2)
(c)
A second pipe runs from B to C with \(\overrightarrow{BC} = \begin{pmatrix}6\\-8\end{pmatrix}\) km. Work out the straight-line distance AC. Give your answer to 3 significant figures.
Common error: Taking only the positive square root loses a solution: \(k^2 = 25\) gives both 5 and −5.
139IGMC3-7-10r24-12Vectors, magnitude and vector geometryPaper EHard6 marks
No calculator
OABC is a parallelogram with \(\overrightarrow{OA} = \mathbf{a}\) and \(\overrightarrow{OC} = \mathbf{c}\). The point E lies on AC such that \(AE : EC = 2 : 1\). The point D lies on OB such that \(OD = \frac{1}{3}OB\).
Diagram not to scale
(a)
Write \(\overrightarrow{OB}\) in terms of \(\mathbf{a}\) and \(\mathbf{c}\).
(1)
(b)
Show that \(\overrightarrow{OE} = \frac{1}{3}\mathbf{a} + \frac{2}{3}\mathbf{c}\).
(2)
(c)
Show that ED is parallel to OC and state the ratio \(ED : OC\).
M1 \(\overrightarrow{OD} = \frac{1}{3}(\mathbf{a} + \mathbf{c})\) and \(\overrightarrow{ED} = \overrightarrow{OD} - \overrightarrow{OE}\) (ECF from (a) and (b))
✓ 1
A1 \(\overrightarrow{ED} = -\frac{1}{3}\mathbf{c}\), a multiple of \(\overrightarrow{OC}\), so parallel
✓ 1
A1 \(ED : OC = 1 : 3\)
✓ 1
Exam tip: To prove two lines are parallel, show that one vector is a scalar multiple of the other.
140IGMC3-7-10r24-13Reflections, rotations, translations and enlargements described in wordsPaper EHard8 marks
No calculator
Triangle T has vertices (2, 1), (4, 1) and (4, 2). Triangle W is the image of T after an enlargement with scale factor −2 and centre (1, 0).
(a)
Find the coordinates of the vertices of W.
(3)
(b)
Work out the area of W.
(2)
(c)
Describe fully the single transformation that maps W onto T.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 vector from centre to a vertex multiplied by −2, e.g. (2, 1) gives \((1, 0) + (-2)(1, 1)\)
✓ 1
A1 (−1, −2) and (−5, −2)
✓ 1
A1 (−5, −4)
✓ 1
Part (b)
M1 base 4 and height 2 for W (ECF from (a)), or area of T × 4
✓ 1
A1 4 square units
✓ 1
Part (c)
B1 enlargement
✓ 1
B1 scale factor \(-\frac{1}{2}\)
✓ 1
B1 centre (1, 0)
✓ 1
Common error: A negative scale factor places the image on the opposite side of the centre; the lengths scale by 2 but the figure is turned through 180°.
141IGMC3-7-10r39-13Vectors, magnitude and vector geometryPaper EHard10 marks
No calculator
A plot of land OABC at an archaeological site is a parallelogram. \(\overrightarrow{OA}\) = a and \(\overrightarrow{OC}\) = c. M is the midpoint of BC. The lines OB and AM cross at X.
Diagram not to scale
(a)
Write down \(\overrightarrow{OB}\) in terms of a and c.
(1)
(b)
Show that \(\overrightarrow{AM}\) = c − ½a.
(2)
(c)
Let \(\overrightarrow{OX}=k\,\overrightarrow{OB}\) and \(\overrightarrow{AX}=m\,\overrightarrow{AM}\). Find the values of k and m.
(5)
(d)
Write down the ratio OX : XB and the ratio AX : XM.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 a + c
✓ 1
Part (b)
M1 \(\overrightarrow{AM}=\overrightarrow{AB}+\overrightarrow{BM}\) with \(\overrightarrow{AB}\) = c and \(\overrightarrow{BM}\) = −½a
✓ 1
A1 c − ½a (shown)
✓ 1
Part (c)
M1 \(\overrightarrow{OX}\) = k(a + c)
✓ 1
M1 \(\overrightarrow{OX}=\overrightarrow{OA}+m\overrightarrow{AM}\) = a + m(c − ½a)
✓ 1
M1 equate coefficients of a and of c: k = 1 − ½m and k = m
✓ 1
A1 m = ⅔
✓ 1
A1 k = ⅔
✓ 1
Part (d)
B1 OX : XB = 2 : 1
✓ 1
B1 AX : XM = 2 : 1
✓ 1
Exam tip: When two different routes lead to the same point, write each route in terms of the same two vectors and equate the coefficients of each vector.
142IGMC3-7-10r39-14Vectors, magnitude and vector geometryPaper EHard7 marks
No calculator
A maintenance robot in a data centre has displacements described by column vectors, in metres. p = \(\begin{pmatrix}k\\-8\end{pmatrix}\), where k is positive, and q = \(\begin{pmatrix}3\\-4\end{pmatrix}\). The magnitude of p is 17 m.
(a)
Find the value of k.
(3)
(b)
Given that sp + tq = \(\begin{pmatrix}27\\-12\end{pmatrix}\), find the values of the constants s and t.
(4)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 k2 + (−8)2 = 172
✓ 1
A1 k2 = 225
✓ 1
A1 k = 15
✓ 1
Part (b)
M1 forms two equations: 15s + 3t = 27 and −8s − 4t = −12
✓ 1
M1 eliminates one variable, for example 2s + t = 3 and t = 3 − 2s substituted into the first
✓ 1
A1 s = 2
✓ 1
A1 t = −1
✓ 1
(ECF from (a))
—
Common error: Always write a vector equation as separate equations for the top and bottom entries, then solve them as simultaneous equations.
143IGMC3-7-12r41-11Vectors, magnitude and vector geometryPaper EHard7 marks
Calculator
In a model of a drug, three binding sites are at O (the origin), A and B, with vector OA = a and vector OB = b. The point P lies on AB so that AP : PB = 1 : 2.
Diagram not to scale
(a)
Write down the vector AB in terms of a and b.
(1)
(b)
Show that OP = (2/3)a + (1/3)b.
(2)
(c)
The point R has vector OR = 2a + b. Show that O, P and R lie on a straight line.
(2)
(d)
Now a = (3, 0) and b = (0, 6). Calculate the magnitude of OP. Give your answer correct to 3 significant figures.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 b − a
✓ 1
Part (b)
M1 OP = OA + ⅓ AB
✓ 1
A1 a + ⅓(b − a) = (2/3)a + (1/3)b shown
✓ 1
Part (c)
M1 OR = 3 × OP, or OP = ⅓ OR
✓ 1
R1 the vectors are parallel and share the point O, so O, P and R are collinear
✓ 1
Part (d)
M1 OP = (2, 2) and √(22 + 22)
✓ 1
A1 2.83
✓ 1
Exam tip: To show three points are collinear, show that two vectors between them are multiples of each other and that they share a point.
144IGMC3-7-12r41-12Reflections, rotations, translations and enlargements described in wordsPaper EHard8 marks
No calculator
Triangle T has vertices (2, 2), (6, 2) and (6, 4) on a game grid. It is mapped to triangle U with vertices (2, −1), (0, −1) and (0, −2) by a single enlargement.
(a)
Describe fully the enlargement that maps T onto U.
(3)
(b)
Find the ratio area of U : area of T. Give your answer in the form 1 : n.
(2)
(c)
Find the equation of the straight line through the centre of the enlargement and the vertex (6, 4) of T.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 enlargement
✓ 1
B1 scale factor −½
✓ 1
B1 centre (2, 0)
✓ 1
Part (b)
M1 area of T = ½ × 4 × 2 = 4 and area of U = ½ × 2 × 1 = 1
✓ 1
A1 1 : 4
✓ 1
Part (c)
M1 gradient (4 − 0)/(6 − 2)
✓ 1
A1 gradient 1 and passes through (2, 0)
✓ 1
A1 y = x − 2
✓ 1
Common error: A negative scale factor puts the image on the opposite side of the centre, and its size is the scale factor with the sign ignored.
145IGMC3-7-12r41-13Vectors, magnitude and vector geometryPaper EHard8 marks
Calculator
A pipeline section is modelled by the vector p = (k, 5), where k > 0 and the magnitude of p is 13. A second section is modelled by q = (−3, 4).
(a)
Find the value of k.
(3)
(b)
Find the value of t for which the vector p + tq is horizontal.
(2)
(c)
Calculate the magnitude of 2p − q. Give your answer correct to 3 significant figures.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 k2 + 25 = 169
✓ 1
M1 k2 = 144
✓ 1
A1 k = 12
✓ 1
Part (b)
M1 vertical component 5 + 4t = 0
✓ 1
A1 t = −5/4 (accept −1.25)
✓ 1
Part (c)
M1 2p − q = (27, 6) (using k = 12)
✓ 1
M1 √(272 + 62) = √765
✓ 1
A1 27.7
✓ 1
Exam tip: A vector is horizontal when its vertical component is zero, which gives an equation for the unknown.
146IGMC3-7-11r42-07Vectors, magnitude and vector geometryPaper EHard7 marks
No calculator
In a roof truss, O, A and B are joints with \(\overrightarrow{OA}=\mathbf{a}\) and \(\overrightarrow{OB}=\mathbf{b}\). M is the midpoint of the beam OA and N is the midpoint of the beam AB. A brace joins M to N.
Diagram not to scale
(a)
Write \(\overrightarrow{AB}\) in terms of \(\mathbf{a}\) and \(\mathbf{b}\).
(1)
(b)
Show that \(\overrightarrow{ON}=\frac{1}{2}(\mathbf{a}+\mathbf{b})\).
(2)
(c)
Show that the brace MN is parallel to OB.
(3)
(d)
The length of OB is 9.6 m. Write down the length of the brace MN.
R1 \(\overrightarrow{MN}\) is a scalar multiple of \(\overrightarrow{OB}\), so they are parallel
✓ 1
Part (d)
B1 4.8 m
✓ 1
Exam tip: To show two vectors are parallel, write one as a scalar multiple of the other and state the conclusion.
147IGMC3-7-11r42-08Vectors, magnitude and vector geometryPaper EHard9 marks
No calculator
On a conveyor frame, OABC is a parallelogram with \(\overrightarrow{OA}=\mathbf{a}\) and \(\overrightarrow{OC}=\mathbf{c}\). M is the midpoint of AB. N is the point on the diagonal OB such that \(ON=\frac{2}{3}OB\).
Diagram not to scale
(a)
Find, in terms of \(\mathbf{a}\) and \(\mathbf{c}\), \(\overrightarrow{OB}\) and \(\overrightarrow{OM}\).
(2)
(b)
Find \(\overrightarrow{ON}\) in terms of \(\mathbf{a}\) and \(\mathbf{c}\).
R1 Parallel vectors with the common point C, so C, N, M are collinear
✓ 1
Part (d)
M1 \(NM=CM-CN=\frac{1}{3}CM\) (or CN = ⅔ CM)
✓ 1
A1 2 : 1
✓ 1
Common error: Parallel vectors are not enough to prove three points lie on one line; you must also say that the vectors share a common point.
148IGMC3-7-11r42-11Reflections, rotations, translations and enlargements described in wordsPaper EHard8 marks
Calculator
An architect studies triangle P with vertices (2, 0), (3, 0) and (3, 1) on a coordinate grid. Triangle Q has vertices (4, 2), (7, 2) and (7, 5). Q is the image of P under a single enlargement.
(a)
Describe fully the enlargement that maps P onto Q.
(3)
(b)
Find the area of Q using the area of P and the scale factor.
(3)
(c)
Describe fully the single transformation that maps Q onto P.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 Enlargement
✓ 1
B1 Scale factor 3
✓ 1
B1 Centre (1, −1)
✓ 1
Part (b)
M1 Area of P = 0.5
✓ 1
M1 0.5 × 32
✓ 1
A1 4.5 square units
✓ 1
Part (c)
B1 Enlargement
✓ 1
B1 Scale factor 1/3 and centre (1, −1)
✓ 1
Exam tip: To find the centre of an enlargement, draw lines through corresponding points on the object and image; they meet at the centre. Areas scale by the square of the scale factor.
We use essential cookies to make this site work. With your permission we'd also use analytics and advertising cookies to understand which resources help students most and how families find us. Nothing optional is set unless you accept. Privacy policy
EssentialNeeded for the site and your cookie choice to work.
Always on
AnalyticsAnonymous visit statistics that help improve the free resources.
MarketingMeasures whether ads reach the right families. Off unless you turn it on.