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IAL Physics (Edexcel) · Unit 3 · Topic 3.1AS≈ 25 min read

3.1 Planning experiments and measuring instruments

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AS content: Unit 3 (Practical Skills in Physics I, WPH13), the planning skills. Processing data is on page 3.2 and the core practicals are reviewed on page 3.3.

What this page covers

7 points
  • What a complete plan contains, and how to set it out
  • Choosing apparatus by range and resolution, and judging it with percentage uncertainty
  • Reading vernier calipers (0.1 mm) and micrometer screw gauges (0.01 mm), including zero errors
  • Measuring techniques: avoiding parallax, set squares, fiducial marks, timing many oscillations, repeating and averaging
  • Variables, repeats, hazards and precautions
  • Choosing the graph that tests a relationship and gives the quantity you want
  • Reducing uncertainty and commenting on the physics

In one minute

5 points
  • A plan names every instrument with its resolution, says what is varied, what is measured and what is kept constant, and ends with the graph and how the result comes from it.
  • Choose the instrument whose resolution makes the percentage uncertainty small: uncertainty ≈ half the resolution.
  • Vernier caliper: main scale (mm) + the vernier line that lines up × 0.1 mm. Micrometer: sleeve (to 0.5 mm) + thimble × 0.01 mm.
  • Corrected reading = reading − zero error. A zero error is systematic: repeating does not remove it.
  • Linearise the relationship so the graph is a straight line; the constant you want is in the gradient or intercept.

Contents

14 sections
  1. What does a planning question ask you to do?
  2. How do you choose the right instrument?
  3. How do you read a vernier caliper and a micrometer?
  4. What are zero errors and calibration?
  5. Which techniques make a measurement trustworthy?
  6. How do you handle variables, repeats and safety?
  7. How will the data be used?
  8. How do you reduce uncertainty and comment on the physics?
  9. Exam tips
  10. Common misconceptions
  11. How this topic connects
  12. Key equations
  13. Check your understanding
  14. Specification checklist

What does a planning question ask you to do?

A planning question describes an aim, such as "investigate how the deflection of a strip depends on its length", and asks how you would do it. Every good plan answers the same short list of questions.

Part of the planWhat to write
Variablesthe independent variable (what you change), the dependent variable (what you measure) and every control variable (what you keep the same, and how)
Apparatuseach instrument with its resolution, and why it suits the size of the quantity
Methodnumbered steps: what you set, what you read, where you read it from
Techniquehow you avoid parallax, keep things vertical, reduce timing errors, check zero
Range and repeatshow many values of the independent variable, over what range, and whether repeats are useful
Safetythe real hazard in this experiment and a precaution that deals with it
Analysiswhat you plot against what, why it should be a straight line, and how the result comes from the gradient or intercept
benchG-clamp0.200 kgbox of sandvertical metre ruleset squarepinL = 0.700 my = 42 mmeye level with pin
A planning context: a strip clamped to a bench with a 0.200 kg load at its free end. With L = 0.700 m the end drops y = 42 mm (deflection drawn three times larger for clarity). A pin on the end, a vertical rule checked with a set square and an eye level with the pin give a reliable reading of y.
Exam tip

Write specific detail, not general advice. "Measure carefully" tells the reader nothing; "read the position of the pin against a vertical metre rule (resolution 1 mm) with the eye level with the pin" is a step someone could follow.

How do you choose the right instrument?

Range is the largest (and smallest) value the instrument can measure; it must cover every reading you expect. Resolution is the smallest change the instrument can show: one scale division, or the last digit on a digital display. At IAS level, take the uncertainty in a single reading as half the resolution, and judge an instrument by the percentage uncertainty it gives for the size of quantity you are measuring.

InstrumentTypical resolutionGood for
metre rule1 mmlengths from about 10 cm to 1 m: heights, lengths of wire or string
vernier caliper0.1 mma few mm to about 15 cm: diameters of tubes, rods and balls; internal diameters; depths
micrometer screw gauge0.01 mmbelow about 25 mm: wire diameters, sheet thickness, small balls
digital stopwatch (hand-operated)0.01 stimes of several seconds; reaction time (about 0.2 s) matters more than the resolution
light gate and timer / data logger0.001 s or bettershort times and speeds
top-pan balance0.01 g or 0.1 gmasses of small objects
protractor1°angles of rays, slopes and strings
digital multimeterlast digit, e.g. 0.01 V or 0.001 Acurrent and p.d.; choose the range with the smallest full-scale value that still fits the reading
Worked example 1 Easy · Justify

A student needs the diameter of a copper wire, which is about 0.38 mm. She has a metre rule, a vernier caliper and a micrometer screw gauge. Use percentage uncertainties to justify the choice of instrument.

metre rule ±0.5 mmvernier ±0.05 mmmicrometer ±0.005 mm0255075100125150% uncertainty for d = 0.38 mm132%13%1.3%
Half the resolution of each instrument as a percentage of 0.38 mm. Only the micrometer gives a useful result; its bar is barely visible on the same scale.

Half the resolution: metre rule ±0.5 mm, vernier ±0.05 mm, micrometer ±0.005 mm. Percentage uncertainty = uncertainty ÷ reading × 100%: \(0.5/0.38 \times 100 = 132\%\), \(0.05/0.38 \times 100 = 13\%\), \(0.005/0.38 \times 100 = 1.3\%\).

Micrometer screw gauge: the only instrument giving a percentage uncertainty of a few per cent or less.

Common error

Choosing an instrument because it is "more accurate" without saying why. The reason is that its resolution is small compared with the quantity, so the percentage uncertainty is small. Quote the resolution with a unit.

How do you read a vernier caliper and a micrometer?

Vernier caliper (0.1 mm)

The main scale is marked in millimetres. The sliding vernier scale has 10 divisions that together span 9 mm, so each vernier division is 0.9 mm long, 0.1 mm shorter than a main-scale division.

  1. Read the main scale at the vernier zero: the whole number of millimetres to its left.
  2. Find the vernier line that lines up best with any main-scale line. Its number gives the tenths of a millimetre.
  3. Reading = main-scale millimetres + (number of the coinciding vernier line × 0.1 mm). Record it to 0.1 mm, for example 23.4 mm, never as 23.40 mm.

Close the jaws first: if the vernier zero does not line up with the main zero, there is a zero error. Outside jaws measure external diameters, inside jaws internal diameters, the tail depths. Close gently: squeezing a soft object makes it read small.

01cm0510(a) jaws closed: line 2 coincides → zero error +0.2 mm
(a) Jaws closed: the vernier zero sits just past the main zero and vernier line 2 lines up, so the zero error is +0.2 mm.
23cm0510(b) measuring: 23 mm + 4 × 0.1 mm = 23.4 mm
(b) The vernier zero is just past 23 mm and vernier line 4 lines up with a main-scale line (the 27 mm line): the reading is 23.4 mm.
Worked example 2 Medium · Determine

The scales above show a vernier caliper with its jaws closed (a) and measuring the outside diameter of a plastic pipe (b). Determine the diameter of the pipe and its percentage uncertainty.

Read (b): main scale 23 mm, vernier line 4 coincides, so reading \(= 23 + 4 \times 0.1 = 23.4\) mm. Zero error from (a): +0.2 mm, so diameter \(= 23.4 - 0.2 = 23.2\) mm. Uncertainty = half the resolution = 0.05 mm, so \(0.05/23.2 \times 100 = 0.22\%\).

Common error

Reading the vernier line that sits under the main-scale value instead of the one that lines up with a main-scale line. In (b), vernier line 4 lines up with the 27 mm line: a different main-scale line from the 23 mm you read first, and that is exactly how a vernier works.

Micrometer screw gauge (0.01 mm)

The sleeve has a horizontal datum line with millimetre marks above it and half-millimetre marks below it. The thimble is a screw with a pitch of 0.50 mm: one full turn moves the spindle 0.50 mm. Its edge carries 50 divisions, so each division is \(0.50/50 = 0.01\) mm.

  • Reading = the last mark visible on the sleeve (to 0.5 mm) + (thimble division on the datum line × 0.01 mm). Record to 0.01 mm.
  • Turn the ratchet, not the thimble, to close on the object: the ratchet slips at the same gentle force every time, so soft wires are not squashed and readings are consistent.
  • Check the zero with the anvil and spindle closed (and clean) before measuring.
0515202530← 23 on the datum linesleeve: mm above the datum line, half-mm below itthimble: 50 divisions = 0.50 mm6.5 mm + 23 × 0.01 mm = 6.73 mm
The half-millimetre mark after 6 mm is visible, so the sleeve gives 6.5 mm; thimble division 23 is on the datum line, adding 0.23 mm. The thimble lines are drawn as they appear on a cylinder: closer together away from the datum line.
Worked example 3 Medium · State, Determine

The micrometer above is measuring the diameter of a steel ball bearing. With the anvil and spindle closed, the datum line lies 2 divisions below the zero on the thimble, so the instrument reads −0.02 mm. (a) State the reading shown. (b) Determine the diameter of the ball bearing. (c) Calculate the percentage uncertainty in the diameter.

(a) \(6.5 + 23 \times 0.01 = 6.73\) mm.

(b) Corrected reading = reading − zero error: \(6.73 - (-0.02) = 6.75\) mm. A negative zero error makes every reading too small, so it is added back.

(c) Uncertainty = 0.005 mm, so \(0.005/6.75 \times 100 = 0.074\%\).

Exam tip

The commonest slip is missing the half-millimetre mark: if a mark below the datum line is visible after the last whole millimetre, add 0.50 mm before adding the thimble reading. A thimble reading can never exceed 0.49 mm.

What are zero errors and calibration?

Zero error: a non-zero reading shown by an instrument when the true value is zero.

A zero error adds (or removes) the same amount from every reading: it is a systematic error. Repeating and averaging cannot remove it, so you must correct for it: corrected reading = reading − zero error.

  • Checking zero before use: close the jaws of a caliper or micrometer; switch on a meter with no current or p.d. and check it reads zero; tare (zero) a balance with the empty container on it; check the end of a metre rule is not worn, or measure from the 10.0 cm mark and subtract.
  • Calibration means checking an instrument against known values and correcting for any difference: for example hanging known masses on a newton meter, or placing a thermometer in melting ice (0 °C) and in steam above boiling water (about 100 °C).
012345601234567independent variablereadingtrue valueswith a zero error of +1same shift everywhere
On a graph, a zero error moves the whole line up or down: it changes the intercept but not the gradient. This is one reason to take a result from a gradient.
Common error

Adding a positive zero error instead of subtracting it: a +0.2 mm zero error makes every reading 0.2 mm too big, so take 0.2 mm away.

Which techniques make a measurement trustworthy?

Avoiding parallax

Parallax error occurs when a pointer (or meniscus) is not touching the scale and the eye is not level with it. Put the eye at the same level as the pointer, perpendicular to the scale; move the scale as close to the pointer as possible; for meters, use one with a mirror behind the pointer and line the pointer up with its image.

pointer 20 mm in fronteye 50 mm above → 417.6 mmeye level → 412.0 mmeye 50 mm below → 406.4 mmscalereadingsincreasedownwards
Drawn to scale: a pointer 20 mm in front of a scale, viewed from 200 mm away. Level, the reading is 412.0 mm. An eye 50 mm too high reads 417.6 mm; 50 mm too low reads 406.4 mm.
Worked example 4 Medium · Calculate, Suggest

A spring hangs beside a vertical metre rule, with readings increasing downwards. A pointer on the bottom of the spring is 20 mm in front of the rule. A student's eye is 200 mm from the rule and 50 mm above the pointer when she reads the stretched position. The unstretched reading was 350.0 mm and the true stretched reading is 412.0 mm. (a) Calculate the reading she obtains. (b) Calculate the percentage error this causes in the extension. (c) Suggest two ways to avoid it.

(a) Similar triangles: the line of sight drops 50 mm over 180 mm, so over a further 20 mm it drops \(50 \times 20/180 = 5.6\) mm. Reading \(= 412.0 + 5.6 = 417.6\) mm.

(b) True extension \(= 412.0 - 350.0 = 62\) mm, so \(5.6/62 \times 100 = 9\%\), far larger than the 0.5 mm reading uncertainty.

(c) Eye level with the pointer, looking perpendicular to the rule; move the rule (or pointer) so they almost touch.

Other techniques worth naming

  • Set square: stand it on the bench against a metre rule to check the rule is vertical, or use it to line up the bottom of an object with the scale. A spirit level does the same job for horizontal surfaces.
  • Fiducial mark: a fixed reference line or pin at the centre of an oscillation (where the object moves fastest), so each pass is timed at the same, sharply defined point.
  • Time many cycles: time 10 or 20 oscillations and divide. The reaction-time error happens once at the start and once at the end, so it is shared across all the cycles.
  • Several places and directions: measure a wire's diameter at several points, turning the micrometer through 90° each time, and take the mean.
  • Electronic timing (light gates) removes reaction time for short events.
clampfiducial mark at the centre of the swinghacksaw bladesmall mass
A vertical hacksaw blade with a small mass on top. The fiducial mark sits at the centre of the swing, where the blade moves fastest, so each pass is timed at a sharply defined instant.
Worked example 5 Medium · Calculate, Explain

A hacksaw blade is clamped vertically with a small mass on its top and set vibrating. A student times single oscillations three times: 0.40 s, 0.47 s, 0.37 s. He then times 20 oscillations three times: 8.46 s, 8.31 s, 8.55 s. (a) Calculate the period and its percentage uncertainty from each set. (b) Explain why timing 20 oscillations is better. (c) Suggest one further improvement.

(a) Single oscillations: mean = 0.41 s; uncertainty = half the range \(= (0.47 - 0.37)/2 = 0.05\) s; percentage \(= 0.05/0.413 \times 100 = 12\%\). Twenty oscillations: mean = 8.44 s; uncertainty \(= (8.55 - 8.31)/2 = 0.12\) s; percentage \(= 0.12/8.44 \times 100 = 1.4\%\); period \(= 8.44/20 = 0.422\) s (1.4%).

(b) The reaction-time error at start and stop is about the same, but it is now spread over a time 20 times longer, so it is a much smaller fraction of the total and the percentage uncertainty falls sharply (1.4% instead of 12%).

(c) A fiducial mark at the centre of the swing; start the count at "zero" as the blade passes it.

How do you handle variables, repeats and safety?

VariableMeaningIn the cantilever experiment
independentthe one you deliberately changelength L beyond the bench edge
dependentthe one you measure as a resultend deflection y
controleverything else that could affect the result, kept constantsame load, same strip (width and thickness), load hung at the same distance from the free end, same clamp position
  • For each control variable say how it is kept constant ("use the same 0.200 kg mass throughout"), not just that it is: "fair test" alone is not an answer.
  • Range and number of readings: at least five or six values of the independent variable, spread across the widest range the apparatus allows, so the shape of the graph is clear.
  • Repeats are useful when readings scatter randomly: timing by hand, rebound heights, readings that drift. Repeat, check for an anomaly, and take the mean.
  • Repeats are not useful when the reading cannot change (a steady digital display, a fixed length), or when the measurement changes the object (a wire stretched beyond its elastic limit, a sample that is destroyed). Then say why, and take readings at more values instead.

For safety, give a hazard that belongs to this experiment and a precaution that deals with it; "wear goggles" only when something could hit the eyes.

HazardWhere it appearsPrecaution
falling massesloaded strips, springs, wires under tensionbox of sand or foam under the load; keep feet clear; clamp the stand to the bench
wire or string snapping and whippingstretching wires, tensioned stringssafety goggles; cover the wire; stand to one side of it, not in line with it
hot componentsresistance wire, filament lamps carrying large currentskeep currents small; switch off between readings; let parts cool before touching
laser lightdiffraction and refraction experimentslow-power laser; never look along the beam; keep beam below eye level; remove reflective objects
water near electrical equipmentripple tanks, heating experimentskeep supplies away from water; use low-voltage supplies; mop spills at once
a tall stand topplinglong pendulums, drop experiments from heightclamp the base or add a counterweight

How will the data be used?

Rearrange the equation linking the variables into the form \(y = mx + c\) and plot the y-quantity against the x-quantity. State the expected shape ("a straight line through the origin" confirms a proportional relationship) and what the gradient or intercept equals.

RelationshipPlotGradient
\(y = \dfrac{4WL^3}{Ebd^3}\) (cantilever)y against \(L^3\)\(\dfrac{4W}{Ebd^3}\)
\(v^2 = u^2 + 2as\)\(v^2\) against s2a (intercept \(u^2\))
\(R = \rho l/A\)R against l\(\rho/A\)
\(I = P/4\pi r^2\)I against \(1/r^2\)\(P/4\pi\)
00.10.20.30.40.50.60.70.80.9010203040506070L / my / mmcurved: the relationship is hard to test
Specimen results for the cantilever: y = 3, 8, 15, 26, 42, 62 mm for L = 0.300 m to 0.800 m in steps of 0.100 m. Plotted directly, the points lie on a curve, and you cannot tell by eye whether it is a cube law.
00.10.20.30.40.5010203040506070L³ / m³y / mm0.45 m³54.7 mm
The same data plotted as y against L³ lie on a straight line through the origin, so y ∝ L³. The gradient triangle runs from (0.05 m³, 6.0 mm) to (0.50 m³, 60.7 mm).
Worked example 6 Hard · Plan, Determine

A wooden strip 25.0 mm wide and 6.0 mm thick is clamped to a bench, as in the first figure. A load of weight \(W = 0.200 \times 9.81 = 1.96\) N hangs from its free end. Theory predicts \(y = \dfrac{4WL^3}{Ebd^3}\), where L is the length beyond the bench, b the width, d the thickness and E the Young modulus of the wood. (a) Write a plan to test the relationship and find E. (b) Use the graph above to determine E.

(a) Variables: vary L; measure y; keep W, the strip and the load position fixed. Measurements: L with a metre rule (1 mm) from the bench edge to the hanger; y as the change in the pin's position on a vertical metre rule, unloaded then loaded; b with a vernier (0.1 mm) and d with a micrometer (0.01 mm), each at several places, averaged. Technique and safety: rule checked vertical with a set square; eye level with the pin; six lengths from 0.300 m to 0.800 m; box of sand under the load. Analysis: plot y against L³: a straight line through the origin confirms the relationship; gradient \(= 4W/(Ebd^3)\).

(b) Gradient \(= (60.7 - 6.0)\) mm ÷ \((0.50 - 0.05)\) m³ \(= 122\) mm m⁻³ \(= 0.122\) m m⁻³. Then \(E = \dfrac{4 \times 1.96}{0.0250 \times 0.0060^3 \times 0.122}\), so \(E = 1.2 \times 10^{10}\) Pa.

Note the unit conversion: y was in mm, so divide the gradient by 1000 before using it in SI units.

How do you reduce uncertainty and comment on the physics?

  • Find the biggest source of uncertainty: the measurement with the largest percentage uncertainty. In the cantilever data the smallest deflection, 3 mm, read to ±0.5 mm, is uncertain by 17%, far more than any length.
  • Reduce it by making the quantity bigger (longer lengths or heavier loads, within the elastic limit), by choosing an instrument with a finer resolution (a travelling microscope or a vernier for small deflections), or by measuring many units at once (20 oscillations; the thickness of 10 sheets).
  • Systematic errors (zero errors, a rule that is not vertical, a thermometer that reads high) shift every reading the same way. Remove them by checking zero, calibrating and using good technique; repeats do not help.
  • Random errors scatter readings either side of the true value. Reduce their effect by repeating and averaging and by plotting a graph.
  • Commenting on the physics: link the result to its context. Is the value sensible for the material? Would the relationship still hold for very large deflections (no: the theory assumes small ones)? What does the result mean for a real use, such as a shelf or a diving board?
Exam tip

When asked to "suggest an improvement", tie it to a named source of uncertainty and say what it changes: "use a travelling microscope to measure y, because the deflections are only a few millimetres and ±0.5 mm is a large percentage of them".

Exam tips for 3.1

Exam tip 1 — name the instrument and its resolution

Every quantity in a plan needs an instrument, and every instrument needs a resolution with a unit: "micrometer screw gauge, resolution 0.01 mm".

Exam tip 2 — number your method, end with the graph

Short numbered steps show that each measurement, control and repeat is covered. The last step states what is plotted against what, the expected shape, and what the gradient or intercept equals: a plan without analysis cannot give a result.

Exam tip 3 — make safety specific

Give one real hazard of this experiment and a precaution that removes it. If the risk is genuinely low, say so briefly and give the one sensible precaution.

Exam tip 4 — read the command word

State needs a short answer; describe needs the steps; explain needs a reason linked to physics; suggest means apply what you know to an unfamiliar situation; justify a choice by comparing percentage uncertainties.

Common misconceptions

MisconceptionWhy it is wrongCorrect idea
Repeating readings removes a zero error.A zero error shifts every reading by the same amount, so the mean is shifted too.Correct each reading (reading − zero error) or take the result from a gradient.
A more expensive instrument is always the better choice.What matters is resolution compared with the size of the quantity, and range.Choose the instrument that gives a small percentage uncertainty and covers the range.
A vernier reading can be written as 23.40 mm.The vernier resolves 0.1 mm; the extra zero claims a precision it does not have.Record vernier readings to 0.1 mm and micrometer readings to 0.01 mm.
Timing one oscillation many times is as good as timing many oscillations once.Each single timing still carries the full reaction-time error on a short time.Time 10–20 oscillations so the error is a small fraction of the total.
"Keep it a fair test" is enough for the control variables.It names no variable and no method.Name each control variable and how it is kept constant.
Parallax is a random error.If the eye is always too high, every reading shifts the same way.Parallax can be systematic; avoid it by keeping the eye level and perpendicular to the scale.

How this topic connects

3.2 Uncertainties and graphs; 3.3 Core practicals

Page 3.2 covers recording, plotting and evaluating the readings (significant figures, half-range uncertainties, best-fit lines, gradients). Every core practical uses the instruments and techniques on this page.

Materials (Unit 1)

The Young modulus and Hooke's law supply many planning contexts; measuring a wire's diameter with a micrometer is the key step in finding stress.

6.1 Planning at A2

The same planning skills return with A2 physics, together with combined uncertainties, precision, accuracy and sensitivity.

Key equations

EquationUseIn the formulae list?
uncertainty of one reading = ½ × resolutionsingle readings at IASNo — learn it
percentage uncertainty = (uncertainty ÷ value) × 100%comparing instruments; finding the biggest source of uncertaintyNo — learn it
vernier reading = main-scale mm + n × 0.1 mmvernier caliper, n = coinciding vernier lineNo — learn it
micrometer reading = sleeve (to 0.5 mm) + n × 0.01 mmmicrometer, n = thimble division on the datum lineNo — learn it
corrected reading = reading − zero errorany instrument with a zero error (keep the sign of the zero error)No — learn it
period = (time for N oscillations) ÷ Ntiming many cyclesNo — derive it

Check your understanding

1. On a vernier caliper the vernier zero is just past the 41 mm mark and vernier line 6 lines up with a main-scale line. What is the reading?

\(41 + 6 \times 0.1 = 41.6\) mm. (Vernier line 6 lines up with the 47 mm line: \(41.6 + 6 \times 0.9 = 47.0\).)

2. A micrometer sleeve shows the 3 mm mark and the half-millimetre mark after it; thimble division 12 is on the datum line. What is the reading?

\(3.5 + 12 \times 0.01 = 3.62\) mm.

3. An ammeter reads 0.02 A before the circuit is switched on. It then reads 0.46 A. What is the current?

The zero error is +0.02 A, so the current is \(0.46 - 0.02 = 0.44\) A. Better still, zero the meter before use.

4. Why should the diameter of a wire be measured at several points and in two perpendicular directions?

The wire may not be uniform along its length or perfectly circular; the mean of several readings is a better estimate, and the spread shows how variable it is.

5. A trolley is released from rest on a ramp and a light gate measures its speed v after it has rolled a distance s. Which graph gives the acceleration, and how?

From rest, \(v^2 = 2as\). Vary s and plot \(v^2\) against s: a straight line through the origin with gradient 2a, so a = gradient ÷ 2.

Specification checklist

The labels P1–P10 are our shorthand for the Unit 3 planning skills in the specification.

  • (P1) I can choose the most suitable apparatus for each measurement and state its range and resolution.
  • (P2) I can read a vernier caliper to 0.1 mm and a micrometer screw gauge to 0.01 mm, and correct for a zero error.
  • (P3) I can explain how to check that an instrument reads zero and how to calibrate it.
  • (P4) I can describe techniques that improve a measurement: avoiding parallax, using a set square, a fiducial mark, timing many cycles, repeating and averaging.
  • (P5) I can identify the independent, dependent and control variables and say how each control is kept constant.
  • (P6) I can decide whether repeat readings are appropriate and justify the decision.
  • (P7) I can identify the real hazards of an experiment and describe precautions that deal with them.
  • (P8) I can say how the data will be used: which graph to plot, its expected shape and what the gradient or intercept gives.
  • (P9) I can identify the main sources of uncertainty and systematic error and suggest how to reduce them.
  • (P10) I can comment on what a result means in the context of the physics being investigated.