Original exam-style questions with full mark schemes. Use the filters to choose level and difficulty, and tick questions to build a printable test.
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Fullmark schemes
Original questions in the style of each exam boardFull worked mark schemes with method and accuracy marksCreated by Evan Kotronis with AI assistanceUpdated 15 October 2026 · new questions added continuouslyFree access until 30 November 2026How every question is checked →
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1IGMC-041-01-01Fractions, decimals and percentagesPaper CEasy4 marks
No calculator
Show all your working. Give each answer as a fraction in its simplest form.
(a)
Work out \(2\frac{3}{4} - 1\frac{5}{6}\).
(2)
(b)
Work out \(\frac{3}{5} \div \frac{9}{10}\).
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 for converting to improper fractions over a common denominator, e.g. \(\frac{33}{12} - \frac{22}{12}\)
✓ 1
A1 \(\frac{11}{12}\)
✓ 1
Part (b)
M1 for \(\frac{3}{5} \times \frac{10}{9}\) or equivalent, e.g. \(\frac{30}{45}\)
✓ 1
A1 \(\frac{2}{3}\)
✓ 1
Exam tip: Without a calculator, you must show the common denominator or the 'multiply by the reciprocal' step. A correct answer alone may not earn the method mark.
2IGMC-041-01-02Fractions, decimals and percentagesPaper CEasy4 marks
Calculator
A jacket normally costs $64.
(a)
In a sale, the price of the jacket is reduced by 15%. Work out the sale price.
(2)
(b)
The shop bought the jacket for $40 and sells it at the normal price of $64. Work out the percentage profit.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 for 64 × 0.85 or 64 − 0.15 × 64
✓ 1
A1 $54.40
✓ 1
Part (b)
M1 for \(\frac{64-40}{40}\) × 100 or \(\frac{64}{40}\) × 100 − 100
✓ 1
A1 60%
✓ 1
Common error: Percentage profit is calculated on the cost price ($40), not the selling price. Dividing 24 by 64 gives 37.5%, which is wrong.
3IGMC-041-01-03Fractions, decimals and percentagesPaper CEasy4 marks
No calculator
(a)
Write 0.35 as a fraction in its simplest form.
(1)
(b)
Write \(\frac{3}{8}\) as a percentage.
(1)
(c)
Write these numbers in order of size, starting with the smallest. 0.38 \(\frac{3}{8}\) 37% \(\frac{7}{20}\)
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 \(\frac{7}{20}\)
✓ 1
Part (b)
B1 37.5%
✓ 1
Part (c)
M1 for converting all four to the same form, e.g. 0.38, 0.375, 0.37, 0.35
✓ 1
A1 \(\frac{7}{20}\), 37%, \(\frac{3}{8}\), 0.38
✓ 1
Exam tip: When ordering, convert everything to decimals and write the decimals down. Then give the final answer using the original numbers, not the decimals.
4IGMC-041-01-04Fractions, decimals and percentagesPaper CEasy4 marks
Calculator
There are 840 students in a school.
(a)
45% of the students walk to school. Work out how many students walk to school.
(1)
(b)
126 students cycle to school. Work out the percentage of students who cycle to school.
(1)
(c)
All the other students travel by bus. Write the fraction of students who travel by bus in its simplest form.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 378
✓ 1
Part (b)
B1 15%
✓ 1
Part (c)
M1 for 100 − 45 − 15 (= 40%) or 840 − 378 − 126 (= 336)
✓ 1
A1 \(\frac{2}{5}\)
✓ 1
Common error: Leaving the answer to (c) as \(\frac{336}{840}\) or 40% loses the accuracy mark. The question asks for a fraction in its simplest form.
5IGMC-041-01-05Fractions, decimals and percentagesPaper CEasy3 marks
Calculator
Kofi invests $2500 in a savings account. The account pays simple interest at a rate of 3.2% per year.
(a)
Work out the interest Kofi earns in 4 years.
(2)
(b)
Work out the total amount in the account after 4 years.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 for 2500 × 0.032 × 4 or \(\frac{2500 \times 3.2 \times 4}{100}\)
✓ 1
A1 $320
✓ 1
Part (b)
B1 $2820, or FT 2500 + their answer to (a)
✓ 1
Common error: Simple interest is the same every year. Using the multiplier 1.032⁴ is compound interest and gives the wrong answer here.
6IGMC-041-03-01Estimation, rounding, bounds, ratio, proportion and moneyPaper CEasy3 marks
No calculator
(a)
Write 0.0047386 correct to 3 significant figures.
(1)
(b)
By rounding each number to 1 significant figure, estimate the value of \(\frac{48.7 \times 3.12}{0.198}\). Show all your working.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1: 0.00474
✓ 1
Part (b)
M1: \(\frac{50 \times 3}{0.2}\) seen
✓ 1
A1: 750
✓ 1
Common error: Leading zeros are not significant. 0.0047386 starts its significant figures at the 4, so 3 s.f. gives 0.00474, not 0.005.
7IGMC-041-03-02Estimation, rounding, bounds, ratio, proportion and moneyPaper CEasy4 marks
No calculator
Amira, Ben and Chen share 360 dollars in the ratio Amira : Ben : Chen = 2 : 3 : 4.
(a)
Work out how much Chen receives.
(2)
(b)
Chen then gives one quarter of his share to Amira. Find the new ratio Amira : Ben : Chen in its simplest form.
M1: new amounts 120, 120, 120 dollars (Amira 80 + 40, Ben 120, Chen 160 − 40)
✓ 1
A1: 1 : 1 : 1
✓ 1
Exam tip: Find the value of one share first (total ÷ sum of the ratio parts). Every other amount then follows by multiplying.
8IGMC-041-03-03Estimation, rounding, bounds, ratio, proportion and moneyPaper CEasy4 marks
No calculator
The side length of a square tile is 12.4 cm, correct to the nearest 0.1 cm.
(a)
Write down the lower bound and the upper bound of the side length.
(2)
(b)
Calculate the upper bound of the perimeter of the tile.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1: lower bound 12.35 cm
✓ 1
B1: upper bound 12.45 cm
✓ 1
Part (b)
M1: 4 × 12.45
✓ 1
A1: 49.8 cm
✓ 1
Common error: The upper bound is 12.45, not 12.44 or 12.449. Use the half-unit either side of the rounded value.
9IGMC-041-03-04Estimation, rounding, bounds, ratio, proportion and moneyPaper CEasy5 marks
Calculator
The exchange rate is 1 euro (€) = 1.08 US dollars ($).
(a)
Change €250 into dollars.
(1)
(b)
Change $500 into euros. Give your answer correct to the nearest cent.
(2)
(c)
A jacket costs €85 in Paris and $95 in New York. Find which city sells the jacket more cheaply and by how many dollars.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1: $270
✓ 1
Part (b)
M1: 500 ÷ 1.08
✓ 1
A1: €462.96
✓ 1
Part (c)
M1: 85 × 1.08 = 91.80
✓ 1
A1: Paris, by $3.20
✓ 1
Exam tip: Check your conversion makes sense: one euro is worth more than one dollar, so the number of euros should be smaller than the number of dollars.
10IGMC-041-03-05Estimation, rounding, bounds, ratio, proportion and moneyPaper CEasy4 marks
No calculator
A recipe for 6 muffins uses 150 g of flour, 2 eggs and 90 ml of milk. The recipe can be scaled up or down to make any whole number of muffins.
(a)
Work out the mass of flour needed for 15 muffins.
(2)
(b)
Lina has 7 eggs and plenty of every other ingredient. Find the greatest number of muffins she can make.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1: 150 ÷ 6 × 15 or 150 × 2.5
✓ 1
A1: 375 g
✓ 1
Part (b)
M1: 6 ÷ 2 = 3 muffins per egg, or 7 ÷ 2 × 6
✓ 1
A1: 21
✓ 1
Exam tip: Work out the amount for one muffin (or one egg) first. Then scale up to any number.
11IGMC-041-00-01Types of number, factors, HCF and LCMPaper CEasy5 marks
No calculator
Here is a list of numbers.
9 17 21 25 31 36 39 64
From the list, write down
(a)
all the prime numbers,
(2)
(b)
all the square numbers,
(1)
(c)
a cube number,
(1)
(d)
a multiple of 13.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 for at least one of 17 or 31 correctly listed, with at most one incorrect number included
✓ 1
B1 for 17 and 31 only, with no other numbers included
✓ 1
Part (b)
B1 for 9, 25, 36 and 64 only
✓ 1
Part (c)
B1 for 64
✓ 1
Part (d)
B1 for 39
✓ 1
Common error: 21 and 39 are odd but not prime: 21 = 3 × 7 and 39 = 3 × 13. Test each odd number for small prime divisors before calling it prime.
12IGMC-041-00-02Types of number, factors, HCF and LCMPaper CEasy3 marks
No calculator
(a)
Write 360 as a product of its prime factors. Give your answer in index form.
(2)
(b)
Find the smallest positive integer k such that 360k is a square number.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 for a correct method, e.g. a factor tree or repeated division reaching 2, 2, 2, 3, 3, 5
✓ 1
A1 for 23 × 32 × 5
✓ 1
Part (b)
B1 for 10
✓ 1
Exam tip: A square number has every prime power even in its prime factorisation. Here 2³ needs one more 2 and 5 needs one more 5, so multiply by 2 × 5.
13IGMC-041-00-03Types of number, factors, HCF and LCMPaper CEasy4 marks
No calculator
(a)
List all the factors of 18.
(2)
(b)
Find the highest common factor (HCF) of 18 and 24.
(1)
(c)
Find the lowest common multiple (LCM) of 18 and 24.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B2 for 1, 2, 3, 6, 9, 18 with no extras
✓ 2
[B1 for at least 4 correct factors with no more than one incorrect]
—
Part (b)
B1 for 6
✓ 1
Part (c)
B1 for 72
✓ 1
Common error: Multiplying 18 × 24 = 432 gives a common multiple, but not the lowest one. List multiples of 24 until one is divisible by 18.
14IGMC-041-00-04Types of number, factors, HCF and LCMPaper CEasy3 marks
No calculator
At a bus station, a red bus leaves every 12 minutes and a blue bus leaves every 20 minutes. Both buses leave together at 08 00.
(a)
Find the next time both buses leave together.
(2)
(b)
Find how many times the two buses leave together from 08 00 to 13 00, including both of these times.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 for finding the LCM of 12 and 20 as 60, or listing multiples of 12 and 20 to 60
✓ 1
A1 for 09 00
✓ 1
Part (b)
B1 for 6
✓ 1
Exam tip: When the question says "including both of these times", count the start time as well: 5 hours gives 5 gaps but 6 departure times.
15IGMC-041-00-05Types of number, factors, HCF and LCMPaper CEasy4 marks
No calculator
(a)
From this list, write down the irrational numbers.
√5 0.25 2π √49 \(\frac{7}{9}\) ∛27
(2)
(b)
Write down an integer between √50 and √70.
(1)
(c)
Write down the prime number between 40 and 50 that is 1 more than a multiple of 6.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 for √5
✓ 1
B1 for 2π, with no incorrect numbers included
✓ 1
Part (b)
B1 for 8
✓ 1
Part (c)
B1 for 43
✓ 1
Common error: √49 = 7 and ∛27 = 3 are whole numbers, so they are rational. A root is only irrational when it does not simplify to a whole number or fraction.
16IGMC-041-02-01Indices, standard form and surdsPaper CEasy4 marks
No calculator
Simplify each expression.
(a)
\(x^5 \times x^3\)
(1)
(b)
\(\frac{y^{12}}{y^4}\)
(1)
(c)
\((2p^3)^4\)
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1: \(x^8\)
✓ 1
Part (b)
B1: \(y^8\)
✓ 1
Part (c)
B1: coefficient 16
✓ 1
B1: \(p^{12}\), giving \(16p^{12}\)
✓ 1
Common error: In (c) the power 4 applies to the 2 as well as to \(p^3\). Writing \(2p^{12}\) or \(8p^{12}\) loses a mark.
17IGMC-041-02-02Indices, standard form and surdsPaper CEasy4 marks
No calculator
Answer each part.
(a)
Write 0.000 407 in standard form.
(1)
(b)
Write 6.3 ×105 as an ordinary number.
(1)
(c)
Work out (4 ×106) × (7 ×10−2). Give your answer in standard form.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1: 4.07 ×10−4
✓ 1
Part (b)
B1: 630 000
✓ 1
Part (c)
M1: 28 ×104 or 280 000 seen
✓ 1
A1: 2.8 ×105
✓ 1
Exam tip: 28 ×10⁴ is not in standard form. The first number must be at least 1 and less than 10, so adjust the power of ten.
18IGMC-041-02-03Indices, standard form and surdsPaper CEasy4 marks
No calculator
Answer each part.
(a)
Write down the value of \(7^0\).
(1)
(b)
Find the value of \(3^{-2}\) as a fraction.
(1)
(c)
Find the value of \(n\) when \(2^n = \frac{1}{32}\).
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1: 1
✓ 1
Part (b)
B1: \(\frac{1}{9}\)
✓ 1
Part (c)
M1: \(32 = 2^5\) or \(\frac{1}{32} = 2^{-5}\) seen
✓ 1
A1: \(n = -5\)
✓ 1
Common error: A negative power gives a reciprocal, not a negative number. \(3^{-2}\) is \(\frac{1}{9}\), not \(-9\) or \(-6\).
19IGMC-041-01-06Fractions, decimals and percentagesPaper CMedium6 marks
Calculator
The monthly rent of a flat increased by 12%. The new monthly rent is $1008.
(a)
Work out the monthly rent before the increase.
(2)
(b)
The following year, the monthly rent of $1008 decreased by 12%. Work out the new monthly rent.
(2)
(c)
Work out the overall percentage change from the original rent to the rent in part (b). State whether it is an increase or a decrease.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 for 1008 ÷ 1.12
✓ 1
A1 $900
✓ 1
Part (b)
M1 for 1008 × 0.88
✓ 1
A1 $887.04
✓ 1
Part (c)
M1 for \(\frac{900 - 887.04}{900}\) × 100 or \(\frac{887.04}{900}\) × 100
✓ 1
A1 1.44% decrease
✓ 1
Common error: In part (a), finding 12% of $1008 and subtracting it gives $887.04, which is wrong. The $1008 is 112% of the original, so divide by 1.12.
20IGMC-041-01-07Fractions, decimals and percentagesPaper CMedium6 marks
No calculator
Amira receives her monthly pay. She spends \(\frac{2}{5}\) of it on rent. She then spends \(\frac{1}{4}\) of the remaining money on food.
(a)
Show that the fraction of her pay that she spends on food is \(\frac{3}{20}\).
(2)
(b)
Work out the fraction of her pay that is left after rent and food.
(2)
(c)
Amira has $360 left after paying for rent and food. Work out her monthly pay.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 for remaining fraction \(1 - \frac{2}{5} = \frac{3}{5}\)
M1 for \(1 - \frac{2}{5} - \frac{3}{20}\) or \(\frac{3}{5} - \frac{3}{20}\)
✓ 1
A1 \(\frac{9}{20}\)
✓ 1
Part (c)
M1 for 360 ÷ \(\frac{9}{20}\) or 360 ÷ 9 × 20
✓ 1
A1 $800
✓ 1
Common error: \(\frac{1}{4}\) is a fraction of the money left after rent, not of the whole pay. Adding \(\frac{2}{5} + \frac{1}{4}\) directly gives the wrong fraction.
21IGMC-041-01-09Fractions, decimals and percentagesPaper CMedium5 marks
Calculator
A car is bought for $18 500. Its value decreases by 14% each year.
(a)
Work out the value of the car after 3 years.
(3)
(b)
Work out the total percentage of the original value that the car has lost after 3 years.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 for multiplier 0.86 seen
✓ 1
M1 for 18 500 × 0.863
✓ 1
A1 $11 767.04 (accept $11 800)
✓ 1
Part (b)
M1 for (1 − 0.863) × 100 or \(\frac{18500 - 11767.04}{18500}\) × 100
✓ 1
A1 36.4%
✓ 1
Common error: The car does not lose 3 × 14% = 42%. Each year's 14% is taken from a smaller value, so the total loss is less than 42%.
22IGMC-041-01-11Fractions, decimals and percentagesPaper CMedium5 marks
Calculator
The cash price of a television is $750. The television can also be bought on hire purchase by paying a deposit of 20% of the cash price followed by 12 monthly payments of $54.50.
(a)
Work out the deposit.
(1)
(b)
Work out the total cost of buying the television on hire purchase.
(2)
(c)
Work out how much more the hire purchase cost is than the cash price, as a percentage of the cash price.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 $150
✓ 1
Part (b)
M1 for 150 + 12 × 54.50
✓ 1
A1 $804
✓ 1
Part (c)
M1 for \(\frac{804 - 750}{750}\) × 100
✓ 1
A1 7.2%
✓ 1
Common error: Remember to add the deposit to the monthly payments. Using only 12 × $54.50 = $654 makes hire purchase look cheaper than paying cash.
23IGMC-041-03-06Estimation, rounding, bounds, ratio, proportion and moneyPaper CMedium4 marks
No calculator
8 workers take 15 days to build a wall. All workers work at the same rate.
(a)
Work out how many days 12 workers would take to build the same wall.
(2)
(b)
The wall must be built in 6 days. Find how many workers are needed in addition to the original 8.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1: 8 × 15 = 120 (worker-days)
✓ 1
A1: 10 days
✓ 1
Part (b)
M1: 120 ÷ 6 = 20
✓ 1
A1: 12
✓ 1
Common error: More workers means fewer days, so this is inverse proportion. Multiplying 15 by 12/8 gives a longer time, which cannot be right.
24IGMC-041-03-09Estimation, rounding, bounds, ratio, proportion and moneyPaper CMedium5 marks
Calculator
Priya invests $4500 at a rate of 3.2% per year compound interest.
(a)
Calculate the value of her investment at the end of 5 years. Give your answer correct to the nearest cent.
(2)
(b)
Sam also invests $4500 for 5 years, but at r% per year simple interest. At the end of 5 years Sam's investment has the same value as Priya's. Find r.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1: 4500 × 1.0325
✓ 1
A1: $5267.58
✓ 1
Part (b)
M1: total interest 5267.58 − 4500 = 767.58
✓ 1
M1: 767.58 ÷ (5 × 4500) × 100
✓ 1
A1: 3.41
✓ 1
Common error: Simple interest is the same each year, so divide the total interest by the number of years. Do not divide the final amount by 5.
25IGMC-041-03-10Estimation, rounding, bounds, ratio, proportion and moneyPaper CMedium5 marks
No calculator
A bag contains only red and blue counters. The ratio red : blue = 5 : 3. 12 blue counters are added to the bag. The ratio red : blue becomes 5 : 6.
(a)
Find the number of red counters in the bag.
(3)
(b)
Some red counters are now removed from the bag. The ratio red : blue becomes 1 : 2. Find how many red counters are removed.
Exam tip: Notice the number of red counters does not change when blue counters are added. Using a multiplier k lets you write both ratios as equations.
26IGMC-041-03-11Estimation, rounding, bounds, ratio, proportion and moneyPaper CMedium6 marks
Without using your calculator, estimate the value of E by rounding each number to 1 significant figure. Show your working.
(2)
(b)
Use your calculator to find the value of E. Give your answer correct to 3 significant figures.
(2)
(c)
Calculate the percentage error in your estimate, using the unrounded value of E.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1: \(\frac{60 \times 0.4}{\sqrt{9 + 7}}\) seen
✓ 1
A1: 24 ÷ 4 = 6
✓ 1
Part (b)
M1: 24.3492 ÷ √16.14 or 24.3492 ÷ 4.0174…
✓ 1
A1: 6.06
✓ 1
Part (c)
M1: (6.0608… − 6) ÷ 6.0608… × 100
✓ 1
A1: 1.00%
✓ 1
Common error: Percentage error is divided by the accurate value, not the estimate. Use the unrounded calculator value, not 6.06.
27IGMC-041-00-06Types of number, factors, HCF and LCMPaper CMedium6 marks
No calculator
A = 24 × 32 × 7 B = 22 × 33 × 5
(a)
Find the highest common factor (HCF) of A and B. Give your answer as an ordinary number.
(2)
(b)
Find the lowest common multiple (LCM) of A and B. Give your answer as an ordinary number.
(2)
(c)
Find the smallest positive integer n such that An is a cube number.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 for 22 × 32
✓ 1
A1 for 36
✓ 1
Part (b)
M1 for 24 × 33 × 5 × 7
✓ 1
A1 for 15 120
✓ 1
Part (c)
M1 for identifying that 22, 3 and 72 are needed, e.g. 22 × 3 × 72
✓ 1
A1 for 588
✓ 1
Exam tip: For the HCF take the lower power of each prime common to both numbers; for the LCM take the higher power of every prime that appears in either.
28IGMC-041-00-07Types of number, factors, HCF and LCMPaper CMedium5 marks
Calculator
A rectangular floor measures 4.2 m by 3.15 m. It is to be covered completely with identical square tiles, with no cutting and no gaps. The side length of each tile is a whole number of centimetres.
(a)
Find the largest possible side length of a tile.
(3)
(b)
Find the number of tiles needed when this largest tile is used.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 for converting to 420 cm and 315 cm
✓ 1
M1 for a method for the HCF, e.g. 420 = 22 × 3 × 5 × 7 and 315 = 32 × 5 × 7
✓ 1
A1 for 105 cm
✓ 1
Part (b)
M1 for (420 ÷ 105) × (315 ÷ 105) or 4 × 3
✓ 1
A1 for 12
✓ 1
Common error: Working in metres hides the HCF. Convert both lengths to centimetres first so that you are finding the HCF of two whole numbers.
29IGMC-041-00-08Types of number, factors, HCF and LCMPaper CMedium4 marks
No calculator
A shop has 84 red sweets and 126 green sweets. All the sweets are packed into identical bags. Each bag contains the same number of red sweets and the same number of green sweets, and no sweets are left over.
(a)
Find the greatest number of bags that can be made.
(3)
(b)
Find the total number of sweets in each bag.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 for 84 = 22 × 3 × 7 or 126 = 2 × 32 × 7, or a correct list of factors of both numbers
✓ 1
M1 for selecting the common factors 2 × 3 × 7, or stating that the highest common factor is needed
✓ 1
A1 for 42
✓ 1
Part (b)
B1 for 5, or (84 + 126) ÷ their (a) if it is a whole number; accept '2 red and 3 green'
✓ 1
Exam tip: "Greatest number of equal groups with nothing left over" signals HCF; "next time things happen together" signals LCM.
30IGMC-041-00-10Types of number, factors, HCF and LCMPaper CMedium6 marks
No calculator
For each statement, decide whether it is true or false and justify your answer.
(a)
"The sum of any two prime numbers is always even."
(2)
(b)
"For every positive integer n, the number n2 + n + 1 is prime."
(2)
(c)
"For every positive integer n, the number n2 + n is even."
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 for false
✓ 1
B1 for a correct counter-example using the prime 2 with an odd prime, e.g. 2 + 3 = 5, which is odd
✓ 1
Part (b)
B1 for false
✓ 1
B1 for a correct counter-example with the factorisation or a factor shown, e.g. n = 4 gives 21 = 3 × 7
✓ 1
Part (c)
M1 for a valid general method, e.g. writing n2 + n = n(n + 1), or considering n even and n odd separately
✓ 1
A1 for true with complete reasoning, e.g. n and n + 1 are consecutive integers so one is even, making the product even; or if n is even both terms are even, and if n is odd both terms are odd, so the sum is even in either case
✓ 1
Common error: Checking a few cases does not prove a statement is always true. One counter-example proves it false, but "true" needs a general argument that covers every value of n.
31IGMC-041-00-11Types of number, factors, HCF and LCMPaper CMedium6 marks
No calculator
(a)
Find the lowest common multiple of 6, 8 and 15.
(2)
(b)
Find the smallest square number that is a multiple of 6, 8 and 15.
(2)
(c)
Find the smallest integer greater than 1000 that leaves a remainder of 1 when divided by 6, by 8 and by 15.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 for 23 × 3 × 5 or for listing multiples to a common value
✓ 1
A1 for 120
✓ 1
Part (b)
M1 for 24 × 32 × 52 or for recognising that each prime power of 120 must be made even
✓ 1
A1 for 3600
✓ 1
Part (c)
M1 for 120k + 1 with a multiple of 120 near 1000, e.g. 120 × 9 = 1080
✓ 1
A1 for 1081
✓ 1
Common error: In (b), 120² = 14 400 is a square multiple but not the smallest. Make each prime's power even, which needs only one extra 2, one 3 and one 5.
32IGMC-041-02-07Indices, standard form and surdsPaper CMedium6 marks
No calculator
Answer each part.
(a)
Write these numbers in order of size, starting with the smallest. 4.1 ×10−3 0.0039 3.9 ×10−4 0.04
(2)
(b)
Work out (8.4 ×107) ÷ (2.1 ×10−3). Give your answer in standard form.
(2)
(c)
Work out 3.2 ×104 + 5 ×103. Give your answer in standard form.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1: at least two of the standard form numbers correctly converted, or three of the four in correct relative order
✓ 1
B1: 3.9 ×10−4, 0.0039, 4.1 ×10−3, 0.04
✓ 1
Part (b)
M1: 8.4 ÷ 2.1 = 4 and 7 − (−3) = 10 used
✓ 1
A1: 4 ×1010
✓ 1
Part (c)
M1: 32 000 + 5000 or 3.2 ×104 + 0.5 ×104
✓ 1
A1: 3.7 ×104
✓ 1
Common error: When adding numbers in standard form, do not add the powers. Write both with the same power of ten, or as ordinary numbers, before adding.
33IGMC-041-02-10Indices, standard form and surdsPaper CMedium5 marks
Calculator
The population of the world is 8.1 ×109. The total land area of the world is 1.49 ×108 km2.
(a)
Calculate the average number of people per km2 of land.
(2)
(b)
On average, each person produces 0.74 kg of waste per day. Calculate the total waste produced by the world's population in one year of 365 days. Give your answer in kilograms, in standard form.
(2)
(c)
1 tonne = 1000 kg. Write your answer to part (b) in tonnes, in standard form.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1: (8.1 ×109) ÷ (1.49 ×108)
✓ 1
A1: 54.4
✓ 1
Part (b)
M1: 8.1 ×109 × 0.74 × 365
✓ 1
A1: 2.19 ×1012 kg
✓ 1
Part (c)
B1ft: 2.19 ×109 tonnes (follow through their (b) ÷ 1000)
✓ 1
Exam tip: Dividing by 1000 lowers the power of ten by 3. You can do this without re-entering the whole calculation.
34IGMC-041-01-13Fractions, decimals and percentagesPaper CHard6 marks
Calculator
A trader buys 250 identical lamps for a total of $1800. She sells 60% of the lamps at a profit of 35% on the cost price of each lamp. She sells the rest of the lamps at a loss. Her overall profit on all 250 lamps is 15%.
(a)
Work out the selling price of each of the lamps sold at a profit.
(2)
(b)
Work out the percentage loss on each of the remaining lamps.
(4)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 for 1800 ÷ 250 (= 7.20) seen or implied, then × 1.35
✓ 1
A1 $9.72
✓ 1
Part (b)
M1 for total income 1800 × 1.15 (= 2070) with income 150 × 9.72 (= 1458); OR total profit 0.15 × 1800 (= 270) with profit 150 × 2.52 (= 378)
✓ 1
M1 for (2070 − 1458) ÷ 100 (= 6.12) OR (378 − 270) ÷ 100 (= 1.08 loss per lamp)
✓ 1
M1 for (7.20 − 6.12) ÷ 7.20 × 100 OR 1.08 ÷ 7.20 × 100, or equivalent
✓ 1
A1 15%
✓ 1
Exam tip: Find the cost of one lamp first ($7.20) and the number of lamps in each group (150 and 100). Then use the overall 15% profit to find either the total income or the total profit needed.
35IGMC-041-01-14Fractions, decimals and percentagesPaper CHard6 marks
No calculator
A water tank is \(\frac{3}{8}\) full. When 55 litres of water are added, the tank is \(\frac{5}{6}\) full.
(a)
Work out the capacity of the tank.
(3)
(b)
40% of the water in the tank is then used. Show that the tank is now exactly half full.
(2)
(c)
Work out how many litres of water are needed to fill the tank completely.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 for \(\frac{5}{6} - \frac{3}{8}\) \(\left(= \frac{11}{24}\right)\)
✓ 1
M1 for \(55 \div \frac{11}{24}\) or \(55 \div 11 \times 24\)
✓ 1
A1 for 120 litres
✓ 1
Part (b)
M1 for \(\frac{5}{6} \times 0.6\) or \(\frac{5}{6} \times 120 \times 0.6\) (= 100 × 0.6)
✓ 1
A1 for \(\frac{1}{2}\), or for 60 litres out of 120 litres shown
✓ 1
Part (c)
B1 for 60 litres
✓ 1
Common error: The 55 litres is the difference between the two fractions, not \(\frac{5}{6}\) of the tank. Subtract the fractions first, then divide 55 by that difference.
36IGMC-041-03-14Estimation, rounding, bounds, ratio, proportion and moneyPaper CHard7 marks
No calculator
Three positive quantities x, y and z satisfy x : y = 3 : 4 and y : z = 6 : 5.
(a)
Find the ratio x : y : z in its simplest form.
(2)
(b)
Given that x + y + z = 155, find the values of x and z.
(2)
(c)
The same number, n, is added to both x and z. The ratio of the new values becomes 11 : 12. Find n.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1: both ratios written with the same value of y, e.g. 9 : 12 and 12 : 10
✓ 1
A1: 9 : 12 : 10
✓ 1
Part (b)
M1: 155 ÷ 31 = 5
✓ 1
A1: x = 45 and z = 50
✓ 1
Part (c)
M1: \(\frac{45 + n}{50 + n} = \frac{11}{12}\)
✓ 1
M1: 540 + 12n = 550 + 11n
✓ 1
A1: n = 10
✓ 1
Exam tip: To combine two ratios, make the shared quantity the same in both. Here y becomes 12, the lowest common multiple of 4 and 6.
37IGMC-041-02-13Indices, standard form and surdsPaper CHard6 marks
Calculator
An adult has 5.0 litres of blood. Red blood cells make up 45% of the volume of the blood. The volume of one red blood cell is 9.0 ×10−17 m3. 1 litre = 1 ×10−3 m3.
(a)
Write 5.0 litres in m3, in standard form.
(1)
(b)
Calculate the number of red blood cells in this adult's blood. Give your answer in standard form.
(3)
(c)
Each red blood cell lasts 120 days and is then replaced. The total number of red blood cells stays the same. Calculate the number of red blood cells replaced each second. Give your answer in standard form, correct to 3 significant figures.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1: 5.0 ×10−3 m3
✓ 1
Part (b)
M1: 0.45 × 5.0 ×10−3, giving 2.25 ×10−3
✓ 1
M1: dividing their volume by 9.0 ×10−17
✓ 1
A1: 2.5 ×1013
✓ 1
Part (c)
M1: their (b) ÷ (120 × 24 × 60 × 60)
✓ 1
A1: 2.41 ×106
✓ 1
Common error: In (c), convert 120 days fully into seconds: 120 × 24 × 60 × 60 = 10 368 000. Dividing by 120 × 24 gives cells per hour, not per second.
38IGMC-041-02-05Indices, standard form and surdsPaper EEasy4 marks
No calculator
Simplify each expression. Give your answers in their simplest form.
(a)
\(\sqrt{50}\)
(1)
(b)
\(\sqrt{12} + \sqrt{75}\)
(2)
(c)
\(\sqrt{3} \times \sqrt{27}\)
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1: \(5\sqrt{2}\)
✓ 1
Part (b)
M1: \(2\sqrt{3}\) or \(5\sqrt{3}\) seen
✓ 1
A1: \(7\sqrt{3}\)
✓ 1
Part (c)
B1: 9
✓ 1
Common error: \(\sqrt{12} + \sqrt{75}\) is not \(\sqrt{87}\). Surds can only be added once they share the same root, so simplify each one first.
39IGMC-041-01-08Fractions, decimals and percentagesPaper EMedium6 marks
No calculator
In this question, show all your algebraic working.
(a)
Show that \(0.\dot{2}\dot{7} = \frac{3}{11}\).
(2)
(b)
Write \(0.1\dot{8}\) as a fraction in its simplest form.
(2)
(c)
Hence write \(0.\dot{2}\dot{7} + 0.1\dot{8}\) as a single fraction in its simplest form.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 for \(x = 0.2727...\) and \(100x = 27.2727...\) leading to \(99x = 27\)
✓ 1
A1 \(x = \frac{27}{99} = \frac{3}{11}\) shown
✓ 1
Part (b)
M1 for \(10x = 1.888...\) and \(100x = 18.888...\) leading to \(90x = 17\), or equivalent
✓ 1
A1 \(\frac{17}{90}\)
✓ 1
Part (c)
M1 for \(\frac{270}{990} + \frac{187}{990}\) or other correct common denominator
✓ 1
A1 \(\frac{457}{990}\)
✓ 1
Exam tip: Choose powers of 10 so that the recurring parts line up exactly after the decimal point. Then subtract to remove the recurring part.
40IGMC-041-01-12Fractions, decimals and percentagesPaper EMedium5 marks
Calculator
Lina invests $5000 in an account that pays compound interest.
(a)
The account pays 4% per year. Show that the value of the investment after 4 years is $5849.29, correct to the nearest cent.
(2)
(b)
A different account pays compound interest at \(r\)% per year. An investment of $5000 in this account is worth $6200 after 5 years. Find the value of \(r\), giving your answer correct to 3 significant figures.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 for 5000 × 1.044
✓ 1
A1 5849.2928 seen, rounding to $5849.29
✓ 1
Part (b)
M1 for \(5000\left(1 + \frac{r}{100}\right)^5 = 6200\)
✓ 1
M1 for \(1 + \frac{r}{100} = \sqrt[5]{1.24}\) (= 1.04396...)
✓ 1
A1 \(r\) = 4.40 (accept 4.396 or more accurate)
✓ 1
Exam tip: In a 'show that' question, write a more accurate value (such as 5849.2928) before rounding. This shows the answer was not simply copied.
41IGMC-041-03-07Estimation, rounding, bounds, ratio, proportion and moneyPaper EMedium5 marks
Calculator
y is inversely proportional to the square of x. When x = 5, y = 12.
(a)
Find an expression for y in terms of x.
(2)
(b)
Find y when x = 4.
(1)
(c)
Find the positive value of x when y = 3.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1: \(12 = \frac{k}{5^2}\)
✓ 1
A1: \(y = \frac{300}{x^2}\)
✓ 1
Part (b)
B1: 18.75
✓ 1
Part (c)
M1: \(x^2 = \frac{300}{3} = 100\)
✓ 1
A1: 10
✓ 1
Common error: Inversely proportional to the square means \(y = \frac{k}{x^2}\). Using \(y = \frac{k}{x}\) or \(y = kx^2\) loses every mark that follows.
42IGMC-041-03-08Estimation, rounding, bounds, ratio, proportion and moneyPaper EMedium4 marks
Calculator
A car travels a distance of 350 km, correct to the nearest 10 km. The journey takes 4.2 hours, correct to the nearest 0.1 hour.
(a)
Complete the statement for the distance, d km: …… ≤ d < ……
(1)
(b)
Calculate the upper bound of the average speed of the car.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1: 345 ≤ d < 355
✓ 1
Part (b)
B1: 4.15 used as the lower bound of the time
✓ 1
M1: 355 ÷ 4.15
✓ 1
A1: 85.5 km/h
✓ 1
Exam tip: To make a quotient as large as possible, divide the largest numerator by the smallest denominator.
43IGMC-041-00-09Types of number, factors, HCF and LCMPaper EMedium3 marks
No calculator
Two positive integers have a highest common factor of 12 and a lowest common multiple of 360.
(a)
Explain why 50 cannot be one of the two integers.
(1)
(b)
One of the integers is 72. Find the other integer.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1 for either valid reason: 50 is not a multiple of 12 (both numbers must be multiples of the HCF), OR 50 is not a factor of 360 (both numbers must divide the LCM)
✓ 1
Part (b)
M1 for 12 × 360 ÷ 72, or 4320 ÷ 72, or a correct prime factor method (e.g. 72 = 23 × 32, 360 = 23 × 32 × 5, HCF 12 = 22 × 3)
✓ 1
A1 for 60
✓ 1
Exam tip: For two numbers, HCF × LCM = product of the numbers. Always check your answer: HCF(72, 60) = 12 and LCM(72, 60) = 360.
44IGMC-041-02-06Indices, standard form and surdsPaper EMedium5 marks
No calculator
Rationalise the denominator of each fraction. Give your answers in their simplest form.
(a)
\(\frac{6}{\sqrt{3}}\)
(2)
(b)
\(\frac{4}{3-\sqrt{5}}\)
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1: multiplying numerator and denominator by \(\sqrt{3}\), giving \(\frac{6\sqrt{3}}{3}\)
✓ 1
A1: \(2\sqrt{3}\)
✓ 1
Part (b)
M1: multiplying numerator and denominator by \(3+\sqrt{5}\)
✓ 1
M1: denominator \(9 - 5 = 4\)
✓ 1
A1: \(3+\sqrt{5}\)
✓ 1
Exam tip: For a denominator of the form \(a - \sqrt{b}\), multiply top and bottom by \(a + \sqrt{b}\). The difference of two squares then removes the surd from the denominator.
45IGMC-041-02-08Indices, standard form and surdsPaper EMedium6 marks
No calculator
Solve each equation.
(a)
\(3^x = 81\)
(1)
(b)
\(2^{x+1} = 8^{x-1}\)
(3)
(c)
\(25^y = \frac{1}{125}\)
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1: \(x = 4\)
✓ 1
Part (b)
M1: \(8 = 2^3\) used, giving \(2^{3x-3}\)
✓ 1
M1: \(x + 1 = 3x - 3\)
✓ 1
A1: \(x = 2\)
✓ 1
Part (c)
M1: \(5^{2y} = 5^{-3}\)
✓ 1
A1: \(y = -\frac{3}{2}\)
✓ 1
Exam tip: Write both sides as powers of the same base. Once the bases match, you can set the powers equal to each other.
46IGMC-041-02-09Indices, standard form and surdsPaper EMedium7 marks
No calculator
Simplify each expression.
(a)
\((16x^8)^{\frac{1}{2}}\)
(2)
(b)
\(\frac{12a^5b^{-2}}{3a^{-1}b^3}\)
(3)
(c)
\(\left(\frac{8}{27x^6}\right)^{-\frac{1}{3}}\)
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1: 4
✓ 1
B1: \(x^4\), giving \(4x^4\)
✓ 1
Part (b)
B1: 4
✓ 1
B1: \(a^6\)
✓ 1
B1: \(b^{-5}\) or \(\frac{1}{b^5}\), giving \(\frac{4a^6}{b^5}\)
✓ 1
Part (c)
M1: reciprocal \(\left(\frac{27x^6}{8}\right)^{\frac{1}{3}}\) or cube root \(\frac{2}{3x^2}\) seen
✓ 1
A1: \(\frac{3x^2}{2}\)
✓ 1
Common error: In (b), \(a^5 \div a^{-1}\) is \(a^{5-(-1)} = a^6\), not \(a^4\). Take care when subtracting a negative power.
47IGMC-041-02-11Indices, standard form and surdsPaper EMedium6 marks
No calculator
A rectangle has length \((3+\sqrt{2})\) cm and width \((3-\sqrt{2})\) cm.
(a)
Find the perimeter of the rectangle.
(1)
(b)
Show that the area of the rectangle is a whole number of square centimetres, and find this area.
(2)
(c)
Find the exact length of a diagonal of the rectangle.
M1: one square correctly expanded, \(11 + 6\sqrt{2}\) or \(11 - 6\sqrt{2}\)
✓ 1
A1: \(\sqrt{22}\) cm
✓ 1
Common error: \((3+\sqrt{2})^2\) is not \(9 + 2\). Expand fully to get \(9 + 6\sqrt{2} + 2\). The middle term matters, even though it cancels later here.
48IGMC-041-01-10Fractions, decimals and percentagesPaper EHard5 marks
No calculator
A shop increases the price of an item by a percentage and later decreases the new price by the same percentage.
(a)
The price is increased by 20% and then decreased by 20%. Show that the overall effect is a decrease of 4%.
(2)
(b)
A different price is increased by \(x\)% and then decreased by \(x\)%. The overall effect is a decrease of 9%. Find the value of \(x\).
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 for 1.2 × 0.8
✓ 1
A1 = 0.96, so a 4% decrease, shown
✓ 1
Part (b)
M1 for \(\left(1 + \frac{x}{100}\right)\left(1 - \frac{x}{100}\right) = 0.91\)
✓ 1
M1 for \(1 - \frac{x^2}{10000} = 0.91\) or \(x^2 = 900\)
✓ 1
A1 \(x = 30\)
✓ 1
Exam tip: Write each percentage change as a multiplier and multiply the multipliers together. The product is the overall multiplier.
49IGMC-041-03-12Estimation, rounding, bounds, ratio, proportion and moneyPaper EHard7 marks
Calculator
The area of a rectangular garden bed is 54 m2, correct to the nearest square metre. The length of the bed is 9.0 m, correct to the nearest 0.1 m.
(a)
Calculate the lower bound of the width of the bed.
(3)
(b)
Calculate the upper bound of the width of the bed.
(2)
(c)
Explain whether the width can be stated correctly to 2 significant figures.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
B1: 53.5 and 9.05 identified as the bounds to use
✓ 1
M1: 53.5 ÷ 9.05
✓ 1
A1: 5.91 m
✓ 1
Part (b)
M1: 54.5 ÷ 8.95
✓ 1
A1: 6.09 m
✓ 1
Part (c)
M1: lower bound rounds to 5.9 and upper bound rounds to 6.1 (to 2 s.f.)
✓ 1
A1: No, because the two bounds do not round to the same value
✓ 1
Exam tip: For a lower bound of a quotient, use the smallest numerator and the largest denominator. Swapping them gives the upper bound.
50IGMC-041-03-13Estimation, rounding, bounds, ratio, proportion and moneyPaper EHard6 marks
Calculator
A new car loses 15% of its value in the first year. In each year after the first, it loses 9% of its value at the start of that year.
(a)
Find the number of complete years after which the value of the car first falls below 40% of its value when new. Show clear working.
(3)
(b)
After 4 years, the car is worth $11 230. Calculate the value of the car when it was new. Give your answer correct to the nearest dollar.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1: value after n years = 0.85 × 0.91n−1 × original, or repeated multiplication
✓ 1
M1: after 8 years 0.85 × 0.917 = 0.439… (above 0.4)
✓ 1
A1: 9 years, with 0.85 × 0.918 = 0.3997…
✓ 1
Part (b)
M1: multiplier 0.85 × 0.913 (= 0.6405…)
✓ 1
M1: 11 230 ÷ (0.85 × 0.913)
✓ 1
A1: $17 532
✓ 1
Common error: A 15% loss followed by three 9% losses is not a 42% loss. Multiply the decimal multipliers together, then divide to undo them.
51IGMC-041-00-12Types of number, factors, HCF and LCMPaper EHard5 marks
No calculator
N = 23 × 32 × 5k, where k is a positive integer. The highest common factor of N and 600 is 120.
(a)
Write 600 as a product of its prime factors.
(2)
(b)
Find the value of k.
(2)
(c)
Find the lowest common multiple of N and 600.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 for a correct method reaching 2, 2, 2, 3, 5, 5
✓ 1
A1 for 23 × 3 × 52
✓ 1
Part (b)
M1 for 120 = 23 × 3 × 5, so the lower power of 5 is 51
✓ 1
A1 for k = 1
✓ 1
Part (c)
B1 for 1800
✓ 1
Exam tip: The HCF uses the smaller power of 5 from the two numbers. Since 600 contains 5² but the HCF contains only 5¹, N must contain 5¹.
52IGMC-041-00-13Types of number, factors, HCF and LCMPaper EHard5 marks
No calculator
a and b are positive integers with a < b. The highest common factor of a and b is 6, and a + b = 60.
(a)
Find all the possible pairs of values of a and b.
(4)
(b)
Find the larger of the two possible values of the lowest common multiple of a and b.
(1)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 for writing a = 6p and b = 6q
✓ 1
M1 for p + q = 10
✓ 1
M1 for recognising that p and q must have no common factor other than 1, rejecting (2, 8) and (4, 6)
✓ 1
A1 for a = 6, b = 54 and a = 18, b = 42 only
✓ 1
Part (b)
B1 for 126
✓ 1
Common error: The pair 12 and 48 adds to 60 and both are multiples of 6, but their HCF is 12, not 6. Always check the HCF of each pair you find.
53IGMC-041-00-14Types of number, factors, HCF and LCMPaper EHard6 marks
No calculator
Two runners, Priya and Tomas, run laps of a track at constant speeds. Priya takes 72 seconds per lap and Tomas takes 84 seconds per lap. They start together from the start line.
(a)
Find how long it is until they are next together at the start line. Give your answer in minutes and seconds.
(2)
(b)
Find how many laps Priya has completed at this time.
(1)
(c)
A third runner, Kofi, joins them at the start. His lap time is t seconds, where t is an integer between 62 and 75. All three runners are next together at the start line after exactly 2520 seconds. Find the value of t.
(3)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1 for LCM of 72 and 84, e.g. 23 × 32 × 7 = 504
✓ 1
A1 for 8 minutes 24 seconds
✓ 1
Part (b)
B1 for 7
✓ 1
Part (c)
M1 for 2520 = 23 × 32 × 5 × 7
✓ 1
M1 for recognising that t must be a factor of 2520 containing the factor 5 (since 504 does not)
✓ 1
A1 for t = 70
✓ 1
Exam tip: Compare the new LCM with the old one: 2520 ÷ 504 = 5, so Kofi's lap time must supply the missing factor 5 and also divide 2520. Test 65, 70 and 75 against both conditions.
54IGMC-041-02-12Indices, standard form and surdsPaper EHard7 marks
No calculator
Answer each part. Do not use a calculator, and show all your working.
(a)
Expand and simplify \((2+\sqrt{3})^2\).
(2)
(b)
Write \(\frac{5+\sqrt{3}}{2-\sqrt{3}}\) in the form \(a + b\sqrt{3}\), where \(a\) and \(b\) are integers.
(3)
(c)
Given that \(x = 2+\sqrt{3}\) and \(\frac{1}{x} = 2-\sqrt{3}\), find the value of \(x^2 + \frac{1}{x^2}\). You may use your answer to part (a).
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1: \(4 + 2\sqrt{3} + 2\sqrt{3} + 3\)
✓ 1
A1: \(7 + 4\sqrt{3}\)
✓ 1
Part (b)
M1: multiplying numerator and denominator by \(2+\sqrt{3}\)
M1: \(\frac{1}{x^2} = (2-\sqrt{3})^2 = 7 - 4\sqrt{3}\) and adding: \((7+4\sqrt{3}) + (7-4\sqrt{3})\); OR \(x + \frac{1}{x} = 4\) and using \(x^2+\frac{1}{x^2} = (x+\frac{1}{x})^2 - 2 = 16 - 2\)
✓ 1
A1: 14
✓ 1
Exam tip: In (c), squaring \(2 - \sqrt{3}\) gives the same terms as part (a) with the sign of the surd changed, so the surds cancel when you add. Spotting this saves working.
55IGMC-041-02-14Indices, standard form and surdsPaper EHard7 marks
No calculator
Answer each part. Show all your working.
(a)
Show that \(4^x \times 8^{x-1}\) can be written as \(2^{5x-3}\).
Show that \(\frac{2^{n+3} - 2^{n+1}}{2^n}\) has the same value for every value of \(n\), and find this value.
(2)
Show mark scheme
Marking point
Mark
Notes
Part (a)
M1: \(4^x = 2^{2x}\) and \(8^{x-1} = 2^{3x-3}\)
✓ 1
A1: \(2^{2x + 3x - 3} = 2^{5x-3}\) with no errors seen
✓ 1
Part (b)
B1: \(\frac{1}{4\sqrt{2}} = 2^{-\frac{5}{2}}\)
✓ 1
M1: \(5x - 3 = -\frac{5}{2}\)
✓ 1
A1: \(x = \frac{1}{10}\)
✓ 1
Part (c)
M1: \(\frac{2^n(2^3 - 2^1)}{2^n}\) or \(2^3 - 2^1\)
✓ 1
A1: 6
✓ 1
Common error: \(2^{n+3} - 2^{n+1}\) is not \(2^2\). Subtracting powers of the same base does not subtract the indices. Take out the common factor \(2^n\) first.
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