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Cambridge IGCSE Maths · Topic 2 · 29 cards
Algebra and graphs flashcards
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- Expand and simplify \((x+3)(x-5)\).Multiply every term: \(x^2-5x+3x-15 = x^2-2x-15\).
- How do you factorise a quadratic \(x^2+bx+c\)?Find two numbers that multiply to \(c\) and add to \(b\). E.g. \(x^2+7x+12=(x+3)(x+4)\) because \(3\times4=12\) and \(3+4=7\).
- Factorise \(x^2-49\) and name the pattern.Difference of two squares: \(a^2-b^2=(a-b)(a+b)\), so \(x^2-49=(x-7)(x+7)\).
- (Extended) How do you factorise \(2x^2+7x+3\)?Find two numbers multiplying to \(2\times3=6\) and adding to 7 (6 and 1), split the middle term: \(2x^2+6x+x+3=2x(x+3)+1(x+3)=(2x+1)(x+3)\).
- State the three index laws for multiplying, dividing and raising a power to a power.\(a^m\times a^n=a^{m+n}\); \(a^m\div a^n=a^{m-n}\); \((a^m)^n=a^{mn}\). Also \(a^0=1\) and \(a^{-n}=\frac{1}{a^n}\).
- (Extended) Evaluate \(27^{\frac{2}{3}}\).The denominator is the root, the numerator the power: \(27^{\frac23}=(\sqrt[3]{27})^2=3^2=9\).
- How do you rearrange a formula to make a different letter the subject?Treat it like an equation: undo operations in reverse order, doing the same to both sides. Collect terms in the new subject on one side and factorise if it appears more than once.
- Make \(x\) the subject of \(y=\frac{3x-2}{5}\).Multiply by 5: \(5y=3x-2\). Add 2: \(5y+2=3x\). Divide by 3: \(x=\frac{5y+2}{3}\).
- Solve the simultaneous equations \(x+y=7\), \(2x-y=2\).Add the equations to eliminate \(y\): \(3x=9\), so \(x=3\). Substitute: \(y=4\). Check in \(2x-y=6-4=2\), correct.
- (Extended) State the quadratic formula and when to use it.For \(ax^2+bx+c=0\): \(x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\). Use it when the quadratic will not factorise easily.
- Solve \(x^2-3x-10=0\) by factorising.\((x-5)(x+2)=0\), so \(x=5\) or \(x=-2\).
- (Extended) Write \(x^2+6x+1\) in the form \((x+p)^2+q\).Halve the coefficient of \(x\): \(p=3\). Then \(x^2+6x+1=(x+3)^2-9+1=(x+3)^2-8\).
- Solve the inequality \(3-2x>9\) and state the key rule for inequalities.\(-2x>6\), so \(x<-3\). Multiplying or dividing both sides by a negative number reverses the inequality sign.
- How do you find the \(n\)th term of a linear sequence such as 5, 8, 11, 14?The common difference \(d=3\) gives \(3n\); compare with the first term: \(5-3=2\). So the \(n\)th term is \(3n+2\).
- (Extended) Find the \(n\)th term of the quadratic sequence 3, 8, 15, 24.Second difference is 2, so the \(n^2\) coefficient is \(\frac22=1\). Subtract \(n^2\): 2, 4, 6, 8, which is \(2n\). So the \(n\)th term is \(n^2+2n\).
- (Extended) If \(f(x)=2x+3\) and \(g(x)=x^2\), find \(fg(x)\).\(fg(x)=f(g(x))\): apply \(g\) first, then \(f\). \(fg(x)=2x^2+3\).
- (Extended) How do you find the inverse function \(f^{-1}(x)\) of \(f(x)=\frac{x+4}{3}\)?Write \(y=\frac{x+4}{3}\), swap \(x\) and \(y\), and solve for \(y\): \(x=\frac{y+4}{3}\Rightarrow y=3x-4\). So \(f^{-1}(x)=3x-4\).
- What do \(m\) and \(c\) represent in \(y=mx+c\)?\(m\) is the gradient (steepness) of the line and \(c\) is the \(y\)-intercept, where the line crosses the \(y\)-axis.
- What shape is the graph of \(y=ax^2+bx+c\) and what does the sign of \(a\) tell you?A parabola. If \(a>0\) it opens upwards (U shape, minimum point); if \(a<0\) it opens downwards (\(\cap\) shape, maximum point).
- Describe the shape of the graph of \(y=\frac{1}{x}\).A hyperbola in two branches, never touching the axes. The \(x\)-axis and \(y\)-axis are asymptotes. The graph is undefined at \(x=0\).
- (Extended) What is the general shape of \(y=a^x\) for \(a>1\), and what does it pass through?Exponential growth: it rises ever more steeply, always above the \(x\)-axis (which is an asymptote), and passes through \((0,1)\).
- (Extended) How do you find the gradient of a curve at a point on a graph?Draw a tangent to the curve at that point, then find its gradient using \(\frac{\text{change in }y}{\text{change in }x}\) between two points on the tangent.
- (Extended) How do you differentiate \(y=ax^n\)?Multiply by the power and reduce the power by 1: \(\frac{dy}{dx}=anx^{n-1}\). E.g. \(y=4x^3\) gives \(\frac{dy}{dx}=12x^2\).
- (Extended) Find the \(x\)-coordinates of the turning points of \(y=x^3-12x\).Set \(\frac{dy}{dx}=3x^2-12=0\), so \(x^2=4\) and \(x=\pm2\).
- (Extended) How can you tell whether a turning point is a maximum or minimum?Find \(\frac{d^2y}{dx^2}\) at that point: positive means a minimum, negative means a maximum. Alternatively check the sign of the gradient either side.
- What is the difference between direct and inverse proportion?Direct: \(y\) increases as \(x\) increases, \(y=kx\). Inverse: \(y\) decreases as \(x\) increases, \(y=\frac{k}{x}\). Find \(k\) from known values.
- (Extended) \(y\) is proportional to \(x^2\), and \(y=50\) when \(x=5\). Find \(y\) when \(x=8\).\(y=kx^2\): \(50=25k\), so \(k=2\). Then \(y=2\times64=128\).
- (Extended) Simplify \(\frac{x^2-9}{x^2+3x}\).Factorise: \(\frac{(x-3)(x+3)}{x(x+3)}\). Cancel the common factor \((x+3)\) to get \(\frac{x-3}{x}\).
- (Extended) Solve \(2x^2-5x-1=0\) giving answers to 2 decimal places.\(x=\frac{5\pm\sqrt{25+8}}{4}=\frac{5\pm\sqrt{33}}{4}\), so \(x=2.69\) or \(x=-0.19\).