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1 · IB Maths

Binomial theorem

Pascal’s triangle is the expansion of (x + y)ⁿ written as pure numbers. Pick a row and a term, then add coefficients a and b to build the term of (ax + by)ⁿ.

Predict first

Start from the default power n = 5. If you increase n by one to n = 6, what happens to the row sum 2ⁿ?

Click any entry to select it. Gold: chosen term. Green: the two entries above that add to it. Outlined: the symmetric partner.

(ax + by)ⁿ = Σ ⁿCₖ (ax)ⁿ⁻ᵏ (by)ᵏ
general term: ⁿCₖ aⁿ⁻ᵏ bᵏ xⁿ⁻ᵏ yᵏ
ⁿCₖ = ⁿ⁻¹Cₖ₋₁ + ⁿ⁻¹Cₖ ; ⁿCₖ = ⁿCₙ₋ₖ
row sum: 2ⁿ (a = b = 1)
Expansion of
Coefficient ⁿCₖ
Working
Term k
Pascal’s rule
Row n
Row sum 2ⁿ

Try this

  1. Set n = 6 and step k from 0 to 6. Check that the coefficients read 1, 6, 15, 20, 15, 6, 1, and that the row sum is 2⁶.
  2. Choose n = 8 and k = 3. Which entry is outlined as the partner, and why does it have the same value?
  3. Set n = 7, a = 2, b = −3 and k = 3. Verify the term of (2x − 3y)⁷ by hand from ⁷C₃ × 2⁴ × (−3)³.

Common error: forgetting that a and b are raised to the powers too, so the term of (2x − 3y)⁷ in y³ is ⁷C₃ × 2⁴ × (−3)³ and not 35 × 2 × (−3), and dropping the sign of an odd power of a negative number.